{"id":2281,"date":"2025-08-12T17:52:48","date_gmt":"2025-08-12T17:52:48","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=2281"},"modified":"2025-08-13T17:04:59","modified_gmt":"2025-08-13T17:04:59","slug":"polar-form-of-complex-numbers-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/polar-form-of-complex-numbers-learn-it-3\/","title":{"raw":"Polar Form of Complex Numbers: Learn It 3","rendered":"Polar Form of Complex Numbers: Learn It 3"},"content":{"raw":"<h2>Converting a Complex Number from Polar to Rectangular Form<\/h2>\r\nConverting a complex number from polar form to rectangular form is a matter of evaluating what is given and using the distributive property. In other words, given [latex]z=r\\left(\\cos \\theta +i\\sin \\theta \\right)[\/latex], first evaluate the trigonometric functions [latex]\\cos \\theta [\/latex] and [latex]\\sin \\theta [\/latex]. Then, multiply through by [latex]r[\/latex].\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">Convert the polar form of the given complex number to rectangular form:\r\n<p style=\"text-align: center;\">[latex]z=12\\left(\\cos \\left(\\frac{\\pi }{6}\\right)+i\\sin \\left(\\frac{\\pi }{6}\\right)\\right)[\/latex]<\/p>\r\n[reveal-answer q=\"145161\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"145161\"]\r\n\r\nWe begin by evaluating the trigonometric expressions.\r\n<p style=\"text-align: center;\">[latex]\\begin{gathered}\\cos \\left(\\frac{\\pi }{6}\\right)=\\frac{\\sqrt{3}}{2}\\\\\\sin \\left(\\frac{\\pi }{6}\\right)=\\frac{1}{2}\\end{gathered}[\/latex]<\/p>\r\nAfter substitution, the complex number is\r\n<p style=\"text-align: center;\">[latex]z=12\\left(\\frac{\\sqrt{3}}{2}+\\frac{1}{2}i\\right)[\/latex]<\/p>\r\nWe apply the distributive property:\r\n<p style=\"text-align: center;\">[latex]\\begin{align}z&amp;=12\\left(\\frac{\\sqrt{3}}{2}+\\frac{1}{2}i\\right) \\\\ &amp;=\\left(12\\right)\\frac{\\sqrt{3}}{2}+\\left(12\\right)\\frac{1}{2}i \\\\ &amp;=6\\sqrt{3}+6i \\end{align}[\/latex]<\/p>\r\nThe rectangular form of the given point in complex form is [latex]6\\sqrt{3}+6i[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the rectangular form of the complex number given [latex]r=13[\/latex] and [latex]\\tan \\theta =\\frac{5}{12}[\/latex].[reveal-answer q=\"11326\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"11326\"]\r\n\r\nIf [latex]\\tan \\theta =\\frac{5}{12}[\/latex], and [latex]\\tan \\theta =\\frac{y}{x}[\/latex], we first determine [latex]r=\\sqrt{{x}^{2}+{y}^{2}}=\\sqrt{{12}^{2}+{5}^{2}}=13\\text{.}[\/latex] We then find [latex]\\cos \\theta =\\frac{x}{r}[\/latex] and [latex]\\sin \\theta =\\frac{y}{r}[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{align}z&amp;=13\\left(\\cos \\theta +i\\sin \\theta \\right) \\\\ &amp;=13\\left(\\frac{12}{13}+\\frac{5}{13}i\\right) \\\\ &amp;=12+5i \\end{align}[\/latex]<\/p>\r\nThe rectangular form of the given number in complex form is [latex]12+5i[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Convert the complex number to rectangular form:\r\n<p style=\"text-align: center;\">[latex]z=4\\left(\\cos \\frac{11\\pi }{6}+i\\sin \\frac{11\\pi }{6}\\right)[\/latex]<\/p>\r\n<p style=\"text-align: left;\">[reveal-answer q=\"9609\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"9609\"]<\/p>\r\n<p style=\"text-align: left;\">[latex]z=2\\sqrt{3}-2i[\/latex]<\/p>\r\n<p style=\"text-align: left;\">[\/hidden-answer]<\/p>\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]173840[\/ohm_question]<\/section>","rendered":"<h2>Converting a Complex Number from Polar to Rectangular Form<\/h2>\n<p>Converting a complex number from polar form to rectangular form is a matter of evaluating what is given and using the distributive property. In other words, given [latex]z=r\\left(\\cos \\theta +i\\sin \\theta \\right)[\/latex], first evaluate the trigonometric functions [latex]\\cos \\theta[\/latex] and [latex]\\sin \\theta[\/latex]. Then, multiply through by [latex]r[\/latex].<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">Convert the polar form of the given complex number to rectangular form:<\/p>\n<p style=\"text-align: center;\">[latex]z=12\\left(\\cos \\left(\\frac{\\pi }{6}\\right)+i\\sin \\left(\\frac{\\pi }{6}\\right)\\right)[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q145161\">Show Solution<\/button><\/p>\n<div id=\"q145161\" class=\"hidden-answer\" style=\"display: none\">\n<p>We begin by evaluating the trigonometric expressions.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{gathered}\\cos \\left(\\frac{\\pi }{6}\\right)=\\frac{\\sqrt{3}}{2}\\\\\\sin \\left(\\frac{\\pi }{6}\\right)=\\frac{1}{2}\\end{gathered}[\/latex]<\/p>\n<p>After substitution, the complex number is<\/p>\n<p style=\"text-align: center;\">[latex]z=12\\left(\\frac{\\sqrt{3}}{2}+\\frac{1}{2}i\\right)[\/latex]<\/p>\n<p>We apply the distributive property:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}z&=12\\left(\\frac{\\sqrt{3}}{2}+\\frac{1}{2}i\\right) \\\\ &=\\left(12\\right)\\frac{\\sqrt{3}}{2}+\\left(12\\right)\\frac{1}{2}i \\\\ &=6\\sqrt{3}+6i \\end{align}[\/latex]<\/p>\n<p>The rectangular form of the given point in complex form is [latex]6\\sqrt{3}+6i[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the rectangular form of the complex number given [latex]r=13[\/latex] and [latex]\\tan \\theta =\\frac{5}{12}[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q11326\">Show Solution<\/button><\/p>\n<div id=\"q11326\" class=\"hidden-answer\" style=\"display: none\">\n<p>If [latex]\\tan \\theta =\\frac{5}{12}[\/latex], and [latex]\\tan \\theta =\\frac{y}{x}[\/latex], we first determine [latex]r=\\sqrt{{x}^{2}+{y}^{2}}=\\sqrt{{12}^{2}+{5}^{2}}=13\\text{.}[\/latex] We then find [latex]\\cos \\theta =\\frac{x}{r}[\/latex] and [latex]\\sin \\theta =\\frac{y}{r}[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}z&=13\\left(\\cos \\theta +i\\sin \\theta \\right) \\\\ &=13\\left(\\frac{12}{13}+\\frac{5}{13}i\\right) \\\\ &=12+5i \\end{align}[\/latex]<\/p>\n<p>The rectangular form of the given number in complex form is [latex]12+5i[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Convert the complex number to rectangular form:<\/p>\n<p style=\"text-align: center;\">[latex]z=4\\left(\\cos \\frac{11\\pi }{6}+i\\sin \\frac{11\\pi }{6}\\right)[\/latex]<\/p>\n<p style=\"text-align: left;\">\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q9609\">Show Solution<\/button><\/p>\n<div id=\"q9609\" class=\"hidden-answer\" style=\"display: none\">\n<p style=\"text-align: left;\">[latex]z=2\\sqrt{3}-2i[\/latex]<\/p>\n<p style=\"text-align: left;\"><\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm173840\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=173840&theme=lumen&iframe_resize_id=ohm173840&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":21,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":247,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2281"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":4,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2281\/revisions"}],"predecessor-version":[{"id":2486,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2281\/revisions\/2486"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/247"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2281\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=2281"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=2281"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=2281"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=2281"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}