{"id":2849,"date":"2025-08-13T20:18:16","date_gmt":"2025-08-13T20:18:16","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=2849"},"modified":"2025-12-02T22:49:24","modified_gmt":"2025-12-02T22:49:24","slug":"finding-limits-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/finding-limits-learn-it-3\/","title":{"raw":"Finding Limits: Learn It 3","rendered":"Finding Limits: Learn It 3"},"content":{"raw":"<h2>Finding a Limit Using a Graph<\/h2>\r\nTo visually determine if a limit exists as [latex]x[\/latex] approaches [latex]a[\/latex], we observe the graph of the function when [latex]x[\/latex] is very near to [latex]x=a[\/latex]. We observe the behavior of the graph on both sides of [latex]a[\/latex].\r\n\r\n<img class=\"aligncenter wp-image-4975\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-300x276.png\" alt=\"Graph of a function that explains the behavior of a limit at (a, L) where the function is increasing when x is less than a and decreasing when x is greater than a.\" width=\"496\" height=\"456\" \/>\r\n\r\nTo determine if a left-hand limit exists, we observe the branch of the graph to the left of [latex]x=a[\/latex], but near [latex]x=a[\/latex]. This is where [latex]x&lt;a[\/latex]. We see that the outputs are getting close to some real number [latex]L[\/latex] so there is a left-hand limit.\r\n\r\nTo determine if a right-hand limit exists, observe the branch of the graph to the right of [latex]x=a[\/latex], but near [latex]x=a[\/latex]. This is where [latex]x&gt;a[\/latex]. We see that the outputs are getting close to some real number [latex]L[\/latex], so there is a right-hand limit.\r\n\r\nIf the left-hand limit and the right-hand limit are the same, then we know that the function has a two-sided limit. Normally, when we refer to a \"limit,\" we mean a two-sided limit, unless we call it a one-sided limit.\r\n\r\nFinally, we can look for an output value for the function [latex]f\\left(x\\right)[\/latex] when the input value [latex]x[\/latex] is equal to [latex]a[\/latex]. The coordinate pair of the point would be [latex]\\left(a,f\\left(a\\right)\\right)[\/latex]. If such a point exists, then [latex]f\\left(a\\right)[\/latex] has a value. If the point does not exist, then we say that [latex]f\\left(a\\right)[\/latex] does not exist.\r\n\r\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a function [latex]f\\left(x\\right)[\/latex], use a graph to find the limits and a function value as [latex]x[\/latex] approaches [latex]a[\/latex].<\/strong>\r\n<ol>\r\n \t<li>Examine the graph to determine whether a left-hand limit exists.<\/li>\r\n \t<li>Examine the graph to determine whether a right-hand limit exists.<\/li>\r\n \t<li>If the two one-sided limits exist and are equal, then there is a two-sided limit\u2014what we normally call a \"limit.\"<\/li>\r\n \t<li>If there is a point at [latex]x=a[\/latex], then [latex]f\\left(a\\right)[\/latex] is the corresponding function value.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">\r\n<ol>\r\n \t<li>Use the graph to answer the following questions.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185230\/CNX_Precalc_Figure_12_01_0052.jpg\" alt=\"Graph of a piecewise function that has a positive parabola centered at the origin and goes from negative infinity to (2, 8), an open point, and a decreasing line from (2, 3), a closed point, to positive infinity on the x-axis.\" width=\"487\" height=\"520\" \/>\r\n<ol>\r\n \t<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]\\underset{x\\to {2}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]f\\left(2\\right)[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Use the graph to answer the following questions.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185232\/CNX_Precalc_Figure_12_01_0062.jpg\" alt=\"Graph of a piecewise function that has a positive parabola from negative infinity to 2 on the x-axis, a decreasing line from 2 to positive infinity on the x-axis, and a point at (2, 4).\" width=\"487\" height=\"483\" \/>\r\n<ol>\r\n \t<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]\\underset{x\\to {2}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]f\\left(2\\right)[\/latex]<\/li>\r\n<\/ol>\r\n<div class=\"mceTemp\"><\/div>\r\n[reveal-answer q=\"459090\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"459090\"]\r\n<ol>\r\n \t<li>\r\n<ol>\r\n \t<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x&lt;2[\/latex], but infinitesimally close to 2, the output values get close to [latex]y=8[\/latex].<\/li>\r\n \t<li>[latex]\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=3[\/latex]; when [latex]x&gt;2[\/latex], but infinitesimally close to 2, the output values approach [latex]y=3[\/latex].<\/li>\r\n \t<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex] does not exist because [latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)\\ne \\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]; the left and right-hand limits are not equal.<\/li>\r\n \t<li>[latex]f\\left(2\\right)=3[\/latex] because the graph of the function [latex]f[\/latex] passes through the point [latex]\\left(2,f\\left(2\\right)\\right)[\/latex] or [latex]\\left(2,3\\right)[\/latex].<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>\r\n<ol>\r\n \t<li>[latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x&lt;2[\/latex] but infinitesimally close to 2, the output values approach [latex]y=8[\/latex].<\/li>\r\n \t<li>[latex]\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x&gt;2[\/latex] but infinitesimally close to 2, the output values approach [latex]y=8[\/latex].<\/li>\r\n \t<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex] because [latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)=\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; the left and right-hand limits are equal.<\/li>\r\n \t<li>[latex]f\\left(2\\right)=4[\/latex] because the graph of the function [latex]f[\/latex] passes through the point [latex]\\left(2,f\\left(2\\right)\\right)[\/latex] or [latex]\\left(2,4\\right)[\/latex].<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Using the graph of the function [latex]y=f\\left(x\\right)[\/latex], estimate the following limits.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185234\/CNX_Precalc_Figure_12_01_007n2.jpg\" alt=\"Graph of a piecewise function that has three segments: 1) negative infinity to 0, 2) 0 to 2, and 3) 2 to positive inifnity, which has a discontinuity at (4, 4)\" width=\"487\" height=\"556\" \/>[reveal-answer q=\"319433\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"319433\"]a. 0; b. 2; c. does not exist; d. [latex]-2[\/latex]; e. 0; f. does not exist; g. 4; h. 4; i. 4\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]174077[\/ohm_question]<\/section>","rendered":"<h2>Finding a Limit Using a Graph<\/h2>\n<p>To visually determine if a limit exists as [latex]x[\/latex] approaches [latex]a[\/latex], we observe the graph of the function when [latex]x[\/latex] is very near to [latex]x=a[\/latex]. We observe the behavior of the graph on both sides of [latex]a[\/latex].<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-4975\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-300x276.png\" alt=\"Graph of a function that explains the behavior of a limit at (a, L) where the function is increasing when x is less than a and decreasing when x is greater than a.\" width=\"496\" height=\"456\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-300x276.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-65x60.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-225x207.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_-350x322.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/08\/02224858\/20.1.L.3.Graph_.png 761w\" sizes=\"(max-width: 496px) 100vw, 496px\" \/><\/p>\n<p>To determine if a left-hand limit exists, we observe the branch of the graph to the left of [latex]x=a[\/latex], but near [latex]x=a[\/latex]. This is where [latex]x<a[\/latex]. We see that the outputs are getting close to some real number [latex]L[\/latex] so there is a left-hand limit.\n\nTo determine if a right-hand limit exists, observe the branch of the graph to the right of [latex]x=a[\/latex], but near [latex]x=a[\/latex]. This is where [latex]x>a[\/latex]. We see that the outputs are getting close to some real number [latex]L[\/latex], so there is a right-hand limit.<\/p>\n<p>If the left-hand limit and the right-hand limit are the same, then we know that the function has a two-sided limit. Normally, when we refer to a &#8220;limit,&#8221; we mean a two-sided limit, unless we call it a one-sided limit.<\/p>\n<p>Finally, we can look for an output value for the function [latex]f\\left(x\\right)[\/latex] when the input value [latex]x[\/latex] is equal to [latex]a[\/latex]. The coordinate pair of the point would be [latex]\\left(a,f\\left(a\\right)\\right)[\/latex]. If such a point exists, then [latex]f\\left(a\\right)[\/latex] has a value. If the point does not exist, then we say that [latex]f\\left(a\\right)[\/latex] does not exist.<\/p>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a function [latex]f\\left(x\\right)[\/latex], use a graph to find the limits and a function value as [latex]x[\/latex] approaches [latex]a[\/latex].<\/strong><\/p>\n<ol>\n<li>Examine the graph to determine whether a left-hand limit exists.<\/li>\n<li>Examine the graph to determine whether a right-hand limit exists.<\/li>\n<li>If the two one-sided limits exist and are equal, then there is a two-sided limit\u2014what we normally call a &#8220;limit.&#8221;<\/li>\n<li>If there is a point at [latex]x=a[\/latex], then [latex]f\\left(a\\right)[\/latex] is the corresponding function value.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">\n<ol>\n<li>Use the graph to answer the following questions.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185230\/CNX_Precalc_Figure_12_01_0052.jpg\" alt=\"Graph of a piecewise function that has a positive parabola centered at the origin and goes from negative infinity to (2, 8), an open point, and a decreasing line from (2, 3), a closed point, to positive infinity on the x-axis.\" width=\"487\" height=\"520\" \/>\n<ol>\n<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]\\underset{x\\to {2}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]f\\left(2\\right)[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>Use the graph to answer the following questions.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185232\/CNX_Precalc_Figure_12_01_0062.jpg\" alt=\"Graph of a piecewise function that has a positive parabola from negative infinity to 2 on the x-axis, a decreasing line from 2 to positive infinity on the x-axis, and a point at (2, 4).\" width=\"487\" height=\"483\" \/>\n<ol>\n<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]\\underset{x\\to {2}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]f\\left(2\\right)[\/latex]<\/li>\n<\/ol>\n<div class=\"mceTemp\"><\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q459090\">Show Solution<\/button><\/p>\n<div id=\"q459090\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>\n<ol>\n<li>[latex]\\underset{x\\to {2}^{-}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x<2[\/latex], but infinitesimally close to 2, the output values get close to [latex]y=8[\/latex].<\/li>\n<li>[latex]\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=3[\/latex]; when [latex]x>2[\/latex], but infinitesimally close to 2, the output values approach [latex]y=3[\/latex].<\/li>\n<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)[\/latex] does not exist because [latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)\\ne \\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)[\/latex]; the left and right-hand limits are not equal.<\/li>\n<li>[latex]f\\left(2\\right)=3[\/latex] because the graph of the function [latex]f[\/latex] passes through the point [latex]\\left(2,f\\left(2\\right)\\right)[\/latex] or [latex]\\left(2,3\\right)[\/latex].<\/li>\n<\/ol>\n<\/li>\n<li>\n<ol>\n<li>[latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x<2[\/latex] but infinitesimally close to 2, the output values approach [latex]y=8[\/latex].<\/li>\n<li>[latex]\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; when [latex]x>2[\/latex] but infinitesimally close to 2, the output values approach [latex]y=8[\/latex].<\/li>\n<li>[latex]\\underset{x\\to 2}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex] because [latex]\\underset{x\\to 2{}^{-}}{\\mathrm{lim}}f\\left(x\\right)=\\underset{x\\to 2{}^{+}}{\\mathrm{lim}}f\\left(x\\right)=8[\/latex]; the left and right-hand limits are equal.<\/li>\n<li>[latex]f\\left(2\\right)=4[\/latex] because the graph of the function [latex]f[\/latex] passes through the point [latex]\\left(2,f\\left(2\\right)\\right)[\/latex] or [latex]\\left(2,4\\right)[\/latex].<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Using the graph of the function [latex]y=f\\left(x\\right)[\/latex], estimate the following limits.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27185234\/CNX_Precalc_Figure_12_01_007n2.jpg\" alt=\"Graph of a piecewise function that has three segments: 1) negative infinity to 0, 2) 0 to 2, and 3) 2 to positive inifnity, which has a discontinuity at (4, 4)\" width=\"487\" height=\"556\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q319433\">Show Solution<\/button><\/p>\n<div id=\"q319433\" class=\"hidden-answer\" style=\"display: none\">a. 0; b. 2; c. does not exist; d. [latex]-2[\/latex]; e. 0; f. does not exist; g. 4; h. 4; i. 4<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm174077\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=174077&theme=lumen&iframe_resize_id=ohm174077&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":263,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2849"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":4,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2849\/revisions"}],"predecessor-version":[{"id":4976,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2849\/revisions\/4976"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/263"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2849\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=2849"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=2849"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=2849"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=2849"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}