{"id":9438,"date":"2023-10-20T19:21:49","date_gmt":"2023-10-20T19:21:49","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/?post_type=chapter&#038;p=9438"},"modified":"2023-12-13T17:31:03","modified_gmt":"2023-12-13T17:31:03","slug":"quadratic-functions-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/quadratic-functions-learn-it-2\/","title":{"raw":"Quadratic Functions: Learn It 2","rendered":"Quadratic Functions: Learn It 2"},"content":{"raw":"<h2>Finding the Domain and Range of a Quadratic Function<\/h2>\r\n<p>Any number can be the input value of a quadratic function. Therefore the <strong>domain<\/strong> of any quadratic function is all real numbers. Because parabolas have a maximum or a minimum at the vertex, the range is restricted. Since the vertex of a parabola will be either a maximum or a minimum, the <strong>range<\/strong> will consist of all [latex]y[\/latex]-values greater than or equal to the [latex]y[\/latex]-coordinate of the vertex or less than or equal to the [latex]y[\/latex]-coordinate at the turning point, depending on whether the parabola opens up or down.<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<h3>domain and range of a quadratic function<\/h3>\r\n<p>The<strong> domain of any quadratic function<\/strong> is all real numbers.<\/p>\r\n<p>&nbsp;<\/p>\r\n\r\nDetermining the <strong>range of a quadratic formula<\/strong> is different depending on which form the quadratic function is in:\r\n\r\n<p>&nbsp;<\/p>\r\n<p><strong>General Form<\/strong><\/p>\r\n<ul>\r\n\t<li>The range of a quadratic function written in general form with a positive [latex]a[\/latex] value is [latex]f\\left(x\\right)\\ge f\\left(-\\frac{b}{2a}\\right)[\/latex], or [latex]\\left[f\\left(-\\frac{b}{2a}\\right),\\infty \\right)[\/latex]<\/li>\r\n\t<li>The range of a quadratic function written in general form with a negative [latex]a[\/latex] value is [latex]f\\left(x\\right)\\le f\\left(-\\frac{b}{2a}\\right)[\/latex], or [latex]\\left(-\\infty ,f\\left(-\\frac{b}{2a}\\right)\\right][\/latex].<\/li>\r\n<\/ul>\r\n<p><strong>Standard Form<\/strong><\/p>\r\n<ul>\r\n\t<li>The range of a quadratic function written in standard form [latex]f\\left(x\\right)=a{\\left(x-h\\right)}^{2}+k[\/latex] with a positive [latex]a[\/latex] value is [latex]f\\left(x\\right)\\ge k[\/latex] or [latex][k,\\infty)[\/latex].<\/li>\r\n\t<li>The range of a quadratic function written in standard form with a negative [latex]a[\/latex] value is [latex]f\\left(x\\right)\\le k[\/latex] or or [latex](-\\infty,k][\/latex].<\/li>\r\n<\/ul>\r\n<\/section>\r\n<section class=\"textbox questionHelp\"><strong>How to: Determine the Domain and Range from the Vertex<\/strong>\r\n<ol>\r\n\t<li>The domain of any quadratic function is all real numbers.<\/li>\r\n\t<li>Determine whether [latex]a[\/latex] is positive or negative. <br \/>\r\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If [latex]a[\/latex] is positive, the parabola has a minimum. <br \/>\r\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If [latex]a[\/latex] is negative, the parabola has a maximum.<\/li>\r\n\t<li>Determine the maximum or minimum value of the parabola, [latex]k[\/latex].<br \/>\r\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If the parabola has a minimum, the range is given by [latex]f\\left(x\\right)\\ge k[\/latex], or [latex]\\left[k,\\infty \\right)[\/latex]. <br \/>\r\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If the parabola has a maximum, the range is given by [latex]f\\left(x\\right)\\le k[\/latex], or [latex]\\left(-\\infty ,k\\right][\/latex].<\/li>\r\n<\/ol>\r\n<\/section>\r\n<section class=\"textbox example\">\r\n<p>Find the domain and range of [latex]f\\left(x\\right)=-5{x}^{2}+9x - 1[\/latex].<\/p>\r\n<p>[reveal-answer q=\"40392\"]Show Solution[\/reveal-answer]<\/p>\r\n<p>[hidden-answer a=\"40392\"]<\/p>\r\n<p>As with any quadratic function, the domain is all real numbers or [latex]\\left(-\\infty,\\infty\\right)[\/latex].<\/p>\r\n<p>Because [latex]a[\/latex] is negative, the parabola opens downward and has a maximum value. We need to determine the maximum value. We can begin by finding the [latex]x[\/latex]-value of the vertex.<\/p>\r\n<p style=\"text-align: center;\">[latex]h=-\\dfrac{b}{2a}=-\\dfrac{9}{2\\left(-5\\right)}=\\dfrac{9}{10}[\/latex]<\/p>\r\n<p>The maximum value is given by [latex]f\\left(h\\right)[\/latex].<\/p>\r\n<p style=\"text-align: center;\">[latex]f\\left(\\dfrac{9}{10}\\right)=5{\\left(\\dfrac{9}{10}\\right)}^{2}+9\\left(\\dfrac{9}{10}\\right)-1=\\dfrac{61}{20}[\/latex]<\/p>\r\n<p>The range is [latex]f\\left(x\\right)\\le \\dfrac{61}{20}[\/latex], or [latex]\\left(-\\infty ,\\dfrac{61}{20}\\right][\/latex].<\/p>\r\n<p>[\/hidden-answer]<\/p>\r\n<\/section>\r\n<section class=\"textbox tryIt\">\r\n<p>[ohm2_question hide_question_numbers=1]13807[\/ohm2_question]<\/p>\r\n<\/section>","rendered":"<h2>Finding the Domain and Range of a Quadratic Function<\/h2>\n<p>Any number can be the input value of a quadratic function. Therefore the <strong>domain<\/strong> of any quadratic function is all real numbers. Because parabolas have a maximum or a minimum at the vertex, the range is restricted. Since the vertex of a parabola will be either a maximum or a minimum, the <strong>range<\/strong> will consist of all [latex]y[\/latex]-values greater than or equal to the [latex]y[\/latex]-coordinate of the vertex or less than or equal to the [latex]y[\/latex]-coordinate at the turning point, depending on whether the parabola opens up or down.<\/p>\n<section class=\"textbox keyTakeaway\">\n<h3>domain and range of a quadratic function<\/h3>\n<p>The<strong> domain of any quadratic function<\/strong> is all real numbers.<\/p>\n<p>&nbsp;<\/p>\n<p>Determining the <strong>range of a quadratic formula<\/strong> is different depending on which form the quadratic function is in:<\/p>\n<p>&nbsp;<\/p>\n<p><strong>General Form<\/strong><\/p>\n<ul>\n<li>The range of a quadratic function written in general form with a positive [latex]a[\/latex] value is [latex]f\\left(x\\right)\\ge f\\left(-\\frac{b}{2a}\\right)[\/latex], or [latex]\\left[f\\left(-\\frac{b}{2a}\\right),\\infty \\right)[\/latex]<\/li>\n<li>The range of a quadratic function written in general form with a negative [latex]a[\/latex] value is [latex]f\\left(x\\right)\\le f\\left(-\\frac{b}{2a}\\right)[\/latex], or [latex]\\left(-\\infty ,f\\left(-\\frac{b}{2a}\\right)\\right][\/latex].<\/li>\n<\/ul>\n<p><strong>Standard Form<\/strong><\/p>\n<ul>\n<li>The range of a quadratic function written in standard form [latex]f\\left(x\\right)=a{\\left(x-h\\right)}^{2}+k[\/latex] with a positive [latex]a[\/latex] value is [latex]f\\left(x\\right)\\ge k[\/latex] or [latex][k,\\infty)[\/latex].<\/li>\n<li>The range of a quadratic function written in standard form with a negative [latex]a[\/latex] value is [latex]f\\left(x\\right)\\le k[\/latex] or or [latex](-\\infty,k][\/latex].<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox questionHelp\"><strong>How to: Determine the Domain and Range from the Vertex<\/strong><\/p>\n<ol>\n<li>The domain of any quadratic function is all real numbers.<\/li>\n<li>Determine whether [latex]a[\/latex] is positive or negative. <br \/>\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If [latex]a[\/latex] is positive, the parabola has a minimum. <br \/>\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If [latex]a[\/latex] is negative, the parabola has a maximum.<\/li>\n<li>Determine the maximum or minimum value of the parabola, [latex]k[\/latex].<br \/>\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If the parabola has a minimum, the range is given by [latex]f\\left(x\\right)\\ge k[\/latex], or [latex]\\left[k,\\infty \\right)[\/latex]. <br \/>\n\u00a0 \u00a0 \u00a0 \u00a0 \u00a0If the parabola has a maximum, the range is given by [latex]f\\left(x\\right)\\le k[\/latex], or [latex]\\left(-\\infty ,k\\right][\/latex].<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\">\n<p>Find the domain and range of [latex]f\\left(x\\right)=-5{x}^{2}+9x - 1[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q40392\">Show Solution<\/button><\/p>\n<div id=\"q40392\" class=\"hidden-answer\" style=\"display: none\">\n<p>As with any quadratic function, the domain is all real numbers or [latex]\\left(-\\infty,\\infty\\right)[\/latex].<\/p>\n<p>Because [latex]a[\/latex] is negative, the parabola opens downward and has a maximum value. We need to determine the maximum value. We can begin by finding the [latex]x[\/latex]-value of the vertex.<\/p>\n<p style=\"text-align: center;\">[latex]h=-\\dfrac{b}{2a}=-\\dfrac{9}{2\\left(-5\\right)}=\\dfrac{9}{10}[\/latex]<\/p>\n<p>The maximum value is given by [latex]f\\left(h\\right)[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]f\\left(\\dfrac{9}{10}\\right)=5{\\left(\\dfrac{9}{10}\\right)}^{2}+9\\left(\\dfrac{9}{10}\\right)-1=\\dfrac{61}{20}[\/latex]<\/p>\n<p>The range is [latex]f\\left(x\\right)\\le \\dfrac{61}{20}[\/latex], or [latex]\\left(-\\infty ,\\dfrac{61}{20}\\right][\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\">\n<iframe loading=\"lazy\" id=\"ohm13807\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=13807&theme=lumen&iframe_resize_id=ohm13807&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><br \/>\n<\/section>\n","protected":false},"author":15,"menu_order":31,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"Revision and Adaptation\",\"author\":\"\",\"organization\":\"Lumen Learning\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"College Algebra\",\"author\":\"Jay Abramson\",\"organization\":\"OpenStax\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Access for free at https:\/\/openstax.org\/books\/college-algebra\/pages\/1-introduction-to-prerequisites\"}]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":72,"module-header":"learn_it","content_attributions":[{"type":"original","description":"Revision and Adaptation","author":"","organization":"Lumen Learning","url":"","project":"","license":"cc-by","license_terms":""},{"type":"cc","description":"College Algebra","author":"Jay Abramson","organization":"OpenStax","url":"","project":"","license":"cc-by","license_terms":"Access for free at https:\/\/openstax.org\/books\/college-algebra\/pages\/1-introduction-to-prerequisites"}],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/9438"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":22,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/9438\/revisions"}],"predecessor-version":[{"id":12602,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/9438\/revisions\/12602"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/72"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/9438\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=9438"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=9438"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=9438"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=9438"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}