{"id":2280,"date":"2025-08-12T17:52:46","date_gmt":"2025-08-12T17:52:46","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=2280"},"modified":"2025-08-13T17:04:43","modified_gmt":"2025-08-13T17:04:43","slug":"polar-form-of-complex-numbers-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/polar-form-of-complex-numbers-learn-it-2\/","title":{"raw":"Polar Form of Complex Numbers: Learn It 2","rendered":"Polar Form of Complex Numbers: Learn It 2"},"content":{"raw":"<h2>Writing Complex Numbers in Polar Form<\/h2>\r\nThe <strong>polar form of a complex number<\/strong> expresses a number in terms of an angle [latex]\\theta [\/latex] and its distance from the origin [latex]r[\/latex]. Given a complex number in <strong>rectangular form<\/strong> expressed as [latex]z=x+yi[\/latex], we use the same conversion formulas as we do to write the number in trigonometric form:\r\n<div style=\"text-align: center;\">[latex]\\begin{gathered}x=r\\cos \\theta \\\\ y=r\\sin \\theta \\\\ r=\\sqrt{{x}^{2}+{y}^{2}} \\end{gathered}[\/latex]<\/div>\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27180851\/CNX_Precalc_Figure_08_05_0062.jpg\" alt=\"Triangle plotted in the complex plane (x axis is real, y axis is imaginary). Base is along the x\/real axis, height is some y\/imaginary value in Q 1, and hypotenuse r extends from origin to that point (x+yi) in Q 1. The angle at the origin is theta. There is an arc going through (x+yi).\" width=\"487\" height=\"331\" \/>\r\n\r\nWe use the term <strong>modulus<\/strong> to represent the absolute value of a complex number, or the distance from the origin to the point [latex]\\left(x,y\\right)[\/latex]. The modulus, then, is the same as [latex]r[\/latex], the radius in polar form. We use [latex]\\theta [\/latex] to indicate the angle of direction (just as with polar coordinates). Substituting, we have\r\n<div style=\"text-align: center;\">[latex]\\begin{align}&amp;z=x+yi \\\\ &amp;z=r\\cos \\theta +\\left(r\\sin \\theta \\right)i \\\\ &amp;z=r\\left(\\cos \\theta +i\\sin \\theta \\right) \\end{align}[\/latex]<\/div>\r\n<div><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<div>\r\n<h3>modulus<\/h3>\r\nThe distance from the origin to the point represented by the complex number. This can be found as the absolute value of the complex number.\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>polar form of a complex number<\/h3>\r\nWriting a complex number in polar form involves the following conversion formulas:\r\n<p style=\"text-align: center;\">[latex]\\begin{gathered} x=r\\cos \\theta \\\\ y=r\\sin \\theta \\\\ r=\\sqrt{{x}^{2}+{y}^{2}} \\end{gathered}[\/latex]<\/p>\r\nMaking a direct substitution, we have\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;z=x+yi \\\\ &amp;z=\\left(r\\cos \\theta \\right)+i\\left(r\\sin \\theta \\right) \\\\ &amp;z=r\\left(\\cos \\theta +i\\sin \\theta \\right) \\end{align}[\/latex]<\/p>\r\nwhere [latex]r[\/latex] is the <strong>modulus<\/strong> and [latex]\\theta [\/latex] is the <strong>argument<\/strong>. We often use the abbreviation [latex]r\\text{cis}\\theta [\/latex] to represent [latex]r\\left(\\cos \\theta +i\\sin \\theta \\right)[\/latex].\r\n\r\n<\/section><\/div>\r\n<section class=\"textbox example\" aria-label=\"Example\">Express the complex number [latex]4i[\/latex] using polar coordinates.[reveal-answer q=\"3488\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"3488\"]\r\n\r\nOn the complex plane, the number [latex]z=4i[\/latex] is the same as [latex]z=0+4i[\/latex]. Writing it in polar form, we have to calculate [latex]r[\/latex] first.\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;r=\\sqrt{{x}^{2}+{y}^{2}} \\\\ &amp;r=\\sqrt{{0}^{2}+{4}^{2}} \\\\ &amp;r=\\sqrt{16} \\\\ &amp;r=4 \\end{align}[\/latex]<\/p>\r\nNext, we look at [latex]x[\/latex]. If [latex]x=r\\cos \\theta [\/latex], and [latex]x=0[\/latex], then [latex]\\theta =\\frac{\\pi }{2}[\/latex]. In polar coordinates, the complex number [latex]z=0+4i[\/latex] can be written as [latex]z=4\\left(\\cos \\left(\\frac{\\pi }{2}\\right)+i\\sin \\left(\\frac{\\pi }{2}\\right)\\right)[\/latex] or [latex]4\\text{cis}\\left(\\frac{\\pi }{2}\\right)[\/latex].\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27180854\/CNX_Precalc_Figure_08_05_0072.jpg\" alt=\"Plot of z=4i in the complex plane, also shows that the in polar coordinate it would be (4,pi\/2).\" width=\"487\" height=\"294\" \/> <b>Figure 6<\/b>[\/caption]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">\r\n<div class=\"bcc-box bcc-success\">\r\n\r\nExpress [latex]z=3i[\/latex] as [latex]r\\text{cis}\\theta [\/latex] in polar form.\r\n\r\n[reveal-answer q=\"364839\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"364839\"]\r\n\r\n[latex]z=3\\left(\\cos \\left(\\frac{\\pi }{2}\\right)+i\\sin \\left(\\frac{\\pi }{2}\\right)\\right)[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the polar form of [latex]-4+4i[\/latex].[reveal-answer q=\"871564\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"871564\"]\r\n\r\nFirst, find the value of [latex]r[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;r=\\sqrt{{x}^{2}+{y}^{2}} \\\\ &amp;r=\\sqrt{{\\left(-4\\right)}^{2}+\\left({4}^{2}\\right)} \\\\ &amp;r=\\sqrt{32} \\\\ &amp;r=4\\sqrt{2} \\end{align}[\/latex]<\/p>\r\nFind the angle [latex]\\theta [\/latex] using the formula:\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;\\cos \\theta =\\frac{x}{r} \\\\ &amp;\\cos \\theta =\\frac{-4}{4\\sqrt{2}} \\\\ &amp;\\cos \\theta =-\\frac{1}{\\sqrt{2}} \\\\ &amp;\\theta ={\\cos }^{-1}\\left(-\\frac{1}{\\sqrt{2}}\\right)=\\frac{3\\pi }{4} \\end{align}[\/latex]<\/p>\r\nThus, the solution is [latex]4\\sqrt{2}\\cos\\left(\\frac{3\\pi }{4}\\right)[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Write [latex]z=\\sqrt{3}+i[\/latex] in polar form.[reveal-answer q=\"164997\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"164997\"][latex]z=2\\left(\\cos \\left(\\frac{\\pi }{6}\\right)+i\\sin \\left(\\frac{\\pi }{6}\\right)\\right)[\/latex][\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]173845[\/ohm_question]<\/section>","rendered":"<h2>Writing Complex Numbers in Polar Form<\/h2>\n<p>The <strong>polar form of a complex number<\/strong> expresses a number in terms of an angle [latex]\\theta[\/latex] and its distance from the origin [latex]r[\/latex]. Given a complex number in <strong>rectangular form<\/strong> expressed as [latex]z=x+yi[\/latex], we use the same conversion formulas as we do to write the number in trigonometric form:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{gathered}x=r\\cos \\theta \\\\ y=r\\sin \\theta \\\\ r=\\sqrt{{x}^{2}+{y}^{2}} \\end{gathered}[\/latex]<\/div>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27180851\/CNX_Precalc_Figure_08_05_0062.jpg\" alt=\"Triangle plotted in the complex plane (x axis is real, y axis is imaginary). Base is along the x\/real axis, height is some y\/imaginary value in Q 1, and hypotenuse r extends from origin to that point (x+yi) in Q 1. The angle at the origin is theta. There is an arc going through (x+yi).\" width=\"487\" height=\"331\" \/><\/p>\n<p>We use the term <strong>modulus<\/strong> to represent the absolute value of a complex number, or the distance from the origin to the point [latex]\\left(x,y\\right)[\/latex]. The modulus, then, is the same as [latex]r[\/latex], the radius in polar form. We use [latex]\\theta[\/latex] to indicate the angle of direction (just as with polar coordinates). Substituting, we have<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align}&z=x+yi \\\\ &z=r\\cos \\theta +\\left(r\\sin \\theta \\right)i \\\\ &z=r\\left(\\cos \\theta +i\\sin \\theta \\right) \\end{align}[\/latex]<\/div>\n<div>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<div>\n<h3>modulus<\/h3>\n<p>The distance from the origin to the point represented by the complex number. This can be found as the absolute value of the complex number.<\/p>\n<\/div>\n<\/section>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>polar form of a complex number<\/h3>\n<p>Writing a complex number in polar form involves the following conversion formulas:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{gathered} x=r\\cos \\theta \\\\ y=r\\sin \\theta \\\\ r=\\sqrt{{x}^{2}+{y}^{2}} \\end{gathered}[\/latex]<\/p>\n<p>Making a direct substitution, we have<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&z=x+yi \\\\ &z=\\left(r\\cos \\theta \\right)+i\\left(r\\sin \\theta \\right) \\\\ &z=r\\left(\\cos \\theta +i\\sin \\theta \\right) \\end{align}[\/latex]<\/p>\n<p>where [latex]r[\/latex] is the <strong>modulus<\/strong> and [latex]\\theta[\/latex] is the <strong>argument<\/strong>. We often use the abbreviation [latex]r\\text{cis}\\theta[\/latex] to represent [latex]r\\left(\\cos \\theta +i\\sin \\theta \\right)[\/latex].<\/p>\n<\/section>\n<\/div>\n<section class=\"textbox example\" aria-label=\"Example\">Express the complex number [latex]4i[\/latex] using polar coordinates.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q3488\">Show Solution<\/button><\/p>\n<div id=\"q3488\" class=\"hidden-answer\" style=\"display: none\">\n<p>On the complex plane, the number [latex]z=4i[\/latex] is the same as [latex]z=0+4i[\/latex]. Writing it in polar form, we have to calculate [latex]r[\/latex] first.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&r=\\sqrt{{x}^{2}+{y}^{2}} \\\\ &r=\\sqrt{{0}^{2}+{4}^{2}} \\\\ &r=\\sqrt{16} \\\\ &r=4 \\end{align}[\/latex]<\/p>\n<p>Next, we look at [latex]x[\/latex]. If [latex]x=r\\cos \\theta[\/latex], and [latex]x=0[\/latex], then [latex]\\theta =\\frac{\\pi }{2}[\/latex]. In polar coordinates, the complex number [latex]z=0+4i[\/latex] can be written as [latex]z=4\\left(\\cos \\left(\\frac{\\pi }{2}\\right)+i\\sin \\left(\\frac{\\pi }{2}\\right)\\right)[\/latex] or [latex]4\\text{cis}\\left(\\frac{\\pi }{2}\\right)[\/latex].<\/p>\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27180854\/CNX_Precalc_Figure_08_05_0072.jpg\" alt=\"Plot of z=4i in the complex plane, also shows that the in polar coordinate it would be (4,pi\/2).\" width=\"487\" height=\"294\" \/><figcaption class=\"wp-caption-text\"><b>Figure 6<\/b><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">\n<div class=\"bcc-box bcc-success\">\n<p>Express [latex]z=3i[\/latex] as [latex]r\\text{cis}\\theta[\/latex] in polar form.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q364839\">Show Solution<\/button><\/p>\n<div id=\"q364839\" class=\"hidden-answer\" style=\"display: none\">\n<p>[latex]z=3\\left(\\cos \\left(\\frac{\\pi }{2}\\right)+i\\sin \\left(\\frac{\\pi }{2}\\right)\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the polar form of [latex]-4+4i[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q871564\">Show Solution<\/button><\/p>\n<div id=\"q871564\" class=\"hidden-answer\" style=\"display: none\">\n<p>First, find the value of [latex]r[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&r=\\sqrt{{x}^{2}+{y}^{2}} \\\\ &r=\\sqrt{{\\left(-4\\right)}^{2}+\\left({4}^{2}\\right)} \\\\ &r=\\sqrt{32} \\\\ &r=4\\sqrt{2} \\end{align}[\/latex]<\/p>\n<p>Find the angle [latex]\\theta[\/latex] using the formula:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&\\cos \\theta =\\frac{x}{r} \\\\ &\\cos \\theta =\\frac{-4}{4\\sqrt{2}} \\\\ &\\cos \\theta =-\\frac{1}{\\sqrt{2}} \\\\ &\\theta ={\\cos }^{-1}\\left(-\\frac{1}{\\sqrt{2}}\\right)=\\frac{3\\pi }{4} \\end{align}[\/latex]<\/p>\n<p>Thus, the solution is [latex]4\\sqrt{2}\\cos\\left(\\frac{3\\pi }{4}\\right)[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Write [latex]z=\\sqrt{3}+i[\/latex] in polar form.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q164997\">Show Solution<\/button><\/p>\n<div id=\"q164997\" class=\"hidden-answer\" style=\"display: none\">[latex]z=2\\left(\\cos \\left(\\frac{\\pi }{6}\\right)+i\\sin \\left(\\frac{\\pi }{6}\\right)\\right)[\/latex]<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" 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