{"id":1750,"date":"2025-07-28T19:01:52","date_gmt":"2025-07-28T19:01:52","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1750"},"modified":"2026-03-26T16:55:38","modified_gmt":"2026-03-26T16:55:38","slug":"counting-principles-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/counting-principles-learn-it-3\/","title":{"raw":"Counting Principles: Learn It 3","rendered":"Counting Principles: Learn It 3"},"content":{"raw":"<h2>Finding the Number of Permutations of [latex]n[\/latex] Non-Distinct Objects<\/h2>\r\nWe have studied permutations where all of the objects involved were distinct. What happens if some of the objects are indistinguishable?\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">For example, suppose there is a sheet of [latex]12[\/latex] stickers. If all of the stickers were distinct, there would be [latex]12![\/latex] ways to order the stickers.\r\n[latex]\\\\[\/latex]\r\nHowever, [latex]4[\/latex] of the stickers are identical stars, and [latex]3[\/latex] are identical moons. Because all of the objects are not distinct, many of the [latex]12![\/latex] permutations we counted are duplicates.\r\n[latex]\\\\[\/latex]\r\nThis means we need to divide by the number of ways to order the [latex]4[\/latex] stars and the ways to order the [latex]3[\/latex] moons to find the number of unique permutations of the stickers. There are [latex]4![\/latex] ways to order the stars and [latex]3![\/latex] ways to order the moon.\r\n<p style=\"text-align: center;\">[latex]\\dfrac{12!}{4!3!}=3\\text{,}326\\text{,}400[\/latex]<\/p>\r\nThere are [latex]3,326,400[\/latex] ways to order the sheet of stickers.\r\n\r\n<\/section><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>formula for finding the number of permutations of [latex]n[\/latex] non-distinct objects<\/h3>\r\nIf there are [latex]n[\/latex] elements in a set and [latex]{r}_{1}[\/latex] are alike, [latex]{r}_{2}[\/latex] are alike, [latex]{r}_{3}[\/latex] are alike, and so on through [latex]{r}_{k}[\/latex], the number of permutations can be found by\r\n<p style=\"text-align: center;\">[latex]\\dfrac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/p>\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the number of rearrangements of the letters in the word DISTINCT.[reveal-answer q=\"162138\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"162138\"]\r\n<ul>\r\n \t<li>There are [latex]8[\/latex] letters.<\/li>\r\n \t<li>Both I and T are repeated [latex]2[\/latex] times.<\/li>\r\n<\/ul>\r\nSubstitute [latex]n=8, {r}_{1}=2, [\/latex] and [latex] {r}_{2}=2 [\/latex] into the formula:\r\n<p style=\"text-align: center;\">[latex]\\dfrac{8!}{2!2!}=10\\text{,}080 [\/latex]<\/p>\r\nThere are [latex]10,080[\/latex] arrangements.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321992[\/ohm_question]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321993[\/ohm_question]<\/section>","rendered":"<h2>Finding the Number of Permutations of [latex]n[\/latex] Non-Distinct Objects<\/h2>\n<p>We have studied permutations where all of the objects involved were distinct. What happens if some of the objects are indistinguishable?<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">For example, suppose there is a sheet of [latex]12[\/latex] stickers. If all of the stickers were distinct, there would be [latex]12![\/latex] ways to order the stickers.<br \/>\n[latex]\\\\[\/latex]<br \/>\nHowever, [latex]4[\/latex] of the stickers are identical stars, and [latex]3[\/latex] are identical moons. Because all of the objects are not distinct, many of the [latex]12![\/latex] permutations we counted are duplicates.<br \/>\n[latex]\\\\[\/latex]<br \/>\nThis means we need to divide by the number of ways to order the [latex]4[\/latex] stars and the ways to order the [latex]3[\/latex] moons to find the number of unique permutations of the stickers. There are [latex]4![\/latex] ways to order the stars and [latex]3![\/latex] ways to order the moon.<\/p>\n<p style=\"text-align: center;\">[latex]\\dfrac{12!}{4!3!}=3\\text{,}326\\text{,}400[\/latex]<\/p>\n<p>There are [latex]3,326,400[\/latex] ways to order the sheet of stickers.<\/p>\n<\/section>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>formula for finding the number of permutations of [latex]n[\/latex] non-distinct objects<\/h3>\n<p>If there are [latex]n[\/latex] elements in a set and [latex]{r}_{1}[\/latex] are alike, [latex]{r}_{2}[\/latex] are alike, [latex]{r}_{3}[\/latex] are alike, and so on through [latex]{r}_{k}[\/latex], the number of permutations can be found by<\/p>\n<p style=\"text-align: center;\">[latex]\\dfrac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the number of rearrangements of the letters in the word DISTINCT.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q162138\">Show Solution<\/button><\/p>\n<div id=\"q162138\" class=\"hidden-answer\" style=\"display: none\">\n<ul>\n<li>There are [latex]8[\/latex] letters.<\/li>\n<li>Both I and T are repeated [latex]2[\/latex] times.<\/li>\n<\/ul>\n<p>Substitute [latex]n=8, {r}_{1}=2,[\/latex] and [latex]{r}_{2}=2[\/latex] into the formula:<\/p>\n<p style=\"text-align: center;\">[latex]\\dfrac{8!}{2!2!}=10\\text{,}080[\/latex]<\/p>\n<p>There are [latex]10,080[\/latex] arrangements.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321992\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321992&theme=lumen&iframe_resize_id=ohm321992&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321993\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321993&theme=lumen&iframe_resize_id=ohm321993&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":513,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1750"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":5,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1750\/revisions"}],"predecessor-version":[{"id":6047,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1750\/revisions\/6047"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/513"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1750\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1750"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1750"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1750"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1750"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}