{"id":178,"date":"2026-01-12T16:00:34","date_gmt":"2026-01-12T16:00:34","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/?post_type=chapter&#038;p=178"},"modified":"2026-01-12T16:00:34","modified_gmt":"2026-01-12T16:00:34","slug":"integration-of-exponential-logarithmic-and-hyperbolic-functions-get-stronger-answer-key-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/integration-of-exponential-logarithmic-and-hyperbolic-functions-get-stronger-answer-key-2\/","title":{"raw":"Integration of Exponential, Logarithmic, and Hyperbolic Functions: Get Stronger Answer Key","rendered":"Integration of Exponential, Logarithmic, and Hyperbolic Functions: Get Stronger Answer Key"},"content":{"raw":"<h2>Integrals, Exponential Functions, and Logarithms<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]\\frac{1}{x}[\/latex]<\/li>\r\n \t<li>[latex]-\\frac{1}{x{(\\text{ln}x)}^{2}}[\/latex]<\/li>\r\n \t<li>[latex]\\text{ln}(x+1)+C[\/latex]<\/li>\r\n \t<li>[latex]\\text{ln}(x)+1[\/latex]<\/li>\r\n \t<li>[latex] \\cot (x)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{7}{x}[\/latex]<\/li>\r\n \t<li>[latex] \\csc (x) \\sec x[\/latex]<\/li>\r\n \t<li>[latex]-2 \\tan x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}\\text{ln}(\\frac{5}{3})[\/latex]<\/li>\r\n \t<li>[latex]2-\\frac{1}{2}\\text{ln}(5)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{\\text{ln}(2)}-1[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}\\text{ln}(2)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{3}{(\\text{ln}x)}^{3}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{2{x}^{3}}{\\sqrt{{x}^{2}+1}\\sqrt{{x}^{2}-1}}[\/latex]<\/li>\r\n \t<li>[latex]{x}^{-2-(1\\text{\/}x)}(\\text{ln}x-1)[\/latex]<\/li>\r\n \t<li>[latex]e{x}^{e-1}[\/latex]<\/li>\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li>[latex]-\\frac{1}{{x}^{2}}[\/latex]<\/li>\r\n \t<li>[latex]\\pi -\\text{ln}(2)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{x}[\/latex]<\/li>\r\n \t<li>[latex]{e}^{5}-6{\\text{units}}^{2}[\/latex]<\/li>\r\n \t<li>[latex]\\text{ln}(4)-1{\\text{units}}^{2}[\/latex]<\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n<\/ol>\r\n<h2>Exponential Growth and Decay<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>True<\/li>\r\n \t<li>False; [latex]k=\\frac{\\text{ln}(2)}{t}[\/latex]<\/li>\r\n \t<li>[latex]20[\/latex] hours<\/li>\r\n \t<li>No. The relic is approximately [latex]871[\/latex] years old.<\/li>\r\n \t<li>[latex]71.92[\/latex] years<\/li>\r\n \t<li>[latex]5[\/latex] days [latex]6[\/latex] hours [latex]27[\/latex] minutes<\/li>\r\n \t<li>[latex]12[\/latex]<\/li>\r\n \t<li>[latex]8.618\\%[\/latex]<\/li>\r\n \t<li>[latex]$6766.76[\/latex]<\/li>\r\n \t<li>[latex]9[\/latex] hours [latex]13[\/latex] minutes<\/li>\r\n \t<li>[latex]239,179[\/latex] years<\/li>\r\n \t<li><\/li>\r\n \t<li>[latex]P\\prime (t)=43{e}^{0.01604t}.[\/latex] The population is always increasing.<\/li>\r\n \t<li><\/li>\r\n \t<li>The population reaches [latex]10[\/latex] billion people in 2027.<\/li>\r\n \t<li><\/li>\r\n \t<li>[latex]P\\prime (t)=2.259{e}^{0.06407t}.[\/latex] The population is always increasing.<\/li>\r\n \t<li><\/li>\r\n<\/ol>\r\n<h2>Calculus of the Hyperbolic Functions<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]{e}^{x}\\text{ and }{e}^{\\text{\u2212}x}[\/latex]<\/li>\r\n \t<li>Answers may vary<\/li>\r\n \t<li>Answers may vary<\/li>\r\n \t<li>Answers may vary<\/li>\r\n \t<li>[latex]3\\text{sinh}(3x+1)[\/latex]<\/li>\r\n \t<li>[latex]\\text{\u2212}\\text{tanh}(x)\\text{sech}(x)[\/latex]<\/li>\r\n \t<li>[latex]4\\text{cosh}(x)\\text{sinh}(x)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{x{\\text{sech}}^{2}(\\sqrt{{x}^{2}+1})}{\\sqrt{{x}^{2}+1}}[\/latex]<\/li>\r\n \t<li>[latex]6{\\text{sinh}}^{5}(x)\\text{cosh}(x)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}\\text{sinh}(2x+1)+C[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}{\\text{sinh}}^{2}({x}^{2})+C[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{3}{\\text{cosh}}^{3}(x)+C[\/latex]<\/li>\r\n \t<li>[latex]\\text{ln}(1+\\text{cosh}(x))+C[\/latex]]<\/li>\r\n \t<li>[latex]\\text{cosh}(x)+\\text{sinh}(x)+C[\/latex]<\/li>\r\n \t<li>[latex]\\frac{4}{1-16{x}^{2}}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{\\text{sinh}(x)}{\\sqrt{{\\text{cosh}}^{2}(x)+1}}[\/latex]<\/li>\r\n \t<li>[latex]\\text{\u2212} \\csc (x)[\/latex]<\/li>\r\n \t<li>[latex]-\\frac{1}{({x}^{2}-1){\\text{tanh}}^{-1}(x)}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{a}{\\text{tanh}}^{-1}(\\frac{x}{a})+C[\/latex]<\/li>\r\n \t<li>[latex]\\sqrt{{x}^{2}+1}+C[\/latex]<\/li>\r\n \t<li>[latex]{\\text{cosh}}^{-1}({e}^{x})+C[\/latex]<\/li>\r\n \t<li>[latex]-0.521095[\/latex]<\/li>\r\n \t<li>[latex]10[\/latex]<\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n \t<li><\/li>\r\n<\/ol>","rendered":"<h2>Integrals, Exponential Functions, and Logarithms<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]\\frac{1}{x}[\/latex]<\/li>\n<li>[latex]-\\frac{1}{x{(\\text{ln}x)}^{2}}[\/latex]<\/li>\n<li>[latex]\\text{ln}(x+1)+C[\/latex]<\/li>\n<li>[latex]\\text{ln}(x)+1[\/latex]<\/li>\n<li>[latex]\\cot (x)[\/latex]<\/li>\n<li>[latex]\\frac{7}{x}[\/latex]<\/li>\n<li>[latex]\\csc (x) \\sec x[\/latex]<\/li>\n<li>[latex]-2 \\tan x[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}\\text{ln}(\\frac{5}{3})[\/latex]<\/li>\n<li>[latex]2-\\frac{1}{2}\\text{ln}(5)[\/latex]<\/li>\n<li>[latex]\\frac{1}{\\text{ln}(2)}-1[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}\\text{ln}(2)[\/latex]<\/li>\n<li>[latex]\\frac{1}{3}{(\\text{ln}x)}^{3}[\/latex]<\/li>\n<li>[latex]\\frac{2{x}^{3}}{\\sqrt{{x}^{2}+1}\\sqrt{{x}^{2}-1}}[\/latex]<\/li>\n<li>[latex]{x}^{-2-(1\\text{\/}x)}(\\text{ln}x-1)[\/latex]<\/li>\n<li>[latex]e{x}^{e-1}[\/latex]<\/li>\n<li>[latex]1[\/latex]<\/li>\n<li>[latex]-\\frac{1}{{x}^{2}}[\/latex]<\/li>\n<li>[latex]\\pi -\\text{ln}(2)[\/latex]<\/li>\n<li>[latex]\\frac{1}{x}[\/latex]<\/li>\n<li>[latex]{e}^{5}-6{\\text{units}}^{2}[\/latex]<\/li>\n<li>[latex]\\text{ln}(4)-1{\\text{units}}^{2}[\/latex]<\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<\/ol>\n<h2>Exponential Growth and Decay<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>True<\/li>\n<li>False; [latex]k=\\frac{\\text{ln}(2)}{t}[\/latex]<\/li>\n<li>[latex]20[\/latex] hours<\/li>\n<li>No. The relic is approximately [latex]871[\/latex] years old.<\/li>\n<li>[latex]71.92[\/latex] years<\/li>\n<li>[latex]5[\/latex] days [latex]6[\/latex] hours [latex]27[\/latex] minutes<\/li>\n<li>[latex]12[\/latex]<\/li>\n<li>[latex]8.618\\%[\/latex]<\/li>\n<li>[latex]$6766.76[\/latex]<\/li>\n<li>[latex]9[\/latex] hours [latex]13[\/latex] minutes<\/li>\n<li>[latex]239,179[\/latex] years<\/li>\n<li><\/li>\n<li>[latex]P\\prime (t)=43{e}^{0.01604t}.[\/latex] The population is always increasing.<\/li>\n<li><\/li>\n<li>The population reaches [latex]10[\/latex] billion people in 2027.<\/li>\n<li><\/li>\n<li>[latex]P\\prime (t)=2.259{e}^{0.06407t}.[\/latex] The population is always increasing.<\/li>\n<li><\/li>\n<\/ol>\n<h2>Calculus of the Hyperbolic Functions<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]{e}^{x}\\text{ and }{e}^{\\text{\u2212}x}[\/latex]<\/li>\n<li>Answers may vary<\/li>\n<li>Answers may vary<\/li>\n<li>Answers may vary<\/li>\n<li>[latex]3\\text{sinh}(3x+1)[\/latex]<\/li>\n<li>[latex]\\text{\u2212}\\text{tanh}(x)\\text{sech}(x)[\/latex]<\/li>\n<li>[latex]4\\text{cosh}(x)\\text{sinh}(x)[\/latex]<\/li>\n<li>[latex]\\frac{x{\\text{sech}}^{2}(\\sqrt{{x}^{2}+1})}{\\sqrt{{x}^{2}+1}}[\/latex]<\/li>\n<li>[latex]6{\\text{sinh}}^{5}(x)\\text{cosh}(x)[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}\\text{sinh}(2x+1)+C[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}{\\text{sinh}}^{2}({x}^{2})+C[\/latex]<\/li>\n<li>[latex]\\frac{1}{3}{\\text{cosh}}^{3}(x)+C[\/latex]<\/li>\n<li>[latex]\\text{ln}(1+\\text{cosh}(x))+C[\/latex]]<\/li>\n<li>[latex]\\text{cosh}(x)+\\text{sinh}(x)+C[\/latex]<\/li>\n<li>[latex]\\frac{4}{1-16{x}^{2}}[\/latex]<\/li>\n<li>[latex]\\frac{\\text{sinh}(x)}{\\sqrt{{\\text{cosh}}^{2}(x)+1}}[\/latex]<\/li>\n<li>[latex]\\text{\u2212} \\csc (x)[\/latex]<\/li>\n<li>[latex]-\\frac{1}{({x}^{2}-1){\\text{tanh}}^{-1}(x)}[\/latex]<\/li>\n<li>[latex]\\frac{1}{a}{\\text{tanh}}^{-1}(\\frac{x}{a})+C[\/latex]<\/li>\n<li>[latex]\\sqrt{{x}^{2}+1}+C[\/latex]<\/li>\n<li>[latex]{\\text{cosh}}^{-1}({e}^{x})+C[\/latex]<\/li>\n<li>[latex]-0.521095[\/latex]<\/li>\n<li>[latex]10[\/latex]<\/li>\n<li><\/li>\n<li><\/li>\n<li><\/li>\n<\/ol>\n","protected":false},"author":15,"menu_order":5,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":109,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/178"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":1,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/178\/revisions"}],"predecessor-version":[{"id":190,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/178\/revisions\/190"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/109"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/178\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=178"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=178"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=178"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=178"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}