{"id":1039,"date":"2025-07-21T22:50:53","date_gmt":"2025-07-21T22:50:53","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=1039"},"modified":"2026-01-14T19:38:21","modified_gmt":"2026-01-14T19:38:21","slug":"variation-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/precalculus\/chapter\/variation-learn-it-3\/","title":{"raw":"Variation: Learn It 3","rendered":"Variation: Learn It 3"},"content":{"raw":"<h2>Joint Variation<\/h2>\r\nMany situations are more complicated than a basic direct variation or inverse variation model. One variable often depends on multiple other variables. When a variable is dependent on the product or quotient of two or more variables, this is called <strong>joint variation<\/strong>. This concept extends the idea of direct variation to multiple variables and is often used in various scientific and engineering contexts.\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>joint variation<\/h3>\r\nJoint variation occurs when a variable varies directly or inversely with multiple variables.\r\n\r\nFor instance:\r\n<ul>\r\n \t<li>If [latex]x[\/latex] varies directly with both [latex]y[\/latex] and [latex]z[\/latex], we have [latex]x=kyz[\/latex].<\/li>\r\n \t<li>If [latex]x[\/latex] varies directly with [latex]y[\/latex] and inversely with [latex]z[\/latex], we have [latex]x=\\dfrac{ky}{z}[\/latex].<\/li>\r\n<\/ul>\r\nNotice that we only use one constant in a joint variation equation.\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">A quantity [latex]x[\/latex]\u00a0varies directly with the square of [latex]y[\/latex]\u00a0and inversely with the cube root of [latex]z[\/latex]. If [latex]x=6[\/latex]\u00a0when [latex]y=2[\/latex]\u00a0and [latex]z=8[\/latex], find [latex]x[\/latex]\u00a0when [latex]y=1[\/latex]\u00a0and [latex]z=27[\/latex].[reveal-answer q=\"396823\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"396823\"]Begin by writing an equation to show the relationship between the variables.\r\n<p style=\"text-align: center;\">[latex]x=\\dfrac{k{y}^{2}}{\\sqrt[3]{z}}[\/latex]<\/p>\r\nSubstitute [latex]x=6[\/latex], [latex]y=2[\/latex], and [latex]z=8[\/latex]\u00a0to find the value of the constant [latex]k[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\begin{align}6&amp;=\\dfrac{k{2}^{2}}{\\sqrt[3]{8}} \\\\[1mm] 6&amp;=\\dfrac{4k}{2} \\\\[1mm] 3&amp;=k \\end{align}[\/latex]<\/p>\r\nNow we can substitute the value of the constant into the equation for the relationship.\r\n<p style=\"text-align: center;\">[latex]x=\\dfrac{3{y}^{2}}{\\sqrt[3]{z}}[\/latex]<\/p>\r\nTo find [latex]x[\/latex]\u00a0when [latex]y=1[\/latex]\u00a0and [latex]z=27[\/latex], we will substitute values for [latex]y[\/latex]\u00a0and [latex]z[\/latex]\u00a0into our equation.\r\n<p style=\"text-align: center;\">[latex]\\begin{align}x&amp;=\\dfrac{3{\\left(1\\right)}^{2}}{\\sqrt[3]{27}} \\\\[1mm] &amp;=1 \\end{align}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]318961[\/ohm_question]<\/section><section class=\"textbox tryIt\" aria-label=\"Try It\">[ohm_question hide_question_numbers=1]318962[\/ohm_question]<\/section>","rendered":"<h2>Joint Variation<\/h2>\n<p>Many situations are more complicated than a basic direct variation or inverse variation model. One variable often depends on multiple other variables. When a variable is dependent on the product or quotient of two or more variables, this is called <strong>joint variation<\/strong>. This concept extends the idea of direct variation to multiple variables and is often used in various scientific and engineering contexts.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>joint variation<\/h3>\n<p>Joint variation occurs when a variable varies directly or inversely with multiple variables.<\/p>\n<p>For instance:<\/p>\n<ul>\n<li>If [latex]x[\/latex] varies directly with both [latex]y[\/latex] and [latex]z[\/latex], we have [latex]x=kyz[\/latex].<\/li>\n<li>If [latex]x[\/latex] varies directly with [latex]y[\/latex] and inversely with [latex]z[\/latex], we have [latex]x=\\dfrac{ky}{z}[\/latex].<\/li>\n<\/ul>\n<p>Notice that we only use one constant in a joint variation equation.<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">A quantity [latex]x[\/latex]\u00a0varies directly with the square of [latex]y[\/latex]\u00a0and inversely with the cube root of [latex]z[\/latex]. If [latex]x=6[\/latex]\u00a0when [latex]y=2[\/latex]\u00a0and [latex]z=8[\/latex], find [latex]x[\/latex]\u00a0when [latex]y=1[\/latex]\u00a0and [latex]z=27[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q396823\">Show Solution<\/button><\/p>\n<div id=\"q396823\" class=\"hidden-answer\" style=\"display: none\">Begin by writing an equation to show the relationship between the variables.<\/p>\n<p style=\"text-align: center;\">[latex]x=\\dfrac{k{y}^{2}}{\\sqrt[3]{z}}[\/latex]<\/p>\n<p>Substitute [latex]x=6[\/latex], [latex]y=2[\/latex], and [latex]z=8[\/latex]\u00a0to find the value of the constant [latex]k[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}6&=\\dfrac{k{2}^{2}}{\\sqrt[3]{8}} \\\\[1mm] 6&=\\dfrac{4k}{2} \\\\[1mm] 3&=k \\end{align}[\/latex]<\/p>\n<p>Now we can substitute the value of the constant into the equation for the relationship.<\/p>\n<p style=\"text-align: center;\">[latex]x=\\dfrac{3{y}^{2}}{\\sqrt[3]{z}}[\/latex]<\/p>\n<p>To find [latex]x[\/latex]\u00a0when [latex]y=1[\/latex]\u00a0and [latex]z=27[\/latex], we will substitute values for [latex]y[\/latex]\u00a0and [latex]z[\/latex]\u00a0into our equation.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}x&=\\dfrac{3{\\left(1\\right)}^{2}}{\\sqrt[3]{27}} \\\\[1mm] &=1 \\end{align}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm318961\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318961&theme=lumen&iframe_resize_id=ohm318961&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\" aria-label=\"Try It\"><iframe loading=\"lazy\" id=\"ohm318962\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=318962&theme=lumen&iframe_resize_id=ohm318962&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":13,"menu_order":22,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":508,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1039"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/13"}],"version-history":[{"count":3,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1039\/revisions"}],"predecessor-version":[{"id":5365,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1039\/revisions\/5365"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/508"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/1039\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=1039"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=1039"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=1039"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=1039"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}