{"id":322,"date":"2026-02-02T19:37:03","date_gmt":"2026-02-02T19:37:03","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/?post_type=chapter&#038;p=322"},"modified":"2026-02-03T15:23:31","modified_gmt":"2026-02-03T15:23:31","slug":"sequences-get-stronger-answer-key","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/sequences-get-stronger-answer-key\/","title":{"raw":"Sequences: Get Stronger Answer Key","rendered":"Sequences: Get Stronger Answer Key"},"content":{"raw":"<h2>Sequences and Their Notations<\/h2>\r\n7.\u00a0First four terms: [latex]-8,\\text{ }-\\frac{16}{3},\\text{ }-4,\\text{ }-\\frac{16}{5}[\/latex]\r\n\r\n11.\u00a0First four terms: [latex]1.25,\\text{ }-5,\\text{ }20,\\text{ }-80[\/latex] .\r\n\r\n13.\u00a0First four terms: [latex]\\frac{1}{3},\\text{ }\\frac{4}{5},\\text{ }\\frac{9}{7},\\text{ }\\frac{16}{9}[\/latex] .\r\n\r\n21.\u00a0[latex]{a}_{n}={n}^{2}+3[\/latex]\r\n\r\n23.\u00a0[latex]{a}_{n}=\\frac{{2}^{n}}{2n}\\text{ or }\\frac{{2}^{n - 1}}{n}[\/latex]\r\n\r\n25.\u00a0[latex]{a}_{n}={\\left(-\\frac{1}{2}\\right)}^{n - 1}[\/latex]\r\n\r\n27.\u00a0First five terms: [latex]3,\\text{ }-9,\\text{ }27,\\text{ }-81,\\text{ }243[\/latex]\r\n\r\n29.\u00a0First five terms: [latex]-1,\\text{ }1,\\text{ }-9,\\text{ }\\frac{27}{11},\\text{ }\\frac{891}{5}[\/latex]\r\n\r\n35.\u00a0[latex]{a}_{1}=-8,{a}_{n}={a}_{n - 1}+n[\/latex]\r\n\r\n37.\u00a0[latex]{a}_{1}=35,{a}_{n}={a}_{n - 1}+3[\/latex]\r\n\r\n43.\u00a0First four terms: [latex]1,\\frac{1}{2},\\frac{2}{3},\\frac{3}{2}[\/latex]\r\n\r\n45.\u00a0First four terms: [latex]-1,2,\\frac{6}{5},\\frac{24}{11}[\/latex]\r\n\r\n55.\u00a0[latex]{a}_{1}=6,\\text{ }{a}_{n}=2{a}_{n - 1}-5[\/latex]\r\n\r\n67.\u00a0If [latex]{a}_{n}=-421[\/latex] is a term in the sequence, then solving the equation [latex]-421=-6 - 8n[\/latex] for [latex]n[\/latex] will yield a non-negative integer. However, if [latex]-421=-6 - 8n[\/latex], then [latex]n=51.875[\/latex] so [latex]{a}_{n}=-421[\/latex] is not a term in the sequence.\r\n<h2>Arithmetic Sequences<\/h2>\r\n1.\u00a0A sequence where each successive term of the sequence increases (or decreases) by a constant value.\r\n\r\n3.\u00a0We find whether the difference between all consecutive terms is the same. This is the same as saying that the sequence has a common difference.\r\n\r\n7.\u00a0The common difference is [latex]\\frac{1}{2}[\/latex]\r\n\r\n9.\u00a0The sequence is not arithmetic because [latex]16 - 4\\ne 64 - 16[\/latex].\r\n\r\n11.\u00a0[latex]0,\\frac{2}{3},\\frac{4}{3},2,\\frac{8}{3}[\/latex]\r\n\r\n13.\u00a0[latex]0,-5,-10,-15,-20[\/latex]\r\n\r\n15.\u00a0[latex]{a}_{4}=19[\/latex]\r\n\r\n17.\u00a0[latex]{a}_{6}=41[\/latex]\r\n\r\n19.\u00a0[latex]{a}_{1}=2[\/latex]\r\n\r\n21.\u00a0[latex]{a}_{1}=5[\/latex]\r\n\r\n23.\u00a0[latex]{a}_{1}=6[\/latex]\r\n\r\n27. [latex]-19,-20.4,-21.8,-23.2,-24.6[\/latex]\r\n\r\n41. First five terms: [latex]20,16,12,8,4[\/latex]\r\n\r\n29. [latex]\\begin{array}{ll}{a}_{1}=17; {a}_{n}={a}_{n - 1}+9\\hfill &amp; n\\ge 2\\hfill \\end{array}[\/latex]\r\n\r\n33.\u00a0[latex]\\begin{array}{ll}{a}_{1}=8.9; {a}_{n}={a}_{n - 1}+1.4\\hfill &amp; n\\ge 2\\hfill \\end{array}[\/latex]\r\n\r\n35.\u00a0[latex]\\begin{array}{ll}{a}_{1}=\\frac{1}{5}; {a}_{n}={a}_{n - 1}+\\frac{1}{4}\\hfill &amp; n\\ge 2\\hfill \\end{array}[\/latex]\r\n\r\n37.\u00a0[latex]\\begin{array}{ll}{}_{1}=\\frac{1}{6}; {a}_{n}={a}_{n - 1}-\\frac{13}{12}\\hfill &amp; n\\ge 2\\hfill \\end{array}[\/latex]\r\n\r\n45.\u00a0[latex]{a}_{n}=-105+100n[\/latex]\r\n\r\n49.\u00a0[latex]{a}_{n}=13.1+2.7n[\/latex]\r\n\r\n51.\u00a0[latex]{a}_{n}=\\frac{1}{3}n-\\frac{1}{3}[\/latex]\r\n\r\n53.\u00a0There are 10 terms in the sequence.\r\n\r\n55.\u00a0There are 6 terms in the sequence.\r\n<h2>Geometric Sequences<\/h2>\r\n1.\u00a0A sequence in which the ratio between any two consecutive terms is constant.\r\n\r\n3.\u00a0Divide each term in a sequence by the preceding term. If the resulting quotients are equal, then the sequence is geometric.\r\n\r\n7.\u00a0The common ratio is [latex]-2[\/latex]\r\n\r\n9.\u00a0The sequence is geometric. The common ratio is 2.\r\n\r\n11.\u00a0The sequence is geometric. The common ratio is [latex]-\\frac{1}{2}[\/latex].\r\n\r\n13.\u00a0The sequence is geometric. The common ratio is [latex]5[\/latex].\r\n\r\n15.\u00a0[latex]5,1,\\frac{1}{5},\\frac{1}{25},\\frac{1}{125}[\/latex]\r\n\r\n17.\u00a0[latex]800,400,200,100,50[\/latex]\r\n\r\n23.\u00a0[latex]7,1.4,0.28,0.056,0.0112[\/latex]\r\n\r\n33.\u00a0[latex]12,-6,3,-\\frac{3}{2},\\frac{3}{4}[\/latex]\r\n\r\n19.\u00a0[latex]{a}_{4}=-\\frac{16}{27}[\/latex]\r\n\r\n21.\u00a0[latex]{a}_{7}=-\\frac{2}{729}[\/latex]\r\n\r\n43.\u00a0[latex]{a}_{12}=\\frac{1}{177,147}[\/latex]\r\n\r\n25.\u00a0[latex]\\begin{array}{cc}a{}_{1}=-32,&amp; {a}_{n}=\\frac{1}{2}{a}_{n - 1}\\end{array}[\/latex]\r\n\r\n27.\u00a0[latex]\\begin{array}{cc}{a}_{1}=10,&amp; {a}_{n}=-0.3{a}_{n - 1}\\end{array}[\/latex]\r\n\r\n29.\u00a0[latex]\\begin{array}{cc}{a}_{1}=\\frac{3}{5},&amp; {a}_{n}=\\frac{1}{6}{a}_{n - 1}\\end{array}[\/latex]\r\n\r\n31.\u00a0[latex]{a}_{1}=\\frac{1}{512},{a}_{n}=-4{a}_{n - 1}[\/latex]\r\n\r\n35.\u00a0[latex]{a}_{n}={3}^{n - 1}[\/latex]\r\n\r\n37.\u00a0[latex]{a}_{n}=0.8\\cdot {\\left(-5\\right)}^{n - 1}[\/latex]\r\n\r\n39.\u00a0[latex]{a}_{n}=-{\\left(\\frac{4}{5}\\right)}^{n - 1}[\/latex]\r\n\r\n41.\u00a0[latex]{a}_{n}=3\\cdot {\\left(-\\frac{1}{3}\\right)}^{n - 1}[\/latex]\r\n\r\n45.\u00a0There are [latex]12[\/latex] terms in the sequence.\r\n\r\n51.\u00a0Answers will vary. Examples: [latex]{\\begin{array}{cc}{a}_{1}=800,&amp; {a}_{n}=0.5a\\end{array}}_{n - 1}[\/latex] and [latex]{\\begin{array}{cc}{a}_{1}=12.5,&amp; {a}_{n}=4a\\end{array}}_{n - 1}[\/latex]\r\n\r\n53.\u00a0[latex]{a}_{5}=256b[\/latex]\r\n<h2>Series and Their Notations<\/h2>\r\n1.\u00a0An [latex]n\\text{th}[\/latex] partial sum is the sum of the first [latex]n[\/latex] terms of a sequence.\r\n\r\n3.\u00a0A geometric series is the sum of the terms in a geometric sequence.\r\n\r\n7.\u00a0[latex]\\sum _{n=0}^{4}5n[\/latex]\r\n\r\n9.\u00a0[latex]\\sum _{k=1}^{5}4[\/latex]\r\n\r\n11.\u00a0[latex]\\sum _{k=1}^{20}8k+2[\/latex]\r\n\r\n17.\u00a0[latex]\\sum _{k=1}^{7}8\\cdot {0.5}^{k - 1}[\/latex]\r\n\r\n13.\u00a0[latex]{S}_{5}=\\frac{5\\left(\\frac{3}{2}+\\frac{7}{2}\\right)}{2}[\/latex]\r\n\r\n15.\u00a0[latex]{S}_{13}=\\frac{13\\left(3.2+5.6\\right)}{2}[\/latex]\r\n\r\n35.\u00a0[latex]{S}_{7}=\\frac{147}{2}[\/latex]\r\n\r\n37.\u00a0[latex]{S}_{11}=\\frac{55}{2}[\/latex]\r\n\r\n19.\u00a0[latex]{S}_{5}=\\frac{9\\left(1-{\\left(\\frac{1}{3}\\right)}^{5}\\right)}{1-\\frac{1}{3}}=\\frac{121}{9}\\approx 13.44[\/latex]\r\n\r\n21.\u00a0[latex]{S}_{11}=\\frac{64\\left(1-{0.2}^{11}\\right)}{1 - 0.2}=\\frac{781,249,984}{9,765,625}\\approx 80[\/latex]\r\n\r\n39.\u00a0[latex]{S}_{7}=5208.4[\/latex]\r\n\r\n41.\u00a0[latex]{S}_{10}=-\\frac{1023}{256}[\/latex]\r\n\r\n23.\u00a0The series is defined. [latex]S=\\frac{2}{1 - 0.8}[\/latex]\r\n\r\n25.\u00a0The series is defined. [latex]S=\\frac{-1}{1-\\left(-\\frac{1}{2}\\right)}[\/latex]\r\n\r\n31.\u00a049\r\n\r\n33.\u00a0254\r\n\r\n43.\u00a0[latex]S=-\\frac{4}{3}[\/latex]\r\n\r\n45.\u00a0[latex]S=9.2[\/latex]\r\n\r\n47.\u00a0$3,705.42\r\n\r\n49.\u00a0$695,823.97\r\n\r\n57.\u00a0$400 per month\r\n\r\n59.\u00a0420 feet\r\n\r\n61.\u00a012 feet","rendered":"<h2>Sequences and Their Notations<\/h2>\n<p>7.\u00a0First four terms: [latex]-8,\\text{ }-\\frac{16}{3},\\text{ }-4,\\text{ }-\\frac{16}{5}[\/latex]<\/p>\n<p>11.\u00a0First four terms: [latex]1.25,\\text{ }-5,\\text{ }20,\\text{ }-80[\/latex] .<\/p>\n<p>13.\u00a0First four terms: [latex]\\frac{1}{3},\\text{ }\\frac{4}{5},\\text{ }\\frac{9}{7},\\text{ }\\frac{16}{9}[\/latex] .<\/p>\n<p>21.\u00a0[latex]{a}_{n}={n}^{2}+3[\/latex]<\/p>\n<p>23.\u00a0[latex]{a}_{n}=\\frac{{2}^{n}}{2n}\\text{ or }\\frac{{2}^{n - 1}}{n}[\/latex]<\/p>\n<p>25.\u00a0[latex]{a}_{n}={\\left(-\\frac{1}{2}\\right)}^{n - 1}[\/latex]<\/p>\n<p>27.\u00a0First five terms: [latex]3,\\text{ }-9,\\text{ }27,\\text{ }-81,\\text{ }243[\/latex]<\/p>\n<p>29.\u00a0First five terms: [latex]-1,\\text{ }1,\\text{ }-9,\\text{ }\\frac{27}{11},\\text{ }\\frac{891}{5}[\/latex]<\/p>\n<p>35.\u00a0[latex]{a}_{1}=-8,{a}_{n}={a}_{n - 1}+n[\/latex]<\/p>\n<p>37.\u00a0[latex]{a}_{1}=35,{a}_{n}={a}_{n - 1}+3[\/latex]<\/p>\n<p>43.\u00a0First four terms: [latex]1,\\frac{1}{2},\\frac{2}{3},\\frac{3}{2}[\/latex]<\/p>\n<p>45.\u00a0First four terms: [latex]-1,2,\\frac{6}{5},\\frac{24}{11}[\/latex]<\/p>\n<p>55.\u00a0[latex]{a}_{1}=6,\\text{ }{a}_{n}=2{a}_{n - 1}-5[\/latex]<\/p>\n<p>67.\u00a0If [latex]{a}_{n}=-421[\/latex] is a term in the sequence, then solving the equation [latex]-421=-6 - 8n[\/latex] for [latex]n[\/latex] will yield a non-negative integer. However, if [latex]-421=-6 - 8n[\/latex], then [latex]n=51.875[\/latex] so [latex]{a}_{n}=-421[\/latex] is not a term in the sequence.<\/p>\n<h2>Arithmetic Sequences<\/h2>\n<p>1.\u00a0A sequence where each successive term of the sequence increases (or decreases) by a constant value.<\/p>\n<p>3.\u00a0We find whether the difference between all consecutive terms is the same. This is the same as saying that the sequence has a common difference.<\/p>\n<p>7.\u00a0The common difference is [latex]\\frac{1}{2}[\/latex]<\/p>\n<p>9.\u00a0The sequence is not arithmetic because [latex]16 - 4\\ne 64 - 16[\/latex].<\/p>\n<p>11.\u00a0[latex]0,\\frac{2}{3},\\frac{4}{3},2,\\frac{8}{3}[\/latex]<\/p>\n<p>13.\u00a0[latex]0,-5,-10,-15,-20[\/latex]<\/p>\n<p>15.\u00a0[latex]{a}_{4}=19[\/latex]<\/p>\n<p>17.\u00a0[latex]{a}_{6}=41[\/latex]<\/p>\n<p>19.\u00a0[latex]{a}_{1}=2[\/latex]<\/p>\n<p>21.\u00a0[latex]{a}_{1}=5[\/latex]<\/p>\n<p>23.\u00a0[latex]{a}_{1}=6[\/latex]<\/p>\n<p>27. [latex]-19,-20.4,-21.8,-23.2,-24.6[\/latex]<\/p>\n<p>41. First five terms: [latex]20,16,12,8,4[\/latex]<\/p>\n<p>29. [latex]\\begin{array}{ll}{a}_{1}=17; {a}_{n}={a}_{n - 1}+9\\hfill & n\\ge 2\\hfill \\end{array}[\/latex]<\/p>\n<p>33.\u00a0[latex]\\begin{array}{ll}{a}_{1}=8.9; {a}_{n}={a}_{n - 1}+1.4\\hfill & n\\ge 2\\hfill \\end{array}[\/latex]<\/p>\n<p>35.\u00a0[latex]\\begin{array}{ll}{a}_{1}=\\frac{1}{5}; {a}_{n}={a}_{n - 1}+\\frac{1}{4}\\hfill & n\\ge 2\\hfill \\end{array}[\/latex]<\/p>\n<p>37.\u00a0[latex]\\begin{array}{ll}{}_{1}=\\frac{1}{6}; {a}_{n}={a}_{n - 1}-\\frac{13}{12}\\hfill & n\\ge 2\\hfill \\end{array}[\/latex]<\/p>\n<p>45.\u00a0[latex]{a}_{n}=-105+100n[\/latex]<\/p>\n<p>49.\u00a0[latex]{a}_{n}=13.1+2.7n[\/latex]<\/p>\n<p>51.\u00a0[latex]{a}_{n}=\\frac{1}{3}n-\\frac{1}{3}[\/latex]<\/p>\n<p>53.\u00a0There are 10 terms in the sequence.<\/p>\n<p>55.\u00a0There are 6 terms in the sequence.<\/p>\n<h2>Geometric Sequences<\/h2>\n<p>1.\u00a0A sequence in which the ratio between any two consecutive terms is constant.<\/p>\n<p>3.\u00a0Divide each term in a sequence by the preceding term. If the resulting quotients are equal, then the sequence is geometric.<\/p>\n<p>7.\u00a0The common ratio is [latex]-2[\/latex]<\/p>\n<p>9.\u00a0The sequence is geometric. The common ratio is 2.<\/p>\n<p>11.\u00a0The sequence is geometric. The common ratio is [latex]-\\frac{1}{2}[\/latex].<\/p>\n<p>13.\u00a0The sequence is geometric. The common ratio is [latex]5[\/latex].<\/p>\n<p>15.\u00a0[latex]5,1,\\frac{1}{5},\\frac{1}{25},\\frac{1}{125}[\/latex]<\/p>\n<p>17.\u00a0[latex]800,400,200,100,50[\/latex]<\/p>\n<p>23.\u00a0[latex]7,1.4,0.28,0.056,0.0112[\/latex]<\/p>\n<p>33.\u00a0[latex]12,-6,3,-\\frac{3}{2},\\frac{3}{4}[\/latex]<\/p>\n<p>19.\u00a0[latex]{a}_{4}=-\\frac{16}{27}[\/latex]<\/p>\n<p>21.\u00a0[latex]{a}_{7}=-\\frac{2}{729}[\/latex]<\/p>\n<p>43.\u00a0[latex]{a}_{12}=\\frac{1}{177,147}[\/latex]<\/p>\n<p>25.\u00a0[latex]\\begin{array}{cc}a{}_{1}=-32,& {a}_{n}=\\frac{1}{2}{a}_{n - 1}\\end{array}[\/latex]<\/p>\n<p>27.\u00a0[latex]\\begin{array}{cc}{a}_{1}=10,& {a}_{n}=-0.3{a}_{n - 1}\\end{array}[\/latex]<\/p>\n<p>29.\u00a0[latex]\\begin{array}{cc}{a}_{1}=\\frac{3}{5},& {a}_{n}=\\frac{1}{6}{a}_{n - 1}\\end{array}[\/latex]<\/p>\n<p>31.\u00a0[latex]{a}_{1}=\\frac{1}{512},{a}_{n}=-4{a}_{n - 1}[\/latex]<\/p>\n<p>35.\u00a0[latex]{a}_{n}={3}^{n - 1}[\/latex]<\/p>\n<p>37.\u00a0[latex]{a}_{n}=0.8\\cdot {\\left(-5\\right)}^{n - 1}[\/latex]<\/p>\n<p>39.\u00a0[latex]{a}_{n}=-{\\left(\\frac{4}{5}\\right)}^{n - 1}[\/latex]<\/p>\n<p>41.\u00a0[latex]{a}_{n}=3\\cdot {\\left(-\\frac{1}{3}\\right)}^{n - 1}[\/latex]<\/p>\n<p>45.\u00a0There are [latex]12[\/latex] terms in the sequence.<\/p>\n<p>51.\u00a0Answers will vary. Examples: [latex]{\\begin{array}{cc}{a}_{1}=800,& {a}_{n}=0.5a\\end{array}}_{n - 1}[\/latex] and [latex]{\\begin{array}{cc}{a}_{1}=12.5,& {a}_{n}=4a\\end{array}}_{n - 1}[\/latex]<\/p>\n<p>53.\u00a0[latex]{a}_{5}=256b[\/latex]<\/p>\n<h2>Series and Their Notations<\/h2>\n<p>1.\u00a0An [latex]n\\text{th}[\/latex] partial sum is the sum of the first [latex]n[\/latex] terms of a sequence.<\/p>\n<p>3.\u00a0A geometric series is the sum of the terms in a geometric sequence.<\/p>\n<p>7.\u00a0[latex]\\sum _{n=0}^{4}5n[\/latex]<\/p>\n<p>9.\u00a0[latex]\\sum _{k=1}^{5}4[\/latex]<\/p>\n<p>11.\u00a0[latex]\\sum _{k=1}^{20}8k+2[\/latex]<\/p>\n<p>17.\u00a0[latex]\\sum _{k=1}^{7}8\\cdot {0.5}^{k - 1}[\/latex]<\/p>\n<p>13.\u00a0[latex]{S}_{5}=\\frac{5\\left(\\frac{3}{2}+\\frac{7}{2}\\right)}{2}[\/latex]<\/p>\n<p>15.\u00a0[latex]{S}_{13}=\\frac{13\\left(3.2+5.6\\right)}{2}[\/latex]<\/p>\n<p>35.\u00a0[latex]{S}_{7}=\\frac{147}{2}[\/latex]<\/p>\n<p>37.\u00a0[latex]{S}_{11}=\\frac{55}{2}[\/latex]<\/p>\n<p>19.\u00a0[latex]{S}_{5}=\\frac{9\\left(1-{\\left(\\frac{1}{3}\\right)}^{5}\\right)}{1-\\frac{1}{3}}=\\frac{121}{9}\\approx 13.44[\/latex]<\/p>\n<p>21.\u00a0[latex]{S}_{11}=\\frac{64\\left(1-{0.2}^{11}\\right)}{1 - 0.2}=\\frac{781,249,984}{9,765,625}\\approx 80[\/latex]<\/p>\n<p>39.\u00a0[latex]{S}_{7}=5208.4[\/latex]<\/p>\n<p>41.\u00a0[latex]{S}_{10}=-\\frac{1023}{256}[\/latex]<\/p>\n<p>23.\u00a0The series is defined. [latex]S=\\frac{2}{1 - 0.8}[\/latex]<\/p>\n<p>25.\u00a0The series is defined. [latex]S=\\frac{-1}{1-\\left(-\\frac{1}{2}\\right)}[\/latex]<\/p>\n<p>31.\u00a049<\/p>\n<p>33.\u00a0254<\/p>\n<p>43.\u00a0[latex]S=-\\frac{4}{3}[\/latex]<\/p>\n<p>45.\u00a0[latex]S=9.2[\/latex]<\/p>\n<p>47.\u00a0$3,705.42<\/p>\n<p>49.\u00a0$695,823.97<\/p>\n<p>57.\u00a0$400 per month<\/p>\n<p>59.\u00a0420 feet<\/p>\n<p>61.\u00a012 feet<\/p>\n","protected":false},"author":13,"menu_order":11,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":224,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/322"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":4,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/322\/revisions"}],"predecessor-version":[{"id":334,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/322\/revisions\/334"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/224"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/322\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=322"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=322"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=322"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=322"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}