{"id":8973,"date":"2023-10-12T18:08:19","date_gmt":"2023-10-12T18:08:19","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/?post_type=chapter&#038;p=8973"},"modified":"2024-10-18T20:58:41","modified_gmt":"2024-10-18T20:58:41","slug":"weighted-voting-learn-it-3","status":"web-only","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/weighted-voting-learn-it-3\/","title":{"raw":"Weighted Voting: Learn It 3","rendered":"Weighted Voting: Learn It 3"},"content":{"raw":"<h2>Calculating Power: Banzhaf Power Index<\/h2>\r\n<p>The <strong>Banzhaf power index<\/strong> was originally created in 1946 by Lionel Penrose, but was reintroduced by John Banzhaf in 1965. The power index is a numerical way of looking at power in a weighted voting situation.<\/p>\r\n<section class=\"textbox questionHelp\">\r\n<p><strong>How To: Calculating Banzhaf Power Index<\/strong><\/p>\r\n<p>To calculate the Banzhaf power index:<\/p>\r\n<ol style=\"list-style-type: decimal;\">\r\n\t<li>List all winning coalitions<\/li>\r\n\t<li>In each coalition, identify the players who are critical<\/li>\r\n\t<li>Count up how many times each player is critical<\/li>\r\n\t<li>Convert these counts to fractions or decimals by dividing by the total times any player is critical.<\/li>\r\n<\/ol>\r\n<\/section>\r\n<section class=\"textbox example\">Revisiting the Scottish Parliament, with voting system [latex][65:47,46,17,16,2][\/latex], the winning coalitions are listed, with the critical players underlined.\r\n\r\n\r\n<p>The winning coalitions are listed below, with the critical players underlined.<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{ll} \\left\\{\\underline{P}_{1}, \\underline{P}_{2}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}\\right\\} &amp; \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{4}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{5}\\right\\} &amp; \\left\\{\\underline{P}_{1}, \\underline{P}_{3}, \\underline{P}_{4}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{3}, \\underline{P}_{5}\\right\\} &amp; \\left\\{\\underline{P}_1, \\underline{P}_{4}, \\underline{P}_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, \\underline{P}_{4}\\right\\} &amp; \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, \\underline{P}_{5}\\right\\}\\\\ \\left\\{P_{1}, P_{2}, P_{3}, P_{4}\\right\\} &amp; \\left\\{P_{1}, P_{2}, P_{3}, P_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, P_{2}, P_{4}, P_{5}\\right\\} &amp; \\left\\{\\underline{P}_{1}, P_{3}, P_{4}, P_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, P_{4}, P_{5}\\right\\} &amp; \\\\ \\left\\{P_{1}, P_{2}, P_{3}, P_{4}, P_{5}\\right\\} &amp; \\end{array} [\/latex]<\/p>\r\n<p>Counting up times that each player is critical:<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|l|} \\hline \\textbf { District } &amp; \\textbf { Times critical } &amp; \\textbf { Power index } \\\\ \\hline P_{1} \\text { (Scottish National Party) } &amp; 9 &amp; 9 \/ 27=33.3 \\% \\\\ \\hline P_{2} \\text { (Labour Party) } &amp; 7 &amp; 7 \/ 27=25.9 \\% \\\\ \\hline P_{3} \\text { (Conservative Party) } &amp; 5 &amp; 5 \/ 27=18.5 \\% \\\\ \\hline P_{4} \\text { (Liberal Democrats Party) } &amp; 3 &amp; 3 \/ 27=11.1 \\% \\\\ \\hline P_{5} \\text { (Scottish Green Party) } &amp; 3 &amp; 3 \/ 27=11.1 \\% \\\\ \\hline \\end{array} [\/latex]<\/p>\r\n<p>Interestingly, even though the Liberal Democrats party has only one less representative than the Conservative Party, and [latex]14[\/latex] more than the Scottish Green Party, their Banzhaf power index is the same as the Scottish Green Party\u2019s. In parliamentary governments, forming coalitions is an essential part of getting results, and a party\u2019s ability to help a coalition reach quota defines its influence.<\/p>\r\n<\/section>\r\n<section class=\"textbox example\">Consider the voting system [latex][16:7,6,3,3,2][\/latex]. Find the Banzhaf power index. [reveal-answer q=\"4331\"]Show Solution[\/reveal-answer] [hidden-answer a=\"4331\"]\r\n\r\n\r\n<p>The winning coalitions are listed below, with the critical players underlined.<\/p>\r\n<p style=\"text-align: center;\">[latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{3}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{4}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}, P_{4}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{3}, P_{5}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{4}, P_{5}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}, P_{4}, P_{5}\\right\\}[\/latex]<\/p>\r\n<p>Counting up times that each player is critical:<\/p>\r\n<p style=\"text-align: center;\">[latex]P_{1}=6[\/latex] [latex]P_{2}=6[\/latex] [latex]P_{3}=2[\/latex] [latex]P_{4}=2[\/latex] [latex]P_{5}=0[\/latex]<\/p>\r\n<p>Total of all: [latex]16[\/latex]<\/p>\r\n<p>Divide each player\u2019s count by [latex]16[\/latex] to convert to fractions or percents:<\/p>\r\n<p style=\"text-align: center;\">[latex]P_{1}=6 \/ 16=3 \/ 8=37.5 \\%[\/latex] [latex]P_{2}=6 \/ 16=3 \/ 8=37.5 \\%[\/latex] [latex]P_{3}=2 \/ 16=1 \/ 8=12.5 \\%[\/latex] [latex]P_{4}=2 \/ 16=1 \/ 8=12.5 \\%[\/latex] [latex]P_{5}=0 \/ 16=0=0 \\%[\/latex]<\/p>\r\n\r\n\r\n[\/hidden-answer]<\/section>\r\n<p>The Banzhaf power index measures a player\u2019s ability to influence the outcome of the vote. Notice that player 5 has a power index of [latex]0[\/latex], indicating that there is no coalition in which they would be critical power and could influence the outcome. This means player 5 is a dummy, as we noted earlier.<\/p>\r\n<section class=\"textbox tryIt\">\r\n<p>[ohm2_question hide_question_numbers=1]13273[\/ohm2_question]<\/p>\r\n<\/section>\r\n<section class=\"textbox example\">Banzhaf used this index to argue that the weighted voting system used in the Nassau County Board of Supervisors in New York was unfair. The county was divided up into [latex]6[\/latex] districts, each getting voting weight proportional to the population in the district, as shown below. Calculate the power index for each district. \r\n\r\n\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|} \\hline \\textbf { District } &amp; \\textbf { Weight } \\\\ \\hline \\text { Hempstead #1 } &amp; 31 \\\\ \\hline \\text { Hempstead #2 } &amp; 31 \\\\ \\hline \\text { Oyster Bay } &amp; 28 \\\\ \\hline \\text { North Hempstead } &amp; 21 \\\\ \\hline \\text { Long Beach } &amp; 2 \\\\ \\hline \\text { Glen Cove } &amp; 2 \\\\ \\hline \\end{array} [\/latex]<\/p>\r\n [reveal-answer q=\"4332\"]Show Solution[\/reveal-answer] [hidden-answer a=\"4332\"]\r\n\r\n\r\n<p>Translated into a weighted voting system, assuming a simple majority is needed for a proposal to pass:<\/p>\r\n<p style=\"text-align: center;\">[latex][58: 31, 31, 28, 21, 2, 2][\/latex]<\/p>\r\n<p>Listing the winning coalitions and marking critical players:<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{array} {lll} {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{LB}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{GC}}\\} \\\\{\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{GC}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{LB}, \\mathrm{GC}}\\} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{LB}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{GC}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{GC}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{LB}, \\mathrm{GC}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{LB}\\}} &amp; {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB} . \\mathrm{GC}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{GC}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{GC}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{LB}, \\mathrm{GC}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{LB}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}} &amp; {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{GC}\\}} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{GC}\\}} \\\\ {} &amp; {} &amp; {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}}\\end{array} [\/latex]<\/p>\r\n<p>There are a lot of them! Counting up how many times each player is critical,<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|l|} \\hline \\textbf { District } &amp; \\textbf { Times critical } &amp; \\textbf { Power index } \\\\ \\hline \\text { Hempstead #1 } &amp; 16 &amp; 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { Hempstead #2 } &amp; 16 &amp; 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { Oyster Bay } &amp; 16 &amp; 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { North Hempstead } &amp; 0 &amp; 0 \/ 48=0 \\% \\\\ \\hline \\text { Long Beach } &amp; 0 &amp; 0 \/ 48=0 \\% \\\\ \\hline \\text { Glen Cove } &amp; 0 &amp; 0 \/ 48=0 \\% \\\\ \\hline \\end{array} [\/latex]<\/p>\r\n<p>It turns out that the three smaller districts are dummies. Any winning coalition requires two of the larger districts.<\/p>\r\n\r\n\r\n[\/hidden-answer]<\/section>\r\n<p>The weighted voting system that Americans are most familiar with is the Electoral College system used to elect the President. In the Electoral College, states are given a number of votes equal to the number of their congressional representatives (house + senate). Most states give all their electoral votes to the candidate that wins a majority in their state, turning the Electoral College into a weighted voting system, in which the states are the players. As I\u2019m sure you can imagine, there are billions of possible winning coalitions, so the power index for the Electoral College has to be computed by a computer using approximation techniques.<\/p>","rendered":"<h2>Calculating Power: Banzhaf Power Index<\/h2>\n<p>The <strong>Banzhaf power index<\/strong> was originally created in 1946 by Lionel Penrose, but was reintroduced by John Banzhaf in 1965. The power index is a numerical way of looking at power in a weighted voting situation.<\/p>\n<section class=\"textbox questionHelp\">\n<p><strong>How To: Calculating Banzhaf Power Index<\/strong><\/p>\n<p>To calculate the Banzhaf power index:<\/p>\n<ol style=\"list-style-type: decimal;\">\n<li>List all winning coalitions<\/li>\n<li>In each coalition, identify the players who are critical<\/li>\n<li>Count up how many times each player is critical<\/li>\n<li>Convert these counts to fractions or decimals by dividing by the total times any player is critical.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\">Revisiting the Scottish Parliament, with voting system [latex][65:47,46,17,16,2][\/latex], the winning coalitions are listed, with the critical players underlined.<\/p>\n<p>The winning coalitions are listed below, with the critical players underlined.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{ll} \\left\\{\\underline{P}_{1}, \\underline{P}_{2}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}\\right\\} & \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{4}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{5}\\right\\} & \\left\\{\\underline{P}_{1}, \\underline{P}_{3}, \\underline{P}_{4}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, \\underline{P}_{3}, \\underline{P}_{5}\\right\\} & \\left\\{\\underline{P}_1, \\underline{P}_{4}, \\underline{P}_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, \\underline{P}_{4}\\right\\} & \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, \\underline{P}_{5}\\right\\}\\\\ \\left\\{P_{1}, P_{2}, P_{3}, P_{4}\\right\\} & \\left\\{P_{1}, P_{2}, P_{3}, P_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{1}, P_{2}, P_{4}, P_{5}\\right\\} & \\left\\{\\underline{P}_{1}, P_{3}, P_{4}, P_{5}\\right\\} \\\\ \\left\\{\\underline{P}_{2}, \\underline{P}_{3}, P_{4}, P_{5}\\right\\} & \\\\ \\left\\{P_{1}, P_{2}, P_{3}, P_{4}, P_{5}\\right\\} & \\end{array}[\/latex]<\/p>\n<p>Counting up times that each player is critical:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|l|} \\hline \\textbf { District } & \\textbf { Times critical } & \\textbf { Power index } \\\\ \\hline P_{1} \\text { (Scottish National Party) } & 9 & 9 \/ 27=33.3 \\% \\\\ \\hline P_{2} \\text { (Labour Party) } & 7 & 7 \/ 27=25.9 \\% \\\\ \\hline P_{3} \\text { (Conservative Party) } & 5 & 5 \/ 27=18.5 \\% \\\\ \\hline P_{4} \\text { (Liberal Democrats Party) } & 3 & 3 \/ 27=11.1 \\% \\\\ \\hline P_{5} \\text { (Scottish Green Party) } & 3 & 3 \/ 27=11.1 \\% \\\\ \\hline \\end{array}[\/latex]<\/p>\n<p>Interestingly, even though the Liberal Democrats party has only one less representative than the Conservative Party, and [latex]14[\/latex] more than the Scottish Green Party, their Banzhaf power index is the same as the Scottish Green Party\u2019s. In parliamentary governments, forming coalitions is an essential part of getting results, and a party\u2019s ability to help a coalition reach quota defines its influence.<\/p>\n<\/section>\n<section class=\"textbox example\">Consider the voting system [latex][16:7,6,3,3,2][\/latex]. Find the Banzhaf power index. <\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q4331\">Show Solution<\/button> <\/p>\n<div id=\"q4331\" class=\"hidden-answer\" style=\"display: none\">\n<p>The winning coalitions are listed below, with the critical players underlined.<\/p>\n<p style=\"text-align: center;\">[latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{3}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{4}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}, P_{4}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{3}, P_{5}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, \\underline{P}_{4}, P_{5}\\right\\}[\/latex] [latex]\\left\\{\\underline{P}_{1}, \\underline{P}_{2}, P_{3}, P_{4}, P_{5}\\right\\}[\/latex]<\/p>\n<p>Counting up times that each player is critical:<\/p>\n<p style=\"text-align: center;\">[latex]P_{1}=6[\/latex] [latex]P_{2}=6[\/latex] [latex]P_{3}=2[\/latex] [latex]P_{4}=2[\/latex] [latex]P_{5}=0[\/latex]<\/p>\n<p>Total of all: [latex]16[\/latex]<\/p>\n<p>Divide each player\u2019s count by [latex]16[\/latex] to convert to fractions or percents:<\/p>\n<p style=\"text-align: center;\">[latex]P_{1}=6 \/ 16=3 \/ 8=37.5 \\%[\/latex] [latex]P_{2}=6 \/ 16=3 \/ 8=37.5 \\%[\/latex] [latex]P_{3}=2 \/ 16=1 \/ 8=12.5 \\%[\/latex] [latex]P_{4}=2 \/ 16=1 \/ 8=12.5 \\%[\/latex] [latex]P_{5}=0 \/ 16=0=0 \\%[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<p>The Banzhaf power index measures a player\u2019s ability to influence the outcome of the vote. Notice that player 5 has a power index of [latex]0[\/latex], indicating that there is no coalition in which they would be critical power and could influence the outcome. This means player 5 is a dummy, as we noted earlier.<\/p>\n<section class=\"textbox tryIt\">\n<iframe loading=\"lazy\" id=\"ohm13273\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=13273&theme=lumen&iframe_resize_id=ohm13273&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><br \/>\n<\/section>\n<section class=\"textbox example\">Banzhaf used this index to argue that the weighted voting system used in the Nassau County Board of Supervisors in New York was unfair. The county was divided up into [latex]6[\/latex] districts, each getting voting weight proportional to the population in the district, as shown below. Calculate the power index for each district. <\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|} \\hline \\textbf { District } & \\textbf { Weight } \\\\ \\hline \\text { Hempstead #1 } & 31 \\\\ \\hline \\text { Hempstead #2 } & 31 \\\\ \\hline \\text { Oyster Bay } & 28 \\\\ \\hline \\text { North Hempstead } & 21 \\\\ \\hline \\text { Long Beach } & 2 \\\\ \\hline \\text { Glen Cove } & 2 \\\\ \\hline \\end{array}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q4332\">Show Solution<\/button> <\/p>\n<div id=\"q4332\" class=\"hidden-answer\" style=\"display: none\">\n<p>Translated into a weighted voting system, assuming a simple majority is needed for a proposal to pass:<\/p>\n<p style=\"text-align: center;\">[latex][58: 31, 31, 28, 21, 2, 2][\/latex]<\/p>\n<p>Listing the winning coalitions and marking critical players:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array} {lll} {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{LB}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{GC}}\\} \\\\{\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{GC}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{LB}, \\mathrm{GC}}\\} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{LB}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{GC}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{GC}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{LB}, \\mathrm{GC}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{LB}\\}} & {\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{OB}}, \\mathrm{NH}, \\mathrm{LB} . \\mathrm{GC}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{GC}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{NH}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{GC}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{LB}, \\mathrm{GC}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{LB}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{LB}\\}} \\\\{\\{\\underline{\\mathrm{H} 1}, \\underline{\\mathrm{H} 2}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}} & {\\{\\underline{\\mathrm{H} 2}, \\underline{\\mathrm{OB}}, \\mathrm{GC}\\}} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{GC}\\}} \\\\ {} & {} & {\\{\\mathrm{H} 1, \\mathrm{H} 2, \\mathrm{OB}, \\mathrm{NH}, \\mathrm{LB}, \\mathrm{GC}\\}}\\end{array}[\/latex]<\/p>\n<p>There are a lot of them! Counting up how many times each player is critical,<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{|l|l|l|} \\hline \\textbf { District } & \\textbf { Times critical } & \\textbf { Power index } \\\\ \\hline \\text { Hempstead #1 } & 16 & 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { Hempstead #2 } & 16 & 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { Oyster Bay } & 16 & 16 \/ 48=1 \/ 3=33 \\% \\\\ \\hline \\text { North Hempstead } & 0 & 0 \/ 48=0 \\% \\\\ \\hline \\text { Long Beach } & 0 & 0 \/ 48=0 \\% \\\\ \\hline \\text { Glen Cove } & 0 & 0 \/ 48=0 \\% \\\\ \\hline \\end{array}[\/latex]<\/p>\n<p>It turns out that the three smaller districts are dummies. Any winning coalition requires two of the larger districts.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<p>The weighted voting system that Americans are most familiar with is the Electoral College system used to elect the President. In the Electoral College, states are given a number of votes equal to the number of their congressional representatives (house + senate). Most states give all their electoral votes to the candidate that wins a majority in their state, turning the Electoral College into a weighted voting system, in which the states are the players. As I\u2019m sure you can imagine, there are billions of possible winning coalitions, so the power index for the Electoral College has to be computed by a computer using approximation techniques.<\/p>\n","protected":false},"author":15,"menu_order":25,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"Math in Society (Lippman)\",\"author\":\"David Lippman\",\"organization\":\"LibreTexts Mathematics\",\"url\":\"https:\/\/math.libretexts.org\/Bookshelves\/Applied_Mathematics\/Math_in_Society_(Lippman)\/03%3A_Weighted_Voting\/3.04%3A_Calculating_Power-__Banzhaf_Power_Index\",\"project\":\"3.4: Calculating Power- Banzhaf Power Index\",\"license\":\"cc-by-sa\",\"license_terms\":\"Access for free at https:\/\/math.libretexts.org\/Bookshelves\/Applied_Mathematics\/Math_in_Society_(Lippman)\"}]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":90,"module-header":"learn_it","content_attributions":[{"type":"cc-attribution","description":"Math in Society (Lippman)","author":"David Lippman","organization":"LibreTexts Mathematics","url":"https:\/\/math.libretexts.org\/Bookshelves\/Applied_Mathematics\/Math_in_Society_(Lippman)\/03%3A_Weighted_Voting\/3.04%3A_Calculating_Power-__Banzhaf_Power_Index","project":"3.4: Calculating Power- Banzhaf Power Index","license":"cc-by-sa","license_terms":"Access for free at https:\/\/math.libretexts.org\/Bookshelves\/Applied_Mathematics\/Math_in_Society_(Lippman)"}],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/8973"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":17,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/8973\/revisions"}],"predecessor-version":[{"id":12870,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/8973\/revisions\/12870"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/90"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/8973\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=8973"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=8973"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=8973"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=8973"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}