{"id":999,"date":"2024-05-01T21:11:23","date_gmt":"2024-05-01T21:11:23","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/?post_type=chapter&#038;p=999"},"modified":"2025-08-13T15:12:20","modified_gmt":"2025-08-13T15:12:20","slug":"graphing-and-analyzing-linear-equations-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/chapter\/graphing-and-analyzing-linear-equations-learn-it-4\/","title":{"raw":"Graphing and Analyzing Linear Equations: Learn It 4","rendered":"Graphing and Analyzing Linear Equations: Learn It 4"},"content":{"raw":"<h2><strong>Slope of a Linear Equation<\/strong><\/h2>\r\nThe <strong>slope<\/strong> of a line refers to the ratio of the vertical change in <em>y<\/em> over the horizontal change in <em>x<\/em> between any two points on a line. It indicates the direction in which a line slants as well as its steepness. Slope is sometimes described as rise over run.\r\n<div style=\"text-align: center;\">[latex]m=\\dfrac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex]<\/div>\r\nIf the slope is positive, the line slants upward to the right. If the slope is negative, the line slants downward to the right. As the slope increases, the line becomes steeper. Some examples are shown below. The lines indicate the following slopes: [latex]m=-3[\/latex], [latex]m=2[\/latex], and [latex]m=\\frac{1}{3}[\/latex].\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/11185922\/CNX_CAT_Figure_02_02_002.jpg\" alt=\"Coordinate plane with the x and y axes ranging from negative 10 to 10. Three linear functions are plotted: y = negative 3 times x minus 2; y = 2 times x plus 1; and y = x over 3 plus 2.\" width=\"487\" height=\"442\" \/> Coordinate plane with three linear functions plotted[\/caption]\r\n\r\n<section class=\"textbox keyTakeaway\">\r\n<h3>Slope of a Line<\/h3>\r\nThe <strong>slope<\/strong> of a line is a measure of its steepness or the angle at which it tilts, expressed as the ratio of the rise (the vertical change) to the run (the horizontal change) between any two points on the line. It quantifies how much the line goes up or down as it moves from left to right.\r\n<ul>\r\n \t<li>A <strong>positive<\/strong> slope means that the line rises from left to right.<\/li>\r\n \t<li>A <strong>negative<\/strong> slope means that the line falls from left to right.<\/li>\r\n \t<li>A slope of\u00a0<strong>zero<\/strong> means the line is flat.<\/li>\r\n<\/ul>\r\nMathematically, the slope is calculated by its rise-to-run ratio:\r\n<p style=\"text-align: center;\">[latex]\\text{slope} = \\dfrac{\\text{rise}}{\\text{run}}[\/latex]<\/p>\r\n&nbsp;\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"301\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5826\/2022\/09\/23234536\/image031.jpeg\" alt=\"A graph illustrating a straight, diagonal line. Points 1 and 2 are labeled, with how to find the measurements for rise and run detailed.\" width=\"301\" height=\"290\" \/> A graph illustrating a straight diagonal line with labels[\/caption]\r\n\r\n&nbsp;\r\n\r\nGiven two points, [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] and [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex], the following formula determines the slope of a line containing these points:\r\n<div style=\"text-align: center;\">[latex]m=\\dfrac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex]<\/div>\r\n<\/section><section class=\"textbox example\">Find the slope of the line:\r\n\r\n[caption id=\"attachment_996\" align=\"aligncenter\" width=\"300\"]<img class=\"wp-image-996 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-300x282.png\" alt=\"\" width=\"300\" height=\"282\" \/> A graph with a linear function with labels for rise and run[\/caption]\r\n\r\n[reveal-answer q=\"746921\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"746921\"]\r\n<ul>\r\n \t<li>Start from a point on the left side of line, such as [latex](2, 1)[\/latex] and move vertically until in line with another point on the line, such as [latex](6, 3)[\/latex]. The rise is [latex]2[\/latex] units. It is positive because you go up. If it is going down, use a negative to represent that.<\/li>\r\n \t<li>Next, move horizontally to the point [latex](6, 3)[\/latex], a point that is to the right of the first point you picked. Count the number of units. The run is [latex]4[\/latex] units. Always make sure that you count to the right.<\/li>\r\n<\/ul>\r\nThen, solve using the formula:\r\n<p style=\"text-align: center;\">[latex]\\text{slope} = \\dfrac{\\text{rise}}{\\text{run}} = \\dfrac{2}{4} = \\dfrac{1}{2}[\/latex].<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox proTip\">When you need to calculate the slope of a line, remember that you can select <strong>any two points<\/strong> along the line to perform your calculation.\r\n<ul>\r\n \t<li>Choose points that are clear and easy to identify on the graph. This often means selecting points where the line crosses grid lines, as the coordinates are straightforward to read.<\/li>\r\n \t<li>Start by selecting the clearest leftmost point where the line intersects the grid, then choose a second point to the right, ensuring it also clearly falls on a grid intersection.<\/li>\r\n \t<li>Measure the vertical change (rise), noting if it increases (positive) or decreases (negative), then measure the horizontal distance (run), which is always positive as you move from left to right, to calculate the slope.<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the slope of a line that passes through the points [latex]\\left(2,-1\\right)[\/latex] and [latex]\\left(-5,3\\right)[\/latex].\r\n[reveal-answer q=\"688301\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"688301\"]We substitute the <em>y-<\/em>values and the <em>x-<\/em>values into the formula.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}m\\hfill&amp;=\\frac{3-\\left(-1\\right)}{-5 - 2}\\hfill \\\\ \\hfill&amp;=\\frac{4}{-7}\\hfill \\\\ \\hfill&amp;=-\\frac{4}{7}\\hfill \\end{array}[\/latex]<\/div>\r\nThe slope is [latex]-\\frac{4}{7}[\/latex].\r\n\r\n<strong>Analysis of the Solution<\/strong>\r\n\r\nIt does not matter which point is called [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] or [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex]. As long as we are consistent with the order of the <em>y<\/em> terms and the order of the <em>x<\/em> terms in the numerator and denominator, the calculation will yield the same result.\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]18920[\/ohm2_question]<\/section>","rendered":"<h2><strong>Slope of a Linear Equation<\/strong><\/h2>\n<p>The <strong>slope<\/strong> of a line refers to the ratio of the vertical change in <em>y<\/em> over the horizontal change in <em>x<\/em> between any two points on a line. It indicates the direction in which a line slants as well as its steepness. Slope is sometimes described as rise over run.<\/p>\n<div style=\"text-align: center;\">[latex]m=\\dfrac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex]<\/div>\n<p>If the slope is positive, the line slants upward to the right. If the slope is negative, the line slants downward to the right. As the slope increases, the line becomes steeper. Some examples are shown below. The lines indicate the following slopes: [latex]m=-3[\/latex], [latex]m=2[\/latex], and [latex]m=\\frac{1}{3}[\/latex].<\/p>\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/11185922\/CNX_CAT_Figure_02_02_002.jpg\" alt=\"Coordinate plane with the x and y axes ranging from negative 10 to 10. Three linear functions are plotted: y = negative 3 times x minus 2; y = 2 times x plus 1; and y = x over 3 plus 2.\" width=\"487\" height=\"442\" \/><figcaption class=\"wp-caption-text\">Coordinate plane with three linear functions plotted<\/figcaption><\/figure>\n<section class=\"textbox keyTakeaway\">\n<h3>Slope of a Line<\/h3>\n<p>The <strong>slope<\/strong> of a line is a measure of its steepness or the angle at which it tilts, expressed as the ratio of the rise (the vertical change) to the run (the horizontal change) between any two points on the line. It quantifies how much the line goes up or down as it moves from left to right.<\/p>\n<ul>\n<li>A <strong>positive<\/strong> slope means that the line rises from left to right.<\/li>\n<li>A <strong>negative<\/strong> slope means that the line falls from left to right.<\/li>\n<li>A slope of\u00a0<strong>zero<\/strong> means the line is flat.<\/li>\n<\/ul>\n<p>Mathematically, the slope is calculated by its rise-to-run ratio:<\/p>\n<p style=\"text-align: center;\">[latex]\\text{slope} = \\dfrac{\\text{rise}}{\\text{run}}[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<figure style=\"width: 301px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5826\/2022\/09\/23234536\/image031.jpeg\" alt=\"A graph illustrating a straight, diagonal line. Points 1 and 2 are labeled, with how to find the measurements for rise and run detailed.\" width=\"301\" height=\"290\" \/><figcaption class=\"wp-caption-text\">A graph illustrating a straight diagonal line with labels<\/figcaption><\/figure>\n<p>&nbsp;<\/p>\n<p>Given two points, [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] and [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex], the following formula determines the slope of a line containing these points:<\/p>\n<div style=\"text-align: center;\">[latex]m=\\dfrac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex]<\/div>\n<\/section>\n<section class=\"textbox example\">Find the slope of the line:<\/p>\n<figure id=\"attachment_996\" aria-describedby=\"caption-attachment-996\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-996 size-medium\" src=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-300x282.png\" alt=\"\" width=\"300\" height=\"282\" srcset=\"https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-300x282.png 300w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-65x61.png 65w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-225x211.png 225w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008-350x329.png 350w, https:\/\/content-cdn.one.lumenlearning.com\/wp-content\/uploads\/sites\/42\/2024\/05\/01205416\/IMG_Econ_01_008.png 480w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-996\" class=\"wp-caption-text\">A graph with a linear function with labels for rise and run<\/figcaption><\/figure>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q746921\">Show Answer<\/button><\/p>\n<div id=\"q746921\" class=\"hidden-answer\" style=\"display: none\">\n<ul>\n<li>Start from a point on the left side of line, such as [latex](2, 1)[\/latex] and move vertically until in line with another point on the line, such as [latex](6, 3)[\/latex]. The rise is [latex]2[\/latex] units. It is positive because you go up. If it is going down, use a negative to represent that.<\/li>\n<li>Next, move horizontally to the point [latex](6, 3)[\/latex], a point that is to the right of the first point you picked. Count the number of units. The run is [latex]4[\/latex] units. Always make sure that you count to the right.<\/li>\n<\/ul>\n<p>Then, solve using the formula:<\/p>\n<p style=\"text-align: center;\">[latex]\\text{slope} = \\dfrac{\\text{rise}}{\\text{run}} = \\dfrac{2}{4} = \\dfrac{1}{2}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox proTip\">When you need to calculate the slope of a line, remember that you can select <strong>any two points<\/strong> along the line to perform your calculation.<\/p>\n<ul>\n<li>Choose points that are clear and easy to identify on the graph. This often means selecting points where the line crosses grid lines, as the coordinates are straightforward to read.<\/li>\n<li>Start by selecting the clearest leftmost point where the line intersects the grid, then choose a second point to the right, ensuring it also clearly falls on a grid intersection.<\/li>\n<li>Measure the vertical change (rise), noting if it increases (positive) or decreases (negative), then measure the horizontal distance (run), which is always positive as you move from left to right, to calculate the slope.<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the slope of a line that passes through the points [latex]\\left(2,-1\\right)[\/latex] and [latex]\\left(-5,3\\right)[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q688301\">Show Solution<\/button><\/p>\n<div id=\"q688301\" class=\"hidden-answer\" style=\"display: none\">We substitute the <em>y-<\/em>values and the <em>x-<\/em>values into the formula.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}m\\hfill&=\\frac{3-\\left(-1\\right)}{-5 - 2}\\hfill \\\\ \\hfill&=\\frac{4}{-7}\\hfill \\\\ \\hfill&=-\\frac{4}{7}\\hfill \\end{array}[\/latex]<\/div>\n<p>The slope is [latex]-\\frac{4}{7}[\/latex].<\/p>\n<p><strong>Analysis of the Solution<\/strong><\/p>\n<p>It does not matter which point is called [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] or [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex]. As long as we are consistent with the order of the <em>y<\/em> terms and the order of the <em>x<\/em> terms in the numerator and denominator, the calculation will yield the same result.\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm18920\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=18920&theme=lumen&iframe_resize_id=ohm18920&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":12,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":75,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/999"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/users\/12"}],"version-history":[{"count":12,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/999\/revisions"}],"predecessor-version":[{"id":7585,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/999\/revisions\/7585"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/parts\/75"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/999\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/media?parent=999"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=999"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/contributor?post=999"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/license?post=999"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}