{"id":1679,"date":"2025-07-25T19:11:58","date_gmt":"2025-07-25T19:11:58","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1679"},"modified":"2026-03-25T21:45:17","modified_gmt":"2026-03-25T21:45:17","slug":"arithmetic-sequences-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/arithmetic-sequences-learn-it-2\/","title":{"raw":"Arithmetic Sequences: Learn It 2","rendered":"Arithmetic Sequences: Learn It 2"},"content":{"raw":"<h2>Writing Terms of Arithmetic Sequences<\/h2>\r\nPreviously, we found a formula for the general term of a sequence, we can also find a formula for the general term of an arithmetic sequence.\r\n\r\nLet\u2019s write the first few terms of a sequence where the first term is [latex]a_1[\/latex] and the common difference [latex]d[\/latex]. We will then look for a pattern.\r\n\r\n<img class=\"aligncenter wp-image-4980\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-300x94.png\" alt=\"A diagram showing how terms in an arithmetic sequence are built from the first term a1 and the common difference d. The second term a2 is written as a1 plus d. The third term a3 is written as a1 plus 2d. The fourth term a4 is written as a1 plus 3d. The fifth term a5 is written as a1 plus 4d. Arrows point from each term to its expanded form, showing that each new term adds one more d than the term before it.\" width=\"527\" height=\"165\" \/>\r\n\r\nDid you notice that t<span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">he number of [latex]d[\/latex]s that were added to [latex]a_1[\/latex] is one less than the number of the term?<\/span>\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>general term (nth term) of an arithmetic sequence<\/h3>\r\nThe general term of an arithmetic sequence with first term [latex]a_1[\/latex] <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">and the common difference [latex]d[\/latex] is\u00a0<\/span>\r\n<p style=\"text-align: center;\">[latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex]<\/p>\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Write the first five terms of the <strong>arithmetic sequence<\/strong> with [latex]{a}_{1}=17[\/latex] and [latex]d=-3[\/latex].\r\n\r\n[reveal-answer q=\"654025\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"654025\"]\r\n\r\nAdding [latex]-3[\/latex] is the same as subtracting [latex]3[\/latex]. Beginning with the first term, subtract [latex]3[\/latex] from each term to find the next term.The first five terms are [latex]\\left\\{17,14,11,8,5\\right\\}[\/latex]<img class=\"alignright\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/03222146\/CNX_Precalc_Figure_11_02_0042.jpg\" alt=\"Graph of the arithmetic sequence. The points form a negative line.\" width=\"300\" height=\"154\" \/><strong>\r\n\r\nAnalysis of the Solution\r\n\r\n<\/strong>As expected, the graph of the sequence consists of points on a line.[\/hidden-answer]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321960[\/ohm_question]<\/section><section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given any the first term and any other term in an arithmetic sequence, find a given term.<\/strong>\r\n<ol>\r\n \t<li>Substitute the values given for [latex]{a}_{1},{a}_{n},n[\/latex] into the formula [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex] to solve for [latex]d[\/latex].<\/li>\r\n \t<li>Find a given term by substituting the appropriate values for [latex]{a}_{1},n[\/latex], and [latex]d[\/latex] into the formula [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex].<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Given [latex]{a}_{1}=8[\/latex] and [latex]{a}_{4}=14[\/latex] , find [latex]{a}_{5}[\/latex] .[reveal-answer q=\"644479\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"644479\"]The sequence can be written in terms of the initial term [latex]8[\/latex] and the common difference [latex]d[\/latex] .\r\n<p style=\"text-align: center;\">[latex]\\left\\{8,8+d,8+2d,8+3d\\right\\}[\/latex]<\/p>\r\nWe know the fourth term equals [latex]14[\/latex]; we know the fourth term has the form [latex]{a}_{1}+3d=8+3d[\/latex] .\r\n\r\nWe can find the common difference [latex]d[\/latex] .\r\n<p style=\"text-align: center;\">[latex]\\begin{align}&amp;{a}_{n}={a}_{1}+\\left(n - 1\\right)d \\\\ &amp;{a}_{4}={a}_{1}+3d \\\\ &amp;{a}_{4}=8+3d &amp;&amp; \\text{Write the fourth term of the sequence in terms of } {a}_{1} \\text{ and } d. \\\\ &amp;14=8+3d &amp;&amp; \\text{Substitute } 14 \\text{ for } {a}_{4}. \\\\ &amp;d=2 &amp;&amp; \\text{Solve for the common difference}. \\end{align}[\/latex]<\/p>\r\nFind the fifth term by adding the common difference to the fourth term.\r\n<p style=\"text-align: center;\">[latex]{a}_{5}={a}_{4}+2=16[\/latex]<\/p>\r\n<strong>Analysis of the Solution<\/strong>\r\n\r\nNotice that the common difference is added to the first term once to find the second term, twice to find the third term, three times to find the fourth term, and so on. The tenth term could be found by adding the common difference to the first term nine times or by using the equation [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321961[\/ohm_question]<\/section>","rendered":"<h2>Writing Terms of Arithmetic Sequences<\/h2>\n<p>Previously, we found a formula for the general term of a sequence, we can also find a formula for the general term of an arithmetic sequence.<\/p>\n<p>Let\u2019s write the first few terms of a sequence where the first term is [latex]a_1[\/latex] and the common difference [latex]d[\/latex]. We will then look for a pattern.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-4980\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-300x94.png\" alt=\"A diagram showing how terms in an arithmetic sequence are built from the first term a1 and the common difference d. The second term a2 is written as a1 plus d. The third term a3 is written as a1 plus 2d. The fourth term a4 is written as a1 plus 3d. The fifth term a5 is written as a1 plus 4d. Arrows point from each term to its expanded form, showing that each new term adds one more d than the term before it.\" width=\"527\" height=\"165\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-300x94.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-768x241.png 768w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-65x20.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-225x71.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram-350x110.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/02235939\/11.2.L2.Diagram.png 836w\" sizes=\"(max-width: 527px) 100vw, 527px\" \/><\/p>\n<p>Did you notice that t<span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">he number of [latex]d[\/latex]s that were added to [latex]a_1[\/latex] is one less than the number of the term?<\/span><\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>general term (nth term) of an arithmetic sequence<\/h3>\n<p>The general term of an arithmetic sequence with first term [latex]a_1[\/latex] <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">and the common difference [latex]d[\/latex] is\u00a0<\/span><\/p>\n<p style=\"text-align: center;\">[latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex]<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Write the first five terms of the <strong>arithmetic sequence<\/strong> with [latex]{a}_{1}=17[\/latex] and [latex]d=-3[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q654025\">Show Solution<\/button><\/p>\n<div id=\"q654025\" class=\"hidden-answer\" style=\"display: none\">\n<p>Adding [latex]-3[\/latex] is the same as subtracting [latex]3[\/latex]. Beginning with the first term, subtract [latex]3[\/latex] from each term to find the next term.The first five terms are [latex]\\left\\{17,14,11,8,5\\right\\}[\/latex]<img loading=\"lazy\" decoding=\"async\" class=\"alignright\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/03222146\/CNX_Precalc_Figure_11_02_0042.jpg\" alt=\"Graph of the arithmetic sequence. The points form a negative line.\" width=\"300\" height=\"154\" \/><strong><\/p>\n<p>Analysis of the Solution<\/p>\n<p><\/strong>As expected, the graph of the sequence consists of points on a line.<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321960\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321960&theme=lumen&iframe_resize_id=ohm321960&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given any the first term and any other term in an arithmetic sequence, find a given term.<\/strong><\/p>\n<ol>\n<li>Substitute the values given for [latex]{a}_{1},{a}_{n},n[\/latex] into the formula [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex] to solve for [latex]d[\/latex].<\/li>\n<li>Find a given term by substituting the appropriate values for [latex]{a}_{1},n[\/latex], and [latex]d[\/latex] into the formula [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex].<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Given [latex]{a}_{1}=8[\/latex] and [latex]{a}_{4}=14[\/latex] , find [latex]{a}_{5}[\/latex] .<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q644479\">Show Solution<\/button><\/p>\n<div id=\"q644479\" class=\"hidden-answer\" style=\"display: none\">The sequence can be written in terms of the initial term [latex]8[\/latex] and the common difference [latex]d[\/latex] .<\/p>\n<p style=\"text-align: center;\">[latex]\\left\\{8,8+d,8+2d,8+3d\\right\\}[\/latex]<\/p>\n<p>We know the fourth term equals [latex]14[\/latex]; we know the fourth term has the form [latex]{a}_{1}+3d=8+3d[\/latex] .<\/p>\n<p>We can find the common difference [latex]d[\/latex] .<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}&{a}_{n}={a}_{1}+\\left(n - 1\\right)d \\\\ &{a}_{4}={a}_{1}+3d \\\\ &{a}_{4}=8+3d && \\text{Write the fourth term of the sequence in terms of } {a}_{1} \\text{ and } d. \\\\ &14=8+3d && \\text{Substitute } 14 \\text{ for } {a}_{4}. \\\\ &d=2 && \\text{Solve for the common difference}. \\end{align}[\/latex]<\/p>\n<p>Find the fifth term by adding the common difference to the fourth term.<\/p>\n<p style=\"text-align: center;\">[latex]{a}_{5}={a}_{4}+2=16[\/latex]<\/p>\n<p><strong>Analysis of the Solution<\/strong><\/p>\n<p>Notice that the common difference is added to the first term once to find the second term, twice to find the third term, three times to find the fourth term, and so on. The tenth term could be found by adding the common difference to the first term nine times or by using the equation [latex]{a}_{n}={a}_{1}+\\left(n - 1\\right)d[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321961\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321961&theme=lumen&iframe_resize_id=ohm321961&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":9,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":156,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1679"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":11,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1679\/revisions"}],"predecessor-version":[{"id":6026,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1679\/revisions\/6026"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/156"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1679\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1679"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1679"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1679"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1679"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}