{"id":825,"date":"2025-07-15T20:08:57","date_gmt":"2025-07-15T20:08:57","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=825"},"modified":"2025-12-30T19:23:59","modified_gmt":"2025-12-30T19:23:59","slug":"absolute-value-functions-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/absolute-value-functions-learn-it-2\/","title":{"raw":"Absolute Value Functions: Learn It 2","rendered":"Absolute Value Functions: Learn It 2"},"content":{"raw":"<h2>Graphing an Absolute Value Function<\/h2>\r\n<p id=\"fs-id1165135570012\">The most significant feature of the absolute value graph is the corner point at which the graph changes direction. This point is shown at the <strong>origin<\/strong>.<span id=\"fs-id1165137530693\">\r\n<\/span><\/p>\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0032.jpg\" alt=\"Graph of an absolute function\" width=\"487\" height=\"251\" \/>\r\n\r\nThe graph of [latex]y=2\\left|x - 3\\right|+4[\/latex] is an absolute value functions after three transformations. The graph of [latex]y=|x|[\/latex] has been shifted right 3 units resulting in [latex]f(x)=\\left|x-3\\right|[\/latex], then vertically stretched by a factor of 2 ([latex]2\\left|x-3\\right|[\/latex]), and shifted up 4 units. This means that the corner point is located at [latex]\\left(3,4\\right)[\/latex] for this transformed function.\r\n\r\n<img class=\"alignnone wp-image-4951\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-298x300.png\" alt=\"Graph of the different types of transformations for an absolute function.\" width=\"503\" height=\"507\" \/>\r\n<div id=\"Example_01_06_03\" class=\"example\">\r\n<div id=\"fs-id1165135187768\" class=\"exercise\"><section class=\"textbox example\" aria-label=\"Example\">Write an equation for the function graphed.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0052.jpg\" alt=\"Graph of an absolute function. Two rays stem from the point 3, negative 2. One ray crosses the point 0, 4. The other ray crosses the point 5, 2.\" width=\"487\" height=\"363\" \/>[reveal-answer q=\"729255\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"729255\"]\r\n\r\nThe basic absolute value function changes direction at the origin, so this graph has been shifted to the right 3 units and down 2 units from the basic toolkit function.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0062.jpg\" alt=\"Graph of two transformations for an absolute function at (3, -2).\" width=\"487\" height=\"363\" \/>\r\n<p id=\"fs-id1165137680556\"><span id=\"fs-id1165137901124\">We also notice that the graph appears vertically stretched, because the width of the final graph on a horizontal line is not equal to 2 times the vertical distance from the corner to this line, as it would be for an unstretched absolute value function. Instead, the width is equal to 1 times the vertical distance.\r\n<\/span><\/p>\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0072.jpg\" alt=\"Graph of two transformations for an absolute function at (3, -2) and describes the ratios between the two different transformations.\" width=\"487\" height=\"363\" \/>\r\n<p id=\"fs-id1165137732766\">From this information we can write the equation<\/p>\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;f\\left(x\\right)=2\\left|x - 3\\right|-2, &amp;&amp; \\text{treating the stretch as a vertical stretch,} \\\\[2mm] \\text{or } &amp;f\\left(x\\right)=\\left|2\\left(x - 3\\right)\\right|-2, &amp;&amp; \\text{treating the stretch as a horizontal compression}. \\end{align}[\/latex]<\/p>\r\n\r\n<h4>Analysis of the Solution<\/h4>\r\n<p id=\"fs-id1165137591631\">Note that these equations are algebraically equivalent\u2014the stretch for an absolute value function can be written interchangeably as a vertical or horizontal stretch or compression.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">If we are unable to determine the stretch based on the width of the graph, we can solve for the stretch factor by putting in a known pair of values for [latex]x[\/latex] and [latex]f\\left(x\\right)[\/latex].[latex]f\\left(x\\right)=a|x - 3|-2[\/latex]Now substituting in the point (1, 2)\r\n\r\n[latex]\\begin{align}&amp;2=a|1 - 3|-2 \\\\ &amp;4=2a \\\\ &amp;a=2 \\end{align}[\/latex]\r\n\r\n<\/section><\/div>\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\"><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]317635[\/ohm_question]\r\n\r\n<\/section><\/div>","rendered":"<h2>Graphing an Absolute Value Function<\/h2>\n<p id=\"fs-id1165135570012\">The most significant feature of the absolute value graph is the corner point at which the graph changes direction. This point is shown at the <strong>origin<\/strong>.<span id=\"fs-id1165137530693\"><br \/>\n<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0032.jpg\" alt=\"Graph of an absolute function\" width=\"487\" height=\"251\" \/><\/p>\n<p>The graph of [latex]y=2\\left|x - 3\\right|+4[\/latex] is an absolute value functions after three transformations. The graph of [latex]y=|x|[\/latex] has been shifted right 3 units resulting in [latex]f(x)=\\left|x-3\\right|[\/latex], then vertically stretched by a factor of 2 ([latex]2\\left|x-3\\right|[\/latex]), and shifted up 4 units. This means that the corner point is located at [latex]\\left(3,4\\right)[\/latex] for this transformed function.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4951\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-298x300.png\" alt=\"Graph of the different types of transformations for an absolute function.\" width=\"503\" height=\"507\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-298x300.png 298w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-150x150.png 150w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-65x65.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-225x227.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_-350x352.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02221854\/3.4.L2.Graph_.png 749w\" sizes=\"(max-width: 503px) 100vw, 503px\" \/><\/p>\n<div id=\"Example_01_06_03\" class=\"example\">\n<div id=\"fs-id1165135187768\" class=\"exercise\">\n<section class=\"textbox example\" aria-label=\"Example\">Write an equation for the function graphed.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0052.jpg\" alt=\"Graph of an absolute function. Two rays stem from the point 3, negative 2. One ray crosses the point 0, 4. The other ray crosses the point 5, 2.\" width=\"487\" height=\"363\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q729255\">Show Solution<\/button><\/p>\n<div id=\"q729255\" class=\"hidden-answer\" style=\"display: none\">\n<p>The basic absolute value function changes direction at the origin, so this graph has been shifted to the right 3 units and down 2 units from the basic toolkit function.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0062.jpg\" alt=\"Graph of two transformations for an absolute function at (3, -2).\" width=\"487\" height=\"363\" \/><\/p>\n<p id=\"fs-id1165137680556\"><span id=\"fs-id1165137901124\">We also notice that the graph appears vertically stretched, because the width of the final graph on a horizontal line is not equal to 2 times the vertical distance from the corner to this line, as it would be for an unstretched absolute value function. Instead, the width is equal to 1 times the vertical distance.<br \/>\n<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010618\/CNX_Precalc_Figure_01_06_0072.jpg\" alt=\"Graph of two transformations for an absolute function at (3, -2) and describes the ratios between the two different transformations.\" width=\"487\" height=\"363\" \/><\/p>\n<p id=\"fs-id1165137732766\">From this information we can write the equation<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&f\\left(x\\right)=2\\left|x - 3\\right|-2, && \\text{treating the stretch as a vertical stretch,} \\\\[2mm] \\text{or } &f\\left(x\\right)=\\left|2\\left(x - 3\\right)\\right|-2, && \\text{treating the stretch as a horizontal compression}. \\end{align}[\/latex]<\/p>\n<h4>Analysis of the Solution<\/h4>\n<p id=\"fs-id1165137591631\">Note that these equations are algebraically equivalent\u2014the stretch for an absolute value function can be written interchangeably as a vertical or horizontal stretch or compression.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">If we are unable to determine the stretch based on the width of the graph, we can solve for the stretch factor by putting in a known pair of values for [latex]x[\/latex] and [latex]f\\left(x\\right)[\/latex].[latex]f\\left(x\\right)=a|x - 3|-2[\/latex]Now substituting in the point (1, 2)<\/p>\n<p>[latex]\\begin{align}&2=a|1 - 3|-2 \\\\ &4=2a \\\\ &a=2 \\end{align}[\/latex]<\/p>\n<\/section>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm317635\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=317635&theme=lumen&iframe_resize_id=ohm317635&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<\/section>\n<\/div>\n","protected":false},"author":13,"menu_order":31,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":61,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/825"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":6,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/825\/revisions"}],"predecessor-version":[{"id":5158,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/825\/revisions\/5158"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/61"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/825\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=825"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=825"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=825"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=825"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}