{"id":774,"date":"2025-07-15T16:08:33","date_gmt":"2025-07-15T16:08:33","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=774"},"modified":"2026-03-05T16:23:43","modified_gmt":"2026-03-05T16:23:43","slug":"linear-functions-learn-it-5","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/linear-functions-learn-it-5\/","title":{"raw":"Linear Functions: Learn It 5","rendered":"Linear Functions: Learn It 5"},"content":{"raw":"<h2>Vertical and Horizontal Lines<\/h2>\r\nMost of the lines we have worked with so far have been slanted, or oblique. In other words, they were neither horizontal nor vertical lines. The equations of vertical and horizontal lines do not require any of the preceding formulas, although we can use the formulas to prove that the equations are correct. The equation of a <strong>vertical line<\/strong> is given as\r\n<div style=\"text-align: center;\">[latex]x=c[\/latex]<\/div>\r\nwhere [latex]c[\/latex] is a constant. The slope of a vertical line is undefined, and regardless of the [latex]y[\/latex]<em>-<\/em>value of any point on the line, the [latex]x[\/latex]<em>-<\/em>coordinate of the point will be [latex]c[\/latex].\r\n\r\n<section class=\"textbox keyTakeaway\">\r\n<h3>vertical line<\/h3>\r\nThe equation of a <strong>vertical line<\/strong> is given as\r\n<div style=\"text-align: center;\">[latex]x=c[\/latex]<\/div>\r\nwhere [latex]c[\/latex] is a constant. The slope of a vertical line is undefined, and regardless of the <em>y-<\/em>value of any point on the line, the <em>x-<\/em>coordinate of the point will be [latex]c[\/latex].\r\n\r\n<\/section>The equation of a <strong>horizontal line<\/strong> is given as\r\n<div style=\"text-align: center;\">[latex]y=c[\/latex]<\/div>\r\nwhere [latex]c[\/latex]<em>\u00a0<\/em>is a constant. The slope of a horizontal line is zero, and for any [latex]x[\/latex]<em>-<\/em>value of a point on the line, the [latex]y[\/latex]<em>-<\/em>coordinate will be [latex]c[\/latex].\r\n\r\n<section class=\"textbox keyTakeaway\">\r\n<h3>horizontal line<\/h3>\r\nThe equation of a <strong>horizontal line<\/strong> is given as\r\n<div style=\"text-align: center;\">[latex]y=c[\/latex]<\/div>\r\nwhere [latex]c[\/latex] is a constant. The slope of a horizontal line is zero, and for any <em>x-<\/em>value of a point on the line, the <em>y-<\/em>coordinate will be [latex]c[\/latex].\r\n\r\n<\/section><section class=\"textbox example\">Find the equation of a line containing the following points:\r\n<ol>\r\n \t<li>[latex]\\left(-3,-5\\right),\\left(-3,1\\right),\\left(-3,3\\right)[\/latex], and [latex]\\left(-3,5\\right)[\/latex].<\/li>\r\n \t<li>[latex]\\left(-2,-2\\right),\\left(0,-2\\right),\\left(3,-2\\right)[\/latex], and [latex]\\left(5,-2\\right)[\/latex].<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"846624\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"846624\"]\r\n<ol>\r\n \t<li>Let's use the point-slope form: [latex]y-y_1 = m(x-x_1)[\/latex].\r\nFirst, we need to find the slope:\r\n[latex]m=\\frac{5 - 3}{-3-\\left(-3\\right)}=\\frac{2}{0}[\/latex]Zero in the denominator means that the slope is undefined and, therefore, we cannot use point-slope form. However, we can plot the points. Notice that all of the <em>x-<\/em>coordinates are the same and we find a vertical line through [latex]x=-3[\/latex].<\/li>\r\n \t<li>Let's use the point-slope form again: [latex]y-y_1 = m(x-x_1)[\/latex].\r\nFirst, we need to find the slope:\r\n[latex]\\begin{array}{l}m=\\frac{-2-\\left(-2\\right)}{0-\\left(-2\\right)}\\hfill \\\\ =\\frac{0}{2}\\hfill \\\\ =0\\hfill \\end{array}[\/latex]Use any point for [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] in the formula, or use the <em>y<\/em>-intercept.\r\n[latex]\\begin{array}{l}y-\\left(-2\\right)=0\\left(x - 3\\right)\\hfill \\\\ y+2=0\\hfill \\\\ y=-2\\hfill \\end{array}[\/latex]The graph is a horizontal line through [latex]y=-2[\/latex]. Notice that all of the <em>y-<\/em>coordinates are the same.<\/li>\r\n<\/ol>\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/11185925\/CNX_CAT_Figure_02_02_003.jpg\" alt=\"Coordinate plane with the x-axis ranging from negative 7 to 4 and the y-axis ranging from negative 4 to 4. The function y = negative 2 and the line x = negative 3 are plotted.\" width=\"487\" height=\"367\" \/> The line <i>x<\/i> = \u22123 is a vertical line. The line <i>y<\/i> = \u22122 is a horizontal line.[\/caption]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\">[ohm_question hide_question_numbers=1]318747[\/ohm_question]<\/section><section class=\"textbox tryIt\">[ohm_question hide_question_numbers=1]318748[\/ohm_question]<\/section>","rendered":"<h2>Vertical and Horizontal Lines<\/h2>\n<p>Most of the lines we have worked with so far have been slanted, or oblique. In other words, they were neither horizontal nor vertical lines. The equations of vertical and horizontal lines do not require any of the preceding formulas, although we can use the formulas to prove that the equations are correct. The equation of a <strong>vertical line<\/strong> is given as<\/p>\n<div style=\"text-align: center;\">[latex]x=c[\/latex]<\/div>\n<p>where [latex]c[\/latex] is a constant. The slope of a vertical line is undefined, and regardless of the [latex]y[\/latex]<em>&#8211;<\/em>value of any point on the line, the [latex]x[\/latex]<em>&#8211;<\/em>coordinate of the point will be [latex]c[\/latex].<\/p>\n<section class=\"textbox keyTakeaway\">\n<h3>vertical line<\/h3>\n<p>The equation of a <strong>vertical line<\/strong> is given as<\/p>\n<div style=\"text-align: center;\">[latex]x=c[\/latex]<\/div>\n<p>where [latex]c[\/latex] is a constant. The slope of a vertical line is undefined, and regardless of the <em>y-<\/em>value of any point on the line, the <em>x-<\/em>coordinate of the point will be [latex]c[\/latex].<\/p>\n<\/section>\n<p>The equation of a <strong>horizontal line<\/strong> is given as<\/p>\n<div style=\"text-align: center;\">[latex]y=c[\/latex]<\/div>\n<p>where [latex]c[\/latex]<em>\u00a0<\/em>is a constant. The slope of a horizontal line is zero, and for any [latex]x[\/latex]<em>&#8211;<\/em>value of a point on the line, the [latex]y[\/latex]<em>&#8211;<\/em>coordinate will be [latex]c[\/latex].<\/p>\n<section class=\"textbox keyTakeaway\">\n<h3>horizontal line<\/h3>\n<p>The equation of a <strong>horizontal line<\/strong> is given as<\/p>\n<div style=\"text-align: center;\">[latex]y=c[\/latex]<\/div>\n<p>where [latex]c[\/latex] is a constant. The slope of a horizontal line is zero, and for any <em>x-<\/em>value of a point on the line, the <em>y-<\/em>coordinate will be [latex]c[\/latex].<\/p>\n<\/section>\n<section class=\"textbox example\">Find the equation of a line containing the following points:<\/p>\n<ol>\n<li>[latex]\\left(-3,-5\\right),\\left(-3,1\\right),\\left(-3,3\\right)[\/latex], and [latex]\\left(-3,5\\right)[\/latex].<\/li>\n<li>[latex]\\left(-2,-2\\right),\\left(0,-2\\right),\\left(3,-2\\right)[\/latex], and [latex]\\left(5,-2\\right)[\/latex].<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q846624\">Show Answer<\/button><\/p>\n<div id=\"q846624\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Let&#8217;s use the point-slope form: [latex]y-y_1 = m(x-x_1)[\/latex].<br \/>\nFirst, we need to find the slope:<br \/>\n[latex]m=\\frac{5 - 3}{-3-\\left(-3\\right)}=\\frac{2}{0}[\/latex]Zero in the denominator means that the slope is undefined and, therefore, we cannot use point-slope form. However, we can plot the points. Notice that all of the <em>x-<\/em>coordinates are the same and we find a vertical line through [latex]x=-3[\/latex].<\/li>\n<li>Let&#8217;s use the point-slope form again: [latex]y-y_1 = m(x-x_1)[\/latex].<br \/>\nFirst, we need to find the slope:<br \/>\n[latex]\\begin{array}{l}m=\\frac{-2-\\left(-2\\right)}{0-\\left(-2\\right)}\\hfill \\\\ =\\frac{0}{2}\\hfill \\\\ =0\\hfill \\end{array}[\/latex]Use any point for [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] in the formula, or use the <em>y<\/em>-intercept.<br \/>\n[latex]\\begin{array}{l}y-\\left(-2\\right)=0\\left(x - 3\\right)\\hfill \\\\ y+2=0\\hfill \\\\ y=-2\\hfill \\end{array}[\/latex]The graph is a horizontal line through [latex]y=-2[\/latex]. Notice that all of the <em>y-<\/em>coordinates are the same.<\/li>\n<\/ol>\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/11185925\/CNX_CAT_Figure_02_02_003.jpg\" alt=\"Coordinate plane with the x-axis ranging from negative 7 to 4 and the y-axis ranging from negative 4 to 4. The function y = negative 2 and the line x = negative 3 are plotted.\" width=\"487\" height=\"367\" \/><figcaption class=\"wp-caption-text\">The line <i>x<\/i> = \u22123 is a vertical line. The line <i>y<\/i> = \u22122 is a horizontal line.<\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm318747\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318747&theme=lumen&iframe_resize_id=ohm318747&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm318748\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318748&theme=lumen&iframe_resize_id=ohm318748&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":18,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":61,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/774"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":7,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/774\/revisions"}],"predecessor-version":[{"id":5782,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/774\/revisions\/5782"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/61"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/774\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=774"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=774"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=774"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=774"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}