{"id":5478,"date":"2023-06-29T18:47:17","date_gmt":"2023-06-29T18:47:17","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/?post_type=chapter&#038;p=5478"},"modified":"2024-10-18T20:50:41","modified_gmt":"2024-10-18T20:50:41","slug":"integers-learn-it-7","status":"web-only","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/integers-learn-it-7\/","title":{"raw":"Integers: Learn It 7","rendered":"Integers: Learn It 7"},"content":{"raw":"<h2>Dividing Integers<\/h2>\r\n<p>Division is the inverse operation of multiplication. So, [latex]15\\div 3=5[\/latex] because [latex]5\\cdot 3=15[\/latex] . In words, this expression says that [latex]\\mathbf{\\text{15}}[\/latex] can be divided into [latex]\\mathbf{\\text{3}}[\/latex] groups of [latex]\\mathbf{\\text{5}}[\/latex] each because adding five three times gives [latex]\\mathbf{\\text{15}}[\/latex].<\/p>\r\n<section class=\"textbox example\">\r\n<p>If we look at some examples of multiplying integers, we might figure out the rules for dividing integers.<\/p>\r\n<center>\r\n<p>[latex]\\begin{array}{ccccc}5\\cdot 3=15\\text{ so }15\\div 3=5\\hfill &amp; &amp; &amp; &amp; -5\\left(3\\right)=-15\\text{ so }-15\\div 3=-5\\hfill \\\\ \\left(-5\\right)\\left(-3\\right)=15\\text{ so }15\\div \\left(-3\\right)=-5\\hfill &amp; &amp; &amp; &amp; 5\\left(-3\\right)=-15\\text{ so }-15\\div -3=5\\hfill \\end{array}[\/latex]<\/p>\r\n<\/center><\/section>\r\n<p>Division of signed numbers follows the same rules as multiplication. When the signs are the same, the quotient is positive, and when the signs are different, the quotient is negative.<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>division of signed numbers<\/h3>\r\n<p>The sign of the quotient of two numbers depends on their signs.<\/p>\r\n<p>&nbsp;<\/p>\r\n<strong>Same Signs<\/strong>\r\n<ul>\r\n\t<li>Two positives: Quotient is positive<\/li>\r\n\t<li>Two negatives: Quotient is positive<\/li>\r\n<\/ul>\r\n<strong>Different Signs<\/strong>\r\n<ul>\r\n\t<li>Positive &amp; negative: Quotient is negative<\/li>\r\n\t<li>Negative &amp; positive: Quotient is negative<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/section>\r\n<section class=\"textbox questionHelp\">Remember, you can always check the answer to a division problem by multiplying.<\/section>\r\n<section class=\"textbox example\">Divide each of the following:\r\n\r\n<ol>\r\n\t<li>[latex]-27\\div 3[\/latex]<\/li>\r\n\t<li>[latex]-100\\div \\left(-4\\right)[\/latex]<\/li>\r\n<\/ol>\r\n<p>[reveal-answer q=\"324876\"]Show Solution[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"324876\"]<\/p>\r\n<ol>\r\n\t<li>\r\n<table>\r\n<tbody>\r\n<tr style=\"height: 15px;\">\r\n<td style=\"height: 15px;\">\u00a0<\/td>\r\n<td style=\"height: 15px;\">[latex]-27\\div 3[\/latex]<\/td>\r\n<\/tr>\r\n<tr style=\"height: 15px;\">\r\n<td style=\"height: 15px;\">Divide, noting that the signs are different and so the quotient is negative.<\/td>\r\n<td style=\"height: 15px;\">[latex]-9[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n\t<li>\r\n<table>\r\n<tbody>\r\n<tr>\r\n<td>&nbsp;<\/td>\r\n<td>[latex]-100\\div \\left(-4\\right)[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Divide, noting that the signs are the same and so the quotient is positive.<\/td>\r\n<td>[latex]25[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n<\/ol>\r\n<p>[\/hidden-answer]<\/p>\r\n<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]8911[\/ohm2_question]<\/section>\r\n<p>Just as we saw with multiplication, when we divide a number by [latex]1[\/latex], the result is the same number. What happens when we divide a number by [latex]-1?[\/latex]<\/p>\r\n<section class=\"textbox example\">\r\n<p>Let\u2019s divide a positive number and then a negative number by [latex]-1[\/latex] to see what we get.<\/p>\r\n<center>\r\n<p>[latex]\\begin{array}{cccc}8\\div \\left(-1\\right)\\hfill &amp; &amp; &amp; -9\\div \\left(-1\\right)\\hfill \\\\ -8\\hfill &amp; &amp; &amp; 9\\hfill \\\\ \\hfill \\text{-8 is the opposite of 8}\\hfill &amp; &amp; &amp; \\hfill \\text{9 is the opposite of -9}\\hfill \\end{array}[\/latex]<\/p>\r\n<\/center><\/section>\r\n<p>When we divide a number by [latex]-1[\/latex] we get its opposite.<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>dividing by [latex]-1[\/latex]<\/h3>\r\n<p>Dividing a number by [latex]-1[\/latex] gives its opposite.<\/p>\r\n<p>&nbsp;<\/p>\r\n<center>\r\n<p>[latex]a\\div \\left(-1\\right)=-a[\/latex]<\/p>\r\n<\/center><\/div>\r\n<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]8913[\/ohm2_question]<\/section>","rendered":"<h2>Dividing Integers<\/h2>\n<p>Division is the inverse operation of multiplication. So, [latex]15\\div 3=5[\/latex] because [latex]5\\cdot 3=15[\/latex] . In words, this expression says that [latex]\\mathbf{\\text{15}}[\/latex] can be divided into [latex]\\mathbf{\\text{3}}[\/latex] groups of [latex]\\mathbf{\\text{5}}[\/latex] each because adding five three times gives [latex]\\mathbf{\\text{15}}[\/latex].<\/p>\n<section class=\"textbox example\">\n<p>If we look at some examples of multiplying integers, we might figure out the rules for dividing integers.<\/p>\n<div style=\"text-align: center;\">\n[latex]\\begin{array}{ccccc}5\\cdot 3=15\\text{ so }15\\div 3=5\\hfill & & & & -5\\left(3\\right)=-15\\text{ so }-15\\div 3=-5\\hfill \\\\ \\left(-5\\right)\\left(-3\\right)=15\\text{ so }15\\div \\left(-3\\right)=-5\\hfill & & & & 5\\left(-3\\right)=-15\\text{ so }-15\\div -3=5\\hfill \\end{array}[\/latex]\n<\/div>\n<\/section>\n<p>Division of signed numbers follows the same rules as multiplication. When the signs are the same, the quotient is positive, and when the signs are different, the quotient is negative.<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>division of signed numbers<\/h3>\n<p>The sign of the quotient of two numbers depends on their signs.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>Same Signs<\/strong><\/p>\n<ul>\n<li>Two positives: Quotient is positive<\/li>\n<li>Two negatives: Quotient is positive<\/li>\n<\/ul>\n<p><strong>Different Signs<\/strong><\/p>\n<ul>\n<li>Positive &amp; negative: Quotient is negative<\/li>\n<li>Negative &amp; positive: Quotient is negative<\/li>\n<\/ul>\n<\/div>\n<\/section>\n<section class=\"textbox questionHelp\">Remember, you can always check the answer to a division problem by multiplying.<\/section>\n<section class=\"textbox example\">Divide each of the following:<\/p>\n<ol>\n<li>[latex]-27\\div 3[\/latex]<\/li>\n<li>[latex]-100\\div \\left(-4\\right)[\/latex]<\/li>\n<\/ol>\n<p><div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q324876\">Show Solution<\/button><\/p>\n<div id=\"q324876\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>\n<table>\n<tbody>\n<tr style=\"height: 15px;\">\n<td style=\"height: 15px;\">\u00a0<\/td>\n<td style=\"height: 15px;\">[latex]-27\\div 3[\/latex]<\/td>\n<\/tr>\n<tr style=\"height: 15px;\">\n<td style=\"height: 15px;\">Divide, noting that the signs are different and so the quotient is negative.<\/td>\n<td style=\"height: 15px;\">[latex]-9[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>\n<table>\n<tbody>\n<tr>\n<td>&nbsp;<\/td>\n<td>[latex]-100\\div \\left(-4\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Divide, noting that the signs are the same and so the quotient is positive.<\/td>\n<td>[latex]25[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm8911\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=8911&theme=lumen&iframe_resize_id=ohm8911&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<p>Just as we saw with multiplication, when we divide a number by [latex]1[\/latex], the result is the same number. What happens when we divide a number by [latex]-1?[\/latex]<\/p>\n<section class=\"textbox example\">\n<p>Let\u2019s divide a positive number and then a negative number by [latex]-1[\/latex] to see what we get.<\/p>\n<div style=\"text-align: center;\">\n[latex]\\begin{array}{cccc}8\\div \\left(-1\\right)\\hfill & & & -9\\div \\left(-1\\right)\\hfill \\\\ -8\\hfill & & & 9\\hfill \\\\ \\hfill \\text{-8 is the opposite of 8}\\hfill & & & \\hfill \\text{9 is the opposite of -9}\\hfill \\end{array}[\/latex]\n<\/div>\n<\/section>\n<p>When we divide a number by [latex]-1[\/latex] we get its opposite.<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>dividing by [latex]-1[\/latex]<\/h3>\n<p>Dividing a number by [latex]-1[\/latex] gives its opposite.<\/p>\n<p>&nbsp;<\/p>\n<div style=\"text-align: center;\">\n[latex]a\\div \\left(-1\\right)=-a[\/latex]\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm8913\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=8913&theme=lumen&iframe_resize_id=ohm8913&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":15,"menu_order":20,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"Revision and Adaptation\",\"author\":\"\",\"organization\":\"Lumen Learning\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc-attribution\",\"description\":\"Prealgebra\",\"author\":\"Lynn Marecek & MaryAnne Anthony-Smith\",\"organization\":\"OpenStax\",\"url\":\"https:\/\/openstax.org\/books\/prealgebra\/pages\/3-4-multiply-and-divide-integers\",\"project\":\"3.4 Multiply and Divide Integers\",\"license\":\"cc-by\",\"license_terms\":\"Access for free at https:\/\/openstax.org\/books\/prealgebra\/pages\/3-introduction-to-integers\"}]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":290,"module-header":"learn_it","content_attributions":[{"type":"original","description":"Revision and Adaptation","author":"","organization":"Lumen Learning","url":"","project":"","license":"cc-by","license_terms":""},{"type":"cc-attribution","description":"Prealgebra","author":"Lynn Marecek & MaryAnne Anthony-Smith","organization":"OpenStax","url":"https:\/\/openstax.org\/books\/prealgebra\/pages\/3-4-multiply-and-divide-integers","project":"3.4 Multiply and Divide Integers","license":"cc-by","license_terms":"Access for free at https:\/\/openstax.org\/books\/prealgebra\/pages\/3-introduction-to-integers"}],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/5478"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":21,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/5478\/revisions"}],"predecessor-version":[{"id":15177,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/5478\/revisions\/15177"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/290"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/5478\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=5478"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=5478"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=5478"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=5478"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}