{"id":731,"date":"2025-07-15T14:54:51","date_gmt":"2025-07-15T14:54:51","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=731"},"modified":"2026-01-09T20:50:23","modified_gmt":"2026-01-09T20:50:23","slug":"graphs-of-linear-functions-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/graphs-of-linear-functions-learn-it-2\/","title":{"raw":"Graphs of Linear Functions: Learn It 2","rendered":"Graphs of Linear Functions: Learn It 2"},"content":{"raw":"<h3>Graphing a Function by Plotting Points<\/h3>\r\nTo find points on a function's graph, select input values, evaluate the function at these inputs, and calculate the corresponding outputs. These input-output pairs form coordinates, which you can plot on a grid. To graph a linear function, you should evaluate it at least two input values to identify at least two points.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">Given the function [latex]f\\left(x\\right)=2x[\/latex], we might use the input values [latex]1[\/latex] and [latex]2[\/latex].[latex]\\\\[\/latex] Evaluating the function for an input value of [latex]1[\/latex] yields an output value of [latex]2[\/latex] which is represented by the point [latex](1, 2)[\/latex]. [latex]\\\\[\/latex]Evaluating the function for an input value of [latex]2[\/latex] yields an output value of [latex]4[\/latex] which is represented by the point [latex](2, 4)[\/latex].Plot each point on the coordinate plane:\r\n<img class=\"alignnone size-full wp-image-3495\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM.png\" alt=\"\" width=\"417\" height=\"413\" \/>\r\nThen connect the points with a straight line:\r\n<img class=\"alignnone size-full wp-image-3496\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM.png\" alt=\"\" width=\"413\" height=\"413\" \/>\r\n\r\n<\/section><section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a linear function, graph by plotting points.<\/strong>\r\n<ol>\r\n \t<li>Choose a minimum of two input values.<\/li>\r\n \t<li>Evaluate the function at each input value.<\/li>\r\n \t<li>Use the resulting output values to identify coordinate pairs.<\/li>\r\n \t<li>Plot the coordinate pairs on a grid.<\/li>\r\n \t<li>Draw a line through the points.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Graph the following by plotting points.\r\n<center>[latex]f\\left(x\\right)=-\\frac{2}{3}x+5[\/latex]<\/center>\r\n[reveal-answer q=\"589508\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"589508\"]Begin by choosing input values. This function includes a fraction with a denominator of [latex]3[\/latex] so let\u2019s choose multiples of [latex]3[\/latex] as input values. We will choose [latex]0[\/latex], [latex]3[\/latex], and [latex]6[\/latex].\r\n[latex]\\\\[\/latex]\r\nEvaluate the function at each input value and use the output value to identify coordinate pairs.\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{llllll}x=0&amp; &amp; f\\left(0\\right)=-\\frac{2}{3}\\left(0\\right)+5=5\\Rightarrow \\left(0,5\\right)\\\\ x=3&amp; &amp; f\\left(3\\right)=-\\frac{2}{3}\\left(3\\right)+5=3\\Rightarrow \\left(3,3\\right)\\\\ x=6&amp; &amp; f\\left(6\\right)=-\\frac{2}{3}\\left(6\\right)+5=1\\Rightarrow \\left(6,1\\right)\\end{array}[\/latex]<\/p>\r\nPlot the coordinate pairs and draw a line through the points. The graph below is of\u00a0the function [latex]f\\left(x\\right)=-\\frac{2}{3}x+5[\/latex].\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184320\/CNX_Precalc_Figure_02_02_0012.jpg\" alt=\"The graph of the linear function [latex]f\\left(x\\right)=-\\frac{2}{3}x+5[\/latex].\" width=\"400\" height=\"347\" \/>\r\n\r\n<strong>Analysis of the Solution<\/strong>\r\n\r\nThe graph of the function is a line as expected for a linear function. In addition, the graph has a downward slant which indicates a negative slope. This is also expected from the negative constant rate of change in the equation for the function.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">If your equation has a fraction, you'll have to divide the number plugged in by whatever is in the denominator. In the previous example, choosing multiples of [latex]3[\/latex] will have the easiest calculation due to the [latex]\\frac{2}{3}[\/latex] in the equation.<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]318705[\/ohm_question]<\/section>","rendered":"<h3>Graphing a Function by Plotting Points<\/h3>\n<p>To find points on a function&#8217;s graph, select input values, evaluate the function at these inputs, and calculate the corresponding outputs. These input-output pairs form coordinates, which you can plot on a grid. To graph a linear function, you should evaluate it at least two input values to identify at least two points.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">Given the function [latex]f\\left(x\\right)=2x[\/latex], we might use the input values [latex]1[\/latex] and [latex]2[\/latex].[latex]\\\\[\/latex] Evaluating the function for an input value of [latex]1[\/latex] yields an output value of [latex]2[\/latex] which is represented by the point [latex](1, 2)[\/latex]. [latex]\\\\[\/latex]Evaluating the function for an input value of [latex]2[\/latex] yields an output value of [latex]4[\/latex] which is represented by the point [latex](2, 4)[\/latex].Plot each point on the coordinate plane:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3495\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM.png\" alt=\"\" width=\"417\" height=\"413\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM.png 417w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM-300x297.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM-150x150.png 150w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM-65x64.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM-225x223.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26161952\/Screenshot-2025-08-26-at-9.19.14%E2%80%AFAM-350x347.png 350w\" sizes=\"(max-width: 417px) 100vw, 417px\" \/><br \/>\nThen connect the points with a straight line:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-3496\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM.png\" alt=\"\" width=\"413\" height=\"413\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM.png 413w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM-300x300.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM-150x150.png 150w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM-65x65.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM-225x225.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/26162047\/Screenshot-2025-08-26-at-9.20.38%E2%80%AFAM-350x350.png 350w\" sizes=\"(max-width: 413px) 100vw, 413px\" \/><\/p>\n<\/section>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a linear function, graph by plotting points.<\/strong><\/p>\n<ol>\n<li>Choose a minimum of two input values.<\/li>\n<li>Evaluate the function at each input value.<\/li>\n<li>Use the resulting output values to identify coordinate pairs.<\/li>\n<li>Plot the coordinate pairs on a grid.<\/li>\n<li>Draw a line through the points.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Graph the following by plotting points.<\/p>\n<div style=\"text-align: center;\">[latex]f\\left(x\\right)=-\\frac{2}{3}x+5[\/latex]<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q589508\">Show Solution<\/button><\/p>\n<div id=\"q589508\" class=\"hidden-answer\" style=\"display: none\">Begin by choosing input values. This function includes a fraction with a denominator of [latex]3[\/latex] so let\u2019s choose multiples of [latex]3[\/latex] as input values. We will choose [latex]0[\/latex], [latex]3[\/latex], and [latex]6[\/latex].<br \/>\n[latex]\\\\[\/latex]<br \/>\nEvaluate the function at each input value and use the output value to identify coordinate pairs.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{llllll}x=0& & f\\left(0\\right)=-\\frac{2}{3}\\left(0\\right)+5=5\\Rightarrow \\left(0,5\\right)\\\\ x=3& & f\\left(3\\right)=-\\frac{2}{3}\\left(3\\right)+5=3\\Rightarrow \\left(3,3\\right)\\\\ x=6& & f\\left(6\\right)=-\\frac{2}{3}\\left(6\\right)+5=1\\Rightarrow \\left(6,1\\right)\\end{array}[\/latex]<\/p>\n<p>Plot the coordinate pairs and draw a line through the points. The graph below is of\u00a0the function [latex]f\\left(x\\right)=-\\frac{2}{3}x+5[\/latex].<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184320\/CNX_Precalc_Figure_02_02_0012.jpg\" alt=\"The graph of the linear function &#091;latex&#093;f\\left(x\\right)=-\\frac{2}{3}x+5&#091;\/latex&#093;.\" width=\"400\" height=\"347\" \/><\/p>\n<p><strong>Analysis of the Solution<\/strong><\/p>\n<p>The graph of the function is a line as expected for a linear function. In addition, the graph has a downward slant which indicates a negative slope. This is also expected from the negative constant rate of change in the equation for the function.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">If your equation has a fraction, you&#8217;ll have to divide the number plugged in by whatever is in the denominator. In the previous example, choosing multiples of [latex]3[\/latex] will have the easiest calculation due to the [latex]\\frac{2}{3}[\/latex] in the equation.<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm318705\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318705&theme=lumen&iframe_resize_id=ohm318705&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":7,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":61,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/731"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":9,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/731\/revisions"}],"predecessor-version":[{"id":5262,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/731\/revisions\/5262"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/61"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/731\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=731"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=731"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=731"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=731"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}