{"id":181,"date":"2026-01-12T16:00:48","date_gmt":"2026-01-12T16:00:48","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/?post_type=chapter&#038;p=181"},"modified":"2026-01-12T16:00:49","modified_gmt":"2026-01-12T16:00:49","slug":"introduction-to-differential-equations-get-stronger-answer-key","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/introduction-to-differential-equations-get-stronger-answer-key\/","title":{"raw":"Introduction to Differential Equations: Get Stronger Answer Key","rendered":"Introduction to Differential Equations: Get Stronger Answer Key"},"content":{"raw":"<h2><span data-sheets-root=\"1\">Basics of Differential Equations<\/span><\/h2>\r\n<ol class=\"tight\" dir=\"ltr\" data-tight=\"true\" data-pm-slice=\"3 3 []\">\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li>[latex]3[\/latex]<\/li>\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li>[latex]y=4+\\dfrac{3{x}^{4}}{4}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{2}{e}^{{x}^{2}}[\/latex]<\/li>\r\n \t<li>[latex]y=2{e}^{\\dfrac{\\text{-}1}{x}}[\/latex]<\/li>\r\n \t<li>[latex]u={\\sin}^{-1}\\left({e}^{-1+t}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=-\\dfrac{\\sqrt{x+1}}{\\sqrt{1-x}}-1[\/latex]<\/li>\r\n \t<li>[latex]y=C-x+x\\text{ln}x-\\text{ln}\\left(\\cos{x}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C+\\dfrac{{4}^{x}}{\\text{ln}\\left(4\\right)}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{2}{3}\\sqrt{{t}^{2}+16}\\left({t}^{2}+16\\right)+C[\/latex]<\/li>\r\n \t<li>[latex]x=\\dfrac{2}{15}\\sqrt{4+t}\\left(3{t}^{2}+4t - 32\\right)+C[\/latex]<\/li>\r\n \t<li>[latex]y=Cx[\/latex]<\/li>\r\n \t<li>[latex]y=1-\\dfrac{{t}^{2}}{2},y=-\\dfrac{{t}^{2}}{2}-1[\/latex]<\/li>\r\n \t<li>[latex]y={e}^{\\text{-}t},y=\\text{-}{e}^{\\text{-}t}[\/latex]<\/li>\r\n \t<li>[latex]y=2\\left({t}^{2}+5\\right),t=3\\sqrt{5}[\/latex]<\/li>\r\n \t<li>[latex]y=10{e}^{-2t},t=-\\dfrac{1}{2}\\text{ln}\\left(\\dfrac{1}{10}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{4}\\left(41-{e}^{-4t}\\right)[\/latex], never<\/li>\r\n \t<li>Solution changes from increasing to decreasing at [latex]y\\left(0\\right)=0[\/latex]<\/li>\r\n \t<li>Solution changes from increasing to decreasing at [latex]y\\left(0\\right)=0[\/latex]<\/li>\r\n \t<li>[latex]v\\left(t\\right)=-32t+a[\/latex]<\/li>\r\n \t<li>[latex]0[\/latex] ft\/s<\/li>\r\n \t<li>[latex]y=4{e}^{3t}[\/latex]<\/li>\r\n \t<li>[latex]y=3 - 2t+{t}^{2}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{k}\\left({e}^{kt}-1\\right)[\/latex] and [latex]y=x[\/latex]<\/li>\r\n<\/ol>\r\n<h2><span data-sheets-root=\"1\">Direction Fields and Euler's Method<\/span><\/h2>\r\n<ol>\r\n \t<li><span id=\"fs-id1170573741999\" data-type=\"media\" data-alt=\"A graph of the given direction field with a flat line drawn on the axis. The arrows point up for y &lt; 0 and down for y &gt; 0. The closer they are to the x axis, the more horizontal the arrows are, and the further away they are, the more vertical they become.\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234127\/CNX_Calc_Figure_08_02_203.jpg\" alt=\"A graph of the given direction field with a flat line drawn on the axis. The arrows point up for y &lt; 0 and down for y &gt; 0. The closer they are to the x axis, the more horizontal the arrows are, and the further away they are, the more vertical they become.\" data-media-type=\"image\/jpeg\" \/><\/span><\/li>\r\n \t<li>[latex]y=0[\/latex] is a stable equilibrium<\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234132\/CNX_Calc_Figure_08_02_207.jpg\" alt=\"A direction field with horizontal arrows at y = 0 and y = 2. The arrows point up for y &gt; 2 and for y &lt; 0. The arrows point down for 0 &lt; y &lt; 2. The closer the arrows are to these lines, the more horizontal they are, and the further away, the more vertical the arrows are. A solution is sketched that follows y = 2 in quadrant two, goes through (0, 1), and then follows the x axis.\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li>[latex]y=0[\/latex] is a stable equilibrium and [latex]y=2[\/latex] is unstable<\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234134\/CNX_Calc_Figure_08_02_210.jpg\" alt=\"A direction field over the four quadrants. As t goes from 0 to infinity, the arrows become more and more vertical after being horizontal closer to x = 0.\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234136\/CNX_Calc_Figure_08_02_212.jpg\" alt=\"A direction field over [-2, 2] in the x and y axes. The arrows point slightly down and to the right over [-2, 0] and gradually become vertical over [0, 2].\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li><span id=\"fs-id1170571043026\" data-type=\"media\" data-alt=\"A direction field with horizontal arrows pointing to the right at y = 1 and y = -1. The arrows point up for y &lt; -1 and y &gt; 1. The arrows point down for -1 &lt; y &lt; 1. The closer the arrows are to these lines, the more horizontal they are, and the further away they are, the more vertical they are.\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234138\/CNX_Calc_Figure_08_02_214.jpg\" alt=\"A direction field with horizontal arrows pointing to the right at y = 1 and y = -1. The arrows point up for y &lt; -1 and y &gt; 1. The arrows point down for -1 &lt; y &lt; 1. The closer the arrows are to these lines, the more horizontal they are, and the further away they are, the more vertical they are.\" data-media-type=\"image\/jpeg\" \/><\/span><\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234141\/CNX_Calc_Figure_08_02_216.jpg\" alt=\"A direction field with arrows pointing down and to the right for nearly all points in [-2, 2] on the x and y axes. Close to the origin, the arrows become more horizontal, point to the upper right, become more horizontal, and then point down to the right again.\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234143\/CNX_Calc_Figure_08_02_218.jpg\" alt=\"A direction field with horizontal arrows pointing to the right on the x-axis and x = -3. Above the x-axis and for x &lt; -3, the arrows point down. For x &gt; -3, the arrows point up. Below the x-axis and for x &lt; -3, the arrows point up. For x &gt; -3, the arrows point down. The further away from the x-axis and x = -3, the arrows become more vertical, and the closer they become, the more horizontal they become.\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li>E<\/li>\r\n \t<li>A<\/li>\r\n \t<li>B<\/li>\r\n \t<li>A<\/li>\r\n \t<li>C<\/li>\r\n \t<li>[latex]2.24[\/latex], exact: [latex]3[\/latex]<\/li>\r\n \t<li>[latex]7.739364[\/latex], exact: [latex]5\\left(e - 1\\right)[\/latex]<\/li>\r\n \t<li>[latex]-0.2535[\/latex], exact: [latex]0[\/latex]<\/li>\r\n \t<li>[latex]1.345[\/latex], exact: [latex]\\dfrac{1}{\\text{ln}\\left(2\\right)}[\/latex]<\/li>\r\n \t<li>[latex]-4[\/latex], exact: [latex]\\dfrac{\\text{-}1}{2}[\/latex]<\/li>\r\n \t<li><img style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234217\/CNX_Calc_Figure_08_02_223.jpg\" alt=\"A direction field with horizontal arrows pointing to the right on the x axis. Above the x axis, the arrows point down and to the right. Below the x axis, the arrows point up and to the right. The closer the arrows are to the x axis, the more horizontal the arrows are, and the further away they are from the x axis, the more vertical the arrows are.\" data-media-type=\"image\/jpeg\" \/><\/li>\r\n \t<li>[latex]4.0741{e}^{-10}[\/latex]<\/li>\r\n<\/ol>\r\n<h2><span data-sheets-root=\"1\">Separation of Variables<\/span><\/h2>\r\n<ol>\r\n \t<li>[latex]y={e}^{t}-1[\/latex]<\/li>\r\n \t<li>[latex]y=1-{e}^{\\text{-}t}[\/latex]<\/li>\r\n \t<li>[latex]y=Cx{e}^{\\dfrac{-1}{x}}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{C-{x}^{2}}[\/latex]<\/li>\r\n \t<li>[latex]y=-\\dfrac{2}{C+\\text{ln}x}[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{x}\\left(x+1\\right)+1[\/latex]<\/li>\r\n \t<li>[latex]y=\\sin\\left(\\text{ln}t+C\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=\\text{-}\\text{ln}\\left({e}^{\\text{-}x}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{\\sqrt{2-{e}^{{x}^{2}}}}[\/latex]<\/li>\r\n \t<li>[latex]y={\\text{tanh}}^{-1}\\left(\\dfrac{{x}^{2}}{2}\\right)[\/latex]<\/li>\r\n \t<li>[latex]x=\\sin\\left(1-t+t\\text{ln}t\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=\\text{ln}\\left(\\text{ln}\\left(5\\right)\\right)-\\text{ln}\\left(2-{5}^{x}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{-2x}+\\dfrac{1}{2}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{1}{\\sqrt{2}\\sqrt{C-{e}^{x}}}[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{\\text{-}x}{x}^{x}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{r}{d}\\left(1-{e}^{\\text{-}dt}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y\\left(t\\right)=10 - 9{e}^{\\dfrac{\\text{-}x}{50}}[\/latex]<\/li>\r\n \t<li>[latex]T\\left(t\\right)=20+50{e}^{-0.125t}[\/latex]<\/li>\r\n \t<li>[latex]T\\left(t\\right)=20+38.5{e}^{-0.125t}[\/latex]<\/li>\r\n \t<li>[latex]24[\/latex] hours [latex]57[\/latex] minutes<\/li>\r\n \t<li>[latex]T\\left(t\\right)=20+50{e}^{-0.125t}[\/latex]<\/li>\r\n \t<li>[latex]T\\left(t\\right)=20+38.5{e}^{-0.125t}[\/latex]<\/li>\r\n \t<li>[latex]y=\\left(c+\\dfrac{b}{a}\\right){e}^{ax}-\\dfrac{b}{a}[\/latex]<\/li>\r\n \t<li>[latex]y\\left(t\\right)=cL+\\left(I-cL\\right){e}^{\\dfrac{\\text{-}rt}{L}}[\/latex]<\/li>\r\n \t<li>[latex]y=40\\left(1-{e}^{-0.1t}\\right),40[\/latex] g\/cm\u00b2<\/li>\r\n<\/ol>\r\n<h2><span data-sheets-root=\"1\">First-Order Linear Equations and Applications<\/span><\/h2>\r\n<ol class=\"tight\" dir=\"ltr\" data-tight=\"true\" data-pm-slice=\"3 3 []\">\r\n \t<li>Yes<\/li>\r\n \t<li>Yes<\/li>\r\n \t<li>[latex]y^{\\prime} -{x}^{3}y=\\sin{x}[\/latex]<\/li>\r\n \t<li>[latex]y^{\\prime} +\\dfrac{\\left(3x+2\\right)}{x}y=\\text{-}{e}^{x}[\/latex]<\/li>\r\n \t<li>[latex]\\dfrac{dy}{dt}-yx\\left(x+1\\right)=0[\/latex]<\/li>\r\n \t<li>[latex]{e}^{x}[\/latex]<\/li>\r\n \t<li>[latex]\\text{-}\\text{ln}\\left(\\text{cosh}x\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{3x}-\\dfrac{2}{3}[\/latex]<\/li>\r\n \t<li>[latex]y=C{x}^{3}+6{x}^{2}[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{\\dfrac{{x}^{2}}{2}}-3[\/latex]<\/li>\r\n \t<li>[latex]y=C\\tan\\left(\\dfrac{x}{2}\\right)-2x+4\\tan\\left(\\dfrac{x}{2}\\right)\\text{ln}\\left(\\sin\\left(\\dfrac{x}{2}\\right)\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C{x}^{3}-{x}^{2}[\/latex]<\/li>\r\n \t<li>[latex]y=C{\\left(x+2\\right)}^{2}+\\dfrac{1}{2}[\/latex]<\/li>\r\n \t<li>[latex]y=\\dfrac{C}{\\sqrt{x}}+2\\sin\\left(3t\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C{\\left(x+1\\right)}^{3}-{x}^{2}-2x - 1[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{{\\text{sinh}}^{-1}x}-2[\/latex]<\/li>\r\n \t<li>[latex]y=x+4{e}^{x}-1[\/latex]<\/li>\r\n \t<li>[latex]y=-\\dfrac{3x}{2}\\left({x}^{2}-1\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=1-{e}^{{\\tan}^{-1}x}[\/latex]<\/li>\r\n \t<li>[latex]y=\\left(x+2\\right)\\text{ln}\\left(\\dfrac{x+2}{2}\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=2{e}^{2\\sqrt{x}}-2x - 2\\sqrt{x}-1[\/latex]<\/li>\r\n \t<li>[latex]v\\left(t\\right)=\\dfrac{gm}{k}\\left(1-{e}^{\\dfrac{\\text{-}kt}{m}}\\right)[\/latex]<\/li>\r\n \t<li>[latex]\\sqrt{\\dfrac{gm}{k}}[\/latex]<\/li>\r\n \t<li>[latex]40.451[\/latex] seconds<\/li>\r\n \t<li>[latex]y=C{e}^{x}-a\\left(x+1\\right)[\/latex]<\/li>\r\n \t<li>[latex]y=C{e}^{\\dfrac{{x}^{2}}{2}}-a[\/latex]<\/li>\r\n \t<li>[latex]P=0[\/latex] semi-stable<\/li>\r\n \t<li>[latex]P=\\dfrac{10{e}^{10x}}{{e}^{10x}+4}[\/latex]<\/li>\r\n \t<li>[latex]P\\left(t\\right)=\\dfrac{10000{e}^{0.02t}}{150+50{e}^{0.02t}}[\/latex]<\/li>\r\n \t<li>[latex]69[\/latex] hours [latex]5[\/latex] minutes<\/li>\r\n \t<li>[latex]8[\/latex] years [latex]11[\/latex] months<\/li>\r\n \t<li>[latex]y=\\dfrac{-20}{4\\times {10}^{-6}-0.002{e}^{0.01t}}[\/latex]<\/li>\r\n \t<li>[latex]P\\left(t\\right)=\\dfrac{850+500{e}^{0.009t}}{85+5{e}^{0.009t}}[\/latex]<\/li>\r\n \t<li>[latex]13[\/latex] years<\/li>\r\n \t<li>[latex]31.465[\/latex] days<\/li>\r\n \t<li>September [latex]2008[\/latex]<\/li>\r\n \t<li>[latex]\\dfrac{K+T}{2}[\/latex]<\/li>\r\n \t<li>[latex]r=0.0405[\/latex]<\/li>\r\n \t<li><\/li>\r\n \t<li>[latex]\\alpha =0.0081[\/latex]<\/li>\r\n \t<li>Logistic: [latex]361[\/latex], Threshold: [latex]436[\/latex], Gompertz: [latex]309[\/latex].<\/li>\r\n<\/ol>","rendered":"<h2><span data-sheets-root=\"1\">Basics of Differential Equations<\/span><\/h2>\n<ol class=\"tight\" dir=\"ltr\" data-tight=\"true\" data-pm-slice=\"3 3 []\">\n<li>[latex]1[\/latex]<\/li>\n<li>[latex]3[\/latex]<\/li>\n<li>[latex]1[\/latex]<\/li>\n<li>[latex]1[\/latex]<\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<li>[latex]y=4+\\dfrac{3{x}^{4}}{4}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{2}{e}^{{x}^{2}}[\/latex]<\/li>\n<li>[latex]y=2{e}^{\\dfrac{\\text{-}1}{x}}[\/latex]<\/li>\n<li>[latex]u={\\sin}^{-1}\\left({e}^{-1+t}\\right)[\/latex]<\/li>\n<li>[latex]y=-\\dfrac{\\sqrt{x+1}}{\\sqrt{1-x}}-1[\/latex]<\/li>\n<li>[latex]y=C-x+x\\text{ln}x-\\text{ln}\\left(\\cos{x}\\right)[\/latex]<\/li>\n<li>[latex]y=C+\\dfrac{{4}^{x}}{\\text{ln}\\left(4\\right)}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{2}{3}\\sqrt{{t}^{2}+16}\\left({t}^{2}+16\\right)+C[\/latex]<\/li>\n<li>[latex]x=\\dfrac{2}{15}\\sqrt{4+t}\\left(3{t}^{2}+4t - 32\\right)+C[\/latex]<\/li>\n<li>[latex]y=Cx[\/latex]<\/li>\n<li>[latex]y=1-\\dfrac{{t}^{2}}{2},y=-\\dfrac{{t}^{2}}{2}-1[\/latex]<\/li>\n<li>[latex]y={e}^{\\text{-}t},y=\\text{-}{e}^{\\text{-}t}[\/latex]<\/li>\n<li>[latex]y=2\\left({t}^{2}+5\\right),t=3\\sqrt{5}[\/latex]<\/li>\n<li>[latex]y=10{e}^{-2t},t=-\\dfrac{1}{2}\\text{ln}\\left(\\dfrac{1}{10}\\right)[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{4}\\left(41-{e}^{-4t}\\right)[\/latex], never<\/li>\n<li>Solution changes from increasing to decreasing at [latex]y\\left(0\\right)=0[\/latex]<\/li>\n<li>Solution changes from increasing to decreasing at [latex]y\\left(0\\right)=0[\/latex]<\/li>\n<li>[latex]v\\left(t\\right)=-32t+a[\/latex]<\/li>\n<li>[latex]0[\/latex] ft\/s<\/li>\n<li>[latex]y=4{e}^{3t}[\/latex]<\/li>\n<li>[latex]y=3 - 2t+{t}^{2}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{k}\\left({e}^{kt}-1\\right)[\/latex] and [latex]y=x[\/latex]<\/li>\n<\/ol>\n<h2><span data-sheets-root=\"1\">Direction Fields and Euler&#8217;s Method<\/span><\/h2>\n<ol>\n<li><span id=\"fs-id1170573741999\" data-type=\"media\" data-alt=\"A graph of the given direction field with a flat line drawn on the axis. The arrows point up for y &lt; 0 and down for y &gt; 0. The closer they are to the x axis, the more horizontal the arrows are, and the further away they are, the more vertical they become.\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234127\/CNX_Calc_Figure_08_02_203.jpg\" alt=\"A graph of the given direction field with a flat line drawn on the axis. The arrows point up for y &lt; 0 and down for y &gt; 0. The closer they are to the x axis, the more horizontal the arrows are, and the further away they are, the more vertical they become.\" data-media-type=\"image\/jpeg\" \/><\/span><\/li>\n<li>[latex]y=0[\/latex] is a stable equilibrium<\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234132\/CNX_Calc_Figure_08_02_207.jpg\" alt=\"A direction field with horizontal arrows at y = 0 and y = 2. The arrows point up for y &gt; 2 and for y &lt; 0. The arrows point down for 0 &lt; y &lt; 2. The closer the arrows are to these lines, the more horizontal they are, and the further away, the more vertical the arrows are. A solution is sketched that follows y = 2 in quadrant two, goes through (0, 1), and then follows the x axis.\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li>[latex]y=0[\/latex] is a stable equilibrium and [latex]y=2[\/latex] is unstable<\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234134\/CNX_Calc_Figure_08_02_210.jpg\" alt=\"A direction field over the four quadrants. As t goes from 0 to infinity, the arrows become more and more vertical after being horizontal closer to x = 0.\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234136\/CNX_Calc_Figure_08_02_212.jpg\" alt=\"A direction field over [-2, 2] in the x and y axes. The arrows point slightly down and to the right over [-2, 0] and gradually become vertical over [0, 2].\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li><span id=\"fs-id1170571043026\" data-type=\"media\" data-alt=\"A direction field with horizontal arrows pointing to the right at y = 1 and y = -1. The arrows point up for y &lt; -1 and y &gt; 1. The arrows point down for -1 &lt; y &lt; 1. The closer the arrows are to these lines, the more horizontal they are, and the further away they are, the more vertical they are.\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234138\/CNX_Calc_Figure_08_02_214.jpg\" alt=\"A direction field with horizontal arrows pointing to the right at y = 1 and y = -1. The arrows point up for y &lt; -1 and y &gt; 1. The arrows point down for -1 &lt; y &lt; 1. The closer the arrows are to these lines, the more horizontal they are, and the further away they are, the more vertical they are.\" data-media-type=\"image\/jpeg\" \/><\/span><\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234141\/CNX_Calc_Figure_08_02_216.jpg\" alt=\"A direction field with arrows pointing down and to the right for nearly all points in [-2, 2] on the x and y axes. Close to the origin, the arrows become more horizontal, point to the upper right, become more horizontal, and then point down to the right again.\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234143\/CNX_Calc_Figure_08_02_218.jpg\" alt=\"A direction field with horizontal arrows pointing to the right on the x-axis and x = -3. Above the x-axis and for x &lt; -3, the arrows point down. For x &gt; -3, the arrows point up. Below the x-axis and for x &lt; -3, the arrows point up. For x &gt; -3, the arrows point down. The further away from the x-axis and x = -3, the arrows become more vertical, and the closer they become, the more horizontal they become.\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li>E<\/li>\n<li>A<\/li>\n<li>B<\/li>\n<li>A<\/li>\n<li>C<\/li>\n<li>[latex]2.24[\/latex], exact: [latex]3[\/latex]<\/li>\n<li>[latex]7.739364[\/latex], exact: [latex]5\\left(e - 1\\right)[\/latex]<\/li>\n<li>[latex]-0.2535[\/latex], exact: [latex]0[\/latex]<\/li>\n<li>[latex]1.345[\/latex], exact: [latex]\\dfrac{1}{\\text{ln}\\left(2\\right)}[\/latex]<\/li>\n<li>[latex]-4[\/latex], exact: [latex]\\dfrac{\\text{-}1}{2}[\/latex]<\/li>\n<li><img decoding=\"async\" style=\"font-size: 1rem; text-align: initial; background-color: initial;\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4175\/2019\/04\/11234217\/CNX_Calc_Figure_08_02_223.jpg\" alt=\"A direction field with horizontal arrows pointing to the right on the x axis. Above the x axis, the arrows point down and to the right. Below the x axis, the arrows point up and to the right. The closer the arrows are to the x axis, the more horizontal the arrows are, and the further away they are from the x axis, the more vertical the arrows are.\" data-media-type=\"image\/jpeg\" \/><\/li>\n<li>[latex]4.0741{e}^{-10}[\/latex]<\/li>\n<\/ol>\n<h2><span data-sheets-root=\"1\">Separation of Variables<\/span><\/h2>\n<ol>\n<li>[latex]y={e}^{t}-1[\/latex]<\/li>\n<li>[latex]y=1-{e}^{\\text{-}t}[\/latex]<\/li>\n<li>[latex]y=Cx{e}^{\\dfrac{-1}{x}}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{C-{x}^{2}}[\/latex]<\/li>\n<li>[latex]y=-\\dfrac{2}{C+\\text{ln}x}[\/latex]<\/li>\n<li>[latex]y=C{e}^{x}\\left(x+1\\right)+1[\/latex]<\/li>\n<li>[latex]y=\\sin\\left(\\text{ln}t+C\\right)[\/latex]<\/li>\n<li>[latex]y=\\text{-}\\text{ln}\\left({e}^{\\text{-}x}\\right)[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{\\sqrt{2-{e}^{{x}^{2}}}}[\/latex]<\/li>\n<li>[latex]y={\\text{tanh}}^{-1}\\left(\\dfrac{{x}^{2}}{2}\\right)[\/latex]<\/li>\n<li>[latex]x=\\sin\\left(1-t+t\\text{ln}t\\right)[\/latex]<\/li>\n<li>[latex]y=\\text{ln}\\left(\\text{ln}\\left(5\\right)\\right)-\\text{ln}\\left(2-{5}^{x}\\right)[\/latex]<\/li>\n<li>[latex]y=C{e}^{-2x}+\\dfrac{1}{2}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{1}{\\sqrt{2}\\sqrt{C-{e}^{x}}}[\/latex]<\/li>\n<li>[latex]y=C{e}^{\\text{-}x}{x}^{x}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{r}{d}\\left(1-{e}^{\\text{-}dt}\\right)[\/latex]<\/li>\n<li>[latex]y\\left(t\\right)=10 - 9{e}^{\\dfrac{\\text{-}x}{50}}[\/latex]<\/li>\n<li>[latex]T\\left(t\\right)=20+50{e}^{-0.125t}[\/latex]<\/li>\n<li>[latex]T\\left(t\\right)=20+38.5{e}^{-0.125t}[\/latex]<\/li>\n<li>[latex]24[\/latex] hours [latex]57[\/latex] minutes<\/li>\n<li>[latex]T\\left(t\\right)=20+50{e}^{-0.125t}[\/latex]<\/li>\n<li>[latex]T\\left(t\\right)=20+38.5{e}^{-0.125t}[\/latex]<\/li>\n<li>[latex]y=\\left(c+\\dfrac{b}{a}\\right){e}^{ax}-\\dfrac{b}{a}[\/latex]<\/li>\n<li>[latex]y\\left(t\\right)=cL+\\left(I-cL\\right){e}^{\\dfrac{\\text{-}rt}{L}}[\/latex]<\/li>\n<li>[latex]y=40\\left(1-{e}^{-0.1t}\\right),40[\/latex] g\/cm\u00b2<\/li>\n<\/ol>\n<h2><span data-sheets-root=\"1\">First-Order Linear Equations and Applications<\/span><\/h2>\n<ol class=\"tight\" dir=\"ltr\" data-tight=\"true\" data-pm-slice=\"3 3 []\">\n<li>Yes<\/li>\n<li>Yes<\/li>\n<li>[latex]y^{\\prime} -{x}^{3}y=\\sin{x}[\/latex]<\/li>\n<li>[latex]y^{\\prime} +\\dfrac{\\left(3x+2\\right)}{x}y=\\text{-}{e}^{x}[\/latex]<\/li>\n<li>[latex]\\dfrac{dy}{dt}-yx\\left(x+1\\right)=0[\/latex]<\/li>\n<li>[latex]{e}^{x}[\/latex]<\/li>\n<li>[latex]\\text{-}\\text{ln}\\left(\\text{cosh}x\\right)[\/latex]<\/li>\n<li>[latex]y=C{e}^{3x}-\\dfrac{2}{3}[\/latex]<\/li>\n<li>[latex]y=C{x}^{3}+6{x}^{2}[\/latex]<\/li>\n<li>[latex]y=C{e}^{\\dfrac{{x}^{2}}{2}}-3[\/latex]<\/li>\n<li>[latex]y=C\\tan\\left(\\dfrac{x}{2}\\right)-2x+4\\tan\\left(\\dfrac{x}{2}\\right)\\text{ln}\\left(\\sin\\left(\\dfrac{x}{2}\\right)\\right)[\/latex]<\/li>\n<li>[latex]y=C{x}^{3}-{x}^{2}[\/latex]<\/li>\n<li>[latex]y=C{\\left(x+2\\right)}^{2}+\\dfrac{1}{2}[\/latex]<\/li>\n<li>[latex]y=\\dfrac{C}{\\sqrt{x}}+2\\sin\\left(3t\\right)[\/latex]<\/li>\n<li>[latex]y=C{\\left(x+1\\right)}^{3}-{x}^{2}-2x - 1[\/latex]<\/li>\n<li>[latex]y=C{e}^{{\\text{sinh}}^{-1}x}-2[\/latex]<\/li>\n<li>[latex]y=x+4{e}^{x}-1[\/latex]<\/li>\n<li>[latex]y=-\\dfrac{3x}{2}\\left({x}^{2}-1\\right)[\/latex]<\/li>\n<li>[latex]y=1-{e}^{{\\tan}^{-1}x}[\/latex]<\/li>\n<li>[latex]y=\\left(x+2\\right)\\text{ln}\\left(\\dfrac{x+2}{2}\\right)[\/latex]<\/li>\n<li>[latex]y=2{e}^{2\\sqrt{x}}-2x - 2\\sqrt{x}-1[\/latex]<\/li>\n<li>[latex]v\\left(t\\right)=\\dfrac{gm}{k}\\left(1-{e}^{\\dfrac{\\text{-}kt}{m}}\\right)[\/latex]<\/li>\n<li>[latex]\\sqrt{\\dfrac{gm}{k}}[\/latex]<\/li>\n<li>[latex]40.451[\/latex] seconds<\/li>\n<li>[latex]y=C{e}^{x}-a\\left(x+1\\right)[\/latex]<\/li>\n<li>[latex]y=C{e}^{\\dfrac{{x}^{2}}{2}}-a[\/latex]<\/li>\n<li>[latex]P=0[\/latex] semi-stable<\/li>\n<li>[latex]P=\\dfrac{10{e}^{10x}}{{e}^{10x}+4}[\/latex]<\/li>\n<li>[latex]P\\left(t\\right)=\\dfrac{10000{e}^{0.02t}}{150+50{e}^{0.02t}}[\/latex]<\/li>\n<li>[latex]69[\/latex] hours [latex]5[\/latex] minutes<\/li>\n<li>[latex]8[\/latex] years [latex]11[\/latex] months<\/li>\n<li>[latex]y=\\dfrac{-20}{4\\times {10}^{-6}-0.002{e}^{0.01t}}[\/latex]<\/li>\n<li>[latex]P\\left(t\\right)=\\dfrac{850+500{e}^{0.009t}}{85+5{e}^{0.009t}}[\/latex]<\/li>\n<li>[latex]13[\/latex] years<\/li>\n<li>[latex]31.465[\/latex] days<\/li>\n<li>September [latex]2008[\/latex]<\/li>\n<li>[latex]\\dfrac{K+T}{2}[\/latex]<\/li>\n<li>[latex]r=0.0405[\/latex]<\/li>\n<li><\/li>\n<li>[latex]\\alpha =0.0081[\/latex]<\/li>\n<li>Logistic: [latex]361[\/latex], Threshold: [latex]436[\/latex], Gompertz: [latex]309[\/latex].<\/li>\n<\/ol>\n","protected":false},"author":15,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":109,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/181"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":1,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/181\/revisions"}],"predecessor-version":[{"id":193,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/181\/revisions\/193"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/109"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/181\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=181"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=181"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=181"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=181"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}