{"id":2058,"date":"2025-08-01T20:41:57","date_gmt":"2025-08-01T20:41:57","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=2058"},"modified":"2025-10-17T21:08:38","modified_gmt":"2025-10-17T21:08:38","slug":"right-triangle-trigonometry-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/right-triangle-trigonometry-learn-it-4\/","title":{"raw":"Right Triangle Trigonometry: Learn It 4","rendered":"Right Triangle Trigonometry: Learn It 4"},"content":{"raw":"<h2>Using Trigonometric Functions<\/h2>\r\nIn previous examples, we evaluated the sine and cosine in triangles where we knew all three sides. But the real power of right-triangle trigonometry emerges when we look at triangles in which we know an angle but do not know all the sides.\r\n\r\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a right triangle, the length of one side, and the measure of one acute angle, find the remaining sides.<\/strong>\r\n<ol>\r\n \t<li>For each side, select the trigonometric function that has the unknown side as either the numerator or the denominator. The known side will in turn be the denominator or the numerator.<\/li>\r\n \t<li>Write an equation setting the function value of the known angle equal to the ratio of the corresponding sides.<\/li>\r\n \t<li>Using the value of the trigonometric function and the known side length, solve for the missing side length.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the unknown sides of the triangle.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27003813\/CNX_Precalc_Figure_05_04_0112.jpg\" alt=\"A right triangle with sides a, c, and 7. Angle of 30 degrees is also labeled.\" width=\"487\" height=\"250\" \/>[reveal-answer q=\"112724\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"112724\"]We know the angle and the opposite side, so we can use the tangent to find the adjacent side.\r\n<p style=\"text-align: center;\">[latex]\\tan \\left(30^\\circ \\right)=\\frac{7}{a}[\/latex]<\/p>\r\nWe rearrange to solve for [latex]a[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{align}a&amp;=\\frac{7}{\\tan \\left(30^\\circ \\right)} \\\\ &amp;=12.1\\end{align}[\/latex]<\/p>\r\nWe can use the sine to find the hypotenuse.\r\n<p style=\"text-align: center;\">[latex]\\sin \\left(30^\\circ \\right)=\\frac{7}{c}[\/latex]<\/p>\r\nAgain, we rearrange to solve for [latex]c[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{align}c&amp;=\\frac{7}{\\sin \\left(30^\\circ \\right)} \\\\ &amp;=14 \\end{align}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">\r\n<div class=\"bcc-box bcc-success\">\r\n\r\nA right triangle has one angle of [latex]\\frac{\\pi }{3}[\/latex]\u00a0and a hypotenuse of 20. Find the unknown sides and angle of the triangle.\r\n\r\n[reveal-answer q=\"869816\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"869816\"]\r\n\r\n[latex]\\text{adjacent}=10[\/latex]; [latex]\\text{opposite}=10\\sqrt{3}[\/latex] ; missing angle is [latex]\\frac{\\pi }{6}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1 height=\"800\"]121967[\/ohm_question]<\/section>","rendered":"<h2>Using Trigonometric Functions<\/h2>\n<p>In previous examples, we evaluated the sine and cosine in triangles where we knew all three sides. But the real power of right-triangle trigonometry emerges when we look at triangles in which we know an angle but do not know all the sides.<\/p>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a right triangle, the length of one side, and the measure of one acute angle, find the remaining sides.<\/strong><\/p>\n<ol>\n<li>For each side, select the trigonometric function that has the unknown side as either the numerator or the denominator. The known side will in turn be the denominator or the numerator.<\/li>\n<li>Write an equation setting the function value of the known angle equal to the ratio of the corresponding sides.<\/li>\n<li>Using the value of the trigonometric function and the known side length, solve for the missing side length.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the unknown sides of the triangle.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27003813\/CNX_Precalc_Figure_05_04_0112.jpg\" alt=\"A right triangle with sides a, c, and 7. Angle of 30 degrees is also labeled.\" width=\"487\" height=\"250\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q112724\">Show Solution<\/button><\/p>\n<div id=\"q112724\" class=\"hidden-answer\" style=\"display: none\">We know the angle and the opposite side, so we can use the tangent to find the adjacent side.<\/p>\n<p style=\"text-align: center;\">[latex]\\tan \\left(30^\\circ \\right)=\\frac{7}{a}[\/latex]<\/p>\n<p>We rearrange to solve for [latex]a[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}a&=\\frac{7}{\\tan \\left(30^\\circ \\right)} \\\\ &=12.1\\end{align}[\/latex]<\/p>\n<p>We can use the sine to find the hypotenuse.<\/p>\n<p style=\"text-align: center;\">[latex]\\sin \\left(30^\\circ \\right)=\\frac{7}{c}[\/latex]<\/p>\n<p>Again, we rearrange to solve for [latex]c[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}c&=\\frac{7}{\\sin \\left(30^\\circ \\right)} \\\\ &=14 \\end{align}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">\n<div class=\"bcc-box bcc-success\">\n<p>A right triangle has one angle of [latex]\\frac{\\pi }{3}[\/latex]\u00a0and a hypotenuse of 20. Find the unknown sides and angle of the triangle.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q869816\">Show Solution<\/button><\/p>\n<div id=\"q869816\" class=\"hidden-answer\" style=\"display: none\">\n<p>[latex]\\text{adjacent}=10[\/latex]; [latex]\\text{opposite}=10\\sqrt{3}[\/latex] ; missing angle is [latex]\\frac{\\pi }{6}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm121967\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=121967&theme=lumen&iframe_resize_id=ohm121967&source=tnh\" width=\"100%\" height=\"800\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":221,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2058"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":7,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2058\/revisions"}],"predecessor-version":[{"id":4730,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2058\/revisions\/4730"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/221"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/2058\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=2058"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=2058"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=2058"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=2058"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}