{"id":1924,"date":"2025-07-30T21:28:40","date_gmt":"2025-07-30T21:28:40","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1924"},"modified":"2025-08-13T16:52:34","modified_gmt":"2025-08-13T16:52:34","slug":"inverse-trigonometric-functions-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/inverse-trigonometric-functions-learn-it-2\/","title":{"raw":"Inverse Trigonometric Functions: Learn It 2","rendered":"Inverse Trigonometric Functions: Learn It 2"},"content":{"raw":"<h2>Finding the Exact Value of Expressions Involving the Inverse Sine, Cosine, and Tangent Functions<\/h2>\r\nNow that we can identify inverse functions, we will learn to evaluate them. For most values in their domains, we must evaluate the inverse trigonometric functions by using a calculator, interpolating from a table, or using some other numerical technique. Just as we did with the original trigonometric functions, we can give exact values for the inverse functions when we are using the special angles, specifically [latex]\\frac{\\pi}{ 6} (30^\\circ)\\text{, }\\frac{\\pi}{ 4} (45^\\circ),\\text{ and } \\frac{\\pi}{ 3} (60^\\circ)[\/latex], and their reflections into other quadrants.\r\n\r\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a \u201cspecial\u201d input value, evaluate an inverse trigonometric function.<\/strong>\r\n<ol>\r\n \t<li>Find angle\u00a0<em>x<\/em>\u00a0for which the original trigonometric function has an output equal to the given input for the inverse trigonometric function.<\/li>\r\n \t<li>If\u00a0<em>x<\/em>\u00a0is not in the defined range of the inverse, find another angle\u00a0<em>y<\/em>\u00a0that is in the defined range and has the same sine, cosine, or tangent as\u00a0<em>x<\/em>, depending on which corresponds to the given inverse function.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Evaluate each of the following.\r\n<p style=\"padding-left: 60px;\">a. [latex]\\sin\u22121\\left(\\frac{1}{2}\\right)[\/latex]<\/p>\r\n<p style=\"padding-left: 60px;\">b. [latex]\\sin\u22121\\left(\u2212\\frac{2}{\\sqrt{2}}\\right)[\/latex]<\/p>\r\n<p style=\"padding-left: 60px;\">c. [latex]\\cos\u22121\\left(\u2212\\frac{3}{\\sqrt{2}}\\right)[\/latex]<\/p>\r\n<p style=\"padding-left: 60px;\">d. [latex]\\tan^{\u2212 1}(1)[\/latex]<\/p>\r\n[reveal-answer q=\"666370\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"666370\"]\r\n<p style=\"padding-left: 60px;\">a. Evaluating [latex]\\sin^{\u22121}(\\frac{1}{2})[\/latex] is the same as determining the angle that would have a sine value of [latex]\\frac{1}{2}[\/latex]. In other words, what angle <em>x<\/em> would satisfy [latex]\\sin(x)=\\frac{1}{2}[\/latex]? There are multiple values that would satisfy this relationship, such as [latex]\\frac{\\pi}{6}[\/latex] and [latex]\\frac{5\\pi}{6}[\/latex], but we know we need the angle in the interval [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex], so the answer will be [latex]\\sin^{\u22121}(\\frac{1}{2})=\\frac{\\pi}{6}[\/latex]. Remember that the inverse is a function, so for each input, we will get exactly one output.<\/p>\r\n<p style=\"padding-left: 60px;\">b. To evaluate [latex]\\sin^{\u22121}\\left(\u2212\\frac{\\sqrt{2}}{2}\\right)[\/latex], we know that [latex]\\frac{5\\pi}{4}[\/latex] and [latex]\\frac{7\\pi}{4}[\/latex] both have a sine value of [latex]\u2212\\frac{\\sqrt{2}}{2}[\/latex], but neither is in the interval [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex]. For that, we need the negative angle coterminal with [latex]\\frac{7\\pi}{4}:\\sin^{\u22121}\\left(\u2212\\frac{\\sqrt{2}}{2}\\right)=\u2212\\frac{\\pi}{4}[\/latex].<\/p>\r\n<p style=\"padding-left: 60px;\">c. To evaluate [latex]\\cos^{\u22121}\\left(\u2212\\frac{\\sqrt{3}}{2}\\right)[\/latex], we are looking for an angle in the interval [0,\u03c0] with a cosine value of [latex]\u2212\\frac{\\sqrt{3}}{2}[\/latex]. The angle that satisfies this is [latex]\\cos^{\u22121}\\left(\u2212\\frac{\\sqrt{3}}{2}\\right)=\\frac{5\\pi}{6}[\/latex].<\/p>\r\n<p style=\"padding-left: 60px;\">d. Evaluating [latex]\\tan^{\u22121}(1)[\/latex], we are looking for an angle in the interval [latex](\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2})[\/latex] with a tangent value of 1. The correct angle is [latex]\\tan^{\u22121}(1)=\\frac{\\pi}{4}[\/latex].<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Evaluate each of the following.\r\n<ol>\r\n \t<li>[latex]\\sin^{\u22121}(\u22121)[\/latex]<\/li>\r\n \t<li>[latex]\\tan^{\u22121}(\u22121)[\/latex]<\/li>\r\n \t<li>[latex]\\cos^{\u22121}(\u22121)[\/latex]<\/li>\r\n \t<li>[latex]\\cos^{\u22121}(\\frac{1}{2})[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"333778\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"333778\"]\r\n\r\n1. [latex]\u2212\\frac{\\pi}{2}[\/latex];\r\n\r\n2. [latex]\u2212\\frac{\\pi}{4}[\/latex]\r\n\r\n3. [latex]\\pi[\/latex]\r\n\r\n4. [latex]\\frac{\\pi}{3}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]173433[\/ohm_question]<\/section>\r\n<h2>Using a Calculator to Evaluate Inverse Trigonometric Functions<\/h2>\r\nTo evaluate <strong>inverse trigonometric functions<\/strong> that do not involve the special angles discussed previously, we will need to use a calculator or other type of technology. Most scientific calculators and calculator-emulating applications have specific keys or buttons for the inverse sine, cosine, and tangent functions. These may be labeled, for example, SIN-1, ARCSIN, or ASIN.\r\n\r\nIn the previous chapter, we worked with trigonometry on a right triangle to solve for the sides of a triangle given one side and an additional angle. Using the inverse trigonometric functions, we can solve for the angles of a right triangle given two sides, and we can use a calculator to find the values to several decimal places.\r\n\r\nIn these examples and exercises, the answers will be interpreted as angles and we will use \u03b8 as the independent variable. The value displayed on the calculator may be in degrees or radians, so be sure to set the mode appropriate to the application.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">Evaluate [latex]\\sin^{\u22121}(0.97)[\/latex] using a calculator.[reveal-answer q=\"931769\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"931769\"]Because the output of the inverse function is an angle, the calculator will give us a degree value if in degree mode and a radian value if in radian mode. Calculators also use the same domain restrictions on the angles as we are using.\r\n\r\nIn radian mode, [latex]\\sin^{\u22121}(0.97)\\approx1.3252[\/latex]. In degree mode, [latex]\\sin^{\u22121}(0.97)\\approx75.93^{\\circ}[\/latex]. Note that in calculus and beyond we will use radians in almost all cases.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Evaluate [latex]\\cos^{\u22121}(\u22120.4)[\/latex] using a calculator.[reveal-answer q=\"728477\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"728477\"]1.9823 or 113.578\u00b0[\/hidden-answer]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]173435[\/ohm_question]<\/section><section aria-label=\"Try It\"><section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Find an angle given two sides of a right triangle.<\/strong><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164012\/CNX_Precalc_Figure_06_03_012.jpg\" alt=\"An illustration of a right triangle with an angle theta. Adjacent to theta is the side a, opposite theta is the side p, and the hypoteneuse is side h.\" width=\"487\" height=\"248\" \/>\r\n<ol>\r\n \t<li>If one given side is the hypotenuse of length h and the side of length a adjacent to the desired angle is given, use the equation [latex]\\theta=\\cos^{\u22121}\\left(\\frac{a}{h}\\right)[\/latex].<\/li>\r\n \t<li>If one given side is the hypotenuse of length <em>h<\/em> and the side of length <em>p<\/em> opposite to the desired angle is given, use the equation [latex]\\theta=\\sin^{\u22121}\\left(\\frac{p}{h}\\right)[\/latex].<\/li>\r\n \t<li>If the two legs (the sides adjacent to the right angle) are given, then use the equation [latex]\\theta=\\tan^{\u22121}\\left(\\frac{p}{a}\\right)[\/latex].<\/li>\r\n<\/ol>\r\n<\/section><\/section><section class=\"textbox example\" aria-label=\"Example\">Solve the triangle for the angle \u03b8.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164015\/CNX_Precalc_Figure_06_03_007.jpg\" alt=\"An illustration of a right triangle with the angle theta. Adjacent to the angle theta is a side with a length of 9 and a hypoteneuse of length 12.\" width=\"487\" height=\"200\" \/>[reveal-answer q=\"24088\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"24088\"]\r\n\r\nBecause we know the hypotenuse and the side adjacent to the angle, it makes sense for us to use the cosine function.\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;\\cos\\theta=\\frac{9}{12}\\\\ &amp;\\theta=\\cos^{\u22121}\\left(\\frac{9}{12}\\right) &amp;&amp; \\text{Apply definition of the inverse.} \\\\ &amp;\\theta\\approx0.7227\\text{ or about }41.4096^{\\circ} &amp;&amp; \\text{Evaluate.} \\end{align}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">Solve the triangle for the angle \u03b8.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164017\/CNX_Precalc_Figure_06_03_008.jpg\" alt=\"An illustration of a right triangle with the angle theta. Opposite to the angle theta is a side with a length of 6 and a hypoteneuse of length 10.\" width=\"487\" height=\"137\" \/>[reveal-answer q=\"230605\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"230605\"]\r\n\r\n[latex]\\sin^{\u22121}(0.6)=36.87^{\\circ}=0.6435[\/latex] radians\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]129737[\/ohm_question]<\/section>","rendered":"<h2>Finding the Exact Value of Expressions Involving the Inverse Sine, Cosine, and Tangent Functions<\/h2>\n<p>Now that we can identify inverse functions, we will learn to evaluate them. For most values in their domains, we must evaluate the inverse trigonometric functions by using a calculator, interpolating from a table, or using some other numerical technique. Just as we did with the original trigonometric functions, we can give exact values for the inverse functions when we are using the special angles, specifically [latex]\\frac{\\pi}{ 6} (30^\\circ)\\text{, }\\frac{\\pi}{ 4} (45^\\circ),\\text{ and } \\frac{\\pi}{ 3} (60^\\circ)[\/latex], and their reflections into other quadrants.<\/p>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a \u201cspecial\u201d input value, evaluate an inverse trigonometric function.<\/strong><\/p>\n<ol>\n<li>Find angle\u00a0<em>x<\/em>\u00a0for which the original trigonometric function has an output equal to the given input for the inverse trigonometric function.<\/li>\n<li>If\u00a0<em>x<\/em>\u00a0is not in the defined range of the inverse, find another angle\u00a0<em>y<\/em>\u00a0that is in the defined range and has the same sine, cosine, or tangent as\u00a0<em>x<\/em>, depending on which corresponds to the given inverse function.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Evaluate each of the following.<\/p>\n<p style=\"padding-left: 60px;\">a. [latex]\\sin\u22121\\left(\\frac{1}{2}\\right)[\/latex]<\/p>\n<p style=\"padding-left: 60px;\">b. [latex]\\sin\u22121\\left(\u2212\\frac{2}{\\sqrt{2}}\\right)[\/latex]<\/p>\n<p style=\"padding-left: 60px;\">c. [latex]\\cos\u22121\\left(\u2212\\frac{3}{\\sqrt{2}}\\right)[\/latex]<\/p>\n<p style=\"padding-left: 60px;\">d. [latex]\\tan^{\u2212 1}(1)[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q666370\">Show Solution<\/button><\/p>\n<div id=\"q666370\" class=\"hidden-answer\" style=\"display: none\">\n<p style=\"padding-left: 60px;\">a. Evaluating [latex]\\sin^{\u22121}(\\frac{1}{2})[\/latex] is the same as determining the angle that would have a sine value of [latex]\\frac{1}{2}[\/latex]. In other words, what angle <em>x<\/em> would satisfy [latex]\\sin(x)=\\frac{1}{2}[\/latex]? There are multiple values that would satisfy this relationship, such as [latex]\\frac{\\pi}{6}[\/latex] and [latex]\\frac{5\\pi}{6}[\/latex], but we know we need the angle in the interval [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex], so the answer will be [latex]\\sin^{\u22121}(\\frac{1}{2})=\\frac{\\pi}{6}[\/latex]. Remember that the inverse is a function, so for each input, we will get exactly one output.<\/p>\n<p style=\"padding-left: 60px;\">b. To evaluate [latex]\\sin^{\u22121}\\left(\u2212\\frac{\\sqrt{2}}{2}\\right)[\/latex], we know that [latex]\\frac{5\\pi}{4}[\/latex] and [latex]\\frac{7\\pi}{4}[\/latex] both have a sine value of [latex]\u2212\\frac{\\sqrt{2}}{2}[\/latex], but neither is in the interval [latex]\\left[\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2}\\right][\/latex]. For that, we need the negative angle coterminal with [latex]\\frac{7\\pi}{4}:\\sin^{\u22121}\\left(\u2212\\frac{\\sqrt{2}}{2}\\right)=\u2212\\frac{\\pi}{4}[\/latex].<\/p>\n<p style=\"padding-left: 60px;\">c. To evaluate [latex]\\cos^{\u22121}\\left(\u2212\\frac{\\sqrt{3}}{2}\\right)[\/latex], we are looking for an angle in the interval [0,\u03c0] with a cosine value of [latex]\u2212\\frac{\\sqrt{3}}{2}[\/latex]. The angle that satisfies this is [latex]\\cos^{\u22121}\\left(\u2212\\frac{\\sqrt{3}}{2}\\right)=\\frac{5\\pi}{6}[\/latex].<\/p>\n<p style=\"padding-left: 60px;\">d. Evaluating [latex]\\tan^{\u22121}(1)[\/latex], we are looking for an angle in the interval [latex](\u2212\\frac{\\pi}{2}\\text{, }\\frac{\\pi}{2})[\/latex] with a tangent value of 1. The correct angle is [latex]\\tan^{\u22121}(1)=\\frac{\\pi}{4}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Evaluate each of the following.<\/p>\n<ol>\n<li>[latex]\\sin^{\u22121}(\u22121)[\/latex]<\/li>\n<li>[latex]\\tan^{\u22121}(\u22121)[\/latex]<\/li>\n<li>[latex]\\cos^{\u22121}(\u22121)[\/latex]<\/li>\n<li>[latex]\\cos^{\u22121}(\\frac{1}{2})[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q333778\">Show Solution<\/button><\/p>\n<div id=\"q333778\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. [latex]\u2212\\frac{\\pi}{2}[\/latex];<\/p>\n<p>2. [latex]\u2212\\frac{\\pi}{4}[\/latex]<\/p>\n<p>3. [latex]\\pi[\/latex]<\/p>\n<p>4. [latex]\\frac{\\pi}{3}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm173433\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=173433&theme=lumen&iframe_resize_id=ohm173433&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<h2>Using a Calculator to Evaluate Inverse Trigonometric Functions<\/h2>\n<p>To evaluate <strong>inverse trigonometric functions<\/strong> that do not involve the special angles discussed previously, we will need to use a calculator or other type of technology. Most scientific calculators and calculator-emulating applications have specific keys or buttons for the inverse sine, cosine, and tangent functions. These may be labeled, for example, SIN-1, ARCSIN, or ASIN.<\/p>\n<p>In the previous chapter, we worked with trigonometry on a right triangle to solve for the sides of a triangle given one side and an additional angle. Using the inverse trigonometric functions, we can solve for the angles of a right triangle given two sides, and we can use a calculator to find the values to several decimal places.<\/p>\n<p>In these examples and exercises, the answers will be interpreted as angles and we will use \u03b8 as the independent variable. The value displayed on the calculator may be in degrees or radians, so be sure to set the mode appropriate to the application.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">Evaluate [latex]\\sin^{\u22121}(0.97)[\/latex] using a calculator.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q931769\">Show Solution<\/button><\/p>\n<div id=\"q931769\" class=\"hidden-answer\" style=\"display: none\">Because the output of the inverse function is an angle, the calculator will give us a degree value if in degree mode and a radian value if in radian mode. Calculators also use the same domain restrictions on the angles as we are using.<\/p>\n<p>In radian mode, [latex]\\sin^{\u22121}(0.97)\\approx1.3252[\/latex]. In degree mode, [latex]\\sin^{\u22121}(0.97)\\approx75.93^{\\circ}[\/latex]. Note that in calculus and beyond we will use radians in almost all cases.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Evaluate [latex]\\cos^{\u22121}(\u22120.4)[\/latex] using a calculator.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q728477\">Show Solution<\/button><\/p>\n<div id=\"q728477\" class=\"hidden-answer\" style=\"display: none\">1.9823 or 113.578\u00b0<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm173435\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=173435&theme=lumen&iframe_resize_id=ohm173435&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section aria-label=\"Try It\">\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Find an angle given two sides of a right triangle.<\/strong><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164012\/CNX_Precalc_Figure_06_03_012.jpg\" alt=\"An illustration of a right triangle with an angle theta. Adjacent to theta is the side a, opposite theta is the side p, and the hypoteneuse is side h.\" width=\"487\" height=\"248\" \/><\/p>\n<ol>\n<li>If one given side is the hypotenuse of length h and the side of length a adjacent to the desired angle is given, use the equation [latex]\\theta=\\cos^{\u22121}\\left(\\frac{a}{h}\\right)[\/latex].<\/li>\n<li>If one given side is the hypotenuse of length <em>h<\/em> and the side of length <em>p<\/em> opposite to the desired angle is given, use the equation [latex]\\theta=\\sin^{\u22121}\\left(\\frac{p}{h}\\right)[\/latex].<\/li>\n<li>If the two legs (the sides adjacent to the right angle) are given, then use the equation [latex]\\theta=\\tan^{\u22121}\\left(\\frac{p}{a}\\right)[\/latex].<\/li>\n<\/ol>\n<\/section>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Solve the triangle for the angle \u03b8.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164015\/CNX_Precalc_Figure_06_03_007.jpg\" alt=\"An illustration of a right triangle with the angle theta. Adjacent to the angle theta is a side with a length of 9 and a hypoteneuse of length 12.\" width=\"487\" height=\"200\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q24088\">Show Solution<\/button><\/p>\n<div id=\"q24088\" class=\"hidden-answer\" style=\"display: none\">\n<p>Because we know the hypotenuse and the side adjacent to the angle, it makes sense for us to use the cosine function.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&\\cos\\theta=\\frac{9}{12}\\\\ &\\theta=\\cos^{\u22121}\\left(\\frac{9}{12}\\right) && \\text{Apply definition of the inverse.} \\\\ &\\theta\\approx0.7227\\text{ or about }41.4096^{\\circ} && \\text{Evaluate.} \\end{align}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">Solve the triangle for the angle \u03b8.<img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3675\/2018\/09\/27164017\/CNX_Precalc_Figure_06_03_008.jpg\" alt=\"An illustration of a right triangle with the angle theta. Opposite to the angle theta is a side with a length of 6 and a hypoteneuse of length 10.\" width=\"487\" height=\"137\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q230605\">Show Solution<\/button><\/p>\n<div id=\"q230605\" class=\"hidden-answer\" style=\"display: none\">\n<p>[latex]\\sin^{\u22121}(0.6)=36.87^{\\circ}=0.6435[\/latex] radians<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm129737\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=129737&theme=lumen&iframe_resize_id=ohm129737&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":12,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":221,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1924"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":5,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1924\/revisions"}],"predecessor-version":[{"id":2468,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1924\/revisions\/2468"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/221"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1924\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1924"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1924"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1924"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1924"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}