- Factor trinomials with a = 1
Factoring a Trinomial with Leading Coefficient of 1
Although we should always begin by looking for a GCF, pulling out the GCF is not the only way that polynomial expressions can be factored. The polynomial [latex]{x}^{2}+5x+6[/latex] has a GCF of 1, but it can be written as the product of the factors [latex]\left(x+2\right)[/latex] and [latex]\left(x+3\right)[/latex].
Factoring a Trinomial (Leading Coefficient [latex]= 1[/latex])
A trinomial of the form [latex]{x}^{2}+bx+c[/latex] can be written in factored form as [latex]\left(x+p\right)\left(x+q\right)[/latex] where [latex]pq=c[/latex] and [latex]p+q=b[/latex].
- List factors of [latex]c[/latex].
- Find [latex]p[/latex] and [latex]q[/latex], a pair of factors of [latex]c[/latex] with a sum of [latex]b[/latex].
- Write the factored expression [latex]\left(x+p\right)\left(x+q\right)[/latex].
Solution
- We have a trinomial with leading coefficient [latex]1,b=2[/latex], and [latex]c=-15[/latex].
- We need to find two numbers with a product of [latex]-15[/latex] and a sum of [latex]2[/latex].
In the table, we list factors until we find a pair with the desired sum.
| Factors of [latex]-15[/latex] | Sum of Factors |
|---|---|
| [latex]1,-15[/latex] | [latex]-14[/latex] |
| [latex]-1,15[/latex] | [latex]14[/latex] |
| [latex]3,-5[/latex] | [latex]-2[/latex] |
| [latex]-3,5[/latex] | [latex]2[/latex] |
- Now that we have identified [latex]p[/latex] and [latex]q[/latex] as [latex]-3[/latex] and [latex]5[/latex], write the factored form as [latex]\left(x - 3\right)\left(x+5\right)[/latex].
Thus, [latex]{x}^{2}+2x - 15 = \left(x - 3\right)\left(x+5\right)[/latex]