Graphing Parametric Equations: Apply It

  • Find a rectangular equation for a curve defined parametrically.
  • Find parametric equations for curves defined by rectangular equations.

Applications of Parametric Equations

Many of the advantages of parametric equations become obvious when applied to solving real-world problems. Although rectangular equations in x and y give an overall picture of an object’s path, they do not reveal the position of an object at a specific time. Parametric equations, however, illustrate how the values of x and y change depending on t, as the location of a moving object at a particular time.

A common application of parametric equations is solving problems involving projectile motion. In this type of motion, an object is propelled forward in an upward direction forming an angle of [latex]\theta[/latex] to the horizontal, with an initial speed of [latex]{v}_{0}[/latex], and at a height [latex]h[/latex] above the horizontal.

The path of an object propelled at an inclination of [latex]\theta[/latex] to the horizontal, with initial speed [latex]{v}_{0}[/latex], and at a height [latex]h[/latex] above the horizontal, is given by

[latex]\begin{align}x&=\left({v}_{0}\cos \theta \right)t \\ y&=-\frac{1}{2}g{t}^{2}+\left({v}_{0}\sin \theta \right)t+h \end{align}[/latex]

where [latex]g[/latex] accounts for the effects of gravity and [latex]h[/latex] is the initial height of the object. Depending on the units involved in the problem, use [latex]g=32\text{ft}\text{/}{\text{s}}^{2}[/latex] or [latex]g=9.8\text{m}\text{/}{\text{s}}^{2}[/latex]. The equation for [latex]x[/latex] gives horizontal distance, and the equation for [latex]y[/latex] gives the vertical distance.

How To: Given a projectile motion problem, use parametric equations to solve.

  1. The horizontal distance is given by [latex]x=\left({v}_{0}\cos \theta \right)t[/latex]. Substitute the initial speed of the object for [latex]{v}_{0}[/latex].
  2. The expression [latex]\cos \theta[/latex] indicates the angle at which the object is propelled. Substitute that angle in degrees for [latex]\cos \theta[/latex].
  3. The vertical distance is given by the formula [latex]y=-\frac{1}{2}g{t}^{2}+\left({v}_{0}\sin \theta \right)t+h[/latex]. The term [latex]-\frac{1}{2}g{t}^{2}[/latex] represents the effect of gravity. Depending on units involved, use [latex]g=32{\text{ft/s}}^{2}[/latex] or [latex]g=9.8{\text{m/s}}^{2}[/latex]. Again, substitute the initial speed for [latex]{v}_{0}[/latex], and the height at which the object was propelled for [latex]h[/latex].
  4. Proceed by calculating each term to solve for [latex]t[/latex].
Solve the problem presented at the beginning of this section. Does the batter hit the game-winning home run? Assume that the ball is hit with an initial velocity of 140 feet per second at an angle of [latex]45^\circ[/latex] to the horizontal, making contact 3 feet above the ground.

  1. Find the parametric equations to model the path of the baseball.
  2. Where is the ball after 2 seconds?
  3. How long is the ball in the air?
  4. Is it a home run?