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{"id":1587,"date":"2025-07-25T03:58:19","date_gmt":"2025-07-25T03:58:19","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1587"},"modified":"2026-03-25T04:13:23","modified_gmt":"2026-03-25T04:13:23","slug":"operations-with-vectors-fresh-take","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/operations-with-vectors-fresh-take\/","title":{"raw":"Operations with Vectors: Fresh Take","rendered":"Operations with Vectors: Fresh Take"},"content":{"raw":"<section class=\"textbox learningGoals\" aria-label=\"Learning Goals\">\r\n<ul>\r\n \t<li>Perform vector addition and scalar multiplication.<\/li>\r\n \t<li>Perform operations with vectors in terms of i and j .<\/li>\r\n \t<li>Find the dot product of two vectors.<\/li>\r\n<\/ul>\r\n<\/section>\r\n<h2>Combining Vectors<\/h2>\r\n<div class=\"textbox shaded\">\r\n\r\n<strong>The Main Idea\u00a0<\/strong>\r\n<p class=\"whitespace-normal break-words\">Vectors show up constantly in real life\u2014think about a boat crossing a river (engine pushing one way, current pushing another) or a quarterback throwing a football (force and angle combined). To solve these problems, you need to know how to combine vectors.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Scalar Multiplication: Stretching and Flipping<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">When you multiply a vector [latex]\\mathbf{v}[\/latex] by a scalar [latex]k[\/latex], you change its length and possibly its direction:<\/p>\r\n\r\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\"><strong>If [latex]k &gt; 0[\/latex]<\/strong>: The vector stretches or shrinks but keeps the same direction. For example, [latex]2\\mathbf{v}[\/latex] doubles the length; [latex]0.5\\mathbf{v}[\/latex] halves it.<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>If [latex]k &lt; 0[\/latex]<\/strong>: The vector flips to point the opposite direction. For instance, [latex]-\\mathbf{v}[\/latex] has the same length as [latex]\\mathbf{v}[\/latex] but points the other way.<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>If [latex]k = 0[\/latex]<\/strong>: You get the zero vector [latex]\\mathbf{0}[\/latex].<\/li>\r\n<\/ul>\r\n<p class=\"whitespace-normal break-words\"><strong>Vector Addition: Two Methods, Same Result<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">To add vectors [latex]\\mathbf{v} + \\mathbf{w}[\/latex], use either approach:<\/p>\r\n\r\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\"><strong>Triangle Method<\/strong>: Place the starting point of [latex]\\mathbf{w}[\/latex] at the endpoint of [latex]\\mathbf{v}[\/latex]. The sum runs from [latex]\\mathbf{v}[\/latex]'s start to [latex]\\mathbf{w}[\/latex]'s end. Think of it like walking from A to B, then B to C\u2014your total displacement goes directly from A to C.<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Parallelogram Method<\/strong>: Start both vectors at the same point and complete the parallelogram. The diagonal is your sum.<\/li>\r\n<\/ul>\r\n<p class=\"whitespace-normal break-words\">Order doesn't matter: [latex]\\mathbf{v} + \\mathbf{w} = \\mathbf{w} + \\mathbf{v}[\/latex] (commutative property).<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Triangle Inequality<\/strong>: The sum's length satisfies [latex]||\\mathbf{v} + \\mathbf{w}|| \\leq ||\\mathbf{v}|| + ||\\mathbf{w}||[\/latex]. Equality only happens when vectors point the same direction.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Vector Subtraction: Adding the Opposite<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">For [latex]\\mathbf{v} - \\mathbf{w}[\/latex], rewrite it as [latex]\\mathbf{v} + (-\\mathbf{w})[\/latex]. Graphically, the difference points from [latex]\\mathbf{w}[\/latex]'s endpoint to [latex]\\mathbf{v}[\/latex]'s endpoint.<\/p>\r\n\r\n<\/div>\r\n<section class=\"textbox example\" aria-label=\"Example\">Using vectors [latex]\\bf{w}[\/latex] and [latex]\\bf{w}[\/latex] from Example: Combining Vectors, sketch the vector [latex]\\bf{2w - v}[\/latex].\r\n<div id=\"fs-id1167793940239\" class=\"exercise\">[reveal-answer q=\"fs-id1167793933124\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1167793933124\"][caption id=\"attachment_3477\" align=\"aligncenter\" width=\"270\"]<img class=\"size-full wp-image-3477\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/28191840\/2-1-tryitans2.jpeg\" alt=\"This figure has two vectors. They are vector v and vector w. They are not connected.\" width=\"270\" height=\"271\" \/> The graph of the combined vector [latex]\\bf{2w - v}[\/latex].[\/caption][\/hidden-answer]<\/div>\r\n<\/section><section class=\"textbox watchIt\" aria-label=\"Watch It\">Watch the following video to see the worked solution to the above example.\r\n<script type=\"text\/javascript\" src=\"https:\/\/www.youtube.com\/iframe_api \"><\/script>\r\n<p class=\"cc-media-iframe-container\"><iframe id=\"tpm-plugin-ddebedgh-0MXVlIKjB4Q\" class=\"cc-media-iframe\" src=\"https:\/\/www.youtube.com\/embed\/0MXVlIKjB4Q?enablejsapi=1 \" frameborder=\"0\" data-mce-fragment=\"1\"><\/iframe><\/p>\r\n<p class=\"cc-media-iframe-container\"><script type='text\/javascript' src='\/\/plugin.3playmedia.com\/ajax.js?cc=1&cc_minimizable=1&cc_minimize_on_load=0&cc_multi_text_track=0&cc_overlay=1&cc_searchable=0&embed=ajax&mf=7699685&p3sdk_version=1.11.7&p=20361&player_type=youtube&plugin_skin=dark&target=3p-plugin-target-ddebedgh-0MXVlIKjB4Q&vembed=0&video_id=0MXVlIKjB4Q&video_target=tpm-plugin-ddebedgh-0MXVlIKjB4Q'><\/script><\/p>\r\nYou can view the\u00a0<a href=\"https:\/\/course-building.s3.us-west-2.amazonaws.com\/Precalculus\/Transcripts\/CP+2.2_transcript.txt\" target=\"_blank\" rel=\"noopener\">transcript for \u201cCP 2.2\u201d here (opens in new window).<\/a>\r\n\r\n<\/section>\r\n<h2>The Dot Product<\/h2>\r\n<div class=\"textbox shaded\">\r\n\r\n<strong>The Main Idea\u00a0<\/strong>\r\n<p class=\"whitespace-normal break-words\">The <strong>dot product<\/strong> is a way to \"multiply\" two vectors, but the result is a scalar (a number), not another vector. It measures how much two vectors align with each other and is essential for calculating work, finding angles between vectors, and determining if vectors are perpendicular.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Calculating the Dot Product<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">For vectors [latex]\\mathbf{u} = \\langle u_1, u_2, u_3 \\rangle[\/latex] and [latex]\\mathbf{v} = \\langle v_1, v_2, v_3 \\rangle[\/latex]:<\/p>\r\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\mathbf{u} \\cdot \\mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Process<\/strong>: Multiply corresponding components, then add the results.<\/p>\r\n<p class=\"whitespace-normal break-words\">For 2D vectors [latex]\\mathbf{u} = \\langle u_1, u_2 \\rangle[\/latex] and [latex]\\mathbf{v} = \\langle v_1, v_2 \\rangle[\/latex], it's the same: [latex]\\mathbf{u} \\cdot \\mathbf{v} = u_1v_1 + u_2v_2[\/latex].<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Example<\/strong>: [latex]\\langle 3, 5, 2 \\rangle \\cdot \\langle -1, 3, 0 \\rangle = (3)(-1) + (5)(3) + (2)(0) = -3 + 15 + 0 = 12[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Key Properties<\/strong><\/p>\r\n\r\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\"><strong>Commutative<\/strong>: [latex]\\mathbf{u} \\cdot \\mathbf{v} = \\mathbf{v} \\cdot \\mathbf{u}[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Distributive<\/strong>: [latex]\\mathbf{u} \\cdot (\\mathbf{v} + \\mathbf{w}) = \\mathbf{u} \\cdot \\mathbf{v} + \\mathbf{u} \\cdot \\mathbf{w}[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Magnitude relationship<\/strong>: [latex]\\mathbf{v} \\cdot \\mathbf{v} = ||\\mathbf{v}||^2[\/latex]<\/li>\r\n<\/ul>\r\n<p class=\"whitespace-normal break-words\"><strong>Important Observations<\/strong><\/p>\r\n\r\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\">[latex]\\mathbf{0} \\cdot \\mathbf{v} = 0[\/latex] for any vector<\/li>\r\n \t<li class=\"whitespace-normal break-words\">A vector's dot product with itself equals its magnitude squared: [latex]\\mathbf{v} \\cdot \\mathbf{v} = ||\\mathbf{v}||^2[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words\">Only the zero vector has a dot product of zero with itself<\/li>\r\n<\/ul>\r\n<p class=\"whitespace-normal break-words\">The dot product tells you how much two vectors point in the same direction. It's the foundation for calculating work (force in the direction of motion) and finding angles between vectors.<\/p>\r\n\r\n<\/div>\r\n<section class=\"textbox example\" aria-label=\"Example\">Find [latex]\\mathbf{u \\cdot v}[\/latex], where [latex]\\mathbf{u} = \\langle 2,9,-1 \\rangle[\/latex] and [latex]\\mathbf{v} =\\langle -3,1,-4 \\rangle[\/latex].[reveal-answer q=\"847271036\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"847271036\"]<span style=\"font-size: 1rem; text-align: initial;\">[latex]7[\/latex]<\/span><span style=\"font-size: 1rem; text-align: initial;\">[\/hidden-answer]<\/span><\/section><section class=\"textbox watchIt\" aria-label=\"Watch It\">Watch the following video to see the worked solution to the above example.\r\n<script type=\"text\/javascript\" src=\"https:\/\/www.youtube.com\/iframe_api \"><\/script>\r\n<p class=\"cc-media-iframe-container\"><iframe id=\"tpm-plugin-bbhdadeg-cKRUC3Ohi9U\" class=\"cc-media-iframe\" src=\"https:\/\/www.youtube.com\/embed\/cKRUC3Ohi9U?enablejsapi=1 \" frameborder=\"0\" data-mce-fragment=\"1\"><\/iframe><\/p>\r\n\r\n<div id=\"3p-plugin-target-bbhdadeg-cKRUC3Ohi9U\" class=\"p3sdk-target\"><\/div>\r\n<p class=\"cc-media-iframe-container\"><script type='text\/javascript' src='\/\/plugin.3playmedia.com\/ajax.js?cc=1&cc_minimizable=1&cc_minimize_on_load=0&cc_multi_text_track=0&cc_overlay=1&cc_searchable=0&embed=ajax&mf=7753520&p3sdk_version=1.11.7&p=20361&player_type=youtube&plugin_skin=dark&target=3p-plugin-target-bbhdadeg-cKRUC3Ohi9U&vembed=0&video_id=cKRUC3Ohi9U&video_target=tpm-plugin-bbhdadeg-cKRUC3Ohi9U'><\/script><\/p>\r\nYou can view the\u00a0<a href=\"https:\/\/course-building.s3.us-west-2.amazonaws.com\/Precalculus\/Transcripts\/CP+2.21_transcript.txt\" target=\"_blank\" rel=\"noopener\">transcript for \u201cCP 2.21\u201d here (opens in new window).<\/a>\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">\r\n<p id=\"fs-id1163723289025\">Find the following products for [latex]\\mathbf{p} = \\langle 7,0,2 \\rangle[\/latex], [latex]\\mathbf{q} = \\langle -2,2,-2 \\rangle[\/latex], and\u00a0[latex]\\mathbf{r} = \\langle 0,2,-3 \\rangle[\/latex].<\/p>\r\n\r\n<ol id=\"fs-id1163723199327\" type=\"a\">\r\n \t<li>[latex](\\mathbf{r} \\cdot \\mathbf{p})\\mathbf{q}[\/latex]<\/li>\r\n \t<li>[latex]||\\mathbf{p}||^2[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"645176472\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"645176472\"]\r\n\r\na.\u00a0[latex](\\mathbf{r} \\cdot \\mathbf{p})\\mathbf{q} = \\langle 12,-12,12 \\rangle[\/latex];\r\nb.\u00a0[latex]||\\mathbf{p}||^2 = 53[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section>\r\n<h2 data-type=\"title\">Using the Dot Product to Find the Angle between Two Vectors<\/h2>\r\n<div class=\"textbox shaded\">\r\n\r\n<strong>The Main Idea\u00a0<\/strong>\r\n<p class=\"whitespace-normal break-words\">The dot product has a geometric interpretation that connects it to angles between vectors. This makes it a powerful tool for finding angles and determining if vectors are perpendicular.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Geometric Dot Product Formula<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">For nonzero vectors [latex]\\mathbf{u}[\/latex] and [latex]\\mathbf{v}[\/latex] with angle [latex]\\theta[\/latex] between them:<\/p>\r\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\mathbf{u} \\cdot \\mathbf{v} = ||\\mathbf{u}|| , ||\\mathbf{v}|| \\cos \\theta[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\">Rearranging to solve for the angle:<\/p>\r\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\cos \\theta = \\frac{\\mathbf{u} \\cdot \\mathbf{v}}{||\\mathbf{u}|| , ||\\mathbf{v}||}[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\">Then [latex]\\theta = \\arccos\\left(\\frac{\\mathbf{u} \\cdot \\mathbf{v}}{||\\mathbf{u}|| , ||\\mathbf{v}||}\\right)[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>What the Angle Tells You<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">The sign of [latex]\\cos \\theta[\/latex] reveals the relationship between vectors:<\/p>\r\n\r\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta &gt; 0[\/latex]: Acute angle (vectors point in similar directions)<\/li>\r\n \t<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta = 0[\/latex]: Right angle (vectors are perpendicular)<\/li>\r\n \t<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta &lt; 0[\/latex]: Obtuse angle (vectors point in opposite-ish directions)<\/li>\r\n<\/ul>\r\n<p class=\"whitespace-normal break-words\"><strong>Orthogonal Vectors: The Perpendicular Test<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">Nonzero vectors [latex]\\mathbf{u}[\/latex] and [latex]\\mathbf{v}[\/latex] are <strong>orthogonal<\/strong> (perpendicular) if and only if [latex]\\mathbf{u} \\cdot \\mathbf{v} = 0[\/latex].<\/p>\r\n<p class=\"whitespace-normal break-words\">To test if vectors are perpendicular, just compute their dot product. If it's zero, they're orthogonal.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>Direction Angles and Cosines<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\">A vector's <strong>direction angles<\/strong> ([latex]\\alpha[\/latex], [latex]\\beta[\/latex], [latex]\\gamma[\/latex]) are the angles it makes with the positive [latex]x[\/latex]-, [latex]y[\/latex]-, and [latex]z[\/latex]-axes. Find them by taking dot products with [latex]\\mathbf{i}[\/latex], [latex]\\mathbf{j}[\/latex], and [latex]\\mathbf{k}[\/latex].<\/p>\r\n\r\n<\/div>\r\n<section class=\"textbox example\" aria-label=\"Example\">Find the measure of the angle, in radians, formed by vectors [latex]\\mathbf{a} = \\langle 1,2,0 \\rangle [\/latex] and [latex]\\mathbf{b} = \\langle 2,4,1 \\rangle[\/latex]. Round to the nearest hundredth.[reveal-answer q=\"875123144\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"875123144\"][latex]\\theta \\approx 0.22[\/latex] rad[\/hidden-answer]<\/section><section class=\"textbox example\" aria-label=\"Example\">For which value of [latex]x[\/latex] is [latex]\\mathbf{p} = \\langle 2,8,-1 \\rangle[\/latex] orthogonal to [latex]\\mathbf{q} = \\langle x,-1,2 \\rangle[\/latex]?[reveal-answer q=\"003746142\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"003746142\"][latex]x=5[\/latex][\/hidden-answer]<\/section><section class=\"textbox example\" aria-label=\"Example\">\r\n<p id=\"fs-id1163724081643\">Let [latex]\\mathbf{v} = \\langle 3,-5,1 \\rangle[\/latex]. Find the measure of the angles formed by each pair of vectors.<\/p>\r\n\r\n<ol id=\"fs-id1163724081678\" type=\"a\">\r\n \t<li>[latex]\\mathbf{v} [\/latex] and\u00a0[latex]\\mathbf{i} [\/latex]<\/li>\r\n \t<li>[latex]\\mathbf{v} [\/latex] and\u00a0[latex]\\mathbf{j} [\/latex]<\/li>\r\n \t<li>[latex]\\mathbf{v} [\/latex] and\u00a0[latex]\\mathbf{k} [\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"552341772\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"552341772\"]\r\n\r\na. [latex]\\alpha \\approx 1.04[\/latex] rad; b. [latex]\\beta \\approx 2.58[\/latex] rad; c. [latex]\\gamma \\approx 1.40[\/latex] rad\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section>","rendered":"<section class=\"textbox learningGoals\" aria-label=\"Learning Goals\">\n<ul>\n<li>Perform vector addition and scalar multiplication.<\/li>\n<li>Perform operations with vectors in terms of i and j .<\/li>\n<li>Find the dot product of two vectors.<\/li>\n<\/ul>\n<\/section>\n<h2>Combining Vectors<\/h2>\n<div class=\"textbox shaded\">\n<p><strong>The Main Idea\u00a0<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">Vectors show up constantly in real life\u2014think about a boat crossing a river (engine pushing one way, current pushing another) or a quarterback throwing a football (force and angle combined). To solve these problems, you need to know how to combine vectors.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Scalar Multiplication: Stretching and Flipping<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">When you multiply a vector [latex]\\mathbf{v}[\/latex] by a scalar [latex]k[\/latex], you change its length and possibly its direction:<\/p>\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\"><strong>If [latex]k > 0[\/latex]<\/strong>: The vector stretches or shrinks but keeps the same direction. For example, [latex]2\\mathbf{v}[\/latex] doubles the length; [latex]0.5\\mathbf{v}[\/latex] halves it.<\/li>\n<li class=\"whitespace-normal break-words\"><strong>If [latex]k < 0[\/latex]<\/strong>: The vector flips to point the opposite direction. For instance, [latex]-\\mathbf{v}[\/latex] has the same length as [latex]\\mathbf{v}[\/latex] but points the other way.<\/li>\n<li class=\"whitespace-normal break-words\"><strong>If [latex]k = 0[\/latex]<\/strong>: You get the zero vector [latex]\\mathbf{0}[\/latex].<\/li>\n<\/ul>\n<p class=\"whitespace-normal break-words\"><strong>Vector Addition: Two Methods, Same Result<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">To add vectors [latex]\\mathbf{v} + \\mathbf{w}[\/latex], use either approach:<\/p>\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\"><strong>Triangle Method<\/strong>: Place the starting point of [latex]\\mathbf{w}[\/latex] at the endpoint of [latex]\\mathbf{v}[\/latex]. The sum runs from [latex]\\mathbf{v}[\/latex]&#8216;s start to [latex]\\mathbf{w}[\/latex]&#8216;s end. Think of it like walking from A to B, then B to C\u2014your total displacement goes directly from A to C.<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Parallelogram Method<\/strong>: Start both vectors at the same point and complete the parallelogram. The diagonal is your sum.<\/li>\n<\/ul>\n<p class=\"whitespace-normal break-words\">Order doesn&#8217;t matter: [latex]\\mathbf{v} + \\mathbf{w} = \\mathbf{w} + \\mathbf{v}[\/latex] (commutative property).<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Triangle Inequality<\/strong>: The sum&#8217;s length satisfies [latex]||\\mathbf{v} + \\mathbf{w}|| \\leq ||\\mathbf{v}|| + ||\\mathbf{w}||[\/latex]. Equality only happens when vectors point the same direction.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Vector Subtraction: Adding the Opposite<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">For [latex]\\mathbf{v} - \\mathbf{w}[\/latex], rewrite it as [latex]\\mathbf{v} + (-\\mathbf{w})[\/latex]. Graphically, the difference points from [latex]\\mathbf{w}[\/latex]&#8216;s endpoint to [latex]\\mathbf{v}[\/latex]&#8216;s endpoint.<\/p>\n<\/div>\n<section class=\"textbox example\" aria-label=\"Example\">Using vectors [latex]\\bf{w}[\/latex] and [latex]\\bf{w}[\/latex] from Example: Combining Vectors, sketch the vector [latex]\\bf{2w - v}[\/latex].<\/p>\n<div id=\"fs-id1167793940239\" class=\"exercise\">\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"qfs-id1167793933124\">Show Solution<\/button><\/p>\n<div id=\"qfs-id1167793933124\" class=\"hidden-answer\" style=\"display: none\">\n<figure id=\"attachment_3477\" aria-describedby=\"caption-attachment-3477\" style=\"width: 270px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-3477\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/28191840\/2-1-tryitans2.jpeg\" alt=\"This figure has two vectors. They are vector v and vector w. They are not connected.\" width=\"270\" height=\"271\" \/><figcaption id=\"caption-attachment-3477\" class=\"wp-caption-text\">The graph of the combined vector [latex]\\bf{2w - v}[\/latex].<\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox watchIt\" aria-label=\"Watch It\">Watch the following video to see the worked solution to the above example.<br \/>\n<script type=\"text\/javascript\" src=\"https:\/\/www.youtube.com\/iframe_api\"><\/script><\/p>\n<p class=\"cc-media-iframe-container\"><iframe id=\"tpm-plugin-ddebedgh-0MXVlIKjB4Q\" class=\"cc-media-iframe\" src=\"https:\/\/www.youtube.com\/embed\/0MXVlIKjB4Q?enablejsapi=1\" frameborder=\"0\" data-mce-fragment=\"1\"><\/iframe><\/p>\n<p class=\"cc-media-iframe-container\"><script type=\"text\/javascript\" src=\"\/\/plugin.3playmedia.com\/ajax.js?cc=1&#38;cc_minimizable=1&#38;cc_minimize_on_load=0&#38;cc_multi_text_track=0&#38;cc_overlay=1&#38;cc_searchable=0&#38;embed=ajax&#38;mf=7699685&#38;p3sdk_version=1.11.7&#38;p=20361&#38;player_type=youtube&#38;plugin_skin=dark&#38;target=3p-plugin-target-ddebedgh-0MXVlIKjB4Q&#38;vembed=0&#38;video_id=0MXVlIKjB4Q&#38;video_target=tpm-plugin-ddebedgh-0MXVlIKjB4Q\"><\/script><\/p>\n<p>You can view the\u00a0<a href=\"https:\/\/course-building.s3.us-west-2.amazonaws.com\/Precalculus\/Transcripts\/CP+2.2_transcript.txt\" target=\"_blank\" rel=\"noopener\">transcript for \u201cCP 2.2\u201d here (opens in new window).<\/a><\/p>\n<\/section>\n<h2>The Dot Product<\/h2>\n<div class=\"textbox shaded\">\n<p><strong>The Main Idea\u00a0<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">The <strong>dot product<\/strong> is a way to &#8220;multiply&#8221; two vectors, but the result is a scalar (a number), not another vector. It measures how much two vectors align with each other and is essential for calculating work, finding angles between vectors, and determining if vectors are perpendicular.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Calculating the Dot Product<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">For vectors [latex]\\mathbf{u} = \\langle u_1, u_2, u_3 \\rangle[\/latex] and [latex]\\mathbf{v} = \\langle v_1, v_2, v_3 \\rangle[\/latex]:<\/p>\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\mathbf{u} \\cdot \\mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Process<\/strong>: Multiply corresponding components, then add the results.<\/p>\n<p class=\"whitespace-normal break-words\">For 2D vectors [latex]\\mathbf{u} = \\langle u_1, u_2 \\rangle[\/latex] and [latex]\\mathbf{v} = \\langle v_1, v_2 \\rangle[\/latex], it&#8217;s the same: [latex]\\mathbf{u} \\cdot \\mathbf{v} = u_1v_1 + u_2v_2[\/latex].<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Example<\/strong>: [latex]\\langle 3, 5, 2 \\rangle \\cdot \\langle -1, 3, 0 \\rangle = (3)(-1) + (5)(3) + (2)(0) = -3 + 15 + 0 = 12[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Key Properties<\/strong><\/p>\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\"><strong>Commutative<\/strong>: [latex]\\mathbf{u} \\cdot \\mathbf{v} = \\mathbf{v} \\cdot \\mathbf{u}[\/latex]<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Distributive<\/strong>: [latex]\\mathbf{u} \\cdot (\\mathbf{v} + \\mathbf{w}) = \\mathbf{u} \\cdot \\mathbf{v} + \\mathbf{u} \\cdot \\mathbf{w}[\/latex]<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Magnitude relationship<\/strong>: [latex]\\mathbf{v} \\cdot \\mathbf{v} = ||\\mathbf{v}||^2[\/latex]<\/li>\n<\/ul>\n<p class=\"whitespace-normal break-words\"><strong>Important Observations<\/strong><\/p>\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\">[latex]\\mathbf{0} \\cdot \\mathbf{v} = 0[\/latex] for any vector<\/li>\n<li class=\"whitespace-normal break-words\">A vector&#8217;s dot product with itself equals its magnitude squared: [latex]\\mathbf{v} \\cdot \\mathbf{v} = ||\\mathbf{v}||^2[\/latex]<\/li>\n<li class=\"whitespace-normal break-words\">Only the zero vector has a dot product of zero with itself<\/li>\n<\/ul>\n<p class=\"whitespace-normal break-words\">The dot product tells you how much two vectors point in the same direction. It&#8217;s the foundation for calculating work (force in the direction of motion) and finding angles between vectors.<\/p>\n<\/div>\n<section class=\"textbox example\" aria-label=\"Example\">Find [latex]\\mathbf{u \\cdot v}[\/latex], where [latex]\\mathbf{u} = \\langle 2,9,-1 \\rangle[\/latex] and [latex]\\mathbf{v} =\\langle -3,1,-4 \\rangle[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q847271036\">Show Solution<\/button><\/p>\n<div id=\"q847271036\" class=\"hidden-answer\" style=\"display: none\"><span style=\"font-size: 1rem; text-align: initial;\">[latex]7[\/latex]<\/span><span style=\"font-size: 1rem; text-align: initial;\"><\/div>\n<\/div>\n<p><\/span><\/section>\n<section class=\"textbox watchIt\" aria-label=\"Watch It\">Watch the following video to see the worked solution to the above example.<br \/>\n<script type=\"text\/javascript\" src=\"https:\/\/www.youtube.com\/iframe_api\"><\/script><\/p>\n<p class=\"cc-media-iframe-container\"><iframe id=\"tpm-plugin-bbhdadeg-cKRUC3Ohi9U\" class=\"cc-media-iframe\" src=\"https:\/\/www.youtube.com\/embed\/cKRUC3Ohi9U?enablejsapi=1\" frameborder=\"0\" data-mce-fragment=\"1\"><\/iframe><\/p>\n<div id=\"3p-plugin-target-bbhdadeg-cKRUC3Ohi9U\" class=\"p3sdk-target\"><\/div>\n<p class=\"cc-media-iframe-container\"><script type=\"text\/javascript\" src=\"\/\/plugin.3playmedia.com\/ajax.js?cc=1&#38;cc_minimizable=1&#38;cc_minimize_on_load=0&#38;cc_multi_text_track=0&#38;cc_overlay=1&#38;cc_searchable=0&#38;embed=ajax&#38;mf=7753520&#38;p3sdk_version=1.11.7&#38;p=20361&#38;player_type=youtube&#38;plugin_skin=dark&#38;target=3p-plugin-target-bbhdadeg-cKRUC3Ohi9U&#38;vembed=0&#38;video_id=cKRUC3Ohi9U&#38;video_target=tpm-plugin-bbhdadeg-cKRUC3Ohi9U\"><\/script><\/p>\n<p>You can view the\u00a0<a href=\"https:\/\/course-building.s3.us-west-2.amazonaws.com\/Precalculus\/Transcripts\/CP+2.21_transcript.txt\" target=\"_blank\" rel=\"noopener\">transcript for \u201cCP 2.21\u201d here (opens in new window).<\/a><\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">\n<p id=\"fs-id1163723289025\">Find the following products for [latex]\\mathbf{p} = \\langle 7,0,2 \\rangle[\/latex], [latex]\\mathbf{q} = \\langle -2,2,-2 \\rangle[\/latex], and\u00a0[latex]\\mathbf{r} = \\langle 0,2,-3 \\rangle[\/latex].<\/p>\n<ol id=\"fs-id1163723199327\" type=\"a\">\n<li>[latex](\\mathbf{r} \\cdot \\mathbf{p})\\mathbf{q}[\/latex]<\/li>\n<li>[latex]||\\mathbf{p}||^2[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q645176472\">Show Solution<\/button><\/p>\n<div id=\"q645176472\" class=\"hidden-answer\" style=\"display: none\">\n<p>a.\u00a0[latex](\\mathbf{r} \\cdot \\mathbf{p})\\mathbf{q} = \\langle 12,-12,12 \\rangle[\/latex];<br \/>\nb.\u00a0[latex]||\\mathbf{p}||^2 = 53[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<h2 data-type=\"title\">Using the Dot Product to Find the Angle between Two Vectors<\/h2>\n<div class=\"textbox shaded\">\n<p><strong>The Main Idea\u00a0<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">The dot product has a geometric interpretation that connects it to angles between vectors. This makes it a powerful tool for finding angles and determining if vectors are perpendicular.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Geometric Dot Product Formula<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">For nonzero vectors [latex]\\mathbf{u}[\/latex] and [latex]\\mathbf{v}[\/latex] with angle [latex]\\theta[\/latex] between them:<\/p>\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\mathbf{u} \\cdot \\mathbf{v} = ||\\mathbf{u}|| , ||\\mathbf{v}|| \\cos \\theta[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\">Rearranging to solve for the angle:<\/p>\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\cos \\theta = \\frac{\\mathbf{u} \\cdot \\mathbf{v}}{||\\mathbf{u}|| , ||\\mathbf{v}||}[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\">Then [latex]\\theta = \\arccos\\left(\\frac{\\mathbf{u} \\cdot \\mathbf{v}}{||\\mathbf{u}|| , ||\\mathbf{v}||}\\right)[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\"><strong>What the Angle Tells You<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">The sign of [latex]\\cos \\theta[\/latex] reveals the relationship between vectors:<\/p>\n<ul class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta > 0[\/latex]: Acute angle (vectors point in similar directions)<\/li>\n<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta = 0[\/latex]: Right angle (vectors are perpendicular)<\/li>\n<li class=\"whitespace-normal break-words\">[latex]\\cos \\theta < 0[\/latex]: Obtuse angle (vectors point in opposite-ish directions)<\/li>\n<\/ul>\n<p class=\"whitespace-normal break-words\"><strong>Orthogonal Vectors: The Perpendicular Test<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">Nonzero vectors [latex]\\mathbf{u}[\/latex] and [latex]\\mathbf{v}[\/latex] are <strong>orthogonal<\/strong> (perpendicular) if and only if [latex]\\mathbf{u} \\cdot \\mathbf{v} = 0[\/latex].<\/p>\n<p class=\"whitespace-normal break-words\">To test if vectors are perpendicular, just compute their dot product. If it&#8217;s zero, they&#8217;re orthogonal.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>Direction Angles and Cosines<\/strong><\/p>\n<p class=\"whitespace-normal break-words\">A vector&#8217;s <strong>direction angles<\/strong> ([latex]\\alpha[\/latex], [latex]\\beta[\/latex], [latex]\\gamma[\/latex]) are the angles it makes with the positive [latex]x[\/latex]-, [latex]y[\/latex]-, and [latex]z[\/latex]-axes. Find them by taking dot products with [latex]\\mathbf{i}[\/latex], [latex]\\mathbf{j}[\/latex], and [latex]\\mathbf{k}[\/latex].<\/p>\n<\/div>\n<section class=\"textbox example\" aria-label=\"Example\">Find the measure of the angle, in radians, formed by vectors [latex]\\mathbf{a} = \\langle 1,2,0 \\rangle[\/latex] and [latex]\\mathbf{b} = \\langle 2,4,1 \\rangle[\/latex]. Round to the nearest hundredth.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q875123144\">Show Solution<\/button><\/p>\n<div id=\"q875123144\" class=\"hidden-answer\" style=\"display: none\">[latex]\\theta \\approx 0.22[\/latex] rad<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">For which value of [latex]x[\/latex] is [latex]\\mathbf{p} = \\langle 2,8,-1 \\rangle[\/latex] orthogonal to [latex]\\mathbf{q} = \\langle x,-1,2 \\rangle[\/latex]?<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q003746142\">Show Solution<\/button><\/p>\n<div id=\"q003746142\" class=\"hidden-answer\" style=\"display: none\">[latex]x=5[\/latex]<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">\n<p id=\"fs-id1163724081643\">Let [latex]\\mathbf{v} = \\langle 3,-5,1 \\rangle[\/latex]. Find the measure of the angles formed by each pair of vectors.<\/p>\n<ol id=\"fs-id1163724081678\" type=\"a\">\n<li>[latex]\\mathbf{v}[\/latex] and\u00a0[latex]\\mathbf{i}[\/latex]<\/li>\n<li>[latex]\\mathbf{v}[\/latex] and\u00a0[latex]\\mathbf{j}[\/latex]<\/li>\n<li>[latex]\\mathbf{v}[\/latex] and\u00a0[latex]\\mathbf{k}[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q552341772\">Show Solution<\/button><\/p>\n<div id=\"q552341772\" class=\"hidden-answer\" style=\"display: none\">\n<p>a. [latex]\\alpha \\approx 1.04[\/latex] rad; b. [latex]\\beta \\approx 2.58[\/latex] rad; c. [latex]\\gamma \\approx 1.40[\/latex] rad<\/p>\n<\/div>\n<\/div>\n<\/section>\n","protected":false},"author":67,"menu_order":24,"template":"","meta":{"_candela_citation":"[{\"type\":\"copyrighted_video\",\"description\":\"CP 2.2\",\"author\":\"Ryan Melton\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/0MXVlIKjB4Q\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"Standard YouTube License\"},{\"type\":\"copyrighted_video\",\"description\":\"CP 2.21\",\"author\":\"Ryan Melton\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/cKRUC3Ohi9U\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"Standard YouTube License\"}]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":520,"module-header":"fresh_take","content_attributions":[{"type":"copyrighted_video","description":"CP 2.2","author":"Ryan Melton","organization":"","url":"https:\/\/youtu.be\/0MXVlIKjB4Q","project":"","license":"arr","license_terms":"Standard YouTube License"},{"type":"copyrighted_video","description":"CP 2.21","author":"Ryan Melton","organization":"","url":"https:\/\/youtu.be\/cKRUC3Ohi9U","project":"","license":"arr","license_terms":"Standard YouTube License"}],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"<script type='text\/javascript' src='https:\/\/www.youtube.com\/iframe_api'><\/script><script type='text\/javascript' src='\/\/plugin.3playmedia.com\/ajax.js?cc=1&cc_minimizable=1&cc_minimize_on_load=0&cc_multi_text_track=0&cc_overlay=1&cc_searchable=0&embed=ajax&mf=7699685&p3sdk_version=1.11.7&p=20361&player_type=youtube&plugin_skin=dark&target=3p-plugin-target-bbhdadeg-cKRUC3Ohi9U&vembed=0&video_id=0MXVlIKjB4Q&video_target=tpm-plugin-ddebedgh-0MXVlIKjB4Q'><\/script>\n<script type='text\/javascript' src='https:\/\/www.youtube.com\/iframe_api'><\/script><script type='text\/javascript' src='\/\/plugin.3playmedia.com\/ajax.js?cc=1&cc_minimizable=1&cc_minimize_on_load=0&cc_multi_text_track=0&cc_overlay=1&cc_searchable=0&embed=ajax&mf=7753520&p3sdk_version=1.11.7&p=20361&player_type=youtube&plugin_skin=dark&target=&vembed=0&video_id=cKRUC3Ohi9U&video_target=tpm-plugin-bbhdadeg-cKRUC3Ohi9U'><\/script>\n","media_targets":["tpm-plugin-ddebedgh-0MXVlIKjB4Q","tpm-plugin-bbhdadeg-cKRUC3Ohi9U"]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1587"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/67"}],"version-history":[{"count":15,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1587\/revisions"}],"predecessor-version":[{"id":6011,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1587\/revisions\/6011"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/520"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1587\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1587"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1587"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1587"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1587"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}