{"id":153,"date":"2026-01-12T15:55:36","date_gmt":"2026-01-12T15:55:36","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/?post_type=chapter&#038;p=153"},"modified":"2026-01-12T15:55:36","modified_gmt":"2026-01-12T15:55:36","slug":"techniques-for-differentiation-get-stronger-answer-key","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/chapter\/techniques-for-differentiation-get-stronger-answer-key\/","title":{"raw":"Techniques for Differentiation: Get Stronger Answer Key","rendered":"Techniques for Differentiation: Get Stronger Answer Key"},"content":{"raw":"<h2>Derivatives of Trigonometric Functions<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]\\frac{dy}{dx}=2x- \\sec x \\tan x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=2x \\cot x-x^2 \\csc^2 x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\frac{x \\sec x \\tan x- \\sec x}{x^2}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=(1- \\sin x)(1- \\sin x)- \\cos x(x+ \\cos x)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\frac{2 \\csc^2 x}{(1+ \\cot x)^2}[\/latex]<\/li>\r\n \t<li>\r\n<p id=\"fs-id1169739266640\">[latex]y=\u2212x[\/latex]<\/p>\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205425\/CNX_Calc_Figure_03_05_201.jpg\" alt=\"The graph shows negative sin(x) and the straight line T(x) with slope \u22121 and y intercept 0.\" \/><\/li>\r\n \t<li>\r\n<p id=\"fs-id1169736655158\">[latex]y=x+\\frac{2-3\\pi}{2}[\/latex]<\/p>\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205428\/CNX_Calc_Figure_03_05_203.jpg\" alt=\"The graph shows the cosine function shifted up one and has the straight line T(x) with slope 1 and y intercept (2 \u2013 3\u03c0)\/2.\" \/><\/li>\r\n \t<li>[latex]y=\u2212x[\/latex]\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205430\/CNX_Calc_Figure_03_05_205.jpg\" alt=\"The graph shows the function as starting at (\u22121, 3), decreasing to the origin, continuing to slowly decrease to about (1, \u22120.5), at which point it decreases very quickly.\" \/><\/li>\r\n \t<li>[latex]\\frac{d^2 y}{dx^2} = 3 \\cos x-x \\sin x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{d^2 y}{dx^2} = \\frac{1}{2} \\sin x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{d^2 y}{dx^2} = 2\\csc x( \\csc^2 x + \\cot^2 x)[\/latex]<\/li>\r\n \t<li>[latex]x = \\frac{(2n+1)\\pi}{4}[\/latex], where [latex]n[\/latex] is an integer<\/li>\r\n \t<li>[latex](\\frac{\\pi}{4},1), \\, (\\frac{3\\pi}{4},-1)[\/latex]<\/li>\r\n \t<li>[latex]a=0, \\, b=3[\/latex]<\/li>\r\n \t<li>[latex]y^{\\prime}=5 \\cos (x)[\/latex], increasing on [latex](0,\\frac{\\pi}{2}), \\, (\\frac{3\\pi}{2},\\frac{5\\pi}{2})[\/latex], and [latex](\\frac{7\\pi}{2},12)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{d^3 y}{dx^3} = 3 \\sin x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{d^4 y}{dx^4} = 5 \\cos x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{d^3 y}{dx^3} = 720x^7-5 \\tan (x) \\sec^3 (x)- \\tan^3 (x) \\sec (x)[\/latex]<\/li>\r\n<\/ol>\r\n<h2>The Chain Rule<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]\\frac{dy}{dx} = 18u^2 \\cdot 7=18(7x-4)^2 \\cdot 7[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = \u2212\\sin u \\cdot \\frac{-1}{8}=\u2212\\sin (\\frac{\u2212x}{8}) \\cdot \\frac{-1}{8}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = \\frac{8x-24}{2\\sqrt{4u+3}}=\\frac{4x-12}{\\sqrt{4x^2-24x+3}}[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]f(u) = u^3, \\, u=3x^2+1[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = 18x(3x^2+1)^2[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]f(u)=u^7, \\, u=\\frac{x}{7}+\\frac{7}{x}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = 7(\\frac{x}{7}+\\frac{7}{x})^6 \\cdot (\\frac{1}{7}-\\frac{7}{x^2})[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]f(u)= \\csc u, \\, u=\\pi x+1[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = \u2212\\pi \\csc (\\pi x+1) \\cdot \\cot (\\pi x+1)[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]f(u)=-6u^{-3}, \\, u= \\sin x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = 18 \\sin^{-4} x \\cdot \\cos x[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = \\frac{4}{(5-2x)^3}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = 6(2x^3-x^2+6x+1)^2(3x^2-x+3)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = -3(\\tan x+ \\sin x)^{-4} \\cdot (\\sec^2 x+ \\cos x)[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = -7 \\cos (\\cos 7x) \\cdot \\sin 7x[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = -12 \\cot^2 (4x+1) \\cdot \\csc^2 (4x+1)[\/latex]<\/li>\r\n \t<li>[latex]10[\/latex]<\/li>\r\n \t<li>[latex]-\\frac{1}{8}[\/latex]<\/li>\r\n \t<li>-[latex]4[\/latex]<\/li>\r\n \t<li>-[latex]12[\/latex]<\/li>\r\n \t<li>[latex]10\\frac{3}{4}[\/latex]<\/li>\r\n \t<li>[latex]y=-\\frac{1}{2}x[\/latex]<\/li>\r\n \t<li>[latex]x= \\pm \\sqrt{6}[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]-\\frac{200}{343}[\/latex] m\/s<\/li>\r\n \t<li>[latex]\\frac{600}{2401} \\, \\text{m\/s}^2[\/latex]<\/li>\r\n \t<li>The train is slowing down since velocity and acceleration have opposite signs<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]C^{\\prime}(x)=0.0003x^2-0.04x+3[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dC}{dt}=100 \\cdot (0.0003x^2-0.04x+3)[\/latex]<\/li>\r\n \t<li>Approximately [latex]$90,300[\/latex] per week<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]\\frac{dS}{dt}=-\\frac{8\\pi r^2}{(t+1)^3}[\/latex]<\/li>\r\n \t<li>The volume is decreasing at a rate of [latex]-\\frac{\\pi}{36} \\, \\text{ft}^3\/\\text{min}[\/latex].<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex] \\approx 2.3[\/latex] ft\/hr<\/li>\r\n<\/ol>\r\n<h2>Derivatives of Inverse Functions<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205442\/CNX_Calc_Figure_03_07_204.jpg\" alt=\"A curved line starting at (\u22123, 0) and passing through (\u22122, 1) and (1, 2). There is another curved line that is symmetric with this about the line x = y. That is, it starts at (0, \u22123) and passes through (1, \u22122) and (2, 1).\" \/><\/li>\r\n \t<li>[latex](f^{-1})^{\\prime}(1) \\approx 2[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205448\/CNX_Calc_Figure_03_07_208.jpg\" alt=\"A quarter circle starting at (0, 4) and ending at (4, 0).\" \/><\/li>\r\n \t<li>[latex](f^{-1})^{\\prime}(1) \\approx -1\/\\sqrt{3}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]6[\/latex]<\/li>\r\n \t<li>[latex]x=f^{-1}(y)=(\\frac{y+3}{2})^{1\/3}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{6}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li>[latex]x=f^{-1}(y)= \\sin^{-1} y[\/latex]<\/li>\r\n \t<li>[latex]1[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]\\frac{1}{5}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{3}[\/latex]<\/li>\r\n \t<li>[latex]1[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]4[\/latex]<\/li>\r\n \t<li>[latex]y=4x[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]-\\frac{1}{13}[\/latex]<\/li>\r\n \t<li>[latex]y=-\\frac{1}{13}x+\\frac{18}{13}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]\\large \\frac{2x}{\\sqrt{1-x^4}}[\/latex]<\/li>\r\n \t<li>[latex]\\large \\frac{-1}{\\sqrt{1-x^2}}[\/latex]<\/li>\r\n \t<li>[latex]\\large \\frac{3(1 + \\tan^{-1} x)^2}{1+x^2}[\/latex]<\/li>\r\n \t<li>[latex]\\large \\frac{-1}{(1+x^2)(\\tan^{-1} x)^2}[\/latex]<\/li>\r\n \t<li>[latex]\\large \\frac{x}{(5-x^2)\\sqrt{4-x^2}}[\/latex]<\/li>\r\n \t<li>-[latex]1[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{10}[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]v(t)=\\frac{1}{1+t^2}[\/latex]<\/li>\r\n \t<li>[latex]a(t)=\\frac{-2t}{(1+t^2)^2}[\/latex]<\/li>\r\n \t<li>[latex]v(2)=0.2, \\, v(4)=0.06, \\, v(6)=0.03; \\, a(2)=-0.16, \\, a(4)=-0.028, \\, a(6)=-0.0088[\/latex]<\/li>\r\n \t<li>The hockey puck is decelerating\/slowing down at [latex]2[\/latex], [latex]4[\/latex], and [latex]6[\/latex] seconds.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>-[latex]0.0168[\/latex] radians per foot<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]\\frac{d\\theta}{dx}=\\frac{10}{100+x^2}-\\frac{40}{1600+x^2}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{18}{325}, \\, \\frac{9}{340}, \\, \\frac{42}{4745}, \\, 0[\/latex]<\/li>\r\n \t<li>As a person moves farther away from the screen, the viewing angle is increasing, which implies that as he or she moves farther away, his or her screen vision is widening.<\/li>\r\n \t<li>[latex]-\\frac{54}{12905}, \\, -\\frac{3}{500}, \\, -\\frac{198}{29945}, \\, -\\frac{9}{1360}[\/latex]<\/li>\r\n \t<li>As the person moves beyond [latex]20[\/latex] feet from the screen, the viewing angle is decreasing. The optimal distance the person should sit for maximizing the viewing angle is [latex]20[\/latex] feet<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<h2>Implicit Differentiation<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]\\frac{dy}{dx}=\\frac{-2x}{y}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\frac{x}{3y}-\\frac{y}{2x}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\large \\frac{y-\\frac{y}{2\\sqrt{x+4}}}{\\sqrt{x+4}-x}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\large \\frac{y^2 \\cos(xy)}{2y- \\sin(xy)-xy \\cos xy}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=\\large \\frac{-3x^2 y-y^3}{x^3+3xy^2}[\/latex]<\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205513\/CNX_Calc_Figure_03_08_202.jpg\" alt=\"The graph has a crescent in each of the four quadrants. There is a straight line marked T(x) with slope \u22121\/2 and y intercept 2.\" \/> [latex]y=-\\frac{1}{2}x+2[\/latex]<\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205517\/CNX_Calc_Figure_03_08_204.jpg\" alt=\"The graph has two curves, one in the first quadrant and one in the fourth quadrant. They are symmetric about the x axis. The curve in the first quadrant goes from (0.3, 5) to (1.5, 3.5) to (5, 4). There is a straight line marked T(x) with slope 1\/(\u03c0 + 12) and y intercept \u2212(3\u03c0 + 38)\/(\u03c0 + 12).\" \/> [latex]y=\\large \\frac{1}{\\pi +12}x-\\frac{3\\pi +38}{\\pi +12}[\/latex]<\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205521\/CNX_Calc_Figure_03_08_206.jpg\" alt=\"The graph starts in the third quadrant near (\u22125, 0), remains near 0 until x = \u22124, at which point it decreases until it reaches near (0, \u22125). There is an asymptote at x = 0. The graph begins again near (0, 5) decreases to (1, 0) and then increases a little bit before decreasing to be near (5, 0). There is a straight line marked T(x) that coincides with y = 0.\" \/> [latex]y=0[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]y=\u2212x+2[\/latex]<\/li>\r\n \t<li>[latex](3,-1)[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex](\\pm \\sqrt{7},0)[\/latex]<\/li>\r\n \t<li>Slope is [latex]-2[\/latex] at both intercepts<\/li>\r\n \t<li>They are parallel since the slope is the same at both intercepts.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]y=\u2212x+1[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>-[latex]0.5926[\/latex]<\/li>\r\n \t<li>When [latex]$81[\/latex] is spent on labor and [latex]$16[\/latex] is spent on capital, the amount spent on capital is decreasing by [latex]$0.5926[\/latex] per [latex]$1[\/latex] spent on labor.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=-8[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx}=-2.67[\/latex]<\/li>\r\n \t<li>[latex]y^{\\prime}=-\\frac{1}{\\sqrt{1-x^2}}[\/latex]<\/li>\r\n<\/ol>\r\n<h2>Derivatives of Exponential and Logarithmic Functions<\/h2>\r\n<ol style=\"list-style-type: decimal;\">\r\n \t<li>[latex]f^{\\prime}(x) = 2xe^x+x^2 e^x[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = e^{x^3 \\ln x}(3x^2 \\ln x+x^2)[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = \\dfrac{4}{(e^x+e^{\u2212x})^2}[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = 2^{4x+2} \\cdot \\ln 2+8x[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = \\pi x^{\\pi -1} \\cdot \\pi^x + x^{\\pi} \\cdot \\pi^x \\ln \\pi [\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = \\frac{5}{2(5x-7)}[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = \\frac{\\tan x}{\\ln 10}[\/latex]<\/li>\r\n \t<li>[latex]f^{\\prime}(x) = 2^x \\cdot \\ln 2 \\cdot \\log_3 7^{x^2-4} + 2^x \\cdot \\frac{2x \\ln 7}{\\ln 3}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = (\\sin 2x)^{4x} [4 \\cdot \\ln(\\sin 2x) + 8x \\cdot \\cot 2x][\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = x^{\\log_2 x} \\cdot \\frac{2 \\ln x}{x \\ln 2}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = x^{\\cot x} \\cdot [\u2212\\csc^2 x \\cdot \\ln x+\\frac{\\cot x}{x}][\/latex]<\/li>\r\n \t<li>[latex]\\frac{dy}{dx} = x^{-1\/2}(x^2+3)^{2\/3}(3x-4)^4 \\cdot [\\frac{-1}{2x}+\\frac{4x}{3(x^2+3)}+\\frac{12}{3x-4}][\/latex]<\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205540\/CNX_Calc_Figure_03_09_202.jpg\" alt=\"The function starts at (\u22123, 0), decreases slightly and then increases through the origin and increases to (1.25, 10). There is a straight line marked T(x) with slope \u22121\/(5 + 5 ln 5) and y intercept 5 + 1\/(5 + 5 ln 5).\" \/> [latex]y=\\frac{-1}{5+5 \\ln 5}x+(5+\\frac{1}{5+5 \\ln 5})[\/latex]<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]x=e \\approx 2.718[\/latex]<\/li>\r\n \t<li>[latex]y^{\\prime}&gt;0[\/latex] on [latex](e,\\infty)[\/latex], and [latex]y^{\\prime}&lt;0[\/latex] on [latex](0,e)[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>[latex]P=500,000(1.05)^t[\/latex] individuals<\/li>\r\n \t<li>[latex]P^{\\prime}(t)=24395 \\cdot (1.05)^t[\/latex] individuals per year<\/li>\r\n \t<li>[latex]39,737[\/latex] individuals per year<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>At the beginning of 1960 there were [latex]5.3[\/latex] thousand cases of the disease in New York City. At the beginning of 1963 there were approximately [latex]723[\/latex] cases of the disease in New York City.<\/li>\r\n \t<li>At the beginning of 1960 the number of cases of the disease was decreasing at rate of [latex]-4.611[\/latex] thousand per year; at the beginning of 1963, the number of cases of the disease was decreasing at a rate of [latex]-0.2808[\/latex] thousand per year.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>[latex]p=35741(1.045)^t[\/latex]<\/li>\r\n \t<li><\/li>\r\n \t<li>\r\n<table id=\"fs-id1169738071176\" class=\"unnumbered\" summary=\"This table has nine rows and two columns. The first row is a header row and it labels each column. The first column header is Years since 1790 and the second column is P\u2019\u2019. Under the first column are the values 0, 10, 20, 30, 40, 50, 60, and 70. Under the second column are the values 69.25, 107.5, 167.0, 259.4, 402.8, 625.5, 971.4, and 1508.5.\">\r\n<thead>\r\n<tr valign=\"top\">\r\n<th style=\"text-align: center;\">Years since 1790<\/th>\r\n<th style=\"text-align: center;\">[latex]P''[\/latex]<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]0[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]69.25[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]10[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]107.5[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]20[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]167.0[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]30[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]259.4[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]40[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]402.8[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]50[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]625.5[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]60[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]971.4[\/latex]<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td style=\"text-align: center;\">[latex]70[\/latex]<\/td>\r\n<td style=\"text-align: center;\">[latex]1508.5[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n \t<li><\/li>\r\n<\/ol>","rendered":"<h2>Derivatives of Trigonometric Functions<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]\\frac{dy}{dx}=2x- \\sec x \\tan x[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=2x \\cot x-x^2 \\csc^2 x[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\frac{x \\sec x \\tan x- \\sec x}{x^2}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=(1- \\sin x)(1- \\sin x)- \\cos x(x+ \\cos x)[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\frac{2 \\csc^2 x}{(1+ \\cot x)^2}[\/latex]<\/li>\n<li>\n<p id=\"fs-id1169739266640\">[latex]y=\u2212x[\/latex]<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205425\/CNX_Calc_Figure_03_05_201.jpg\" alt=\"The graph shows negative sin(x) and the straight line T(x) with slope \u22121 and y intercept 0.\" \/><\/li>\n<li>\n<p id=\"fs-id1169736655158\">[latex]y=x+\\frac{2-3\\pi}{2}[\/latex]<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205428\/CNX_Calc_Figure_03_05_203.jpg\" alt=\"The graph shows the cosine function shifted up one and has the straight line T(x) with slope 1 and y intercept (2 \u2013 3\u03c0)\/2.\" \/><\/li>\n<li>[latex]y=\u2212x[\/latex]\n<p><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205430\/CNX_Calc_Figure_03_05_205.jpg\" alt=\"The graph shows the function as starting at (\u22121, 3), decreasing to the origin, continuing to slowly decrease to about (1, \u22120.5), at which point it decreases very quickly.\" \/><\/li>\n<li>[latex]\\frac{d^2 y}{dx^2} = 3 \\cos x-x \\sin x[\/latex]<\/li>\n<li>[latex]\\frac{d^2 y}{dx^2} = \\frac{1}{2} \\sin x[\/latex]<\/li>\n<li>[latex]\\frac{d^2 y}{dx^2} = 2\\csc x( \\csc^2 x + \\cot^2 x)[\/latex]<\/li>\n<li>[latex]x = \\frac{(2n+1)\\pi}{4}[\/latex], where [latex]n[\/latex] is an integer<\/li>\n<li>[latex](\\frac{\\pi}{4},1), \\, (\\frac{3\\pi}{4},-1)[\/latex]<\/li>\n<li>[latex]a=0, \\, b=3[\/latex]<\/li>\n<li>[latex]y^{\\prime}=5 \\cos (x)[\/latex], increasing on [latex](0,\\frac{\\pi}{2}), \\, (\\frac{3\\pi}{2},\\frac{5\\pi}{2})[\/latex], and [latex](\\frac{7\\pi}{2},12)[\/latex]<\/li>\n<li>[latex]\\frac{d^3 y}{dx^3} = 3 \\sin x[\/latex]<\/li>\n<li>[latex]\\frac{d^4 y}{dx^4} = 5 \\cos x[\/latex]<\/li>\n<li>[latex]\\frac{d^3 y}{dx^3} = 720x^7-5 \\tan (x) \\sec^3 (x)- \\tan^3 (x) \\sec (x)[\/latex]<\/li>\n<\/ol>\n<h2>The Chain Rule<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]\\frac{dy}{dx} = 18u^2 \\cdot 7=18(7x-4)^2 \\cdot 7[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = \u2212\\sin u \\cdot \\frac{-1}{8}=\u2212\\sin (\\frac{\u2212x}{8}) \\cdot \\frac{-1}{8}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = \\frac{8x-24}{2\\sqrt{4u+3}}=\\frac{4x-12}{\\sqrt{4x^2-24x+3}}[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]f(u) = u^3, \\, u=3x^2+1[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = 18x(3x^2+1)^2[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]f(u)=u^7, \\, u=\\frac{x}{7}+\\frac{7}{x}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = 7(\\frac{x}{7}+\\frac{7}{x})^6 \\cdot (\\frac{1}{7}-\\frac{7}{x^2})[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]f(u)= \\csc u, \\, u=\\pi x+1[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = \u2212\\pi \\csc (\\pi x+1) \\cdot \\cot (\\pi x+1)[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]f(u)=-6u^{-3}, \\, u= \\sin x[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = 18 \\sin^{-4} x \\cdot \\cos x[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>[latex]\\frac{dy}{dx} = \\frac{4}{(5-2x)^3}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = 6(2x^3-x^2+6x+1)^2(3x^2-x+3)[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = -3(\\tan x+ \\sin x)^{-4} \\cdot (\\sec^2 x+ \\cos x)[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = -7 \\cos (\\cos 7x) \\cdot \\sin 7x[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = -12 \\cot^2 (4x+1) \\cdot \\csc^2 (4x+1)[\/latex]<\/li>\n<li>[latex]10[\/latex]<\/li>\n<li>[latex]-\\frac{1}{8}[\/latex]<\/li>\n<li>&#8211;[latex]4[\/latex]<\/li>\n<li>&#8211;[latex]12[\/latex]<\/li>\n<li>[latex]10\\frac{3}{4}[\/latex]<\/li>\n<li>[latex]y=-\\frac{1}{2}x[\/latex]<\/li>\n<li>[latex]x= \\pm \\sqrt{6}[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]-\\frac{200}{343}[\/latex] m\/s<\/li>\n<li>[latex]\\frac{600}{2401} \\, \\text{m\/s}^2[\/latex]<\/li>\n<li>The train is slowing down since velocity and acceleration have opposite signs<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]C^{\\prime}(x)=0.0003x^2-0.04x+3[\/latex]<\/li>\n<li>[latex]\\frac{dC}{dt}=100 \\cdot (0.0003x^2-0.04x+3)[\/latex]<\/li>\n<li>Approximately [latex]$90,300[\/latex] per week<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]\\frac{dS}{dt}=-\\frac{8\\pi r^2}{(t+1)^3}[\/latex]<\/li>\n<li>The volume is decreasing at a rate of [latex]-\\frac{\\pi}{36} \\, \\text{ft}^3\/\\text{min}[\/latex].<\/li>\n<\/ol>\n<\/li>\n<li>[latex]\\approx 2.3[\/latex] ft\/hr<\/li>\n<\/ol>\n<h2>Derivatives of Inverse Functions<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205442\/CNX_Calc_Figure_03_07_204.jpg\" alt=\"A curved line starting at (\u22123, 0) and passing through (\u22122, 1) and (1, 2). There is another curved line that is symmetric with this about the line x = y. That is, it starts at (0, \u22123) and passes through (1, \u22122) and (2, 1).\" \/><\/li>\n<li>[latex](f^{-1})^{\\prime}(1) \\approx 2[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205448\/CNX_Calc_Figure_03_07_208.jpg\" alt=\"A quarter circle starting at (0, 4) and ending at (4, 0).\" \/><\/li>\n<li>[latex](f^{-1})^{\\prime}(1) \\approx -1\/\\sqrt{3}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]6[\/latex]<\/li>\n<li>[latex]x=f^{-1}(y)=(\\frac{y+3}{2})^{1\/3}[\/latex]<\/li>\n<li>[latex]\\frac{1}{6}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]1[\/latex]<\/li>\n<li>[latex]x=f^{-1}(y)= \\sin^{-1} y[\/latex]<\/li>\n<li>[latex]1[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>[latex]\\frac{1}{5}[\/latex]<\/li>\n<li>[latex]\\frac{1}{3}[\/latex]<\/li>\n<li>[latex]1[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]4[\/latex]<\/li>\n<li>[latex]y=4x[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]-\\frac{1}{13}[\/latex]<\/li>\n<li>[latex]y=-\\frac{1}{13}x+\\frac{18}{13}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>[latex]\\large \\frac{2x}{\\sqrt{1-x^4}}[\/latex]<\/li>\n<li>[latex]\\large \\frac{-1}{\\sqrt{1-x^2}}[\/latex]<\/li>\n<li>[latex]\\large \\frac{3(1 + \\tan^{-1} x)^2}{1+x^2}[\/latex]<\/li>\n<li>[latex]\\large \\frac{-1}{(1+x^2)(\\tan^{-1} x)^2}[\/latex]<\/li>\n<li>[latex]\\large \\frac{x}{(5-x^2)\\sqrt{4-x^2}}[\/latex]<\/li>\n<li>&#8211;[latex]1[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}[\/latex]<\/li>\n<li>[latex]\\frac{1}{10}[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]v(t)=\\frac{1}{1+t^2}[\/latex]<\/li>\n<li>[latex]a(t)=\\frac{-2t}{(1+t^2)^2}[\/latex]<\/li>\n<li>[latex]v(2)=0.2, \\, v(4)=0.06, \\, v(6)=0.03; \\, a(2)=-0.16, \\, a(4)=-0.028, \\, a(6)=-0.0088[\/latex]<\/li>\n<li>The hockey puck is decelerating\/slowing down at [latex]2[\/latex], [latex]4[\/latex], and [latex]6[\/latex] seconds.<\/li>\n<\/ol>\n<\/li>\n<li>&#8211;[latex]0.0168[\/latex] radians per foot<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]\\frac{d\\theta}{dx}=\\frac{10}{100+x^2}-\\frac{40}{1600+x^2}[\/latex]<\/li>\n<li>[latex]\\frac{18}{325}, \\, \\frac{9}{340}, \\, \\frac{42}{4745}, \\, 0[\/latex]<\/li>\n<li>As a person moves farther away from the screen, the viewing angle is increasing, which implies that as he or she moves farther away, his or her screen vision is widening.<\/li>\n<li>[latex]-\\frac{54}{12905}, \\, -\\frac{3}{500}, \\, -\\frac{198}{29945}, \\, -\\frac{9}{1360}[\/latex]<\/li>\n<li>As the person moves beyond [latex]20[\/latex] feet from the screen, the viewing angle is decreasing. The optimal distance the person should sit for maximizing the viewing angle is [latex]20[\/latex] feet<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<h2>Implicit Differentiation<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]\\frac{dy}{dx}=\\frac{-2x}{y}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\frac{x}{3y}-\\frac{y}{2x}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\large \\frac{y-\\frac{y}{2\\sqrt{x+4}}}{\\sqrt{x+4}-x}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\large \\frac{y^2 \\cos(xy)}{2y- \\sin(xy)-xy \\cos xy}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=\\large \\frac{-3x^2 y-y^3}{x^3+3xy^2}[\/latex]<\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205513\/CNX_Calc_Figure_03_08_202.jpg\" alt=\"The graph has a crescent in each of the four quadrants. There is a straight line marked T(x) with slope \u22121\/2 and y intercept 2.\" \/> [latex]y=-\\frac{1}{2}x+2[\/latex]<\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205517\/CNX_Calc_Figure_03_08_204.jpg\" alt=\"The graph has two curves, one in the first quadrant and one in the fourth quadrant. They are symmetric about the x axis. The curve in the first quadrant goes from (0.3, 5) to (1.5, 3.5) to (5, 4). There is a straight line marked T(x) with slope 1\/(\u03c0 + 12) and y intercept \u2212(3\u03c0 + 38)\/(\u03c0 + 12).\" \/> [latex]y=\\large \\frac{1}{\\pi +12}x-\\frac{3\\pi +38}{\\pi +12}[\/latex]<\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205521\/CNX_Calc_Figure_03_08_206.jpg\" alt=\"The graph starts in the third quadrant near (\u22125, 0), remains near 0 until x = \u22124, at which point it decreases until it reaches near (0, \u22125). There is an asymptote at x = 0. The graph begins again near (0, 5) decreases to (1, 0) and then increases a little bit before decreasing to be near (5, 0). There is a straight line marked T(x) that coincides with y = 0.\" \/> [latex]y=0[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]y=\u2212x+2[\/latex]<\/li>\n<li>[latex](3,-1)[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex](\\pm \\sqrt{7},0)[\/latex]<\/li>\n<li>Slope is [latex]-2[\/latex] at both intercepts<\/li>\n<li>They are parallel since the slope is the same at both intercepts.<\/li>\n<\/ol>\n<\/li>\n<li>[latex]y=\u2212x+1[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>&#8211;[latex]0.5926[\/latex]<\/li>\n<li>When [latex]$81[\/latex] is spent on labor and [latex]$16[\/latex] is spent on capital, the amount spent on capital is decreasing by [latex]$0.5926[\/latex] per [latex]$1[\/latex] spent on labor.<\/li>\n<\/ol>\n<\/li>\n<li>[latex]\\frac{dy}{dx}=-8[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx}=-2.67[\/latex]<\/li>\n<li>[latex]y^{\\prime}=-\\frac{1}{\\sqrt{1-x^2}}[\/latex]<\/li>\n<\/ol>\n<h2>Derivatives of Exponential and Logarithmic Functions<\/h2>\n<ol style=\"list-style-type: decimal;\">\n<li>[latex]f^{\\prime}(x) = 2xe^x+x^2 e^x[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = e^{x^3 \\ln x}(3x^2 \\ln x+x^2)[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = \\dfrac{4}{(e^x+e^{\u2212x})^2}[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = 2^{4x+2} \\cdot \\ln 2+8x[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = \\pi x^{\\pi -1} \\cdot \\pi^x + x^{\\pi} \\cdot \\pi^x \\ln \\pi[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = \\frac{5}{2(5x-7)}[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = \\frac{\\tan x}{\\ln 10}[\/latex]<\/li>\n<li>[latex]f^{\\prime}(x) = 2^x \\cdot \\ln 2 \\cdot \\log_3 7^{x^2-4} + 2^x \\cdot \\frac{2x \\ln 7}{\\ln 3}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = (\\sin 2x)^{4x} [4 \\cdot \\ln(\\sin 2x) + 8x \\cdot \\cot 2x][\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = x^{\\log_2 x} \\cdot \\frac{2 \\ln x}{x \\ln 2}[\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = x^{\\cot x} \\cdot [\u2212\\csc^2 x \\cdot \\ln x+\\frac{\\cot x}{x}][\/latex]<\/li>\n<li>[latex]\\frac{dy}{dx} = x^{-1\/2}(x^2+3)^{2\/3}(3x-4)^4 \\cdot [\\frac{-1}{2x}+\\frac{4x}{3(x^2+3)}+\\frac{12}{3x-4}][\/latex]<\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2332\/2018\/01\/11205540\/CNX_Calc_Figure_03_09_202.jpg\" alt=\"The function starts at (\u22123, 0), decreases slightly and then increases through the origin and increases to (1.25, 10). There is a straight line marked T(x) with slope \u22121\/(5 + 5 ln 5) and y intercept 5 + 1\/(5 + 5 ln 5).\" \/> [latex]y=\\frac{-1}{5+5 \\ln 5}x+(5+\\frac{1}{5+5 \\ln 5})[\/latex]<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]x=e \\approx 2.718[\/latex]<\/li>\n<li>[latex]y^{\\prime}>0[\/latex] on [latex](e,\\infty)[\/latex], and [latex]y^{\\prime}<0[\/latex] on [latex](0,e)[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>[latex]P=500,000(1.05)^t[\/latex] individuals<\/li>\n<li>[latex]P^{\\prime}(t)=24395 \\cdot (1.05)^t[\/latex] individuals per year<\/li>\n<li>[latex]39,737[\/latex] individuals per year<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>At the beginning of 1960 there were [latex]5.3[\/latex] thousand cases of the disease in New York City. At the beginning of 1963 there were approximately [latex]723[\/latex] cases of the disease in New York City.<\/li>\n<li>At the beginning of 1960 the number of cases of the disease was decreasing at rate of [latex]-4.611[\/latex] thousand per year; at the beginning of 1963, the number of cases of the disease was decreasing at a rate of [latex]-0.2808[\/latex] thousand per year.<\/li>\n<\/ol>\n<\/li>\n<li>[latex]p=35741(1.045)^t[\/latex]<\/li>\n<li><\/li>\n<li>\n<table id=\"fs-id1169738071176\" class=\"unnumbered\" summary=\"This table has nine rows and two columns. The first row is a header row and it labels each column. The first column header is Years since 1790 and the second column is P\u2019\u2019. Under the first column are the values 0, 10, 20, 30, 40, 50, 60, and 70. Under the second column are the values 69.25, 107.5, 167.0, 259.4, 402.8, 625.5, 971.4, and 1508.5.\">\n<thead>\n<tr valign=\"top\">\n<th style=\"text-align: center;\">Years since 1790<\/th>\n<th style=\"text-align: center;\">[latex]P''[\/latex]<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]0[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]69.25[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]10[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]107.5[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]20[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]167.0[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]30[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]259.4[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]40[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]402.8[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]50[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]625.5[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]60[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]971.4[\/latex]<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td style=\"text-align: center;\">[latex]70[\/latex]<\/td>\n<td style=\"text-align: center;\">[latex]1508.5[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li><\/li>\n<\/ol>\n","protected":false},"author":15,"menu_order":6,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":108,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/153"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":1,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/153\/revisions"}],"predecessor-version":[{"id":166,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/153\/revisions\/166"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/parts\/108"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapters\/153\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/media?parent=153"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/pressbooks\/v2\/chapter-type?post=153"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/contributor?post=153"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/qrpracticepages\/wp-json\/wp\/v2\/license?post=153"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}