{"id":2573,"date":"2025-08-13T18:07:29","date_gmt":"2025-08-13T18:07:29","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=2573"},"modified":"2025-08-13T18:07:49","modified_gmt":"2025-08-13T18:07:49","slug":"rotation-of-axes-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/rotation-of-axes-learn-it-4\/","title":{"raw":"Rotation of Axes: Learn It 4","rendered":"Rotation of Axes: Learn It 4"},"content":{"raw":"<h2><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">Identifying Conics without Rotating Axes<\/span><\/h2>\r\nNow we have come full circle. How do we identify the type of conic described by an equation? What happens when the axes are rotated? Recall, the general form of a conic is\r\n<div style=\"text-align: center;\">[latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex]<\/div>\r\nIf we apply the rotation formulas to this equation we get the form\r\n<div style=\"text-align: center;\">[latex]\\begin{align}{A}^{\\prime }{{x}^{\\prime }}^{2}+{B}^{\\prime }{x}^{\\prime }{y}^{\\prime }+{C}^{\\prime }{{y}^{\\prime }}^{2}+{D}^{\\prime }{x}^{\\prime }+{E}^{\\prime }{y}^{\\prime }+{F}^{\\prime }=0\\end{align}[\/latex]<\/div>\r\nIt may be shown that [latex]\\begin{align}{B}^{2}-4AC={{B}^{\\prime }}^{2}-4{A}^{\\prime }{C}^{\\prime }\\end{align}[\/latex]. The expression does not vary after rotation, so we call the expression invariant<strong>.<\/strong> The discriminant, [latex]{B}^{2}-4AC[\/latex], is invariant and remains unchanged after rotation. Because the discriminant remains unchanged, observing the discriminant enables us to identify the conic section.\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>the discriminant<\/h3>\r\nIf the equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex] is transformed by rotating axes into the equation [latex]\\begin{align}{A}^{\\prime }{{x}^{\\prime }}^{2}+{B}^{\\prime }{x}^{\\prime }{y}^{\\prime }+{C}^{\\prime }{{y}^{\\prime }}^{2}+{D}^{\\prime }{x}^{\\prime }+{E}^{\\prime }{y}^{\\prime }+{F}^{\\prime }=0\\end{align}[\/latex], then [latex]\\begin{align}{B}^{2}-4AC={{B}^{\\prime }}^{2}-4{A}^{\\prime }{C}^{\\prime }\\end{align}[\/latex].\r\n\r\nThe equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex] is an ellipse, a parabola, or a hyperbola, or a degenerate case of one of these.\r\n\r\nIf the discriminant, [latex]{B}^{2}-4AC[\/latex], is\r\n<ul>\r\n \t<li>[latex]&lt;0[\/latex], the conic section is an ellipse<\/li>\r\n \t<li>[latex]=0[\/latex], the conic section is a parabola<\/li>\r\n \t<li>[latex]&gt;0[\/latex], the conic section is a hyperbola<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Identify the conic for each of the following without rotating axes.\r\n<ol>\r\n \t<li>[latex]5{x}^{2}+2\\sqrt{3}xy+2{y}^{2}-5=0[\/latex]<\/li>\r\n \t<li>[latex]5{x}^{2}+2\\sqrt{3}xy+12{y}^{2}-5=0[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"255593\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"255593\"]\r\n<ol>\r\n \t<li>Let\u2019s begin by determining [latex]A,B[\/latex], and [latex]C[\/latex].\r\n<div style=\"text-align: center;\">[latex]\\underset{A}{\\underbrace{5}}{x}^{2}+\\underset{B}{\\underbrace{2\\sqrt{3}}}xy+\\underset{C}{\\underbrace{2}}{y}^{2}-5=0[\/latex]<\/div>\r\nNow, we find the discriminant.\r\n<div style=\"text-align: center;\">[latex]\\begin{align}{B}^{2}-4AC&amp;={\\left(2\\sqrt{3}\\right)}^{2}-4\\left(5\\right)\\left(2\\right) \\\\ &amp;=4\\left(3\\right)-40 \\\\ &amp;=12 - 40 \\\\ &amp;=-28&lt;0 \\end{align}[\/latex]<\/div>\r\nTherefore, [latex]5{x}^{2}+2\\sqrt{3}xy+2{y}^{2}-5=0[\/latex] represents an ellipse.<\/li>\r\n \t<li>Again, let\u2019s begin by determining [latex]A,B[\/latex], and [latex]C[\/latex].\r\n<div style=\"text-align: center;\">[latex]\\underset{A}{\\underbrace{5}}{x}^{2}+\\underset{B}{\\underbrace{2\\sqrt{3}}}xy+\\underset{C}{\\underbrace{12}}{y}^{2}-5=0[\/latex]<\/div>\r\nNow, we find the discriminant.\r\n<div style=\"text-align: center;\">[latex]\\begin{align}{B}^{2}-4AC&amp;={\\left(2\\sqrt{3}\\right)}^{2}-4\\left(5\\right)\\left(12\\right) \\\\ &amp;=4\\left(3\\right)-240 \\\\ &amp;=12 - 240 \\\\ &amp;=-228&lt;0 \\end{align}[\/latex]<\/div>\r\nTherefore, [latex]5{x}^{2}+2\\sqrt{3}xy+12{y}^{2}-5=0[\/latex] represents an ellipse.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Identify the conic for each of the following without rotating axes.\r\n<ol>\r\n \t<li>[latex]{x}^{2}-9xy+3{y}^{2}-12=0[\/latex]<\/li>\r\n \t<li>[latex]10{x}^{2}-9xy+4{y}^{2}-4=0[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"67134\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"67134\"]\r\n<ol>\r\n \t<li>hyperbola<\/li>\r\n \t<li>ellipse<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section>","rendered":"<h2><span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">Identifying Conics without Rotating Axes<\/span><\/h2>\n<p>Now we have come full circle. How do we identify the type of conic described by an equation? What happens when the axes are rotated? Recall, the general form of a conic is<\/p>\n<div style=\"text-align: center;\">[latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex]<\/div>\n<p>If we apply the rotation formulas to this equation we get the form<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align}{A}^{\\prime }{{x}^{\\prime }}^{2}+{B}^{\\prime }{x}^{\\prime }{y}^{\\prime }+{C}^{\\prime }{{y}^{\\prime }}^{2}+{D}^{\\prime }{x}^{\\prime }+{E}^{\\prime }{y}^{\\prime }+{F}^{\\prime }=0\\end{align}[\/latex]<\/div>\n<p>It may be shown that [latex]\\begin{align}{B}^{2}-4AC={{B}^{\\prime }}^{2}-4{A}^{\\prime }{C}^{\\prime }\\end{align}[\/latex]. The expression does not vary after rotation, so we call the expression invariant<strong>.<\/strong> The discriminant, [latex]{B}^{2}-4AC[\/latex], is invariant and remains unchanged after rotation. Because the discriminant remains unchanged, observing the discriminant enables us to identify the conic section.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>the discriminant<\/h3>\n<p>If the equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex] is transformed by rotating axes into the equation [latex]\\begin{align}{A}^{\\prime }{{x}^{\\prime }}^{2}+{B}^{\\prime }{x}^{\\prime }{y}^{\\prime }+{C}^{\\prime }{{y}^{\\prime }}^{2}+{D}^{\\prime }{x}^{\\prime }+{E}^{\\prime }{y}^{\\prime }+{F}^{\\prime }=0\\end{align}[\/latex], then [latex]\\begin{align}{B}^{2}-4AC={{B}^{\\prime }}^{2}-4{A}^{\\prime }{C}^{\\prime }\\end{align}[\/latex].<\/p>\n<p>The equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex] is an ellipse, a parabola, or a hyperbola, or a degenerate case of one of these.<\/p>\n<p>If the discriminant, [latex]{B}^{2}-4AC[\/latex], is<\/p>\n<ul>\n<li>[latex]<0[\/latex], the conic section is an ellipse<\/li>\n<li>[latex]=0[\/latex], the conic section is a parabola<\/li>\n<li>[latex]>0[\/latex], the conic section is a hyperbola<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Identify the conic for each of the following without rotating axes.<\/p>\n<ol>\n<li>[latex]5{x}^{2}+2\\sqrt{3}xy+2{y}^{2}-5=0[\/latex]<\/li>\n<li>[latex]5{x}^{2}+2\\sqrt{3}xy+12{y}^{2}-5=0[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q255593\">Show Solution<\/button><\/p>\n<div id=\"q255593\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Let\u2019s begin by determining [latex]A,B[\/latex], and [latex]C[\/latex].\n<div style=\"text-align: center;\">[latex]\\underset{A}{\\underbrace{5}}{x}^{2}+\\underset{B}{\\underbrace{2\\sqrt{3}}}xy+\\underset{C}{\\underbrace{2}}{y}^{2}-5=0[\/latex]<\/div>\n<p>Now, we find the discriminant.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align}{B}^{2}-4AC&={\\left(2\\sqrt{3}\\right)}^{2}-4\\left(5\\right)\\left(2\\right) \\\\ &=4\\left(3\\right)-40 \\\\ &=12 - 40 \\\\ &=-28<0 \\end{align}[\/latex]<\/div>\n<p>Therefore, [latex]5{x}^{2}+2\\sqrt{3}xy+2{y}^{2}-5=0[\/latex] represents an ellipse.<\/li>\n<li>Again, let\u2019s begin by determining [latex]A,B[\/latex], and [latex]C[\/latex].\n<div style=\"text-align: center;\">[latex]\\underset{A}{\\underbrace{5}}{x}^{2}+\\underset{B}{\\underbrace{2\\sqrt{3}}}xy+\\underset{C}{\\underbrace{12}}{y}^{2}-5=0[\/latex]<\/div>\n<p>Now, we find the discriminant.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align}{B}^{2}-4AC&={\\left(2\\sqrt{3}\\right)}^{2}-4\\left(5\\right)\\left(12\\right) \\\\ &=4\\left(3\\right)-240 \\\\ &=12 - 240 \\\\ &=-228<0 \\end{align}[\/latex]<\/div>\n<p>Therefore, [latex]5{x}^{2}+2\\sqrt{3}xy+12{y}^{2}-5=0[\/latex] represents an ellipse.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Identify the conic for each of the following without rotating axes.<\/p>\n<ol>\n<li>[latex]{x}^{2}-9xy+3{y}^{2}-12=0[\/latex]<\/li>\n<li>[latex]10{x}^{2}-9xy+4{y}^{2}-4=0[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q67134\">Show Solution<\/button><\/p>\n<div id=\"q67134\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>hyperbola<\/li>\n<li>ellipse<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n","protected":false},"author":13,"menu_order":25,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":522,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2573"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":1,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2573\/revisions"}],"predecessor-version":[{"id":2588,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2573\/revisions\/2588"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/522"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2573\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=2573"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=2573"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=2573"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=2573"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}