{"id":1056,"date":"2025-07-22T00:04:53","date_gmt":"2025-07-22T00:04:53","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1056"},"modified":"2026-03-16T19:07:21","modified_gmt":"2026-03-16T19:07:21","slug":"exponential-functions-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/exponential-functions-learn-it-4\/","title":{"raw":"Graphs of Exponential Functions: Learn It 4","rendered":"Graphs of Exponential Functions: Learn It 4"},"content":{"raw":"<h2>Stretching, Compressing, or Reflecting an Exponential Function<\/h2>\r\nWhile horizontal and vertical shifts involve adding constants to the input or to the function itself, a <strong>stretch<\/strong> or <strong>compression<\/strong> occurs when we multiply the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] by a constant [latex]|a|&gt;0[\/latex].\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">For example, if we begin by graphing the parent function [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph the stretch, using [latex]a=3[\/latex], to get [latex]g\\left(x\\right)=3{\\left(2\\right)}^{x}[\/latex] and the compression, using [latex]a=\\frac{1}{3}[\/latex], to get [latex]h\\left(x\\right)=\\frac{1}{3}{\\left(2\\right)}^{x}[\/latex].\r\n[caption id=\"attachment_5005\" align=\"aligncenter\" width=\"679\"]<img class=\"wp-image-5005\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-300x166.png\" alt=\"Two graphs where graph a is an example of vertical stretch and graph b is an example of vertical compression.\" width=\"679\" height=\"376\" \/> (a) [latex]g\\left(x\\right)=3{\\left(2\\right)}^{x}[\/latex] stretches the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically by a factor of 3. (b) [latex]h\\left(x\\right)=\\frac{1}{3}{\\left(2\\right)}^{x}[\/latex] compresses the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically by a factor of [latex]\\frac{1}{3}[\/latex].[\/caption]<\/section><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>stretches and compressions of the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/h3>\r\nThe function [latex]f\\left(x\\right)=a{b}^{x}[\/latex]\r\n<ul>\r\n \t<li>is stretched vertically by a factor of [latex]a[\/latex]if [latex]|a|&gt;1[\/latex].<\/li>\r\n \t<li>is compressed vertically by a factor of [latex]a[\/latex]\u00a0if [latex]|a|&lt;1[\/latex].<\/li>\r\n \t<li>has a\u00a0[latex]y[\/latex]-intercept is [latex]\\left(0,a\\right)[\/latex].<\/li>\r\n \t<li>has a horizontal asymptote of [latex]y=0[\/latex], range of [latex]\\left(0,\\infty \\right)[\/latex], and domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are all unchanged from the parent function.<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">Exponential functions are stretched, compressed or reflected in the same manner you've used to transform other functions. Multipliers or negatives inside the function argument (in the exponent) affect horizontal transformations. Multipliers or negatives outside the function argument affect vertical transformations.<\/section><section class=\"textbox example\" aria-label=\"Example\">Sketch a graph of [latex]f\\left(x\\right)=4{\\left(\\frac{1}{2}\\right)}^{x}[\/latex]. State the domain, range, and asymptote.[reveal-answer q=\"418729\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"418729\"]Before graphing, identify the behavior and key points on the graph.\r\n<ul>\r\n \t<li>Since [latex]b=\\frac{1}{2}[\/latex] is between zero and one, the left tail of the graph will increase without bound as [latex]x[\/latex]\u00a0decreases, and the right tail will approach the [latex]x[\/latex]-axis as [latex]x[\/latex]\u00a0increases.<\/li>\r\n \t<li>Since [latex]a\u00a0= 4[\/latex], the graph of [latex]f\\left(x\\right)={\\left(\\frac{1}{2}\\right)}^{x}[\/latex] will be stretched vertically by a factor of [latex]4[\/latex].<\/li>\r\n \t<li>Create a table of points:\r\n<table summary=\"Two rows and eight columns. The first row is labeled,\">\r\n<tbody>\r\n<tr>\r\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td>[latex]\u20133[\/latex]<\/td>\r\n<td>[latex]\u20132[\/latex]<\/td>\r\n<td>[latex]\u20131[\/latex]<\/td>\r\n<td>[latex]0[\/latex]<\/td>\r\n<td>[latex]1[\/latex]<\/td>\r\n<td>[latex]2[\/latex]<\/td>\r\n<td>[latex]3[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><strong>[latex]f\\left(x\\right)=4\\left(\\frac{1}{2}\\right)^{x}[\/latex]<\/strong><\/td>\r\n<td>[latex]32[\/latex]<\/td>\r\n<td>[latex]16[\/latex]<\/td>\r\n<td>[latex]8[\/latex]<\/td>\r\n<td>[latex]4[\/latex]<\/td>\r\n<td>[latex]2[\/latex]<\/td>\r\n<td>[latex]1[\/latex]<\/td>\r\n<td>[latex]0.5[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n \t<li>Plot the [latex]y[\/latex]<em>-<\/em>intercept, [latex]\\left(0,4\\right)[\/latex], along with two other points. We can use [latex]\\left(-1,8\\right)[\/latex] and [latex]\\left(1,2\\right)[\/latex].<\/li>\r\n \t<li>Draw a smooth curve connecting the points.<\/li>\r\n<\/ul>\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/02231155\/CNX_Precalc_Figure_04_02_0112.jpg\" alt=\"Graph of the function, f(x) = 4(1\/2)^(x), with an asymptote at y=0. Labeled points in the graph are (-1, 8), (0, 4), and (1, 2).\" width=\"487\" height=\"482\" \/> The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range is [latex]\\left(0,\\infty \\right)[\/latex], the horizontal asymptote is y\u00a0= 0.[\/caption][\/hidden-answer]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321399[\/ohm_question]<\/section>\r\n<h3>Graphing Reflections<\/h3>\r\nIn addition to shifting, compressing, and stretching a graph, we can also reflect it about the [latex]x[\/latex]-axis or the [latex]y[\/latex]-axis. When we multiply the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] by [latex]\u20131[\/latex], we get a reflection about the [latex]x[\/latex]-axis. When we multiply the input by[latex] \u20131[\/latex], we get a reflection about the [latex]y[\/latex]-axis.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">For example, if we begin by graphing the parent function [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph the two reflections alongside it. The reflection about the [latex]x[\/latex]-axis, [latex]g\\left(x\\right)={-2}^{x}[\/latex], and the reflection about the [latex]y[\/latex]-axis, [latex]h\\left(x\\right)={2}^{-x}[\/latex], are both shown below.\r\n[caption id=\"attachment_5009\" align=\"aligncenter\" width=\"676\"]<img class=\"wp-image-5009 \" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-300x233.png\" alt=\"Two graphs where graph a is an example of a reflection about the x-axis and graph b is an example of a reflection about the y-axis.\" width=\"676\" height=\"525\" \/> (a) [latex]g\\left(x\\right)=-{2}^{x}[\/latex] reflects the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] about the x-axis. (b) [latex]h\\left(x\\right)={2}^{-x}[\/latex] reflects the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] about the y-axis.[\/caption]<\/section><section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>reflecting the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/h3>\r\nThe function [latex]f\\left(x\\right)=-{b}^{x}[\/latex]\r\n<ul>\r\n \t<li>reflects the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] about the [latex]x[\/latex]-axis.<\/li>\r\n \t<li>has a [latex]y[\/latex]-intercept of [latex]\\left(0,-1\\right)[\/latex].<\/li>\r\n \t<li>has a range of [latex]\\left(-\\infty ,0\\right)[\/latex].<\/li>\r\n \t<li>has a horizontal asymptote of [latex]y=0[\/latex] and domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are unchanged from the parent function.<\/li>\r\n<\/ul>\r\nThe function [latex]f\\left(x\\right)={b}^{-x}[\/latex]\r\n<ul>\r\n \t<li>reflects the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] about the [latex]y[\/latex]-axis.<\/li>\r\n \t<li>has a [latex]y[\/latex]-intercept of [latex]\\left(0,1\\right)[\/latex], a horizontal asymptote at [latex]y=0[\/latex], a range of [latex]\\left(0,\\infty \\right)[\/latex], and a domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are unchanged from the parent function.<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find and graph the equation for a function, [latex]g\\left(x\\right)[\/latex], that reflects [latex]f\\left(x\\right)={\\left(\\frac{1}{4}\\right)}^{x}[\/latex] about the [latex]x[\/latex]-axis. State its domain, range, and asymptote.[reveal-answer q=\"91748\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"91748\"]Since we want to reflect the parent function [latex]f\\left(x\\right)={\\left(\\frac{1}{4}\\right)}^{x}[\/latex] about the [latex]x[\/latex]<em>-<\/em>axis, we multiply [latex]f\\left(x\\right)[\/latex] by [latex]\u20131[\/latex] to get [latex]g\\left(x\\right)=-{\\left(\\frac{1}{4}\\right)}^{x}[\/latex]. Next we create a table of points.\r\n<table summary=\"Two rows and eight columns. The first row is labeled,\"><colgroup> <col \/> <col \/> <col \/> <col \/> <col \/> <col \/> <col \/> <col \/><\/colgroup>\r\n<tbody>\r\n<tr>\r\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td>[latex]\u20133[\/latex]<\/td>\r\n<td>[latex]\u20132[\/latex]<\/td>\r\n<td>[latex]\u20131[\/latex]<\/td>\r\n<td>[latex]0[\/latex]<\/td>\r\n<td>[latex]1[\/latex]<\/td>\r\n<td>[latex]2[\/latex]<\/td>\r\n<td>[latex]3[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex]g\\left(x\\right)=-\\left(\\frac{1}{4}\\right)^{x}[\/latex]<\/td>\r\n<td>[latex]\u201364[\/latex]<\/td>\r\n<td>[latex]\u201316[\/latex]<\/td>\r\n<td>[latex]\u20134[\/latex]<\/td>\r\n<td>[latex]\u20131[\/latex]<\/td>\r\n<td>[latex]\u20130.25[\/latex]<\/td>\r\n<td>[latex]\u20130.0625[\/latex]<\/td>\r\n<td>[latex]\u20130.0156[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nPlot the [latex]y[\/latex]<em>-<\/em>intercept, [latex]\\left(0,-1\\right)[\/latex], along with two other points. We can use [latex]\\left(-1,-4\\right)[\/latex] and [latex]\\left(1,-0.25\\right)[\/latex].\r\n\r\nDraw a smooth curve connecting the points:\r\n\r\n[caption id=\"attachment_5007\" align=\"aligncenter\" width=\"306\"]<img class=\"wp-image-5007\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-214x300.png\" alt=\"Graph of the function, g(x) = -(0.25)^(x), with an asymptote at y=0. Labeled points in the graph are (-1, -4), (0, -1), and (1, -0.25).\" width=\"306\" height=\"429\" \/> The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range is [latex]\\left(-\\infty ,0\\right)[\/latex], and the horizontal asymptote is [latex]y=0[\/latex].[\/caption][\/hidden-answer]<\/section><section aria-label=\"Example\">\r\n<h3>Summarizing Transformations of the Exponential Function<\/h3>\r\nNow that we have worked with each type of translation for the exponential function, we can summarize them\u00a0to arrive at the general equation for transforming exponential functions.\r\n<table style=\"width: 100%;\">\r\n<thead>\r\n<tr>\r\n<th style=\"text-align: center; width: 98.9051%;\" colspan=\"2\">Transformations of the Parent Function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/th>\r\n<\/tr>\r\n<tr>\r\n<th style=\"text-align: center; width: 70.073%;\">Translation<\/th>\r\n<th style=\"text-align: center; width: 28.8321%;\">Form<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td style=\"width: 70.073%;\">Shift\r\n<ul>\r\n \t<li>Horizontally [latex]c[\/latex]\u00a0units to the left<\/li>\r\n \t<li>Vertically [latex]d[\/latex]\u00a0units up<\/li>\r\n<\/ul>\r\n<\/td>\r\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)={b}^{x+c}+d[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 70.073%;\">Stretch and Compress\r\n<ul>\r\n \t<li>Stretch if [latex]|a| \\gt 1[\/latex]<\/li>\r\n \t<li>Compression if [latex]0 \\lt |a| \\lt 1[\/latex]<\/li>\r\n<\/ul>\r\n<\/td>\r\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=a{b}^{x}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 70.073%;\">Reflect about the [latex]x[\/latex]-axis<\/td>\r\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=-{b}^{x}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 70.073%;\">Reflect about the [latex]y[\/latex]-axis<\/td>\r\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)={b}^{-x}={\\left(\\frac{1}{b}\\right)}^{x}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 70.073%;\">General equation for all transformations<\/td>\r\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=a{b}^{x+c}+d[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>transformations of exponential functions<\/h3>\r\nA transformation of an exponential function has the form\r\n\r\n[latex] f\\left(x\\right)=a{b}^{x+c}+d[\/latex], where the parent function, [latex]y={b}^{x}[\/latex], [latex]b&gt;1[\/latex], is\r\n<ul>\r\n \t<li>shifted horizontally [latex]c[\/latex]\u00a0units to the left.<\/li>\r\n \t<li>stretched vertically by a factor of [latex]|a|[\/latex] if [latex]|a| &gt; 0[\/latex].<\/li>\r\n \t<li>compressed vertically by a factor of [latex]|a|[\/latex] if [latex]0 &lt; |a| &lt; 1[\/latex].<\/li>\r\n \t<li>shifted vertically [latex]d[\/latex]\u00a0units.<\/li>\r\n \t<li>reflected about the [latex]x[\/latex]<em>-<\/em>axis when [latex]a\u00a0&lt; 0[\/latex].<\/li>\r\n<\/ul>\r\nNote the order of the shifts, transformations, and reflections follow the order of operations.\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Write the equation for the function described below. Give the horizontal asymptote, domain, and range.\r\n<ul>\r\n \t<li>[latex]f\\left(x\\right)={e}^{x}[\/latex] is vertically stretched by a factor of [latex]2[\/latex], reflected across the [latex]y[\/latex]-axis, and then shifted up [latex]4[\/latex]\u00a0units.<\/li>\r\n<\/ul>\r\n[reveal-answer q=\"290621\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"290621\"]\r\n\r\nWe want to find an equation of the general form [latex] f\\left(x\\right)=a{b}^{x+c}+d[\/latex]. We use the description provided to find [latex]a, b, c[\/latex], and [latex]d[\/latex].\r\n<ul>\r\n \t<li>We are given the parent function [latex]f\\left(x\\right)={e}^{x}[\/latex], so [latex]b\u00a0= e[\/latex].<\/li>\r\n \t<li>The function is stretched by a factor of [latex]2[\/latex], so [latex]a\u00a0= 2[\/latex].<\/li>\r\n \t<li>The function is reflected about the [latex]y[\/latex]-axis. We replace [latex]x[\/latex]\u00a0with [latex]\u2013x[\/latex]\u00a0to get: [latex]{e}^{-x}[\/latex].<\/li>\r\n \t<li>The graph is shifted vertically [latex]4[\/latex] units, so [latex]d\u00a0= 4[\/latex].<\/li>\r\n<\/ul>\r\nSubstituting in the general form, we get:\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{llll}f\\left(x\\right)\\hfill &amp; =a{b}^{x+c}+d\\hfill \\\\ \\hfill &amp; =2{e}^{-x+0}+4\\hfill \\\\ \\hfill &amp; =2{e}^{-x}+4\\hfill \\end{array}[\/latex]<\/p>\r\nThe domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex]; the range is [latex]\\left(4,\\infty \\right)[\/latex]; the horizontal asymptote is [latex]y=4[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321400[\/ohm_question]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]321401[\/ohm_question]<\/section><\/section>","rendered":"<h2>Stretching, Compressing, or Reflecting an Exponential Function<\/h2>\n<p>While horizontal and vertical shifts involve adding constants to the input or to the function itself, a <strong>stretch<\/strong> or <strong>compression<\/strong> occurs when we multiply the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] by a constant [latex]|a|>0[\/latex].<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">For example, if we begin by graphing the parent function [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph the stretch, using [latex]a=3[\/latex], to get [latex]g\\left(x\\right)=3{\\left(2\\right)}^{x}[\/latex] and the compression, using [latex]a=\\frac{1}{3}[\/latex], to get [latex]h\\left(x\\right)=\\frac{1}{3}{\\left(2\\right)}^{x}[\/latex].<\/p>\n<figure id=\"attachment_5005\" aria-describedby=\"caption-attachment-5005\" style=\"width: 679px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5005\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-300x166.png\" alt=\"Two graphs where graph a is an example of vertical stretch and graph b is an example of vertical compression.\" width=\"679\" height=\"376\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-300x166.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-768x425.png 768w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-65x36.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-225x125.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression-350x194.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03180727\/7.1.L.Stretch-Compression.png 858w\" sizes=\"(max-width: 679px) 100vw, 679px\" \/><figcaption id=\"caption-attachment-5005\" class=\"wp-caption-text\">(a) [latex]g\\left(x\\right)=3{\\left(2\\right)}^{x}[\/latex] stretches the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically by a factor of 3. (b) [latex]h\\left(x\\right)=\\frac{1}{3}{\\left(2\\right)}^{x}[\/latex] compresses the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] vertically by a factor of [latex]\\frac{1}{3}[\/latex].<\/figcaption><\/figure>\n<\/section>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>stretches and compressions of the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/h3>\n<p>The function [latex]f\\left(x\\right)=a{b}^{x}[\/latex]<\/p>\n<ul>\n<li>is stretched vertically by a factor of [latex]a[\/latex]if [latex]|a|>1[\/latex].<\/li>\n<li>is compressed vertically by a factor of [latex]a[\/latex]\u00a0if [latex]|a|<1[\/latex].<\/li>\n<li>has a\u00a0[latex]y[\/latex]-intercept is [latex]\\left(0,a\\right)[\/latex].<\/li>\n<li>has a horizontal asymptote of [latex]y=0[\/latex], range of [latex]\\left(0,\\infty \\right)[\/latex], and domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are all unchanged from the parent function.<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">Exponential functions are stretched, compressed or reflected in the same manner you&#8217;ve used to transform other functions. Multipliers or negatives inside the function argument (in the exponent) affect horizontal transformations. Multipliers or negatives outside the function argument affect vertical transformations.<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Sketch a graph of [latex]f\\left(x\\right)=4{\\left(\\frac{1}{2}\\right)}^{x}[\/latex]. State the domain, range, and asymptote.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q418729\">Show Solution<\/button><\/p>\n<div id=\"q418729\" class=\"hidden-answer\" style=\"display: none\">Before graphing, identify the behavior and key points on the graph.<\/p>\n<ul>\n<li>Since [latex]b=\\frac{1}{2}[\/latex] is between zero and one, the left tail of the graph will increase without bound as [latex]x[\/latex]\u00a0decreases, and the right tail will approach the [latex]x[\/latex]-axis as [latex]x[\/latex]\u00a0increases.<\/li>\n<li>Since [latex]a\u00a0= 4[\/latex], the graph of [latex]f\\left(x\\right)={\\left(\\frac{1}{2}\\right)}^{x}[\/latex] will be stretched vertically by a factor of [latex]4[\/latex].<\/li>\n<li>Create a table of points:<br \/>\n<table summary=\"Two rows and eight columns. The first row is labeled,\">\n<tbody>\n<tr>\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\n<td>[latex]\u20133[\/latex]<\/td>\n<td>[latex]\u20132[\/latex]<\/td>\n<td>[latex]\u20131[\/latex]<\/td>\n<td>[latex]0[\/latex]<\/td>\n<td>[latex]1[\/latex]<\/td>\n<td>[latex]2[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<\/tr>\n<tr>\n<td><strong>[latex]f\\left(x\\right)=4\\left(\\frac{1}{2}\\right)^{x}[\/latex]<\/strong><\/td>\n<td>[latex]32[\/latex]<\/td>\n<td>[latex]16[\/latex]<\/td>\n<td>[latex]8[\/latex]<\/td>\n<td>[latex]4[\/latex]<\/td>\n<td>[latex]2[\/latex]<\/td>\n<td>[latex]1[\/latex]<\/td>\n<td>[latex]0.5[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>Plot the [latex]y[\/latex]<em>&#8211;<\/em>intercept, [latex]\\left(0,4\\right)[\/latex], along with two other points. We can use [latex]\\left(-1,8\\right)[\/latex] and [latex]\\left(1,2\\right)[\/latex].<\/li>\n<li>Draw a smooth curve connecting the points.<\/li>\n<\/ul>\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/02231155\/CNX_Precalc_Figure_04_02_0112.jpg\" alt=\"Graph of the function, f(x) = 4(1\/2)^(x), with an asymptote at y=0. Labeled points in the graph are (-1, 8), (0, 4), and (1, 2).\" width=\"487\" height=\"482\" \/><figcaption class=\"wp-caption-text\">The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range is [latex]\\left(0,\\infty \\right)[\/latex], the horizontal asymptote is y\u00a0= 0.<\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321399\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321399&theme=lumen&iframe_resize_id=ohm321399&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<h3>Graphing Reflections<\/h3>\n<p>In addition to shifting, compressing, and stretching a graph, we can also reflect it about the [latex]x[\/latex]-axis or the [latex]y[\/latex]-axis. When we multiply the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] by [latex]\u20131[\/latex], we get a reflection about the [latex]x[\/latex]-axis. When we multiply the input by[latex]\u20131[\/latex], we get a reflection about the [latex]y[\/latex]-axis.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">For example, if we begin by graphing the parent function [latex]f\\left(x\\right)={2}^{x}[\/latex], we can then graph the two reflections alongside it. The reflection about the [latex]x[\/latex]-axis, [latex]g\\left(x\\right)={-2}^{x}[\/latex], and the reflection about the [latex]y[\/latex]-axis, [latex]h\\left(x\\right)={2}^{-x}[\/latex], are both shown below.<\/p>\n<figure id=\"attachment_5009\" aria-describedby=\"caption-attachment-5009\" style=\"width: 676px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5009\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-300x233.png\" alt=\"Two graphs where graph a is an example of a reflection about the x-axis and graph b is an example of a reflection about the y-axis.\" width=\"676\" height=\"525\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-300x233.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-768x596.png 768w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-65x50.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-225x175.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections-350x272.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181721\/7.1.L.Reflections.png 815w\" sizes=\"(max-width: 676px) 100vw, 676px\" \/><figcaption id=\"caption-attachment-5009\" class=\"wp-caption-text\">(a) [latex]g\\left(x\\right)=-{2}^{x}[\/latex] reflects the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] about the x-axis. (b) [latex]h\\left(x\\right)={2}^{-x}[\/latex] reflects the graph of [latex]f\\left(x\\right)={2}^{x}[\/latex] about the y-axis.<\/figcaption><\/figure>\n<\/section>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>reflecting the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/h3>\n<p>The function [latex]f\\left(x\\right)=-{b}^{x}[\/latex]<\/p>\n<ul>\n<li>reflects the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] about the [latex]x[\/latex]-axis.<\/li>\n<li>has a [latex]y[\/latex]-intercept of [latex]\\left(0,-1\\right)[\/latex].<\/li>\n<li>has a range of [latex]\\left(-\\infty ,0\\right)[\/latex].<\/li>\n<li>has a horizontal asymptote of [latex]y=0[\/latex] and domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are unchanged from the parent function.<\/li>\n<\/ul>\n<p>The function [latex]f\\left(x\\right)={b}^{-x}[\/latex]<\/p>\n<ul>\n<li>reflects the parent function [latex]f\\left(x\\right)={b}^{x}[\/latex] about the [latex]y[\/latex]-axis.<\/li>\n<li>has a [latex]y[\/latex]-intercept of [latex]\\left(0,1\\right)[\/latex], a horizontal asymptote at [latex]y=0[\/latex], a range of [latex]\\left(0,\\infty \\right)[\/latex], and a domain of [latex]\\left(-\\infty ,\\infty \\right)[\/latex] which are unchanged from the parent function.<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find and graph the equation for a function, [latex]g\\left(x\\right)[\/latex], that reflects [latex]f\\left(x\\right)={\\left(\\frac{1}{4}\\right)}^{x}[\/latex] about the [latex]x[\/latex]-axis. State its domain, range, and asymptote.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q91748\">Show Solution<\/button><\/p>\n<div id=\"q91748\" class=\"hidden-answer\" style=\"display: none\">Since we want to reflect the parent function [latex]f\\left(x\\right)={\\left(\\frac{1}{4}\\right)}^{x}[\/latex] about the [latex]x[\/latex]<em>&#8211;<\/em>axis, we multiply [latex]f\\left(x\\right)[\/latex] by [latex]\u20131[\/latex] to get [latex]g\\left(x\\right)=-{\\left(\\frac{1}{4}\\right)}^{x}[\/latex]. Next we create a table of points.<\/p>\n<table summary=\"Two rows and eight columns. The first row is labeled,\">\n<colgroup>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/><\/colgroup>\n<tbody>\n<tr>\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\n<td>[latex]\u20133[\/latex]<\/td>\n<td>[latex]\u20132[\/latex]<\/td>\n<td>[latex]\u20131[\/latex]<\/td>\n<td>[latex]0[\/latex]<\/td>\n<td>[latex]1[\/latex]<\/td>\n<td>[latex]2[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]g\\left(x\\right)=-\\left(\\frac{1}{4}\\right)^{x}[\/latex]<\/td>\n<td>[latex]\u201364[\/latex]<\/td>\n<td>[latex]\u201316[\/latex]<\/td>\n<td>[latex]\u20134[\/latex]<\/td>\n<td>[latex]\u20131[\/latex]<\/td>\n<td>[latex]\u20130.25[\/latex]<\/td>\n<td>[latex]\u20130.0625[\/latex]<\/td>\n<td>[latex]\u20130.0156[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Plot the [latex]y[\/latex]<em>&#8211;<\/em>intercept, [latex]\\left(0,-1\\right)[\/latex], along with two other points. We can use [latex]\\left(-1,-4\\right)[\/latex] and [latex]\\left(1,-0.25\\right)[\/latex].<\/p>\n<p>Draw a smooth curve connecting the points:<\/p>\n<figure id=\"attachment_5007\" aria-describedby=\"caption-attachment-5007\" style=\"width: 306px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5007\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-214x300.png\" alt=\"Graph of the function, g(x) = -(0.25)^(x), with an asymptote at y=0. Labeled points in the graph are (-1, -4), (0, -1), and (1, -0.25).\" width=\"306\" height=\"429\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-214x300.png 214w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-65x91.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-225x315.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_-350x490.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/61\/2025\/07\/03181030\/7.1.L.gx_.png 375w\" sizes=\"(max-width: 306px) 100vw, 306px\" \/><figcaption id=\"caption-attachment-5007\" class=\"wp-caption-text\">The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex], the range is [latex]\\left(-\\infty ,0\\right)[\/latex], and the horizontal asymptote is [latex]y=0[\/latex].<\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/section>\n<section aria-label=\"Example\">\n<h3>Summarizing Transformations of the Exponential Function<\/h3>\n<p>Now that we have worked with each type of translation for the exponential function, we can summarize them\u00a0to arrive at the general equation for transforming exponential functions.<\/p>\n<table style=\"width: 100%;\">\n<thead>\n<tr>\n<th style=\"text-align: center; width: 98.9051%;\" colspan=\"2\">Transformations of the Parent Function [latex]f\\left(x\\right)={b}^{x}[\/latex]<\/th>\n<\/tr>\n<tr>\n<th style=\"text-align: center; width: 70.073%;\">Translation<\/th>\n<th style=\"text-align: center; width: 28.8321%;\">Form<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td style=\"width: 70.073%;\">Shift<\/p>\n<ul>\n<li>Horizontally [latex]c[\/latex]\u00a0units to the left<\/li>\n<li>Vertically [latex]d[\/latex]\u00a0units up<\/li>\n<\/ul>\n<\/td>\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)={b}^{x+c}+d[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 70.073%;\">Stretch and Compress<\/p>\n<ul>\n<li>Stretch if [latex]|a| \\gt 1[\/latex]<\/li>\n<li>Compression if [latex]0 \\lt |a| \\lt 1[\/latex]<\/li>\n<\/ul>\n<\/td>\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=a{b}^{x}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 70.073%;\">Reflect about the [latex]x[\/latex]-axis<\/td>\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=-{b}^{x}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 70.073%;\">Reflect about the [latex]y[\/latex]-axis<\/td>\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)={b}^{-x}={\\left(\\frac{1}{b}\\right)}^{x}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 70.073%;\">General equation for all transformations<\/td>\n<td style=\"width: 28.8321%;\">[latex]f\\left(x\\right)=a{b}^{x+c}+d[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>transformations of exponential functions<\/h3>\n<p>A transformation of an exponential function has the form<\/p>\n<p>[latex]f\\left(x\\right)=a{b}^{x+c}+d[\/latex], where the parent function, [latex]y={b}^{x}[\/latex], [latex]b>1[\/latex], is<\/p>\n<ul>\n<li>shifted horizontally [latex]c[\/latex]\u00a0units to the left.<\/li>\n<li>stretched vertically by a factor of [latex]|a|[\/latex] if [latex]|a| > 0[\/latex].<\/li>\n<li>compressed vertically by a factor of [latex]|a|[\/latex] if [latex]0 < |a| < 1[\/latex].<\/li>\n<li>shifted vertically [latex]d[\/latex]\u00a0units.<\/li>\n<li>reflected about the [latex]x[\/latex]<em>&#8211;<\/em>axis when [latex]a\u00a0< 0[\/latex].<\/li>\n<\/ul>\n<p>Note the order of the shifts, transformations, and reflections follow the order of operations.<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Write the equation for the function described below. Give the horizontal asymptote, domain, and range.<\/p>\n<ul>\n<li>[latex]f\\left(x\\right)={e}^{x}[\/latex] is vertically stretched by a factor of [latex]2[\/latex], reflected across the [latex]y[\/latex]-axis, and then shifted up [latex]4[\/latex]\u00a0units.<\/li>\n<\/ul>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q290621\">Show Solution<\/button><\/p>\n<div id=\"q290621\" class=\"hidden-answer\" style=\"display: none\">\n<p>We want to find an equation of the general form [latex]f\\left(x\\right)=a{b}^{x+c}+d[\/latex]. We use the description provided to find [latex]a, b, c[\/latex], and [latex]d[\/latex].<\/p>\n<ul>\n<li>We are given the parent function [latex]f\\left(x\\right)={e}^{x}[\/latex], so [latex]b\u00a0= e[\/latex].<\/li>\n<li>The function is stretched by a factor of [latex]2[\/latex], so [latex]a\u00a0= 2[\/latex].<\/li>\n<li>The function is reflected about the [latex]y[\/latex]-axis. We replace [latex]x[\/latex]\u00a0with [latex]\u2013x[\/latex]\u00a0to get: [latex]{e}^{-x}[\/latex].<\/li>\n<li>The graph is shifted vertically [latex]4[\/latex] units, so [latex]d\u00a0= 4[\/latex].<\/li>\n<\/ul>\n<p>Substituting in the general form, we get:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{llll}f\\left(x\\right)\\hfill & =a{b}^{x+c}+d\\hfill \\\\ \\hfill & =2{e}^{-x+0}+4\\hfill \\\\ \\hfill & =2{e}^{-x}+4\\hfill \\end{array}[\/latex]<\/p>\n<p>The domain is [latex]\\left(-\\infty ,\\infty \\right)[\/latex]; the range is [latex]\\left(4,\\infty \\right)[\/latex]; the horizontal asymptote is [latex]y=4[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321400\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321400&theme=lumen&iframe_resize_id=ohm321400&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm321401\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=321401&theme=lumen&iframe_resize_id=ohm321401&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<\/section>\n","protected":false},"author":13,"menu_order":9,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":105,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1056"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":9,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1056\/revisions"}],"predecessor-version":[{"id":5875,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1056\/revisions\/5875"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/105"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1056\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1056"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1056"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1056"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1056"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}