{"id":42,"date":"2025-01-02T23:03:47","date_gmt":"2025-01-02T23:03:47","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/data-organization-get-stronger-answer-key\/"},"modified":"2025-01-02T23:03:47","modified_gmt":"2025-01-02T23:03:47","slug":"data-organization-get-stronger-answer-key","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/data-organization-get-stronger-answer-key\/","title":{"raw":"Data Organization: Get Stronger Answer Key","rendered":"Data Organization: Get Stronger Answer Key"},"content":{"raw":"\n
    \n\t
  1. \n
      \n\t
    1. Different tables are possible
      \n[latex]\\begin{array}{|l|l|}
      \n\\hline \\text { Score } & \\text { Frequency } \\\\
      \n\\hline 30 & 1 \\\\
      \n\\hline 40 & 0 \\\\
      \n\\hline 50 & 4 \\\\
      \n\\hline 60 & 3 \\\\
      \n\\hline 70 & 6 \\\\
      \n\\hline 80 & 5 \\\\
      \n\\hline 90 & 2 \\\\
      \n\\hline 100 & 3 \\\\
      \n\\hline
      \n\\end{array}[\/latex]<\/li>\n\t
    2. This is technically a bar graph, not a histogram:
      \n\"Bar<\/li>\n\t
    3. \"\"<\/li>\n<\/ol>\n<\/li>\n\t
    4.  <\/li>\n\t
    5. [latex]5+3+4+2+12 = 15[\/latex]
      \n[latex]5\/15 = 0.3333 = 33.33\\%[\/latex]<\/li>\n\t
    6.  <\/li>\n\t
    7. Bar is at [latex]25\\%[\/latex]. [latex]25\\%[\/latex] of [latex]20[\/latex] = [latex]5[\/latex] students earned an A<\/li>\n\t
    8.  <\/li>\n\t
    9. \n
        \n\t
      1. [latex](7.25+8.25+9.00+8.00+7.25+7.50+8.00+7.00)\/8 = $7.781[\/latex]<\/li>\n\t
      2. In order, [latex]7.50  [\/latex] and [latex] 8.00[\/latex] are in middle positions. Median = [latex]$7.75[\/latex]<\/li>\n\t
      3. [latex]0.25*8 = 2 Q1[\/latex] is average of = [latex]2[\/latex]nd and [latex]3[\/latex]rd data values: [latex]$7.375 0.75*8 = 6[\/latex]; [latex]Q3[\/latex] is the average of [latex]6[\/latex]th and [latex]7[\/latex]th data values: [latex]$8.125[\/latex]; 5 number summary: [latex]$7.00, $7.375, $7.75, $8.125, $9.00 [\/latex]<\/li>\n<\/ol>\n<\/li>\n\t
      4.  <\/li>\n\t
      5. \n
          \n\t
        1. ([latex]5[\/latex] x [latex]0[\/latex] + [latex]3[\/latex] x [latex]1[\/latex] + [latex]4[\/latex] x [latex]2[\/latex] + [latex]2[\/latex] x [latex]3[\/latex] + [latex]1[\/latex] x [latex]5[\/latex])\/[latex]15[\/latex] = [latex]1.4667[\/latex]<\/li>\n\t
        2. Median is [latex]8[\/latex]th data value: [latex]1[\/latex] child<\/li>\n\t
        3. [latex]0.25x15 = 3.75[\/latex]. Q1 is 4th data value: [latex]0[\/latex] children [latex] 0.75*15 = 11.25[\/latex]; Q3 is 12th data value: [latex]2[\/latex]; 5-number summary: [latex]0,0 1,2,5[\/latex]<\/li>\n\t
        4. \"\"<\/li>\n<\/ol>\n<\/li>\n\t
        5.  <\/li>\n\t
        6. Kendra makes [latex]$90,000[\/latex]. Kelsey makes [latex]$40,000[\/latex]. Kendra makes [latex]$50,000[\/latex] more.<\/li>\n\t
        7.  <\/li>\n<\/ol>\n

          Answers for questions 13-24 can be found in this Google Sheet: Data Organization: Get Stronger Solutions to Questions 13-24 <\/a>.<\/p>\n","rendered":"

            \n
          1. \n
              \n
            1. Different tables are possible
              \n[latex]\\begin{array}{|l|l|}
              \\hline \\text { Score } & \\text { Frequency } \\\\
              \\hline 30 & 1 \\\\
              \\hline 40 & 0 \\\\
              \\hline 50 & 4 \\\\
              \\hline 60 & 3 \\\\
              \\hline 70 & 6 \\\\
              \\hline 80 & 5 \\\\
              \\hline 90 & 2 \\\\
              \\hline 100 & 3 \\\\
              \\hline
              \\end{array}[\/latex]<\/li>\n
            2. This is technically a bar graph, not a histogram:
              \n\"Bar<\/li>\n
            3. \"\"<\/li>\n<\/ol>\n<\/li>\n
            4.  <\/li>\n
            5. [latex]5+3+4+2+12 = 15[\/latex]
              \n[latex]5\/15 = 0.3333 = 33.33\\%[\/latex]<\/li>\n
            6.  <\/li>\n
            7. Bar is at [latex]25\\%[\/latex]. [latex]25\\%[\/latex] of [latex]20[\/latex] = [latex]5[\/latex] students earned an A<\/li>\n
            8.  <\/li>\n
            9. \n
                \n
              1. [latex](7.25+8.25+9.00+8.00+7.25+7.50+8.00+7.00)\/8 = $7.781[\/latex]<\/li>\n
              2. In order, [latex]7.50 [\/latex] and [latex]8.00[\/latex] are in middle positions. Median = [latex]$7.75[\/latex]<\/li>\n
              3. [latex]0.25*8 = 2 Q1[\/latex] is average of = [latex]2[\/latex]nd and [latex]3[\/latex]rd data values: [latex]$7.375 0.75*8 = 6[\/latex]; [latex]Q3[\/latex] is the average of [latex]6[\/latex]th and [latex]7[\/latex]th data values: [latex]$8.125[\/latex]; 5 number summary: [latex]$7.00, $7.375, $7.75, $8.125, $9.00[\/latex]<\/li>\n<\/ol>\n<\/li>\n
              4.  <\/li>\n
              5. \n
                  \n
                1. ([latex]5[\/latex] x [latex]0[\/latex] + [latex]3[\/latex] x [latex]1[\/latex] + [latex]4[\/latex] x [latex]2[\/latex] + [latex]2[\/latex] x [latex]3[\/latex] + [latex]1[\/latex] x [latex]5[\/latex])\/[latex]15[\/latex] = [latex]1.4667[\/latex]<\/li>\n
                2. Median is [latex]8[\/latex]th data value: [latex]1[\/latex] child<\/li>\n
                3. [latex]0.25x15 = 3.75[\/latex]. Q1 is 4th data value: [latex]0[\/latex] children [latex]0.75*15 = 11.25[\/latex]; Q3 is 12th data value: [latex]2[\/latex]; 5-number summary: [latex]0,0 1,2,5[\/latex]<\/li>\n
                4. \"\"<\/li>\n<\/ol>\n<\/li>\n
                5.  <\/li>\n
                6. Kendra makes [latex]$90,000[\/latex]. Kelsey makes [latex]$40,000[\/latex]. Kendra makes [latex]$50,000[\/latex] more.<\/li>\n
                7.  <\/li>\n<\/ol>\n

                  Answers for questions 13-24 can be found in this Google Sheet: Data Organization: Get Stronger Solutions to Questions 13-24 <\/a>.<\/p>\n","protected":false},"author":6,"menu_order":10,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":3,"module-header":"","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/42"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/6"}],"version-history":[{"count":0,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/42\/revisions"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/3"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/42\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=42"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=42"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=42"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=42"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}