{"id":1748,"date":"2025-07-28T19:01:56","date_gmt":"2025-07-28T19:01:56","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1748"},"modified":"2026-03-26T17:03:30","modified_gmt":"2026-03-26T17:03:30","slug":"counting-principles-learn-it-5","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/counting-principles-learn-it-5\/","title":{"raw":"Counting Principles: Learn It 5","rendered":"Counting Principles: Learn It 5"},"content":{"raw":"<h2>Finding the Number of Subsets of a Set<\/h2>\r\nWe have looked only at combination problems in which we chose exactly objects. In some problems, we want to consider choosing every possible number of objects.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">\r\n<div class=\"page\" title=\"Page 1127\">\r\n<div class=\"layoutArea\">\r\n<div class=\"column\">\r\n\r\nA pizza restaurant that offers [latex]5[\/latex] toppings. Any number of toppings can be ordered. How many different pizzas are possible?\r\n\r\nTo answer this question, we need to consider pizzas with any number of toppings.\r\n<ul>\r\n \t<li>There is [latex]C\\left(5,0\\right)=1[\/latex] way to order a pizza with no toppings.<\/li>\r\n \t<li>There are [latex]C\\left(5,1\\right)=5[\/latex] ways to order a pizza with exactly one topping.<\/li>\r\n \t<li>If we continue this process, we get:<\/li>\r\n<\/ul>\r\n<p style=\"text-align: center;\">[latex]C\\left(5,0\\right)+C\\left(5,1\\right)+C\\left(5,2\\right)+C\\left(5,3\\right)+C\\left(5,4\\right)+C\\left(5,5\\right)=32[\/latex]<\/p>\r\nThere are [latex]32[\/latex] possible pizzas.\r\n\r\nThis result [latex]32[\/latex] is equal to [latex]{2}^{5}[\/latex] possible pizzas, which offers [latex]5[\/latex] toppings. Coincidence? Definitely not!\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/section><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>formula for the number of subsets of a set<\/h3>\r\nA set containing [latex]n[\/latex] distinct objects has [latex]{2}^{n}[\/latex] subsets.\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">A restaurant offers butter, cheese, chives, and sour cream as toppings for a baked potato. How many different ways are there to order a potato?[reveal-answer q=\"961255\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"961255\"]We are looking for the number of subsets of a set with [latex]4[\/latex] objects. Substitute [latex]n=4[\/latex] into the formula.\r\n<p style=\"text-align: center;\">[latex]{2}^{n}={2}^{4} =16[\/latex]<\/p>\r\nThere are [latex]16[\/latex] possible ways to order a potato.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321997[\/ohm_question]<\/section>","rendered":"<h2>Finding the Number of Subsets of a Set<\/h2>\n<p>We have looked only at combination problems in which we chose exactly objects. In some problems, we want to consider choosing every possible number of objects.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">\n<div class=\"page\" title=\"Page 1127\">\n<div class=\"layoutArea\">\n<div class=\"column\">\n<p>A pizza restaurant that offers [latex]5[\/latex] toppings. Any number of toppings can be ordered. How many different pizzas are possible?<\/p>\n<p>To answer this question, we need to consider pizzas with any number of toppings.<\/p>\n<ul>\n<li>There is [latex]C\\left(5,0\\right)=1[\/latex] way to order a pizza with no toppings.<\/li>\n<li>There are [latex]C\\left(5,1\\right)=5[\/latex] ways to order a pizza with exactly one topping.<\/li>\n<li>If we continue this process, we get:<\/li>\n<\/ul>\n<p style=\"text-align: center;\">[latex]C\\left(5,0\\right)+C\\left(5,1\\right)+C\\left(5,2\\right)+C\\left(5,3\\right)+C\\left(5,4\\right)+C\\left(5,5\\right)=32[\/latex]<\/p>\n<p>There are [latex]32[\/latex] possible pizzas.<\/p>\n<p>This result [latex]32[\/latex] is equal to [latex]{2}^{5}[\/latex] possible pizzas, which offers [latex]5[\/latex] toppings. Coincidence? Definitely not!<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>formula for the number of subsets of a set<\/h3>\n<p>A set containing [latex]n[\/latex] distinct objects has [latex]{2}^{n}[\/latex] subsets.<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">A restaurant offers butter, cheese, chives, and sour cream as toppings for a baked potato. How many different ways are there to order a potato?<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q961255\">Show Solution<\/button><\/p>\n<div id=\"q961255\" class=\"hidden-answer\" style=\"display: none\">We are looking for the number of subsets of a set with [latex]4[\/latex] objects. Substitute [latex]n=4[\/latex] into the formula.<\/p>\n<p style=\"text-align: center;\">[latex]{2}^{n}={2}^{4} =16[\/latex]<\/p>\n<p>There are [latex]16[\/latex] possible ways to order a potato.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321997\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321997&theme=lumen&iframe_resize_id=ohm321997&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":10,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":513,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1748"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":3,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1748\/revisions"}],"predecessor-version":[{"id":6050,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1748\/revisions\/6050"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/513"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1748\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1748"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1748"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1748"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1748"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}