{"id":64,"date":"2023-01-25T16:33:59","date_gmt":"2023-01-25T16:33:59","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/us-units-of-measurement-learn-it-page-1\/"},"modified":"2024-10-18T20:52:01","modified_gmt":"2024-10-18T20:52:01","slug":"us-units-of-measurement-learn-it-1","status":"web-only","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/us-units-of-measurement-learn-it-1\/","title":{"raw":"US Units of Measurement: Learn It 1","rendered":"US Units of Measurement: Learn It 1"},"content":{"raw":"<section class=\"textbox learningGoals\">\r\n<ul>\r\n\t<li>Choose the appropriate units of measurement for a given problem or situation<\/li>\r\n\t<li>Convert between units of measurement using conversion factors<\/li>\r\n\t<li>Perform basic arithmetic operations on units of length, weight, and capacity<\/li>\r\n\t<li>Apply knowledge of units of length, weight, and capacity to solve real-world problems.<\/li>\r\n<\/ul>\r\n<\/section>\r\n<h2>Length<\/h2>\r\n<p><iframe src=\"https:\/\/lumenlearning.h5p.com\/content\/1291931902664342378\/embed\" width=\"1088\" height=\"637\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" aria-label=\"Length Interactive\"><\/iframe><script src=\"https:\/\/lumenlearning.h5p.com\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>units of length<\/h3>\r\n<p><b>Length<\/b> is the distance from one end of an object to the other end, or from one object to another. The system for measuring length in the United States is based on the four customary units of length: <b>inch<\/b>, <b>foot<\/b>, <b>yard<\/b>, and <b>mile<\/b>.<\/p>\r\n<p>&nbsp;<\/p>\r\n<center>\r\n<table border=\"1\" cellspacing=\"0\" cellpadding=\"0\">\r\n<tbody>\r\n<tr>\r\n<td style=\"text-align: center; width: 30%;\"><b>Unit Equivalents<\/b><\/td>\r\n<td style=\"text-align: center;\"><b>Conversion Factors <\/b><b>(longer to shorter units of measurement)<\/b><\/td>\r\n<td style=\"text-align: center;\"><b>Conversion Factors <\/b><b>(shorter to longer units of measurement)<\/b><\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">[latex]1[\/latex] foot [latex]= 12[\/latex] inches<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{12\\ \\text{inches}}{1\\ \\text{foot}}[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{1\\text{ foot}}{12\\text{ inches}}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">[latex]1[\/latex] yard [latex]= 3[\/latex] feet<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{3\\ \\text{feet}}{1\\ \\text{yard}}[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{1\\text{ yard}}{3\\text{ feet}}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">[latex]1[\/latex] mile [latex]= 5,280[\/latex] feet<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{5,280\\text{ feet}}{1\\text{ mile}}[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex] \\displaystyle \\frac{\\text{1 mile}}{\\text{5,280 feet}}[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/center><\/div>\r\n<\/section>\r\n<h3>Convert Between Different Units of Length<\/h3>\r\n<p>You can use the conversion factors to convert a measurement, such as feet, to another type of measurement, such as inches.<\/p>\r\n<p>Note that there are many more inches for a measurement than there are feet for the same measurement, as feet is a longer unit of measurement. You could use the conversion factor [latex] \\displaystyle \\frac{\\text{12 inches}}{\\text{1 foot}}[\/latex].<\/p>\r\n<p>If a length is measured in feet, and you'd like to convert the length to yards, you can think, \"I am converting from a shorter unit to a longer one, so the length in yards will be less than the length in feet.\" You could use the conversion factor [latex] \\displaystyle \\frac{\\text{1 yard}}{\\text{3 feet}}[\/latex].<\/p>\r\n<p>If a distance is measured in miles, and you want to know how many feet it is, you can think, \"I am converting from a longer unit of measurement to a shorter one, so the number of feet would be greater than the number of miles.\" You could use the conversion factor [latex] \\displaystyle \\frac{5,280\\text{ feet}}{1\\text{ mile}}[\/latex].<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>factor label method<\/h3>\r\n<p>You can use the <b>factor<\/b> <b>label<\/b> <b>method<\/b> (also known as <b>dimensional analysis<\/b>) to convert a length from one unit of measure to another using the conversion factors. In the factor label method, you multiply by unit fractions to convert a measurement from one unit to another.\u00a0<\/p>\r\n<\/div>\r\n<\/section>\r\n<section class=\"textbox recall\">\r\n<p><strong>Convert a mixed number to an improper fraction<\/strong><\/p>\r\n<p>You can use a handy shortcut to convert a mixed number to its equivalent fractional form. First multiply the whole number part by the denominator of the fraction then add the numerator to the result. Finally place that number over the denominator.<\/p>\r\n<p style=\"text-align: center;\">[latex]a\\dfrac{b}{c}=\\dfrac{ac+b}{c}[\/latex].<\/p>\r\n<p>Ex. Convert [latex]3\\dfrac{1}{2}[\/latex] to an improper fraction.<\/p>\r\n<p style=\"text-align: center;\">[latex]3\\dfrac{1}{2}=\\dfrac{3\\cdot 2 + 1}{2}=\\dfrac{7}{2}[\/latex].<\/p>\r\n<p>[reveal-answer q=\"442275\"]Click for more information[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"442275\"]<\/p>\r\n<p>The shortcut for converting mixed numbers to improper fractions is based on the way we add fractions. That is, a mixed number such as\u00a0 [latex]3\\dfrac{1}{2}[\/latex] is actually an addition problem,\u00a0[latex]3 + \\dfrac{1}{2}[\/latex]. Let's add those numbers together.<\/p>\r\n<p>[latex]<br \/>\r\n\\begin{array}{rcl} &amp;&amp;3 + \\dfrac{1}{2} &amp; \\\\<br \/>\r\n&amp;=&amp;\\dfrac{3}{1}+\\dfrac{1}{2} &amp; \\text{write the whole number as a fraction} \\\\<br \/>\r\n&amp;=&amp;\\dfrac{6}{2}+\\dfrac{1}{2} &amp; \\text{rewrite as equivalent fractions with the same denominators} \\\\<br \/>\r\n&amp;=&amp;\\dfrac{7}{2} &amp; \\text{add fractions with common denominators}<br \/>\r\n\\end{array}[\/latex]<\/p>\r\n<p>[\/hidden-answer]<\/p>\r\n<\/section>\r\n<p>Study the example below to see how the factor label method can be used to convert [latex] \\displaystyle 3\\frac{1}{2}[\/latex] feet into an equivalent number of inches.<\/p>\r\n<section class=\"textbox example\">How many inches are in [latex] \\displaystyle 3\\frac{1}{2}[\/latex] feet?<br \/>\r\n[reveal-answer q=\"4330\"]Show Solution[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"4330\"]Begin by reasoning about your answer. Since a foot is longer than an inch, this means the answer would be greater than [latex] \\displaystyle 3\\frac{1}{2}[\/latex].Find the conversion factor that compares inches and feet, with inches in the numerator, and multiply.\r\n\r\n\r\n<p style=\"text-align: center;\">[latex]3\\frac{1}{2}\\text{feet}\\cdot\\frac{12\\text{ inches}}{1\\text{foot}}=\\text{? inches}[\/latex]<\/p>\r\n<p>Rewrite the mixed number as an improper fraction before multiplying.<\/p>\r\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\text{feet}\\cdot\\frac{12\\text{ inches}}{1\\text{foot}}=\\text{? inches}[\/latex]<\/p>\r\n<p>You can cancel similar units when they appear in the numerator <i>and<\/i> the denominator. So here, cancel the similar units \"feet\" and \"foot.\" This eliminates this unit from the problem.<\/p>\r\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\cancel{\\text{feet}}\\cdot\\frac{12\\text{ inches}}{\\cancel{1\\text{foot}}}=\\text{? inches}[\/latex]<\/p>\r\n<p>Rewrite as multiplication of numerators and denominators.<\/p>\r\n<p style=\"text-align: center;\">[latex]\\frac{7\\cdot12\\text{ inches}}{2}=\\frac{84\\text{ inches}}{2}=42\\text{ inches}[\/latex]<\/p>\r\n<p>There are [latex]42[\/latex] inches in [latex] \\displaystyle 3\\frac{1}{2}[\/latex] feet.<\/p>\r\n<p>[\/hidden-answer]<\/p>\r\n<\/section>\r\n<p>Notice that by using the factor label method you can cancel the units out of the problem, just as if they were numbers. You can only cancel if the unit being canceled is in both the numerator and denominator of the fractions you are multiplying.<\/p>\r\n<section class=\"textbox questionHelp\">In the problem above, you cancelled <i>feet<\/i> and <i>foot<\/i> leaving you with <i>inches<\/i>, which is what you were trying to find.\r\n\r\n\r\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\cancel{\\text{feet}}\\cdot\\frac{12\\text{ inches}}{\\cancel{1\\text{foot}}}=\\text{? inches}[\/latex]<\/p>\r\n<p>What if you had used the wrong conversion factor?<\/p>\r\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\text{feet}\\cdot\\frac{1\\text{foot}}{12\\text{ inches}}=\\text{? inches}[\/latex]?<\/p>\r\n<p>You could not cancel the feet because the unit is not the same in <i>both <\/i>the numerator and the denominator. So if you complete the computation, you would still have both feet and inches in the answer and no conversion would take place.<\/p>\r\n<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]1851[\/ohm2_question]<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]1852[\/ohm2_question]<\/section>","rendered":"<section class=\"textbox learningGoals\">\n<ul>\n<li>Choose the appropriate units of measurement for a given problem or situation<\/li>\n<li>Convert between units of measurement using conversion factors<\/li>\n<li>Perform basic arithmetic operations on units of length, weight, and capacity<\/li>\n<li>Apply knowledge of units of length, weight, and capacity to solve real-world problems.<\/li>\n<\/ul>\n<\/section>\n<h2>Length<\/h2>\n<p><iframe loading=\"lazy\" src=\"https:\/\/lumenlearning.h5p.com\/content\/1291931902664342378\/embed\" width=\"1088\" height=\"637\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" aria-label=\"Length Interactive\"><\/iframe><script src=\"https:\/\/lumenlearning.h5p.com\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>units of length<\/h3>\n<p><b>Length<\/b> is the distance from one end of an object to the other end, or from one object to another. The system for measuring length in the United States is based on the four customary units of length: <b>inch<\/b>, <b>foot<\/b>, <b>yard<\/b>, and <b>mile<\/b>.<\/p>\n<p>&nbsp;<\/p>\n<div style=\"text-align: center;\">\n<table cellpadding=\"0\" style=\"border-spacing: 0px;\">\n<tbody>\n<tr>\n<td style=\"text-align: center; width: 30%;\"><b>Unit Equivalents<\/b><\/td>\n<td style=\"text-align: center;\"><b>Conversion Factors <\/b><b>(longer to shorter units of measurement)<\/b><\/td>\n<td style=\"text-align: center;\"><b>Conversion Factors <\/b><b>(shorter to longer units of measurement)<\/b><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">[latex]1[\/latex] foot [latex]= 12[\/latex] inches<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{12\\ \\text{inches}}{1\\ \\text{foot}}[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{1\\text{ foot}}{12\\text{ inches}}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">[latex]1[\/latex] yard [latex]= 3[\/latex] feet<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{3\\ \\text{feet}}{1\\ \\text{yard}}[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{1\\text{ yard}}{3\\text{ feet}}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">[latex]1[\/latex] mile [latex]= 5,280[\/latex] feet<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{5,280\\text{ feet}}{1\\text{ mile}}[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]\\displaystyle \\frac{\\text{1 mile}}{\\text{5,280 feet}}[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<\/section>\n<h3>Convert Between Different Units of Length<\/h3>\n<p>You can use the conversion factors to convert a measurement, such as feet, to another type of measurement, such as inches.<\/p>\n<p>Note that there are many more inches for a measurement than there are feet for the same measurement, as feet is a longer unit of measurement. You could use the conversion factor [latex]\\displaystyle \\frac{\\text{12 inches}}{\\text{1 foot}}[\/latex].<\/p>\n<p>If a length is measured in feet, and you&#8217;d like to convert the length to yards, you can think, &#8220;I am converting from a shorter unit to a longer one, so the length in yards will be less than the length in feet.&#8221; You could use the conversion factor [latex]\\displaystyle \\frac{\\text{1 yard}}{\\text{3 feet}}[\/latex].<\/p>\n<p>If a distance is measured in miles, and you want to know how many feet it is, you can think, &#8220;I am converting from a longer unit of measurement to a shorter one, so the number of feet would be greater than the number of miles.&#8221; You could use the conversion factor [latex]\\displaystyle \\frac{5,280\\text{ feet}}{1\\text{ mile}}[\/latex].<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>factor label method<\/h3>\n<p>You can use the <b>factor<\/b> <b>label<\/b> <b>method<\/b> (also known as <b>dimensional analysis<\/b>) to convert a length from one unit of measure to another using the conversion factors. In the factor label method, you multiply by unit fractions to convert a measurement from one unit to another.\u00a0<\/p>\n<\/div>\n<\/section>\n<section class=\"textbox recall\">\n<p><strong>Convert a mixed number to an improper fraction<\/strong><\/p>\n<p>You can use a handy shortcut to convert a mixed number to its equivalent fractional form. First multiply the whole number part by the denominator of the fraction then add the numerator to the result. Finally place that number over the denominator.<\/p>\n<p style=\"text-align: center;\">[latex]a\\dfrac{b}{c}=\\dfrac{ac+b}{c}[\/latex].<\/p>\n<p>Ex. Convert [latex]3\\dfrac{1}{2}[\/latex] to an improper fraction.<\/p>\n<p style=\"text-align: center;\">[latex]3\\dfrac{1}{2}=\\dfrac{3\\cdot 2 + 1}{2}=\\dfrac{7}{2}[\/latex].<\/p>\n<p><div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q442275\">Click for more information<\/button><\/p>\n<div id=\"q442275\" class=\"hidden-answer\" style=\"display: none\">\n<p>The shortcut for converting mixed numbers to improper fractions is based on the way we add fractions. That is, a mixed number such as\u00a0 [latex]3\\dfrac{1}{2}[\/latex] is actually an addition problem,\u00a0[latex]3 + \\dfrac{1}{2}[\/latex]. Let&#8217;s add those numbers together.<\/p>\n<p>[latex]<br \/>  \\begin{array}{rcl} &&3 + \\dfrac{1}{2} & \\\\<br \/>  &=&\\dfrac{3}{1}+\\dfrac{1}{2} & \\text{write the whole number as a fraction} \\\\<br \/>  &=&\\dfrac{6}{2}+\\dfrac{1}{2} & \\text{rewrite as equivalent fractions with the same denominators} \\\\<br \/>  &=&\\dfrac{7}{2} & \\text{add fractions with common denominators}<br \/>  \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<p>Study the example below to see how the factor label method can be used to convert [latex]\\displaystyle 3\\frac{1}{2}[\/latex] feet into an equivalent number of inches.<\/p>\n<section class=\"textbox example\">How many inches are in [latex]\\displaystyle 3\\frac{1}{2}[\/latex] feet?<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q4330\">Show Solution<\/button><\/p>\n<div id=\"q4330\" class=\"hidden-answer\" style=\"display: none\">Begin by reasoning about your answer. Since a foot is longer than an inch, this means the answer would be greater than [latex]\\displaystyle 3\\frac{1}{2}[\/latex].Find the conversion factor that compares inches and feet, with inches in the numerator, and multiply.<\/p>\n<p style=\"text-align: center;\">[latex]3\\frac{1}{2}\\text{feet}\\cdot\\frac{12\\text{ inches}}{1\\text{foot}}=\\text{? inches}[\/latex]<\/p>\n<p>Rewrite the mixed number as an improper fraction before multiplying.<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\text{feet}\\cdot\\frac{12\\text{ inches}}{1\\text{foot}}=\\text{? inches}[\/latex]<\/p>\n<p>You can cancel similar units when they appear in the numerator <i>and<\/i> the denominator. So here, cancel the similar units &#8220;feet&#8221; and &#8220;foot.&#8221; This eliminates this unit from the problem.<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\cancel{\\text{feet}}\\cdot\\frac{12\\text{ inches}}{\\cancel{1\\text{foot}}}=\\text{? inches}[\/latex]<\/p>\n<p>Rewrite as multiplication of numerators and denominators.<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{7\\cdot12\\text{ inches}}{2}=\\frac{84\\text{ inches}}{2}=42\\text{ inches}[\/latex]<\/p>\n<p>There are [latex]42[\/latex] inches in [latex]\\displaystyle 3\\frac{1}{2}[\/latex] feet.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<p>Notice that by using the factor label method you can cancel the units out of the problem, just as if they were numbers. You can only cancel if the unit being canceled is in both the numerator and denominator of the fractions you are multiplying.<\/p>\n<section class=\"textbox questionHelp\">In the problem above, you cancelled <i>feet<\/i> and <i>foot<\/i> leaving you with <i>inches<\/i>, which is what you were trying to find.<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\cancel{\\text{feet}}\\cdot\\frac{12\\text{ inches}}{\\cancel{1\\text{foot}}}=\\text{? inches}[\/latex]<\/p>\n<p>What if you had used the wrong conversion factor?<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{7}{2}\\text{feet}\\cdot\\frac{1\\text{foot}}{12\\text{ inches}}=\\text{? inches}[\/latex]?<\/p>\n<p>You could not cancel the feet because the unit is not the same in <i>both <\/i>the numerator and the denominator. So if you complete the computation, you would still have both feet and inches in the answer and no conversion would take place.<\/p>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm1851\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=1851&theme=lumen&iframe_resize_id=ohm1851&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm1852\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=1852&theme=lumen&iframe_resize_id=ohm1852&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":15,"menu_order":4,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":62,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/64"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":31,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/64\/revisions"}],"predecessor-version":[{"id":15477,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/64\/revisions\/15477"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/62"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/64\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=64"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=64"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=64"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=64"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}