{"id":1485,"date":"2023-04-10T15:59:04","date_gmt":"2023-04-10T15:59:04","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/?post_type=chapter&#038;p=1485"},"modified":"2024-10-18T20:53:51","modified_gmt":"2024-10-18T20:53:51","slug":"fractals-generated-by-complex-numbers-learn-it-4","status":"web-only","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/chapter\/fractals-generated-by-complex-numbers-learn-it-4\/","title":{"raw":"Fractals Generated by Complex Numbers: Learn It 4","rendered":"Fractals Generated by Complex Numbers: Learn It 4"},"content":{"raw":"<h2>Complex Recursive Sequences<\/h2>\r\n<p>We will now explore recursively defined sequences of complex numbers. Recursively defined sequences are sequences in which subsequent terms are constructed based on preceding terms using a specific set of rules or formulas, allowing each term to be defined as a function of its predecessors.<\/p>\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>Recursive Sequence<\/h3>\r\n<p>A <strong>recursive relationship<\/strong> is a formula which relates the next value, [latex]{{z}_{n+1}}[\/latex], in a sequence to the previous value, [latex]{{z}_{n}}[\/latex]. In addition to the formula, we need an initial value, [latex]{{z}_{0}}[\/latex].<\/p>\r\n<p>&nbsp;<\/p>\r\n<p>The sequence of values produced is the <strong>recursive sequence<\/strong>.<\/p>\r\n<\/div>\r\n<\/section>\r\n<section class=\"textbox recall\">In mathematics, we often use subscripts to denote specific elements or terms in a sequence or set. Imagine you have a list of data entries represented by the symbol [latex]x[\/latex]. These entries can be labeled as [latex]x_1,x_2,x_3, ...[\/latex], where the subscript indicates the position of the entry in the list.\r\n\r\n\r\n<p>For instance, [latex]x_1[\/latex] refers to the first entry, and [latex]x_2[\/latex] refers to the second entry, and so on. We sometimes start our list with a \"zeroth\" term, denoted as [latex]x_0[\/latex]. When we want to talk about a general term in the list, we use [latex]x_n[\/latex], where [latex]n[\/latex] represents any position in the list. This notation also allows us to refer to the terms before and after [latex]x_n[\/latex] as [latex]x_{n-1}[\/latex] and [latex]x_{n+1}[\/latex], respectively.<\/p>\r\n<\/section>\r\n<section class=\"textbox questionHelp\">\r\n<p><strong>How To: Apply a Recursive Sequence<\/strong><\/p>\r\n<ol>\r\n\t<li><strong>Identify the Initial Term:<\/strong> Start by determining the first term of the sequence, often denoted as [latex]a_0[\/latex] or [latex]a_1[\/latex], provided in the sequence definition. This term serves as the starting point for building the rest of the sequence.<\/li>\r\n\t<li><strong>Understand the Recursive Formula:<\/strong> Look at the recursive relationship that defines how to find each term from the previous term(s). The formula will generally be given in the form of [latex]a_{n+1}=f(a_n)[\/latex], where [latex]f[\/latex]\u00a0represents a function.<\/li>\r\n\t<li><strong>Apply the Formula:<\/strong> Use the formula to calculate the next term in the sequence by substituting the previous term into the formula.<\/li>\r\n\t<li><strong>Repeat the Process:<\/strong> Continue applying the recursive formula to each new term to find subsequent terms as needed.<\/li>\r\n<\/ol>\r\n<\/section>\r\n<section class=\"textbox example\">Given the recursive relationship [latex]{{z}_{n+1}}={{z}_{n}}+2, {{z}_{0}}=4[\/latex], generate several terms of the recursive sequence.<br \/>\r\n[reveal-answer q=\"703380\"]Show Solution[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"703380\"]<br \/>\r\nWe are given the starting value, [latex]{{z}_{0}}=4[\/latex]. The recursive formula holds for any value of [latex]n[\/latex], so if [latex]n = 0[\/latex], then [latex]{{z}_{n+1}}={{z}_{n}}+2[\/latex] would tell us [latex]{{z}_{0+1}}={{z}_{0}}+2[\/latex], or more simply, [latex]{{z}_{1}}={{z}_{0}}+2[\/latex]. Notice this defines [latex]{{z}_{1}}[\/latex] in terms of the known [latex]{{z}_{0}}[\/latex], so we can compute the value:\r\n\r\n\r\n<p style=\"text-align: center;\">[latex]{{z}_{1}}={{z}_{0}}+2=4+2=6[\/latex].<\/p>\r\n<p>Now letting [latex]n = 1[\/latex], the formula tells us [latex]{{z}_{1+1}}={{z}_{1}}+2[\/latex], or [latex]{{z}_{2}}={{z}_{1}}+2[\/latex]. Again, the formula gives the next value in the sequence in terms of the previous value.<\/p>\r\n<p style=\"text-align: center;\">[latex]{{z}_{2}}={{z}_{1}}+2=6+2=8[\/latex]<\/p>\r\n<p>Continuing,<\/p>\r\n<center>[latex]{{z}_{3}}={{z}_{2}}+2=8+2=10[\/latex]<\/center><center>[latex]{{z}_{4}}={{z}_{3}}+2=10+2=12[\/latex]<\/center>\r\n<p><br \/>\r\n[\/hidden-answer]<\/p>\r\n<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]6897[\/ohm2_question]<\/section>\r\n<p>The previous example generated a basic linear sequence of real numbers. The same process can be used with complex numbers.<\/p>\r\n<section class=\"textbox example\">Given the recursive relationship [latex]{{z}_{n+1}}={{z}_{n}}\\cdot{i}+(1-i), {{z}_{0}}=4[\/latex], generate several terms of the recursive sequence.<br \/>\r\n[reveal-answer q=\"703381\"]Show Solution[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"703381\"]\r\n\r\n\r\n<p>We are given [latex]{{z}_{0}}=4[\/latex]. Using the recursive formula:<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}\r\nz_1 = z_0 \\cdot i + (1 - i) = 4 \\cdot i + (1 - i) = 1 + 3i \\\\\r\nz_2 = z_1 \\cdot i + (1 - i) = (1 + 3i) \\cdot i + (1 - i) = i + 3i^2 + (1 - i) = i - 3 + (1 - i) = -2 \\\\\r\nz_3 = z_2 \\cdot i + (1 - i) = (-2) \\cdot i + (1 - i) = -2i + (1 - i) = 1 - 3i \\\\\r\nz_4 = z_3 \\cdot i + (1 - i) = (1 - 3i) \\cdot i + (1 - i) = i - 3i^2 + (1 - i) = i + 3 + (1 - i) = 4 \\\\\r\nz_5 = z_4 \\cdot i + (1 - i) = 4 \\cdot i + (1 - i) = 1 + 3i\r\n\\end{array}\r\n[\/latex]<\/p>\r\n<p>Notice this sequence is exhibiting an interesting pattern\u2014it began to repeat itself.<\/p>\r\n\r\n\r\n[\/hidden-answer]<\/section>\r\n<section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]6898[\/ohm2_question]<\/section>","rendered":"<h2>Complex Recursive Sequences<\/h2>\n<p>We will now explore recursively defined sequences of complex numbers. Recursively defined sequences are sequences in which subsequent terms are constructed based on preceding terms using a specific set of rules or formulas, allowing each term to be defined as a function of its predecessors.<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>Recursive Sequence<\/h3>\n<p>A <strong>recursive relationship<\/strong> is a formula which relates the next value, [latex]{{z}_{n+1}}[\/latex], in a sequence to the previous value, [latex]{{z}_{n}}[\/latex]. In addition to the formula, we need an initial value, [latex]{{z}_{0}}[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p>The sequence of values produced is the <strong>recursive sequence<\/strong>.<\/p>\n<\/div>\n<\/section>\n<section class=\"textbox recall\">In mathematics, we often use subscripts to denote specific elements or terms in a sequence or set. Imagine you have a list of data entries represented by the symbol [latex]x[\/latex]. These entries can be labeled as [latex]x_1,x_2,x_3, ...[\/latex], where the subscript indicates the position of the entry in the list.<\/p>\n<p>For instance, [latex]x_1[\/latex] refers to the first entry, and [latex]x_2[\/latex] refers to the second entry, and so on. We sometimes start our list with a &#8220;zeroth&#8221; term, denoted as [latex]x_0[\/latex]. When we want to talk about a general term in the list, we use [latex]x_n[\/latex], where [latex]n[\/latex] represents any position in the list. This notation also allows us to refer to the terms before and after [latex]x_n[\/latex] as [latex]x_{n-1}[\/latex] and [latex]x_{n+1}[\/latex], respectively.<\/p>\n<\/section>\n<section class=\"textbox questionHelp\">\n<p><strong>How To: Apply a Recursive Sequence<\/strong><\/p>\n<ol>\n<li><strong>Identify the Initial Term:<\/strong> Start by determining the first term of the sequence, often denoted as [latex]a_0[\/latex] or [latex]a_1[\/latex], provided in the sequence definition. This term serves as the starting point for building the rest of the sequence.<\/li>\n<li><strong>Understand the Recursive Formula:<\/strong> Look at the recursive relationship that defines how to find each term from the previous term(s). The formula will generally be given in the form of [latex]a_{n+1}=f(a_n)[\/latex], where [latex]f[\/latex]\u00a0represents a function.<\/li>\n<li><strong>Apply the Formula:<\/strong> Use the formula to calculate the next term in the sequence by substituting the previous term into the formula.<\/li>\n<li><strong>Repeat the Process:<\/strong> Continue applying the recursive formula to each new term to find subsequent terms as needed.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\">Given the recursive relationship [latex]{{z}_{n+1}}={{z}_{n}}+2, {{z}_{0}}=4[\/latex], generate several terms of the recursive sequence.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q703380\">Show Solution<\/button><\/p>\n<div id=\"q703380\" class=\"hidden-answer\" style=\"display: none\">\nWe are given the starting value, [latex]{{z}_{0}}=4[\/latex]. The recursive formula holds for any value of [latex]n[\/latex], so if [latex]n = 0[\/latex], then [latex]{{z}_{n+1}}={{z}_{n}}+2[\/latex] would tell us [latex]{{z}_{0+1}}={{z}_{0}}+2[\/latex], or more simply, [latex]{{z}_{1}}={{z}_{0}}+2[\/latex]. Notice this defines [latex]{{z}_{1}}[\/latex] in terms of the known [latex]{{z}_{0}}[\/latex], so we can compute the value:<\/p>\n<p style=\"text-align: center;\">[latex]{{z}_{1}}={{z}_{0}}+2=4+2=6[\/latex].<\/p>\n<p>Now letting [latex]n = 1[\/latex], the formula tells us [latex]{{z}_{1+1}}={{z}_{1}}+2[\/latex], or [latex]{{z}_{2}}={{z}_{1}}+2[\/latex]. Again, the formula gives the next value in the sequence in terms of the previous value.<\/p>\n<p style=\"text-align: center;\">[latex]{{z}_{2}}={{z}_{1}}+2=6+2=8[\/latex]<\/p>\n<p>Continuing,<\/p>\n<div style=\"text-align: center;\">[latex]{{z}_{3}}={{z}_{2}}+2=8+2=10[\/latex]<\/div>\n<div style=\"text-align: center;\">[latex]{{z}_{4}}={{z}_{3}}+2=10+2=12[\/latex]<\/div>\n<p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm6897\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=6897&theme=lumen&iframe_resize_id=ohm6897&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<p>The previous example generated a basic linear sequence of real numbers. The same process can be used with complex numbers.<\/p>\n<section class=\"textbox example\">Given the recursive relationship [latex]{{z}_{n+1}}={{z}_{n}}\\cdot{i}+(1-i), {{z}_{0}}=4[\/latex], generate several terms of the recursive sequence.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q703381\">Show Solution<\/button><\/p>\n<div id=\"q703381\" class=\"hidden-answer\" style=\"display: none\">\n<p>We are given [latex]{{z}_{0}}=4[\/latex]. Using the recursive formula:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}  z_1 = z_0 \\cdot i + (1 - i) = 4 \\cdot i + (1 - i) = 1 + 3i \\\\  z_2 = z_1 \\cdot i + (1 - i) = (1 + 3i) \\cdot i + (1 - i) = i + 3i^2 + (1 - i) = i - 3 + (1 - i) = -2 \\\\  z_3 = z_2 \\cdot i + (1 - i) = (-2) \\cdot i + (1 - i) = -2i + (1 - i) = 1 - 3i \\\\  z_4 = z_3 \\cdot i + (1 - i) = (1 - 3i) \\cdot i + (1 - i) = i - 3i^2 + (1 - i) = i + 3 + (1 - i) = 4 \\\\  z_5 = z_4 \\cdot i + (1 - i) = 4 \\cdot i + (1 - i) = 1 + 3i  \\end{array}[\/latex]<\/p>\n<p>Notice this sequence is exhibiting an interesting pattern\u2014it began to repeat itself.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm6898\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=6898&theme=lumen&iframe_resize_id=ohm6898&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":15,"menu_order":13,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":74,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/1485"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":30,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/1485\/revisions"}],"predecessor-version":[{"id":13863,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/1485\/revisions\/13863"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/parts\/74"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapters\/1485\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/media?parent=1485"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=1485"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/contributor?post=1485"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/quantitativereasoning\/wp-json\/wp\/v2\/license?post=1485"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}