{"id":63,"date":"2025-02-13T22:43:20","date_gmt":"2025-02-13T22:43:20","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/graphs-of-linear-functions\/"},"modified":"2026-01-09T20:54:25","modified_gmt":"2026-01-09T20:54:25","slug":"graphs-of-linear-functions","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/graphs-of-linear-functions\/","title":{"raw":"Graphs of Linear Functions: Learn It 5","rendered":"Graphs of Linear Functions: Learn It 5"},"content":{"raw":"<h2>Finding the [latex]x[\/latex]-intercept of a Line<\/h2>\r\nSo far we have only discussed the [latex]y-[\/latex]intercepts of functions: the point at which the graph of a function crosses the [latex]y[\/latex]-axis. A function may also have an <strong>[latex]x[\/latex]-intercept,<\/strong> which is the [latex]x[\/latex]-coordinate of the point where the graph of a function crosses the [latex]x[\/latex]-axis. In other words, it is the input value when the output value is zero.\r\n\r\nTo find the [latex]x[\/latex]-intercept, set the function [latex]f[\/latex]([latex]x[\/latex]) equal to zero and solve for the value of [latex]x[\/latex]. For example, consider the function shown:\r\n<p style=\"text-align: center;\">[latex]f\\left(x\\right)=3x - 6[\/latex]<\/p>\r\nSet the function equal to [latex]0[\/latex] and solve for [latex]x[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}0=3x - 6\\hfill \\\\ 6=3x\\hfill \\\\ 2=x\\hfill \\\\ x=2\\hfill \\end{array}[\/latex]<\/p>\r\nThe graph of the function crosses the [latex]x[\/latex]-axis at the point [latex](2, 0)[\/latex].\r\n\r\n<section class=\"textbox keyTakeaway\">\r\n<div>\r\n<h3>[latex]x[\/latex]-intercept of a Line<\/h3>\r\nThe <strong>[latex]x[\/latex]-intercept<\/strong> of a function is the value of [latex]x[\/latex] where [latex]f(x) = 0[\/latex]. It can be found by solving the equation [latex]0 = mx + b[\/latex].\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox questionHelp\"><strong>Do all linear functions have [latex]x[\/latex]-intercepts?<\/strong>\r\n\r\n<hr \/>\r\n\r\nNo. However, linear functions of the form [latex]y = c[\/latex], where [latex]c[\/latex] is a nonzero real number are the only examples of linear functions with no [latex]x[\/latex]-intercept. For example, [latex]y = 5[\/latex] is a horizontal line [latex]5[\/latex] units above the [latex]x[\/latex]-axis. This function has no [latex]x[\/latex]-intercepts.\r\n\r\n<center><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184348\/CNX_Precalc_Figure_02_02_0262.jpg\" alt=\"Graph of y = 5.\" width=\"421\" height=\"231\" \/><\/center><\/section><section class=\"textbox example\">Find the [latex]x[\/latex]-intercept of the following:\r\n<center>[latex]f\\left(x\\right)=\\frac{1}{2}x - 3[\/latex]<\/center>\r\n[reveal-answer q=\"400055\"]Show Solution[\/reveal-answer] [hidden-answer a=\"400055\"] Set the function equal to zero to solve for [latex]x[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}0=\\frac{1}{2}x - 3\\\\ 3=\\frac{1}{2}x\\\\ 6=x\\\\ x=6\\end{array}[\/latex]<\/p>\r\nThe graph crosses the [latex]x[\/latex]-axis at the point [latex](6, 0)[\/latex].\r\n[latex]\\\\[\/latex]\r\n<strong>Analysis of the Solution<\/strong> [latex]\\\\[\/latex]A graph of the function is shown below. We can see that the [latex]x[\/latex]-intercept is [latex](6, 0)[\/latex] as expected.\r\n\r\n<center><img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184351\/CNX_Precalc_Figure_02_02_0132.jpg\" alt=\"The graph of the linear function f(x)=frac{1}{2}x - 3\" width=\"369\" height=\"378\" \/><\/center><center><strong><span style=\"font-size: 10pt;\">The graph of the linear function [latex]f\\left(x\\right)=\\frac{1}{2}x - 3[\/latex]. \u00a0[\/hidden-answer]<\/span><\/strong><\/center><\/section><section class=\"textbox tryIt\">[ohm_question hide_question_numbers=1]318707[\/ohm_question]<\/section>","rendered":"<h2>Finding the [latex]x[\/latex]-intercept of a Line<\/h2>\n<p>So far we have only discussed the [latex]y-[\/latex]intercepts of functions: the point at which the graph of a function crosses the [latex]y[\/latex]-axis. A function may also have an <strong>[latex]x[\/latex]-intercept,<\/strong> which is the [latex]x[\/latex]-coordinate of the point where the graph of a function crosses the [latex]x[\/latex]-axis. In other words, it is the input value when the output value is zero.<\/p>\n<p>To find the [latex]x[\/latex]-intercept, set the function [latex]f[\/latex]([latex]x[\/latex]) equal to zero and solve for the value of [latex]x[\/latex]. For example, consider the function shown:<\/p>\n<p style=\"text-align: center;\">[latex]f\\left(x\\right)=3x - 6[\/latex]<\/p>\n<p>Set the function equal to [latex]0[\/latex] and solve for [latex]x[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}0=3x - 6\\hfill \\\\ 6=3x\\hfill \\\\ 2=x\\hfill \\\\ x=2\\hfill \\end{array}[\/latex]<\/p>\n<p>The graph of the function crosses the [latex]x[\/latex]-axis at the point [latex](2, 0)[\/latex].<\/p>\n<section class=\"textbox keyTakeaway\">\n<div>\n<h3>[latex]x[\/latex]-intercept of a Line<\/h3>\n<p>The <strong>[latex]x[\/latex]-intercept<\/strong> of a function is the value of [latex]x[\/latex] where [latex]f(x) = 0[\/latex]. It can be found by solving the equation [latex]0 = mx + b[\/latex].<\/p>\n<\/div>\n<\/section>\n<section class=\"textbox questionHelp\"><strong>Do all linear functions have [latex]x[\/latex]-intercepts?<\/strong><\/p>\n<hr \/>\n<p>No. However, linear functions of the form [latex]y = c[\/latex], where [latex]c[\/latex] is a nonzero real number are the only examples of linear functions with no [latex]x[\/latex]-intercept. For example, [latex]y = 5[\/latex] is a horizontal line [latex]5[\/latex] units above the [latex]x[\/latex]-axis. This function has no [latex]x[\/latex]-intercepts.<\/p>\n<div style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184348\/CNX_Precalc_Figure_02_02_0262.jpg\" alt=\"Graph of y = 5.\" width=\"421\" height=\"231\" \/><\/div>\n<\/section>\n<section class=\"textbox example\">Find the [latex]x[\/latex]-intercept of the following:<\/p>\n<div style=\"text-align: center;\">[latex]f\\left(x\\right)=\\frac{1}{2}x - 3[\/latex]<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q400055\">Show Solution<\/button> <\/p>\n<div id=\"q400055\" class=\"hidden-answer\" style=\"display: none\"> Set the function equal to zero to solve for [latex]x[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{l}0=\\frac{1}{2}x - 3\\\\ 3=\\frac{1}{2}x\\\\ 6=x\\\\ x=6\\end{array}[\/latex]<\/p>\n<p>The graph crosses the [latex]x[\/latex]-axis at the point [latex](6, 0)[\/latex].<br \/>\n[latex]\\\\[\/latex]<br \/>\n<strong>Analysis of the Solution<\/strong> [latex]\\\\[\/latex]A graph of the function is shown below. We can see that the [latex]x[\/latex]-intercept is [latex](6, 0)[\/latex] as expected.<\/p>\n<div style=\"text-align: center;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/21184351\/CNX_Precalc_Figure_02_02_0132.jpg\" alt=\"The graph of the linear function f(x)=frac{1}{2}x - 3\" width=\"369\" height=\"378\" \/><\/div>\n<div style=\"text-align: center;\"><strong><span style=\"font-size: 10pt;\">The graph of the linear function [latex]f\\left(x\\right)=\\frac{1}{2}x - 3[\/latex]. \u00a0<\/div>\n<\/div>\n<p><\/span><\/strong><\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm318707\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318707&theme=lumen&iframe_resize_id=ohm318707&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":6,"menu_order":10,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"Precalculus\",\"author\":\"OpenStax College\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":61,"module-header":"learn_it","content_attributions":[{"type":"cc-attribution","description":"Precalculus","author":"OpenStax College","organization":"OpenStax","url":"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface","project":"","license":"cc-by","license_terms":""}],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/63"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/6"}],"version-history":[{"count":8,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/63\/revisions"}],"predecessor-version":[{"id":5265,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/63\/revisions\/5265"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/61"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/63\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=63"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=63"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=63"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=63"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}