{"id":708,"date":"2025-07-14T21:22:09","date_gmt":"2025-07-14T21:22:09","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=708"},"modified":"2026-01-16T20:38:29","modified_gmt":"2026-01-16T20:38:29","slug":"module-16-triangle-trigonometry-cheat-sheet","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/module-16-triangle-trigonometry-cheat-sheet\/","title":{"raw":"Triangle Trigonometry: Cheat Sheet","rendered":"Triangle Trigonometry: Cheat Sheet"},"content":{"raw":"<div>\r\n<div class=\"standard-markdown grid-cols-1 grid gap-3 [&amp;_&gt;_*]:min-w-0 !gap-3.5\">\r\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Essential Concepts<\/h2>\r\n<h3 class=\"text-text-100 mt-2 -mb-1 text-base font-bold\">Right Triangle Trigonometry<\/h3>\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle relative to an acute angle [latex]\\theta[\/latex]:<\/li>\r\n<\/ul>\r\n<ul>\r\n \t<li style=\"list-style-type: none;\">\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>Hypotenuse<\/strong>: side opposite the right angle (longest side)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>Adjacent side<\/strong>: side next to angle [latex]\\theta[\/latex] (between [latex]\\theta[\/latex] and the right angle)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>Opposite side<\/strong>: side across from angle [latex]\\theta[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SOH-CAH-TOA<\/strong> - Essential memory device for the three primary ratios:\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sin(t) = \\frac{\\text{opposite}}{\\text{hypotenuse}}[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\cos(t) = \\frac{\\text{adjacent}}{\\text{hypotenuse}}[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\tan(t) = \\frac{\\text{opposite}}{\\text{adjacent}}[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Reciprocal functions\r\n<ul>\r\n \t<li>Reciprocal of sine: [latex]\\csc(t) = \\frac{\\text{hypotenuse}}{\\text{opposite}}[\/latex]<\/li>\r\n \t<li>Reciprocal of cosine: [latex]\\sec(t) = \\frac{\\text{hypotenuse}}{\\text{adjacent}}[\/latex]<\/li>\r\n \t<li>Reciprocal of tangent: [latex]\\cot(t) = \\frac{\\text{adjacent}}{\\text{opposite}}[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<strong style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">Special Right Triangles<\/strong><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\"> - Memorize these exact values:<\/span>\r\n<ul>\r\n \t<li><em style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">45\u00b0-45\u00b0-90\u00b0 triangle<\/em><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\"> ([latex]\\frac{\\pi}{4}[\/latex]):<\/span>\r\n<ul>\r\n \t<li>Sides in ratio [latex]s : s : s\\sqrt{2}[\/latex]<\/li>\r\n \t<li>[latex]\\sin(45\u00b0) = \\cos(45\u00b0) = \\frac{\\sqrt{2}}{2}[\/latex]<\/li>\r\n \t<li>[latex]\\tan(45\u00b0) = 1[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><em>30\u00b0-60\u00b0-90\u00b0 triangle<\/em> ([latex]\\frac{\\pi}{6}[\/latex] and [latex]\\frac{\\pi}{3}[\/latex]):\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Sides in ratio [latex]s : s\\sqrt{3} : 2s[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">For 30\u00b0: [latex]\\sin(30\u00b0) = \\frac{1}{2}[\/latex], [latex]\\cos(30\u00b0) = \\frac{\\sqrt{3}}{2}[\/latex], [latex]\\tan(30\u00b0) = \\frac{\\sqrt{3}}{3}[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">For 60\u00b0: [latex]\\sin(60\u00b0) = \\frac{\\sqrt{3}}{2}[\/latex], [latex]\\cos(60\u00b0) = \\frac{1}{2}[\/latex], [latex]\\tan(60\u00b0) = \\sqrt{3}[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Cofunction Identities<\/strong> - Complementary angles (angles that sum to [latex]\\frac{\\pi}{2}[\/latex] or 90\u00b0) have related trig values. The sine of an angle equals the cosine of its complement\r\n<ul>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\cos(t) = \\sin(\\frac{\\pi}{2} - t)[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\tan(t) = \\cot(\\frac{\\pi}{2} - t)[\/latex]<\/li>\r\n \t<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sec(t) = \\csc(\\frac{\\pi}{2} - t)[\/latex]<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Solving Right Triangles<\/strong> - When you know one acute angle and one side:<\/p>\r\n\r\n<ol class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">Identify which sides you know and which you need (opposite, adjacent, hypotenuse)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Choose the trig function that relates the known and unknown sides<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Set up an equation and solve algebraically<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Use inverse trig functions to find unknown angles when you know two sides<\/li>\r\n<\/ol>\r\n<h3 class=\"text-text-100 mt-2 -mb-1 text-base font-bold\">Non-Right Triangles with Law of Sines<\/h3>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">An oblique triangle is any triangle without a right angle. Standard labeling uses angles [latex]\\alpha[\/latex], [latex]\\beta[\/latex], [latex]\\gamma[\/latex] opposite sides [latex]a[\/latex], [latex]b[\/latex], [latex]c[\/latex] respectively.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Sines<\/strong> - Use when you know:<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">Two angles and any side (AAS or ASA)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Two sides and an angle opposite one of them (SSA - ambiguous case)<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-pre-wrap leading-[1.7]\">The Law of Sines states that the ratio of each side to the sine of its opposite angle is constant: [latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex]<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Can also be written as: [latex]\\frac{\\sin\\alpha}{a} = \\frac{\\sin\\beta}{b} = \\frac{\\sin\\gamma}{c}[\/latex]<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SSA Ambiguous Case<\/strong> - When you know two sides and an angle opposite one of them, there may be:<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>No triangle<\/strong> (if the known side opposite the angle is too short)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>One triangle<\/strong> (if the known side opposite equals the altitude, or if it's the longest side)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\"><strong>Two triangles<\/strong> (if the known side opposite is longer than the altitude but shorter than the other known side)<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Check both the acute and obtuse angle possibilities when solving for an unknown angle with inverse sine.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Area of Oblique Triangle<\/strong> (when you know two sides and the included angle):<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}ab\\sin\\gamma[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}bc\\sin\\alpha[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}ac\\sin\\beta[\/latex]<\/li>\r\n<\/ul>\r\n<h3>Solving Non-Right Triangles with Law of Cosines<\/h3>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Cosines<\/strong> - Use when you know:<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">Three sides (SSS)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Two sides and the included angle between them (SAS)<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The Law of Cosines generalizes the Pythagorean theorem for non-right triangles:<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]a^2 = b^2 + c^2 - 2bc\\cos\\alpha[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]b^2 = a^2 + c^2 - 2ac\\cos\\beta[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">[latex]c^2 = a^2 + b^2 - 2ab\\cos\\gamma[\/latex]<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">When to Use Which Law:<\/p>\r\n\r\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">Law of Sines: AAS, ASA, or SSA situations<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Law of Cosines: SAS or SSS situations<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Law of Cosines produces unique angle values (no ambiguous case)<\/li>\r\n<\/ul>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>General Strategy for Solving Oblique Triangles<\/strong>:<\/p>\r\n\r\n<ol class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal flex flex-col gap-1 pl-8 mb-3\">\r\n \t<li class=\"whitespace-normal break-words pl-2\">Identify what information is given (ASA, AAS, SSA, SAS, or SSS)<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Choose the appropriate law<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Solve for one unknown<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Use either law to find a second unknown<\/li>\r\n \t<li class=\"whitespace-normal break-words pl-2\">Use the angle sum property ([latex]\\alpha + \\beta + \\gamma = 180\u00b0[\/latex]) to find the third angle<\/li>\r\n<\/ol>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Heron's Formula<\/strong> (when you know all three sides):<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">First calculate the semi-perimeter: [latex]s = \\frac{a + b + c}{2}[\/latex]<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Then: [latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex]<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">This formula works for any triangle when all three sides are known, eliminating the need to find heights or angles.<\/p>\r\n\r\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Key Equations<\/h2>\r\n<table style=\"width: 96.7886%;\">\r\n<tbody>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Right triangle trig functions<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\sin(t) = \\frac{\\text{opposite}}{\\text{hypotenuse}}[\/latex]\r\n\r\n[latex]\\cos(t) = \\frac{\\text{adjacent}}{\\text{hypotenuse}}[\/latex]\r\n\r\n[latex]\\tan(t) = \\frac{\\text{opposite}}{\\text{adjacent}}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Right triangle reciprocal functions<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\csc(t) = \\frac{\\text{hypotenuse}}{\\text{opposite}}[\/latex]\r\n\r\n[latex]\\sec(t) = \\frac{\\text{hypotenuse}}{\\text{adjacent}}[\/latex]\r\n\r\n[latex]\\cot(t) = \\frac{\\text{adjacent}}{\\text{opposite}}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Cofunction identities<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex]\r\n[latex]\\tan(t) = \\cot(\\frac{\\pi}{2} - t)[\/latex]\r\n[latex]\\sec(t) = \\csc(\\frac{\\pi}{2} - t)[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Law of Sines<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Law of Cosines<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]a^2 = b^2 + c^2 - 2bc\\cos(A)[\/latex]\r\n\r\n[latex]b^2 = a^2 + c^2 - 2ac\\cos(B)[\/latex]\r\n\r\n[latex]c^2 = a^2 + b^2 - 2ab\\cos(C)[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Area with two sides and included angle<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\text{Area} = \\frac{1}{2}ab\\sin\\gamma[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 43.3604%;\"><strong>Heron's formula<\/strong><\/td>\r\n<td style=\"width: 52.5898%;\">[latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex]\r\nwhere [latex]s = \\frac{a+b+c}{2}[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Glossary<\/h2>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>adjacent side<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle, the side next to a given acute angle that is not the hypotenuse; the side between the angle and the right angle.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>altitude<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A perpendicular line segment from a vertex of a triangle to the opposite side (or the line containing the opposite side).<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>ambiguous case<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A situation in triangle solving (SSA configuration) where the given information may result in zero, one, or two valid triangles.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>angle of elevation<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The angle formed between a horizontal line and the line of sight looking upward to an object.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>cofunction identities<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Trigonometric identities showing the relationship between a trigonometric function and the cofunction of its complementary angle; for example, [latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex].<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Heron's formula<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula for finding the area of a triangle when all three side lengths are known: [latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex] where [latex]s[\/latex] is the semi-perimeter.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>hypotenuse<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The longest side of a right triangle; the side opposite the right angle.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Cosines<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula relating the sides and angles of any triangle: [latex]c^2 = a^2 + b^2 - 2ab\\cos\\gamma[\/latex]. Generalizes the Pythagorean theorem to oblique triangles.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Sines<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula stating that in any triangle, the ratio of each side length to the sine of its opposite angle is constant: [latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex].<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>oblique triangle<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Any triangle that does not contain a right angle; can be acute (all angles less than 90\u00b0) or obtuse (one angle greater than 90\u00b0).<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>opposite side<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle, the side across from a given acute angle; the side not touching the angle.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>semi-perimeter<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">One-half of the perimeter of a triangle, denoted [latex]s = \\frac{a+b+c}{2}[\/latex]; used in Heron's formula.<\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SOH-CAH-TOA<\/strong><\/p>\r\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A mnemonic device for remembering the three primary trigonometric ratios in right triangles: Sine is Opposite over Hypotenuse, Cosine is Adjacent over Hypotenuse, Tangent is Opposite over Adjacent.<\/p>\r\n\r\n<\/div>\r\n<\/div>","rendered":"<div>\n<div class=\"standard-markdown grid-cols-1 grid gap-3 [&amp;_&gt;_*]:min-w-0 !gap-3.5\">\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Essential Concepts<\/h2>\n<h3 class=\"text-text-100 mt-2 -mb-1 text-base font-bold\">Right Triangle Trigonometry<\/h3>\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle relative to an acute angle [latex]\\theta[\/latex]:<\/li>\n<\/ul>\n<ul>\n<li style=\"list-style-type: none;\">\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\"><strong>Hypotenuse<\/strong>: side opposite the right angle (longest side)<\/li>\n<li class=\"whitespace-normal break-words pl-2\"><strong>Adjacent side<\/strong>: side next to angle [latex]\\theta[\/latex] (between [latex]\\theta[\/latex] and the right angle)<\/li>\n<li class=\"whitespace-normal break-words pl-2\"><strong>Opposite side<\/strong>: side across from angle [latex]\\theta[\/latex]<\/li>\n<\/ul>\n<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SOH-CAH-TOA<\/strong> &#8211; Essential memory device for the three primary ratios:\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sin(t) = \\frac{\\text{opposite}}{\\text{hypotenuse}}[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\cos(t) = \\frac{\\text{adjacent}}{\\text{hypotenuse}}[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\tan(t) = \\frac{\\text{opposite}}{\\text{adjacent}}[\/latex]<\/li>\n<\/ul>\n<\/li>\n<li>Reciprocal functions\n<ul>\n<li>Reciprocal of sine: [latex]\\csc(t) = \\frac{\\text{hypotenuse}}{\\text{opposite}}[\/latex]<\/li>\n<li>Reciprocal of cosine: [latex]\\sec(t) = \\frac{\\text{hypotenuse}}{\\text{adjacent}}[\/latex]<\/li>\n<li>Reciprocal of tangent: [latex]\\cot(t) = \\frac{\\text{adjacent}}{\\text{opposite}}[\/latex]<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<p><strong style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">Special Right Triangles<\/strong><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\"> &#8211; Memorize these exact values:<\/span><\/p>\n<ul>\n<li><em style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">45\u00b0-45\u00b0-90\u00b0 triangle<\/em><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\"> ([latex]\\frac{\\pi}{4}[\/latex]):<\/span>\n<ul>\n<li>Sides in ratio [latex]s : s : s\\sqrt{2}[\/latex]<\/li>\n<li>[latex]\\sin(45\u00b0) = \\cos(45\u00b0) = \\frac{\\sqrt{2}}{2}[\/latex]<\/li>\n<li>[latex]\\tan(45\u00b0) = 1[\/latex]<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><em>30\u00b0-60\u00b0-90\u00b0 triangle<\/em> ([latex]\\frac{\\pi}{6}[\/latex] and [latex]\\frac{\\pi}{3}[\/latex]):\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Sides in ratio [latex]s : s\\sqrt{3} : 2s[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">For 30\u00b0: [latex]\\sin(30\u00b0) = \\frac{1}{2}[\/latex], [latex]\\cos(30\u00b0) = \\frac{\\sqrt{3}}{2}[\/latex], [latex]\\tan(30\u00b0) = \\frac{\\sqrt{3}}{3}[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">For 60\u00b0: [latex]\\sin(60\u00b0) = \\frac{\\sqrt{3}}{2}[\/latex], [latex]\\cos(60\u00b0) = \\frac{1}{2}[\/latex], [latex]\\tan(60\u00b0) = \\sqrt{3}[\/latex]<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Cofunction Identities<\/strong> &#8211; Complementary angles (angles that sum to [latex]\\frac{\\pi}{2}[\/latex] or 90\u00b0) have related trig values. The sine of an angle equals the cosine of its complement\n<ul>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\cos(t) = \\sin(\\frac{\\pi}{2} - t)[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\tan(t) = \\cot(\\frac{\\pi}{2} - t)[\/latex]<\/li>\n<li class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">[latex]\\sec(t) = \\csc(\\frac{\\pi}{2} - t)[\/latex]<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Solving Right Triangles<\/strong> &#8211; When you know one acute angle and one side:<\/p>\n<ol class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">Identify which sides you know and which you need (opposite, adjacent, hypotenuse)<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Choose the trig function that relates the known and unknown sides<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Set up an equation and solve algebraically<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Use inverse trig functions to find unknown angles when you know two sides<\/li>\n<\/ol>\n<h3 class=\"text-text-100 mt-2 -mb-1 text-base font-bold\">Non-Right Triangles with Law of Sines<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">An oblique triangle is any triangle without a right angle. Standard labeling uses angles [latex]\\alpha[\/latex], [latex]\\beta[\/latex], [latex]\\gamma[\/latex] opposite sides [latex]a[\/latex], [latex]b[\/latex], [latex]c[\/latex] respectively.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Sines<\/strong> &#8211; Use when you know:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">Two angles and any side (AAS or ASA)<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Two sides and an angle opposite one of them (SSA &#8211; ambiguous case)<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-pre-wrap leading-[1.7]\">The Law of Sines states that the ratio of each side to the sine of its opposite angle is constant: [latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex]<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Can also be written as: [latex]\\frac{\\sin\\alpha}{a} = \\frac{\\sin\\beta}{b} = \\frac{\\sin\\gamma}{c}[\/latex]<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SSA Ambiguous Case<\/strong> &#8211; When you know two sides and an angle opposite one of them, there may be:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\"><strong>No triangle<\/strong> (if the known side opposite the angle is too short)<\/li>\n<li class=\"whitespace-normal break-words pl-2\"><strong>One triangle<\/strong> (if the known side opposite equals the altitude, or if it&#8217;s the longest side)<\/li>\n<li class=\"whitespace-normal break-words pl-2\"><strong>Two triangles<\/strong> (if the known side opposite is longer than the altitude but shorter than the other known side)<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Check both the acute and obtuse angle possibilities when solving for an unknown angle with inverse sine.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Area of Oblique Triangle<\/strong> (when you know two sides and the included angle):<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}ab\\sin\\gamma[\/latex]<\/li>\n<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}bc\\sin\\alpha[\/latex]<\/li>\n<li class=\"whitespace-normal break-words pl-2\">[latex]\\text{Area} = \\frac{1}{2}ac\\sin\\beta[\/latex]<\/li>\n<\/ul>\n<h3>Solving Non-Right Triangles with Law of Cosines<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Cosines<\/strong> &#8211; Use when you know:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">Three sides (SSS)<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Two sides and the included angle between them (SAS)<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The Law of Cosines generalizes the Pythagorean theorem for non-right triangles:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">[latex]a^2 = b^2 + c^2 - 2bc\\cos\\alpha[\/latex]<\/li>\n<li class=\"whitespace-normal break-words pl-2\">[latex]b^2 = a^2 + c^2 - 2ac\\cos\\beta[\/latex]<\/li>\n<li class=\"whitespace-normal break-words pl-2\">[latex]c^2 = a^2 + b^2 - 2ab\\cos\\gamma[\/latex]<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">When to Use Which Law:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">Law of Sines: AAS, ASA, or SSA situations<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Law of Cosines: SAS or SSS situations<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Law of Cosines produces unique angle values (no ambiguous case)<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>General Strategy for Solving Oblique Triangles<\/strong>:<\/p>\n<ol class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal flex flex-col gap-1 pl-8 mb-3\">\n<li class=\"whitespace-normal break-words pl-2\">Identify what information is given (ASA, AAS, SSA, SAS, or SSS)<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Choose the appropriate law<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Solve for one unknown<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Use either law to find a second unknown<\/li>\n<li class=\"whitespace-normal break-words pl-2\">Use the angle sum property ([latex]\\alpha + \\beta + \\gamma = 180\u00b0[\/latex]) to find the third angle<\/li>\n<\/ol>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Heron&#8217;s Formula<\/strong> (when you know all three sides):<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">First calculate the semi-perimeter: [latex]s = \\frac{a + b + c}{2}[\/latex]<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Then: [latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex]<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">This formula works for any triangle when all three sides are known, eliminating the need to find heights or angles.<\/p>\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Key Equations<\/h2>\n<table style=\"width: 96.7886%;\">\n<tbody>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Right triangle trig functions<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\sin(t) = \\frac{\\text{opposite}}{\\text{hypotenuse}}[\/latex]<\/p>\n<p>[latex]\\cos(t) = \\frac{\\text{adjacent}}{\\text{hypotenuse}}[\/latex]<\/p>\n<p>[latex]\\tan(t) = \\frac{\\text{opposite}}{\\text{adjacent}}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Right triangle reciprocal functions<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\csc(t) = \\frac{\\text{hypotenuse}}{\\text{opposite}}[\/latex]<\/p>\n<p>[latex]\\sec(t) = \\frac{\\text{hypotenuse}}{\\text{adjacent}}[\/latex]<\/p>\n<p>[latex]\\cot(t) = \\frac{\\text{adjacent}}{\\text{opposite}}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Cofunction identities<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex]<br \/>\n[latex]\\tan(t) = \\cot(\\frac{\\pi}{2} - t)[\/latex]<br \/>\n[latex]\\sec(t) = \\csc(\\frac{\\pi}{2} - t)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Law of Sines<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Law of Cosines<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]a^2 = b^2 + c^2 - 2bc\\cos(A)[\/latex]<\/p>\n<p>[latex]b^2 = a^2 + c^2 - 2ac\\cos(B)[\/latex]<\/p>\n<p>[latex]c^2 = a^2 + b^2 - 2ab\\cos(C)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Area with two sides and included angle<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\text{Area} = \\frac{1}{2}ab\\sin\\gamma[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 43.3604%;\"><strong>Heron&#8217;s formula<\/strong><\/td>\n<td style=\"width: 52.5898%;\">[latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex]<br \/>\nwhere [latex]s = \\frac{a+b+c}{2}[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2 class=\"text-text-100 mt-3 -mb-1 text-[1.125rem] font-bold\">Glossary<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>adjacent side<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle, the side next to a given acute angle that is not the hypotenuse; the side between the angle and the right angle.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>altitude<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A perpendicular line segment from a vertex of a triangle to the opposite side (or the line containing the opposite side).<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>ambiguous case<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A situation in triangle solving (SSA configuration) where the given information may result in zero, one, or two valid triangles.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>angle of elevation<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The angle formed between a horizontal line and the line of sight looking upward to an object.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>cofunction identities<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Trigonometric identities showing the relationship between a trigonometric function and the cofunction of its complementary angle; for example, [latex]\\sin(t) = \\cos(\\frac{\\pi}{2} - t)[\/latex].<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Heron&#8217;s formula<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula for finding the area of a triangle when all three side lengths are known: [latex]\\text{Area} = \\sqrt{s(s-a)(s-b)(s-c)}[\/latex] where [latex]s[\/latex] is the semi-perimeter.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>hypotenuse<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">The longest side of a right triangle; the side opposite the right angle.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Cosines<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula relating the sides and angles of any triangle: [latex]c^2 = a^2 + b^2 - 2ab\\cos\\gamma[\/latex]. Generalizes the Pythagorean theorem to oblique triangles.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>Law of Sines<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A formula stating that in any triangle, the ratio of each side length to the sine of its opposite angle is constant: [latex]\\frac{a}{\\sin\\alpha} = \\frac{b}{\\sin\\beta} = \\frac{c}{\\sin\\gamma}[\/latex].<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>oblique triangle<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">Any triangle that does not contain a right angle; can be acute (all angles less than 90\u00b0) or obtuse (one angle greater than 90\u00b0).<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>opposite side<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">In a right triangle, the side across from a given acute angle; the side not touching the angle.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>semi-perimeter<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">One-half of the perimeter of a triangle, denoted [latex]s = \\frac{a+b+c}{2}[\/latex]; used in Heron&#8217;s formula.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\"><strong>SOH-CAH-TOA<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal leading-[1.7]\">A mnemonic device for remembering the three primary trigonometric ratios in right triangles: Sine is Opposite over Hypotenuse, Cosine is Adjacent over Hypotenuse, Tangent is Opposite over Adjacent.<\/p>\n<\/div>\n<\/div>\n","protected":false},"author":67,"menu_order":1,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":221,"module-header":"cheat_sheet","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/708"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/67"}],"version-history":[{"count":8,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/708\/revisions"}],"predecessor-version":[{"id":5414,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/708\/revisions\/5414"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/221"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/708\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=708"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=708"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=708"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=708"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}