{"id":1217,"date":"2025-07-23T20:57:21","date_gmt":"2025-07-23T20:57:21","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1217"},"modified":"2026-03-20T19:07:56","modified_gmt":"2026-03-20T19:07:56","slug":"systems-of-nonlinear-equations-and-inequalities-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/systems-of-nonlinear-equations-and-inequalities-learn-it-2\/","title":{"raw":"Systems of Nonlinear Equations and Inequalities: Learn It 2","rendered":"Systems of Nonlinear Equations and Inequalities: Learn It 2"},"content":{"raw":"<h2>Intersection of a Circle and a Line<\/h2>\r\nJust as with a parabola and a line, there are three possible outcomes when solving a system of equations representing a circle and a line.\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>possible types of solutions for the points of intersection of a circle and a line<\/h3>\r\nThe graph below illustrates possible solution sets for a system of equations involving a <strong>circle<\/strong> and a line.\r\n<ul>\r\n \t<li>No solution. The line does not intersect the circle.<\/li>\r\n \t<li>One solution. The line is tangent to the circle and intersects the circle at exactly one point.<\/li>\r\n \t<li>Two solutions. The line crosses the circle and intersects it at two points.<\/li>\r\n<\/ul>\r\n<img class=\"size-full wp-image-5690 aligncenter\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/07\/28163244\/dc6316c2933c3aad2b12f0bf07560cf82f2d7251.jpg\" alt=\"This image shows three cases of intersections between a line and a circle. In the first case, the line does not touch the circle, resulting in no solutions. In the second case, the line is tangent to the circle, touching it at a single point, indicating one solution. In the third case, the line crosses the circle at two points, giving two solutions.\" width=\"717\" height=\"260\" \/>\r\n\r\n<\/section><section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a system of equations containing a line and a circle, find the solution.\r\n<\/strong>\r\n<ol>\r\n \t<li>Solve the linear equation for one of the variables.<\/li>\r\n \t<li>Substitute the expression obtained in step one into the equation for the circle.<\/li>\r\n \t<li>Solve for the remaining variable.<\/li>\r\n \t<li>Check your solutions in both equations.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the intersection of the given circle and the given line by substitution.\r\n<div style=\"text-align: center;\">[latex]\\begin{gathered}{x}^{2}+{y}^{2}=5 \\\\ y=3x - 5 \\end{gathered}[\/latex]<\/div>\r\n<p style=\"text-align: left;\">[reveal-answer q=\"766252\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"766252\"]<\/p>\r\nOne of the equations has already been solved for [latex]y[\/latex]. We will substitute [latex]y=3x - 5[\/latex] into the equation for the circle.\r\n<div style=\"text-align: center;\">[latex]\\begin{gathered}{x}^{2}+{\\left(3x - 5\\right)}^{2}=5\\\\ {x}^{2}+9{x}^{2}-30x+25=5\\\\ 10{x}^{2}-30x+20=0\\end{gathered}[\/latex]<\/div>\r\n&nbsp;\r\n\r\nNow, we factor and solve for [latex]x[\/latex].\r\n<div style=\"text-align: center;\">[latex]\\begin{gathered}10\\left({x}^{2}-3x+2\\right)=0 \\\\ 10\\left(x - 2\\right)\\left(x - 1\\right)=0 \\\\ x=2 \\hspace{5mm} x=1 \\end{gathered}[\/latex]<\/div>\r\nSubstitute the two <em>x<\/em>-values into the original linear equation to solve for [latex]y[\/latex].\r\n<div style=\"text-align: center;\">[latex]\\begin{align}y&amp;=3\\left(2\\right)-5 \\\\ &amp;=1 \\\\[3mm] y&amp;=3\\left(1\\right)-5 \\\\ &amp;=-2 \\end{align}[\/latex]<\/div>\r\n<div>\r\n\r\nThe line intersects the circle at [latex]\\left(2,1\\right)[\/latex] and [latex]\\left(1,-2\\right)[\/latex], which can be verified by substituting these [latex]\\left(x,y\\right)[\/latex] values into both of the original equations.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/03190511\/CNX_Precalc_Figure_09_03_0052.jpg\" alt=\"Line y equals 3x minus 5 crosses circle x squared plus y squared equals five at the points 2,1 and 1, negative 2.\" width=\"487\" height=\"367\" \/>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">\r\n<div class=\"bcc-box bcc-success\">\r\n\r\n[ohm_question hide_question_numbers=1]321627[\/ohm_question]\r\n\r\n<\/div>\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321628[\/ohm_question]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321629[\/ohm_question]<\/section>","rendered":"<h2>Intersection of a Circle and a Line<\/h2>\n<p>Just as with a parabola and a line, there are three possible outcomes when solving a system of equations representing a circle and a line.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>possible types of solutions for the points of intersection of a circle and a line<\/h3>\n<p>The graph below illustrates possible solution sets for a system of equations involving a <strong>circle<\/strong> and a line.<\/p>\n<ul>\n<li>No solution. The line does not intersect the circle.<\/li>\n<li>One solution. The line is tangent to the circle and intersects the circle at exactly one point.<\/li>\n<li>Two solutions. The line crosses the circle and intersects it at two points.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5690 aligncenter\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/07\/28163244\/dc6316c2933c3aad2b12f0bf07560cf82f2d7251.jpg\" alt=\"This image shows three cases of intersections between a line and a circle. In the first case, the line does not touch the circle, resulting in no solutions. In the second case, the line is tangent to the circle, touching it at a single point, indicating one solution. In the third case, the line crosses the circle at two points, giving two solutions.\" width=\"717\" height=\"260\" \/><\/p>\n<\/section>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a system of equations containing a line and a circle, find the solution.<br \/>\n<\/strong><\/p>\n<ol>\n<li>Solve the linear equation for one of the variables.<\/li>\n<li>Substitute the expression obtained in step one into the equation for the circle.<\/li>\n<li>Solve for the remaining variable.<\/li>\n<li>Check your solutions in both equations.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the intersection of the given circle and the given line by substitution.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{gathered}{x}^{2}+{y}^{2}=5 \\\\ y=3x - 5 \\end{gathered}[\/latex]<\/div>\n<p style=\"text-align: left;\">\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q766252\">Show Solution<\/button><\/p>\n<div id=\"q766252\" class=\"hidden-answer\" style=\"display: none\">\n<p>One of the equations has already been solved for [latex]y[\/latex]. We will substitute [latex]y=3x - 5[\/latex] into the equation for the circle.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{gathered}{x}^{2}+{\\left(3x - 5\\right)}^{2}=5\\\\ {x}^{2}+9{x}^{2}-30x+25=5\\\\ 10{x}^{2}-30x+20=0\\end{gathered}[\/latex]<\/div>\n<p>&nbsp;<\/p>\n<p>Now, we factor and solve for [latex]x[\/latex].<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{gathered}10\\left({x}^{2}-3x+2\\right)=0 \\\\ 10\\left(x - 2\\right)\\left(x - 1\\right)=0 \\\\ x=2 \\hspace{5mm} x=1 \\end{gathered}[\/latex]<\/div>\n<p>Substitute the two <em>x<\/em>-values into the original linear equation to solve for [latex]y[\/latex].<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align}y&=3\\left(2\\right)-5 \\\\ &=1 \\\\[3mm] y&=3\\left(1\\right)-5 \\\\ &=-2 \\end{align}[\/latex]<\/div>\n<div>\n<p>The line intersects the circle at [latex]\\left(2,1\\right)[\/latex] and [latex]\\left(1,-2\\right)[\/latex], which can be verified by substituting these [latex]\\left(x,y\\right)[\/latex] values into both of the original equations.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/03190511\/CNX_Precalc_Figure_09_03_0052.jpg\" alt=\"Line y equals 3x minus 5 crosses circle x squared plus y squared equals five at the points 2,1 and 1, negative 2.\" width=\"487\" height=\"367\" \/><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\">\n<div class=\"bcc-box bcc-success\">\n<p><iframe loading=\"lazy\" id=\"ohm321627\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321627&theme=lumen&iframe_resize_id=ohm321627&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321628\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321628&theme=lumen&iframe_resize_id=ohm321628&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321629\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321629&theme=lumen&iframe_resize_id=ohm321629&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":21,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":131,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1217"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":6,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1217\/revisions"}],"predecessor-version":[{"id":5946,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1217\/revisions\/5946"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/131"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1217\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1217"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1217"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1217"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1217"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}