{"id":344,"date":"2026-02-16T20:55:08","date_gmt":"2026-02-16T20:55:08","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/?post_type=chapter&#038;p=344"},"modified":"2026-02-18T16:32:48","modified_gmt":"2026-02-18T16:32:48","slug":"triangle-trigonometry-get-stronger-answer-key","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/triangle-trigonometry-get-stronger-answer-key\/","title":{"raw":"Triangle Trigonometry: Get Stronger Answer Key","rendered":"Triangle Trigonometry: Get Stronger Answer Key"},"content":{"raw":"<h1>Right Triangle Trigonometry<\/h1>\r\n1.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27003910\/CNX_Precalc_Figure_05_04_2022.jpg\" alt=\"A right triangle with side opposite, adjacent, and hypotenuse labeled.\" \/>\r\n\r\n4. The two acute angles are complementary.\r\n\r\n7.\u00a0[latex]\\frac{\\pi }{6}[\/latex]\r\n\r\n9.\u00a0[latex]\\frac{\\pi }{4}[\/latex]\r\n\r\n11.\u00a0[latex]b=\\frac{20\\sqrt{3}}{3},c=\\frac{40\\sqrt{3}}{3}[\/latex]\r\n\r\n13.\u00a0[latex]a=10,000,c=10,000.5[\/latex]\r\n\r\n15.\u00a0[latex]b=\\frac{5\\sqrt{3}}{3},c=\\frac{10\\sqrt{3}}{3}[\/latex]\r\n\r\n17.\u00a0[latex]\\frac{5\\sqrt{29}}{29}[\/latex]\r\n\r\n19.\u00a0[latex]\\frac{5}{2}[\/latex]\r\n\r\n21.\u00a0[latex]\\frac{\\sqrt{29}}{2}[\/latex]\r\n\r\n23.\u00a0[latex]\\frac{5\\sqrt{41}}{41}[\/latex]\r\n\r\n25.\u00a0[latex]\\frac{5}{4}[\/latex]\r\n\r\n27.\u00a0[latex]\\frac{\\sqrt{41}}{4}[\/latex]\r\n\r\n29.\u00a0[latex]c=14, b=7\\sqrt{3}[\/latex]\r\n\r\n31.\u00a0[latex]a=15, b=15[\/latex]\r\n\r\n33.\u00a0[latex]b=9.9970, c=12.2041[\/latex]\r\n\r\n35.\u00a0[latex]a=2.0838, b=11.8177[\/latex]\r\n\r\n37.\u00a0[latex]a=55.9808,c=57.9555[\/latex]\r\n\r\n39.\u00a0[latex]a=46.6790,b=17.9184[\/latex]\r\n\r\n41.\u00a0[latex]a=16.4662,c=16.8341[\/latex]\r\n\r\n43.\u00a0188.3159\r\n\r\n45.\u00a0200.6737\r\n\r\n47.\u00a0498.3471 ft\r\n\r\n49.\u00a01060.09 ft\r\n\r\n51.\u00a027.372 ft\r\n\r\n53.\u00a022.6506 ft\r\n\r\n55.\u00a0368.7633 ft\r\n<h1>Inverse Trigonometric Functions<\/h1>\r\n1.\u00a0The function [latex]y=\\sin x[\/latex] is one-to-one on [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex]; thus, this interval is the range of the inverse function of [latex]y=\\sin x\\text{, }f\\left(x\\right)=\\sin^{\u22121}x[\/latex]. The function [latex]y=\\cos x[\/latex] is one-to-one on [0,\u03c0]; thus, this interval is the range of the inverse function of [latex]y=\\cos x\\text{, }f(x)=\\cos^{\u22121}x[\/latex].\r\n\r\n4. Rewrite the expression as: [latex]\\sec^{-1}(2)=\\cos^{-1}!\\left(\\frac{1}{2}\\right)[\/latex]. Then use the inverse cosine (arccos) function on the calculator: [latex]\\theta=\\cos^{-1}\\left(\\frac{1}{2}\\right)[\/latex]\r\n\r\n9. [latex]\u2212\\frac{\\pi}{6}[\/latex]\r\n\r\n11. [latex]\\frac{3\\pi}{4}[\/latex]\r\n\r\n15. [latex]\\frac{\\pi}{3}[\/latex]\r\n\r\n17. 1.98\r\n\r\n19. 0.93\r\n\r\n21. 1.41\r\n\r\n23. 0.56 radians\r\n\r\n25. 0\r\n\r\n29.\u00a0\u22120.71\r\n\r\n31. [latex]\u2212\\frac{\\pi}{4}[\/latex]\r\n\r\n33. 0.8\r\n\r\n35. [latex]\\frac{5}{13}[\/latex]\r\n\r\n43. [latex]\\frac{\\sqrt{2x+1}}{x+1}[\/latex]\r\n\r\n45. [latex]\\frac{\\sqrt{2x+1}}{x+1}[\/latex]\r\n\r\n47.\u00a0t\r\n\r\n49.\u00a0domain [\u22121,1]; range [0,\u03c0]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164027\/CNX_Precalc_Figure_06_03_204.jpg\" alt=\"A graph of the function arc cosine of x over \u22121 to 1. The range of the function is 0 to pi.\" \/>\r\n\r\n53. 0.395 radians\r\n\r\n55. 1.11 radians\r\n\r\n57. 1.25 radians\r\n\r\n59. 0.405 radians\r\n\r\n61. No. The angle the ladder makes with the horizontal is 60 degrees.\r\n<h1>Non-Right Triangles: Law of Sines<\/h1>\r\n3.\u00a0When the known values are the side opposite the missing angle and another side and its opposite angle.\r\n\r\n5.\u00a0A triangle with two given sides and a non-included angle.\r\n\r\n7.\u00a0[latex] \\beta =72^\\circ ,a\\approx 12.0,b\\approx 19.9[\/latex]\r\n\r\n9.\u00a0[latex] \\gamma =20^\\circ ,b\\approx 4.5,c\\approx 1.6[\/latex]\r\n\r\n11.\u00a0[latex]b\\approx 3.78[\/latex]\r\n\r\n13.\u00a0[latex]c\\approx 13.70[\/latex]\r\n\r\n15.\u00a0one triangle, [latex]\\alpha \\approx 50.3^\\circ ,\\beta \\approx 16.7^\\circ ,a\\approx 26.7[\/latex]\r\n\r\n17.\u00a0two triangles, [latex] \\gamma \\approx 54.3^\\circ ,\\beta \\approx 90.7^\\circ ,b\\approx 20.9[\/latex] or [latex] {\\gamma }^{\\prime }\\approx 125.7^\\circ ,{\\beta }^{\\prime }\\approx 19.3^\\circ ,{b}^{\\prime }\\approx 6.9[\/latex]\r\n\r\n19.\u00a0two triangles, [latex] \\beta \\approx 75.7^\\circ , \\gamma \\approx 61.3^\\circ ,b\\approx 9.9[\/latex] or [latex] {\\beta }^{\\prime }\\approx 18.3^\\circ ,{\\gamma }^{\\prime }\\approx 118.7^\\circ ,{b}^{\\prime }\\approx 3.2[\/latex]\r\n\r\n21.\u00a0two triangles, [latex]\\alpha \\approx 143.2^\\circ ,\\beta \\approx 26.8^\\circ ,a\\approx 17.3[\/latex] or [latex]{\\alpha }^{\\prime }\\approx 16.8^\\circ ,{\\beta }^{\\prime }\\approx 153.2^\\circ ,{a}^{\\prime }\\approx 8.3[\/latex]\r\n\r\n23.\u00a0no triangle possible\r\n\r\n25.\u00a0[latex]A\\approx 47.8^\\circ [\/latex] or [latex]{A}^{\\prime }\\approx 132.2^\\circ [\/latex]\r\n\r\n27.\u00a0[latex]8.6[\/latex]\r\n\r\n29.\u00a0[latex]370.9[\/latex]\r\n\r\n31.\u00a0[latex]12.3[\/latex]\r\n\r\n33.\u00a0[latex]12.2 [\/latex]\r\n\r\n35.\u00a0[latex]16.0 [\/latex]\r\n\r\n37.\u00a0[latex]29.7^\\circ [\/latex]\r\n\r\n39.\u00a0[latex]x=76.9^\\circ \\text{or }x=103.1^\\circ [\/latex]\r\n\r\n41.\u00a0[latex]110.6^\\circ [\/latex]\r\n\r\n43.\u00a0[latex]A\\approx 39.4,\\text{ }C\\approx 47.6,\\text{ }BC\\approx 20.7 [\/latex]\r\n\r\n45.\u00a0[latex]57.1[\/latex]\r\n\r\n47.\u00a0[latex]42.0 [\/latex]\r\n\r\n49.\u00a0[latex]430.2 [\/latex]\r\n\r\n59.\u00a051.4 feet\r\n\r\n61.\u00a0The distance from the satellite to station [latex]A[\/latex] is approximately 1716 miles. The satellite is approximately 1706 miles above the ground.\r\n\r\n63.\u00a02.6\u00a0ft\r\n\r\n65.\u00a05.6\u00a0km\r\n\r\n67.\u00a0371\u00a0ft\r\n\r\n71.\u00a024.1\u00a0ft\r\n\r\n73.\u00a019,056\u00a0ft2\r\n\r\n75.\u00a0445,624\u00a0square\u00a0miles\r\n<h1>Non-Right Triangles: Law of Cosines<\/h1>\r\n1.\u00a0two sides and the angle opposite the missing side\r\n\r\n3.\u00a0[latex]s[\/latex] is the semi-perimeter, which is half the perimeter of the triangle.\r\n\r\n5.\u00a0The Law of Cosines must be used for any oblique (non-right) triangle.\r\n\r\n7.\u00a011.3\r\n\r\n13.\u00a0257.4\r\n\r\n15.\u00a0not possible\r\n\r\n17.\u00a095.5\u00b0\r\n\r\n19.\u00a026.9\u00b0\r\n\r\n21.\u00a0[latex]B\\approx 45.9^\\circ ,C\\approx 99.1^\\circ ,a\\approx 6.4[\/latex]\r\n\r\n23.\u00a0[latex]A\\approx 20.6^\\circ ,B\\approx 38.4^\\circ ,c\\approx 51.1[\/latex]\r\n\r\n25.\u00a0[latex]A\\approx 37.8^\\circ ,B\\approx 43.8,C\\approx 98.4^\\circ [\/latex]\r\n\r\n27.\u00a0177.56 in2\r\n\r\n29.\u00a00.04 m2\r\n\r\n31.\u00a00.91 yd2\r\n\r\n33.\u00a03.0\r\n\r\n37.\u00a00.5\r\n\r\n39.\u00a070.7\u00b0\r\n\r\n41.\u00a077.4\u00b0\r\n\r\n43.\u00a025.0\r\n\r\n47.\u00a043.52\r\n\r\n49.\u00a01.41\r\n\r\n51.\u00a00.14\r\n\r\n59.\u00a07.62\r\n\r\n61.\u00a085.1\r\n\r\n63.\u00a024.0 km\r\n\r\n65.\u00a099.9 ft\r\n\r\n67.\u00a037.3 miles\r\n\r\n69.\u00a02371 miles\r\n\r\n71.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27165342\/CNX_Precalc_Figure_08_02_233.jpg\" alt=\"Angle BO is 9.1 degrees, angle PH is 150.2 degrees, and angle DC is 20.7 degrees.\" \/>\r\n\r\n73.\u00a0599.8 miles\r\n\r\n75.\u00a065.4 cm2\r\n\r\n77.\u00a0468 ft2","rendered":"<h1>Right Triangle Trigonometry<\/h1>\n<p>1.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27003910\/CNX_Precalc_Figure_05_04_2022.jpg\" alt=\"A right triangle with side opposite, adjacent, and hypotenuse labeled.\" \/><\/p>\n<p>4. The two acute angles are complementary.<\/p>\n<p>7.\u00a0[latex]\\frac{\\pi }{6}[\/latex]<\/p>\n<p>9.\u00a0[latex]\\frac{\\pi }{4}[\/latex]<\/p>\n<p>11.\u00a0[latex]b=\\frac{20\\sqrt{3}}{3},c=\\frac{40\\sqrt{3}}{3}[\/latex]<\/p>\n<p>13.\u00a0[latex]a=10,000,c=10,000.5[\/latex]<\/p>\n<p>15.\u00a0[latex]b=\\frac{5\\sqrt{3}}{3},c=\\frac{10\\sqrt{3}}{3}[\/latex]<\/p>\n<p>17.\u00a0[latex]\\frac{5\\sqrt{29}}{29}[\/latex]<\/p>\n<p>19.\u00a0[latex]\\frac{5}{2}[\/latex]<\/p>\n<p>21.\u00a0[latex]\\frac{\\sqrt{29}}{2}[\/latex]<\/p>\n<p>23.\u00a0[latex]\\frac{5\\sqrt{41}}{41}[\/latex]<\/p>\n<p>25.\u00a0[latex]\\frac{5}{4}[\/latex]<\/p>\n<p>27.\u00a0[latex]\\frac{\\sqrt{41}}{4}[\/latex]<\/p>\n<p>29.\u00a0[latex]c=14, b=7\\sqrt{3}[\/latex]<\/p>\n<p>31.\u00a0[latex]a=15, b=15[\/latex]<\/p>\n<p>33.\u00a0[latex]b=9.9970, c=12.2041[\/latex]<\/p>\n<p>35.\u00a0[latex]a=2.0838, b=11.8177[\/latex]<\/p>\n<p>37.\u00a0[latex]a=55.9808,c=57.9555[\/latex]<\/p>\n<p>39.\u00a0[latex]a=46.6790,b=17.9184[\/latex]<\/p>\n<p>41.\u00a0[latex]a=16.4662,c=16.8341[\/latex]<\/p>\n<p>43.\u00a0188.3159<\/p>\n<p>45.\u00a0200.6737<\/p>\n<p>47.\u00a0498.3471 ft<\/p>\n<p>49.\u00a01060.09 ft<\/p>\n<p>51.\u00a027.372 ft<\/p>\n<p>53.\u00a022.6506 ft<\/p>\n<p>55.\u00a0368.7633 ft<\/p>\n<h1>Inverse Trigonometric Functions<\/h1>\n<p>1.\u00a0The function [latex]y=\\sin x[\/latex] is one-to-one on [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex]; thus, this interval is the range of the inverse function of [latex]y=\\sin x\\text{, }f\\left(x\\right)=\\sin^{\u22121}x[\/latex]. The function [latex]y=\\cos x[\/latex] is one-to-one on [0,\u03c0]; thus, this interval is the range of the inverse function of [latex]y=\\cos x\\text{, }f(x)=\\cos^{\u22121}x[\/latex].<\/p>\n<p>4. Rewrite the expression as: [latex]\\sec^{-1}(2)=\\cos^{-1}!\\left(\\frac{1}{2}\\right)[\/latex]. Then use the inverse cosine (arccos) function on the calculator: [latex]\\theta=\\cos^{-1}\\left(\\frac{1}{2}\\right)[\/latex]<\/p>\n<p>9. [latex]\u2212\\frac{\\pi}{6}[\/latex]<\/p>\n<p>11. [latex]\\frac{3\\pi}{4}[\/latex]<\/p>\n<p>15. [latex]\\frac{\\pi}{3}[\/latex]<\/p>\n<p>17. 1.98<\/p>\n<p>19. 0.93<\/p>\n<p>21. 1.41<\/p>\n<p>23. 0.56 radians<\/p>\n<p>25. 0<\/p>\n<p>29.\u00a0\u22120.71<\/p>\n<p>31. [latex]\u2212\\frac{\\pi}{4}[\/latex]<\/p>\n<p>33. 0.8<\/p>\n<p>35. [latex]\\frac{5}{13}[\/latex]<\/p>\n<p>43. [latex]\\frac{\\sqrt{2x+1}}{x+1}[\/latex]<\/p>\n<p>45. [latex]\\frac{\\sqrt{2x+1}}{x+1}[\/latex]<\/p>\n<p>47.\u00a0t<\/p>\n<p>49.\u00a0domain [\u22121,1]; range [0,\u03c0]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164027\/CNX_Precalc_Figure_06_03_204.jpg\" alt=\"A graph of the function arc cosine of x over \u22121 to 1. The range of the function is 0 to pi.\" \/><\/p>\n<p>53. 0.395 radians<\/p>\n<p>55. 1.11 radians<\/p>\n<p>57. 1.25 radians<\/p>\n<p>59. 0.405 radians<\/p>\n<p>61. No. The angle the ladder makes with the horizontal is 60 degrees.<\/p>\n<h1>Non-Right Triangles: Law of Sines<\/h1>\n<p>3.\u00a0When the known values are the side opposite the missing angle and another side and its opposite angle.<\/p>\n<p>5.\u00a0A triangle with two given sides and a non-included angle.<\/p>\n<p>7.\u00a0[latex]\\beta =72^\\circ ,a\\approx 12.0,b\\approx 19.9[\/latex]<\/p>\n<p>9.\u00a0[latex]\\gamma =20^\\circ ,b\\approx 4.5,c\\approx 1.6[\/latex]<\/p>\n<p>11.\u00a0[latex]b\\approx 3.78[\/latex]<\/p>\n<p>13.\u00a0[latex]c\\approx 13.70[\/latex]<\/p>\n<p>15.\u00a0one triangle, [latex]\\alpha \\approx 50.3^\\circ ,\\beta \\approx 16.7^\\circ ,a\\approx 26.7[\/latex]<\/p>\n<p>17.\u00a0two triangles, [latex]\\gamma \\approx 54.3^\\circ ,\\beta \\approx 90.7^\\circ ,b\\approx 20.9[\/latex] or [latex]{\\gamma }^{\\prime }\\approx 125.7^\\circ ,{\\beta }^{\\prime }\\approx 19.3^\\circ ,{b}^{\\prime }\\approx 6.9[\/latex]<\/p>\n<p>19.\u00a0two triangles, [latex]\\beta \\approx 75.7^\\circ , \\gamma \\approx 61.3^\\circ ,b\\approx 9.9[\/latex] or [latex]{\\beta }^{\\prime }\\approx 18.3^\\circ ,{\\gamma }^{\\prime }\\approx 118.7^\\circ ,{b}^{\\prime }\\approx 3.2[\/latex]<\/p>\n<p>21.\u00a0two triangles, [latex]\\alpha \\approx 143.2^\\circ ,\\beta \\approx 26.8^\\circ ,a\\approx 17.3[\/latex] or [latex]{\\alpha }^{\\prime }\\approx 16.8^\\circ ,{\\beta }^{\\prime }\\approx 153.2^\\circ ,{a}^{\\prime }\\approx 8.3[\/latex]<\/p>\n<p>23.\u00a0no triangle possible<\/p>\n<p>25.\u00a0[latex]A\\approx 47.8^\\circ[\/latex] or [latex]{A}^{\\prime }\\approx 132.2^\\circ[\/latex]<\/p>\n<p>27.\u00a0[latex]8.6[\/latex]<\/p>\n<p>29.\u00a0[latex]370.9[\/latex]<\/p>\n<p>31.\u00a0[latex]12.3[\/latex]<\/p>\n<p>33.\u00a0[latex]12.2[\/latex]<\/p>\n<p>35.\u00a0[latex]16.0[\/latex]<\/p>\n<p>37.\u00a0[latex]29.7^\\circ[\/latex]<\/p>\n<p>39.\u00a0[latex]x=76.9^\\circ \\text{or }x=103.1^\\circ[\/latex]<\/p>\n<p>41.\u00a0[latex]110.6^\\circ[\/latex]<\/p>\n<p>43.\u00a0[latex]A\\approx 39.4,\\text{ }C\\approx 47.6,\\text{ }BC\\approx 20.7[\/latex]<\/p>\n<p>45.\u00a0[latex]57.1[\/latex]<\/p>\n<p>47.\u00a0[latex]42.0[\/latex]<\/p>\n<p>49.\u00a0[latex]430.2[\/latex]<\/p>\n<p>59.\u00a051.4 feet<\/p>\n<p>61.\u00a0The distance from the satellite to station [latex]A[\/latex] is approximately 1716 miles. The satellite is approximately 1706 miles above the ground.<\/p>\n<p>63.\u00a02.6\u00a0ft<\/p>\n<p>65.\u00a05.6\u00a0km<\/p>\n<p>67.\u00a0371\u00a0ft<\/p>\n<p>71.\u00a024.1\u00a0ft<\/p>\n<p>73.\u00a019,056\u00a0ft2<\/p>\n<p>75.\u00a0445,624\u00a0square\u00a0miles<\/p>\n<h1>Non-Right Triangles: Law of Cosines<\/h1>\n<p>1.\u00a0two sides and the angle opposite the missing side<\/p>\n<p>3.\u00a0[latex]s[\/latex] is the semi-perimeter, which is half the perimeter of the triangle.<\/p>\n<p>5.\u00a0The Law of Cosines must be used for any oblique (non-right) triangle.<\/p>\n<p>7.\u00a011.3<\/p>\n<p>13.\u00a0257.4<\/p>\n<p>15.\u00a0not possible<\/p>\n<p>17.\u00a095.5\u00b0<\/p>\n<p>19.\u00a026.9\u00b0<\/p>\n<p>21.\u00a0[latex]B\\approx 45.9^\\circ ,C\\approx 99.1^\\circ ,a\\approx 6.4[\/latex]<\/p>\n<p>23.\u00a0[latex]A\\approx 20.6^\\circ ,B\\approx 38.4^\\circ ,c\\approx 51.1[\/latex]<\/p>\n<p>25.\u00a0[latex]A\\approx 37.8^\\circ ,B\\approx 43.8,C\\approx 98.4^\\circ[\/latex]<\/p>\n<p>27.\u00a0177.56 in2<\/p>\n<p>29.\u00a00.04 m2<\/p>\n<p>31.\u00a00.91 yd2<\/p>\n<p>33.\u00a03.0<\/p>\n<p>37.\u00a00.5<\/p>\n<p>39.\u00a070.7\u00b0<\/p>\n<p>41.\u00a077.4\u00b0<\/p>\n<p>43.\u00a025.0<\/p>\n<p>47.\u00a043.52<\/p>\n<p>49.\u00a01.41<\/p>\n<p>51.\u00a00.14<\/p>\n<p>59.\u00a07.62<\/p>\n<p>61.\u00a085.1<\/p>\n<p>63.\u00a024.0 km<\/p>\n<p>65.\u00a099.9 ft<\/p>\n<p>67.\u00a037.3 miles<\/p>\n<p>69.\u00a02371 miles<\/p>\n<p>71.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27165342\/CNX_Precalc_Figure_08_02_233.jpg\" alt=\"Angle BO is 9.1 degrees, angle PH is 150.2 degrees, and angle DC is 20.7 degrees.\" \/><\/p>\n<p>73.\u00a0599.8 miles<\/p>\n<p>75.\u00a065.4 cm2<\/p>\n<p>77.\u00a0468 ft2<\/p>\n","protected":false},"author":13,"menu_order":16,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":224,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/344"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":3,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/344\/revisions"}],"predecessor-version":[{"id":364,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/344\/revisions\/364"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/224"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/344\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=344"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=344"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=344"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=344"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}