{"id":2826,"date":"2023-05-15T18:55:47","date_gmt":"2023-05-15T18:55:47","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/?post_type=chapter&#038;p=2826"},"modified":"2025-08-26T03:57:18","modified_gmt":"2025-08-26T03:57:18","slug":"volume-and-surface-area-learn-it-4","status":"web-only","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/volume-and-surface-area-learn-it-4\/","title":{"raw":"Volume and Surface Area: Learn It 4","rendered":"Volume and Surface Area: Learn It 4"},"content":{"raw":"<h2>Finding the Volume of a Cone<\/h2>\r\n<p>The first image that many of us have when we hear the word \u2018cone\u2019 is an ice cream cone. There are many other applications of cones (but most are not as tasty as ice cream cones). In geometry, a <strong>cone<\/strong> is a solid figure with one circular base and a vertex. The height of a cone is the distance between its base and the vertex. The cones that we will look at in this section will always have the height perpendicular to the base.<\/p>\r\n<center>\r\n[caption id=\"attachment_9099\" align=\"aligncenter\" width=\"300\"]<img class=\"wp-image-9099 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-300x239.png\" alt=\"A cone. The top is labeled vertex. The height is labeled h. The radius of the base is labeled r.\" width=\"300\" height=\"239\" \/> Figure 1. The cone's height, h, and radius, r, is labeled[\/caption]\r\n<\/center>\r\n<p>&nbsp;<\/p>\r\n<p>Earlier in this section, we saw that the volume of a cylinder is [latex]V=\\pi{r}^{2}h[\/latex]. We can think of a cone as part of a cylinder. The image below shows a cone placed inside a cylinder with the same height and same base. If we compare the volume of the cone and the cylinder, we can see that the volume of the cone is less than that of the cylinder.<\/p>\r\n<center>\r\n[caption id=\"attachment_9100\" align=\"aligncenter\" width=\"225\"]<img class=\"wp-image-9100 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141856\/large-Cone1-225x300.png\" alt=\"A cone with a cylinder drawn around it.\" width=\"225\" height=\"300\" \/> Figure 2. Think of the cone as part of a cylinder[\/caption]\r\n<\/center>\r\n<p>&nbsp;<\/p>\r\n<p>In fact, the volume of a cone is exactly one-third of the volume of a cylinder with the same base and height. The volume of a cone is:<\/p>\r\n<center>[latex]V = \\frac{1}{3}\\textcolor{orange}{B}h[\/latex]<\/center>\r\n<p>&nbsp;<\/p>\r\n<p>Since the base of a cone is a circle, we can substitute the formula of area of a circle, [latex]\\pi{r}^{2}[\/latex], for [latex]B[\/latex] to get the formula for volume of a cone.<\/p>\r\n<center>[latex]V = \\frac{1}{3}\\textcolor{orange}{\\pi r^2}h[\/latex]<\/center>\r\n<p>&nbsp;<\/p>\r\n<p>In this book, we will only find the volume of a cone, and not its surface area.<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>volume of a cone<\/h3>\r\n\r\nFor a cone with radius [latex]r[\/latex] and height [latex]h[\/latex].<center><img class=\"aligncenter size-medium wp-image-9109\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-300x192.png\" alt=\"A cone. The height is labeled h, the radius of the base is labeled r. Beside this is Volume: V equals one-third times pi times r squared times h.\" width=\"300\" height=\"192\" \/><\/center>\r\n<p>&nbsp;<\/p>\r\n<\/div>\r\n<\/section>\r\n<section class=\"textbox example\">Find the volume of a cone with height [latex]6[\/latex] inches and radius of its base [latex]2[\/latex] inches.[reveal-answer q=\"57883\"]Show Solution[\/reveal-answer] [hidden-answer a=\"57883\"]\r\n\r\n<table id=\"eip-id1168467046430\" class=\"unnumbered unstyled\" summary=\"The text reads, \">\r\n<tbody>\r\n<tr>\r\n<td>Step 1. <strong>Read<\/strong> the problem. Draw the figure and label it with the given information.<\/td>\r\n<td><img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/04\/24224203\/CNX_BMath_Figure_09_06_048_img-01.png\" alt=\"A cone with height 6 and radius of base 2.\" width=\"119\" height=\"168\" \/><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 2. <strong>Identify<\/strong> what you are looking for.<\/td>\r\n<td>the volume of the cone<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 3. <strong>Name.<\/strong> Choose a variable to represent it.<\/td>\r\n<td>let [latex]V[\/latex] = volume<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 4. <strong>Translate.<\/strong> Write the appropriate formula. Substitute. (Use [latex]3.14[\/latex] for [latex]\\pi [\/latex] )<\/td>\r\n<td>[latex]V=\\Large\\frac{1}{3}\\normalsize\\pi {r}^{2}h[\/latex] [latex]V\\approx \\Large\\frac{1}{3}\\normalsize 3.14{\\left(2\\right)}^{2}\\left(6\\right)[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 5. <strong>Solve.<\/strong><\/td>\r\n<td>[latex]V\\approx 25.12[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 6. <strong>Check:<\/strong> We leave it to you to check your calculations.<\/td>\r\n<td>&nbsp;<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step 7. <strong>Answer<\/strong> the question.<\/td>\r\n<td>The volume is approximately [latex]25.12[\/latex] cubic inches.<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n\r\n[\/hidden-answer]<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]6987[\/ohm2_question]<\/section>","rendered":"<h2>Finding the Volume of a Cone<\/h2>\n<p>The first image that many of us have when we hear the word \u2018cone\u2019 is an ice cream cone. There are many other applications of cones (but most are not as tasty as ice cream cones). In geometry, a <strong>cone<\/strong> is a solid figure with one circular base and a vertex. The height of a cone is the distance between its base and the vertex. The cones that we will look at in this section will always have the height perpendicular to the base.<\/p>\n<div style=\"text-align: center;\">\n<figure id=\"attachment_9099\" aria-describedby=\"caption-attachment-9099\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-9099 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-300x239.png\" alt=\"A cone. The top is labeled vertex. The height is labeled h. The radius of the base is labeled r.\" width=\"300\" height=\"239\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-300x239.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-65x52.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-225x179.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3-350x279.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141828\/large-Cone3.png 502w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-9099\" class=\"wp-caption-text\">Figure 1. The cone&#8217;s height, h, and radius, r, is labeled<\/figcaption><\/figure>\n<\/div>\n<p>&nbsp;<\/p>\n<p>Earlier in this section, we saw that the volume of a cylinder is [latex]V=\\pi{r}^{2}h[\/latex]. We can think of a cone as part of a cylinder. The image below shows a cone placed inside a cylinder with the same height and same base. If we compare the volume of the cone and the cylinder, we can see that the volume of the cone is less than that of the cylinder.<\/p>\n<div style=\"text-align: center;\">\n<figure id=\"attachment_9100\" aria-describedby=\"caption-attachment-9100\" style=\"width: 225px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-9100 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141856\/large-Cone1-225x300.png\" alt=\"A cone with a cylinder drawn around it.\" width=\"225\" height=\"300\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141856\/large-Cone1-225x300.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141856\/large-Cone1-65x87.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16141856\/large-Cone1.png 300w\" sizes=\"(max-width: 225px) 100vw, 225px\" \/><figcaption id=\"caption-attachment-9100\" class=\"wp-caption-text\">Figure 2. Think of the cone as part of a cylinder<\/figcaption><\/figure>\n<\/div>\n<p>&nbsp;<\/p>\n<p>In fact, the volume of a cone is exactly one-third of the volume of a cylinder with the same base and height. The volume of a cone is:<\/p>\n<div style=\"text-align: center;\">[latex]V = \\frac{1}{3}\\textcolor{orange}{B}h[\/latex]<\/div>\n<p>&nbsp;<\/p>\n<p>Since the base of a cone is a circle, we can substitute the formula of area of a circle, [latex]\\pi{r}^{2}[\/latex], for [latex]B[\/latex] to get the formula for volume of a cone.<\/p>\n<div style=\"text-align: center;\">[latex]V = \\frac{1}{3}\\textcolor{orange}{\\pi r^2}h[\/latex]<\/div>\n<p>&nbsp;<\/p>\n<p>In this book, we will only find the volume of a cone, and not its surface area.<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>volume of a cone<\/h3>\n<p>For a cone with radius [latex]r[\/latex] and height [latex]h[\/latex].<\/p>\n<div style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-9109\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-300x192.png\" alt=\"A cone. The height is labeled h, the radius of the base is labeled r. Beside this is Volume: V equals one-third times pi times r squared times h.\" width=\"300\" height=\"192\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-300x192.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-65x42.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-225x144.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2-350x224.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/18\/2023\/05\/16142418\/large-Cone2.png 625w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/div>\n<p>&nbsp;<\/p>\n<\/div>\n<\/section>\n<section class=\"textbox example\">Find the volume of a cone with height [latex]6[\/latex] inches and radius of its base [latex]2[\/latex] inches.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q57883\">Show Solution<\/button> <\/p>\n<div id=\"q57883\" class=\"hidden-answer\" style=\"display: none\">\n<table id=\"eip-id1168467046430\" class=\"unnumbered unstyled\" summary=\"The text reads,\">\n<tbody>\n<tr>\n<td>Step 1. <strong>Read<\/strong> the problem. Draw the figure and label it with the given information.<\/td>\n<td><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/04\/24224203\/CNX_BMath_Figure_09_06_048_img-01.png\" alt=\"A cone with height 6 and radius of base 2.\" width=\"119\" height=\"168\" \/><\/td>\n<\/tr>\n<tr>\n<td>Step 2. <strong>Identify<\/strong> what you are looking for.<\/td>\n<td>the volume of the cone<\/td>\n<\/tr>\n<tr>\n<td>Step 3. <strong>Name.<\/strong> Choose a variable to represent it.<\/td>\n<td>let [latex]V[\/latex] = volume<\/td>\n<\/tr>\n<tr>\n<td>Step 4. <strong>Translate.<\/strong> Write the appropriate formula. Substitute. (Use [latex]3.14[\/latex] for [latex]\\pi[\/latex] )<\/td>\n<td>[latex]V=\\Large\\frac{1}{3}\\normalsize\\pi {r}^{2}h[\/latex] [latex]V\\approx \\Large\\frac{1}{3}\\normalsize 3.14{\\left(2\\right)}^{2}\\left(6\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Step 5. <strong>Solve.<\/strong><\/td>\n<td>[latex]V\\approx 25.12[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Step 6. <strong>Check:<\/strong> We leave it to you to check your calculations.<\/td>\n<td>&nbsp;<\/td>\n<\/tr>\n<tr>\n<td>Step 7. <strong>Answer<\/strong> the question.<\/td>\n<td>The volume is approximately [latex]25.12[\/latex] cubic inches.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm6987\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=6987&theme=lumen&iframe_resize_id=ohm6987&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":15,"menu_order":29,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":71,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/2826"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":32,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/2826\/revisions"}],"predecessor-version":[{"id":15663,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/2826\/revisions\/15663"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/71"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/2826\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=2826"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=2826"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=2826"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=2826"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}