{"id":1057,"date":"2025-07-22T00:04:45","date_gmt":"2025-07-22T00:04:45","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&p=1057"},"modified":"2026-03-16T18:59:50","modified_gmt":"2026-03-16T18:59:50","slug":"exponential-functions-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/exponential-functions-learn-it-3\/","title":{"raw":"Graphs of Exponential Functions: Learn It 3","rendered":"Graphs of Exponential Functions: Learn It 3"},"content":{"raw":"

Transformations of Exponential Graphs<\/h2>\r\nTransformations of exponential graphs behave similarly to those of other functions. Just as with other parent functions, we can apply the four types of transformations\u2014shifts, reflections, stretches, and compressions\u2014to the parent function [latex]f(x)={b}^{x}[\/latex] without loss of shape.\r\n\r\n
Translating exponential functions follows the same ideas you've used to translate other functions. Add or subtract a value inside the function argument (in the exponent) to shift horizontally, and add or subtract a value outside the function argument to shift vertically.<\/section>\r\n

Graphing a Vertical Shift<\/h3>\r\nThe first transformation occurs when we add a constant [latex]d[\/latex]\u00a0to the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] giving us a vertical shift<\/strong> [latex]d[\/latex]\u00a0units in the same direction as the sign.\r\n\r\n
For example, if we begin by graphing a parent function, [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph two vertical shifts alongside it using [latex]d=3[\/latex]: the upward shift, [latex]g\\left(x\\right)={2}^{x}+3[\/latex] and the downward shift, [latex]h\\left(x\\right)={2}^{x}-3[\/latex]. Both vertical shifts are shown in the figure below.\r\n\"Graph\r\nObserve the results of shifting [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically:\r\n
    \r\n \t
  • The domain [latex]\\left(-\\infty ,\\infty \\right)[\/latex] remains unchanged.<\/li>\r\n \t
  • When the function is shifted up [latex]3[\/latex]\u00a0units giving [latex]g\\left(x\\right)={2}^{x}+3[\/latex]:\r\n
      \r\n \t
    • The [latex]y[\/latex]-<\/em>intercept shifts up [latex]3[\/latex] units to [latex]\\left(0,4\\right)[\/latex].<\/li>\r\n \t
    • The asymptote shifts up [latex]3[\/latex] units to [latex]y=3[\/latex].<\/li>\r\n \t
    • The range becomes [latex]\\left(3,\\infty \\right)[\/latex].<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t
    • When the function is shifted down [latex]3[\/latex] units giving [latex]h\\left(x\\right)={2}^{x}-3[\/latex]:\r\n
        \r\n \t
      • The [latex]y[\/latex]-<\/em>intercept shifts down [latex]3[\/latex] units to [latex]\\left(0,-2\\right)[\/latex].<\/li>\r\n \t
      • The asymptote also shifts down [latex]3[\/latex] units to [latex]y=-3[\/latex].<\/li>\r\n \t
      • The range becomes [latex]\\left(-3,\\infty \\right)[\/latex].<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<\/section>
        \r\n
          \r\n \t
        1. Use an online graphing calculator to plot\u00a0[latex]f(x) = 2^x+a[\/latex]<\/li>\r\n \t
        2. Adjust the value of [latex]a[\/latex] until the graph has been shifted [latex]4[\/latex] units up.<\/li>\r\n \t
        3. Add a line that represents the horizontal asymptote for this function. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What is its domain and range?<\/li>\r\n \t
        4. Now create a graph of the function [latex]f(x) = 2^x[\/latex] that has been shifted down [latex]2[\/latex] units. Add a line that represents the horizontal asymptote. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What is its domain and range?<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"619964\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"619964\"]\r\n
            \r\n \t
          1. Equation: [latex]f(x) = 2^x+4[\/latex], Horizontal Asymptote: [latex]y = 4[\/latex], [latex]y[\/latex]-intercept: [latex](0,5)[\/latex], Domain: [latex](-\\infty,\\infty)[\/latex], Range: [latex](4,\\infty)[\/latex]<\/li>\r\n \t
          2. Equation: [latex]f(x) = 2^x-2[\/latex], Horizontal Asymptote: [latex]y = -2[\/latex], [latex]y[\/latex]-intercept: [latex](0,-1)[\/latex], Domain: [latex](-\\infty,\\infty)[\/latex], Range: [latex](-2,\\infty)[\/latex]<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section>\r\n

            Graphing a Horizontal Shift<\/h3>\r\nThe next transformation occurs when we add a constant [latex]c[\/latex]\u00a0to the input of the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] giving us a horizontal shift<\/strong> [latex]c[\/latex]\u00a0units in the opposite<\/em> direction of the sign.\r\n\r\n
            For example, if we begin by graphing the parent function [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph two horizontal shifts alongside it using [latex]c=3[\/latex]: the shift left, [latex]g\\left(x\\right)={2}^{x+3}[\/latex], and the shift right, [latex]h\\left(x\\right)={2}^{x - 3}[\/latex]. Both horizontal shifts are shown in the graph below.\r\n\"A\r\nObserve the results of shifting [latex]f\\left(x\\right)={2}^{x}[\/latex] horizontally:\r\n
              \r\n \t
            • The domain, [latex]\\left(-\\infty ,\\infty \\right)[\/latex], remains unchanged.<\/li>\r\n \t
            • The asymptote, [latex]y=0[\/latex], remains unchanged.<\/li>\r\n \t
            • The [latex]y[\/latex]-<\/em>intercept shifts such that:\r\n
                \r\n \t
              • When the function is shifted left [latex]3[\/latex]\u00a0units to [latex]g\\left(x\\right)={2}^{x+3}[\/latex], the [latex]y[\/latex]-intercept becomes [latex]\\left(0,8\\right)[\/latex]. This is because [latex]{2}^{x+3}=\\left({2}^{3}\\right){2}^{x}=\\left(8\\right){2}^{x}[\/latex], so the initial value of the function is [latex]8[\/latex].<\/li>\r\n \t
              • When the function is shifted right [latex]3[\/latex]\u00a0units to [latex]h\\left(x\\right)={2}^{x - 3}[\/latex], the [latex]y[\/latex]-intercept becomes [latex]\\left(0,\\frac{1}{8}\\right)[\/latex]. Again, see that [latex]{2}^{x-3}=\\left({2}^{-3}\\right){2}^{x}=\\left(\\frac{1}{8}\\right){2}^{x}[\/latex], so the initial value of the function is [latex]\\frac{1}{8}[\/latex].<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<\/section>
                \r\n
                  \r\n \t
                1. Using an online graphing calculator, plot\u00a0[latex]f(x) = 2^{(x+a)}[\/latex]<\/li>\r\n \t
                2. Adjust the value of [latex]a[\/latex] until the graph is shifted [latex]4[\/latex] units to the right. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What are its domain and range?<\/li>\r\n \t
                3. Now adjust the value of [latex]a[\/latex] until the graph has been shifted [latex]3[\/latex] units to the left. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What are its domain and range?<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"94739\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"94739\"]\r\n
                    \r\n \t
                  1. Equation: [latex]f(x) = 2^{x-4}[\/latex], [latex]y[\/latex]-intercept: [latex](0,\\frac{1}{32}), [\/latex]Domain: [latex](-\\infty,\\infty)[\/latex], Range: [latex](0,\\infty)[\/latex]<\/li>\r\n \t
                  2. Equation: [latex]f(x) = 2^{x+3}[\/latex], [latex]y[\/latex]-intercept: [latex](0,8)[\/latex], Domain: [latex](-\\infty,\\infty)[\/latex], Range: [latex](0,\\infty)[\/latex]<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section>
                    \r\n

                    shifts of the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/h3>\r\nFor any constants [latex]c[\/latex]\u00a0and [latex]d[\/latex], the function [latex]f\\left(x\\right)={b}^{x+c}+d[\/latex] shifts the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]\r\n
                      \r\n \t
                    • shifts the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] vertically [latex]d[\/latex]\u00a0units, in the same<\/em> direction as the sign of [latex]d[\/latex].<\/li>\r\n \t
                    • shifts the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] horizontally [latex]c[\/latex]\u00a0units, in the opposite<\/em> direction as the sign of [latex]c[\/latex].<\/li>\r\n \t
                    • has a\u00a0[latex]y[\/latex]-intercept of [latex]\\left(0,{b}^{c}+d\\right)[\/latex].<\/li>\r\n \t
                    • has a horizontal asymptote of\u00a0[latex]y =\u00a0d[\/latex].<\/li>\r\n \t
                    • has a range of [latex]\\left(d,\\infty \\right)[\/latex].<\/li>\r\n \t
                    • has a domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which remains unchanged.<\/li>\r\n<\/ul>\r\n<\/section>
                      How To: Given an exponential function with the form [latex]f\\left(x\\right)={b}^{x+c}+d[\/latex], graph the translation<\/strong>\r\n
                        \r\n \t
                      1. Draw the horizontal asymptote [latex]y =\u00a0d[\/latex].<\/li>\r\n \t
                      2. Shift the graph of [latex]f\\left(x\\right)={b}^{x}[\/latex] left [latex]c[\/latex]\u00a0units if [latex]c[\/latex]\u00a0is positive and right [latex]c[\/latex] units if [latex]c[\/latex]\u00a0is negative.<\/li>\r\n \t
                      3. Shift the graph of [latex]f\\left(x\\right)={b}^{x}[\/latex] up [latex]d[\/latex]\u00a0units if [latex]d[\/latex]\u00a0is positive and down [latex]d[\/latex]\u00a0units if [latex]d[\/latex]\u00a0is negative.<\/li>\r\n \t
                      4. State the domain, [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range, [latex]\\left(d,\\infty \\right)[\/latex], and the horizontal asymptote [latex]y=d[\/latex].<\/li>\r\n<\/ol>\r\n<\/section>
                        Graph [latex]f\\left(x\\right)={2}^{x+1}-3[\/latex]. State the domain, range, and asymptote.[reveal-answer q=\"344344\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"344344\"]We have an exponential equation of the form [latex]f\\left(x\\right)={b}^{x+c}+d[\/latex], with [latex]b=2[\/latex], [latex]c=1[\/latex], and [latex]d=-3[\/latex].Draw the horizontal asymptote [latex]y=d[\/latex], so draw [latex]y=-3[\/latex].\r\n[latex]\\\\[\/latex]\r\nIdentify the shift; it is [latex]\\left(-1,-3\\right)[\/latex].[caption id=\"\" align=\"aligncenter\" width=\"487\"]\"Graph The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range is [latex]\\left(-3,\\infty \\right)[\/latex], and the horizontal asymptote is [latex]y=-3[\/latex].[\/caption]Shift the graph of [latex]f\\left(x\\right)={b}^{x}[\/latex] left [latex]1[\/latex] unit and down [latex]3[\/latex] units.\r\n<\/span>The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex]; the range is [latex]\\left(-3,\\infty \\right)[\/latex]; the horizontal asymptote is [latex]y=-3[\/latex].[\/hidden-answer]<\/section>
                        [ohm_question hide_question_numbers=1]321397[\/ohm_question]<\/section>
                        [ohm_question hide_question_numbers=1]321398[\/ohm_question]<\/section>","rendered":"

                        Transformations of Exponential Graphs<\/h2>\n

                        Transformations of exponential graphs behave similarly to those of other functions. Just as with other parent functions, we can apply the four types of transformations\u2014shifts, reflections, stretches, and compressions\u2014to the parent function [latex]f(x)={b}^{x}[\/latex] without loss of shape.<\/p>\n

                        Translating exponential functions follows the same ideas you’ve used to translate other functions. Add or subtract a value inside the function argument (in the exponent) to shift horizontally, and add or subtract a value outside the function argument to shift vertically.<\/section>\n

                        Graphing a Vertical Shift<\/h3>\n

                        The first transformation occurs when we add a constant [latex]d[\/latex]\u00a0to the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] giving us a vertical shift<\/strong> [latex]d[\/latex]\u00a0units in the same direction as the sign.<\/p>\n

                        For example, if we begin by graphing a parent function, [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph two vertical shifts alongside it using [latex]d=3[\/latex]: the upward shift, [latex]g\\left(x\\right)={2}^{x}+3[\/latex] and the downward shift, [latex]h\\left(x\\right)={2}^{x}-3[\/latex]. Both vertical shifts are shown in the figure below.
                        \n\"Graph
                        \nObserve the results of shifting [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically:<\/p>\n
                          \n
                        • The domain [latex]\\left(-\\infty ,\\infty \\right)[\/latex] remains unchanged.<\/li>\n
                        • When the function is shifted up [latex]3[\/latex]\u00a0units giving [latex]g\\left(x\\right)={2}^{x}+3[\/latex]:\n
                            \n
                          • The [latex]y[\/latex]–<\/em>intercept shifts up [latex]3[\/latex] units to [latex]\\left(0,4\\right)[\/latex].<\/li>\n
                          • The asymptote shifts up [latex]3[\/latex] units to [latex]y=3[\/latex].<\/li>\n
                          • The range becomes [latex]\\left(3,\\infty \\right)[\/latex].<\/li>\n<\/ul>\n<\/li>\n
                          • When the function is shifted down [latex]3[\/latex] units giving [latex]h\\left(x\\right)={2}^{x}-3[\/latex]:\n
                              \n
                            • The [latex]y[\/latex]–<\/em>intercept shifts down [latex]3[\/latex] units to [latex]\\left(0,-2\\right)[\/latex].<\/li>\n
                            • The asymptote also shifts down [latex]3[\/latex] units to [latex]y=-3[\/latex].<\/li>\n
                            • The range becomes [latex]\\left(-3,\\infty \\right)[\/latex].<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/section>\n
                              \n
                                \n
                              1. Use an online graphing calculator to plot\u00a0[latex]f(x) = 2^x+a[\/latex]<\/li>\n
                              2. Adjust the value of [latex]a[\/latex] until the graph has been shifted [latex]4[\/latex] units up.<\/li>\n
                              3. Add a line that represents the horizontal asymptote for this function. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What is its domain and range?<\/li>\n
                              4. Now create a graph of the function [latex]f(x) = 2^x[\/latex] that has been shifted down [latex]2[\/latex] units. Add a line that represents the horizontal asymptote. What is the equation for this function? What is the new [latex]y[\/latex]-intercept? What is its domain and range?<\/li>\n<\/ol>\n