{"id":4154,"date":"2024-09-18T15:30:40","date_gmt":"2024-09-18T15:30:40","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/?post_type=chapter&#038;p=4154"},"modified":"2025-08-14T01:09:24","modified_gmt":"2025-08-14T01:09:24","slug":"complex-numbers-and-operations-learn-it-5","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/chapter\/complex-numbers-and-operations-learn-it-5\/","title":{"raw":"Complex Numbers and Operations: Learn It 5","rendered":"Complex Numbers and Operations: Learn It 5"},"content":{"raw":"<h2>Complex\u00a0Roots<\/h2>\r\nRecall that we find the <span class=\"s1\">[latex]y[\/latex]<\/span>-intercept of a quadratic by evaluating the function at an input of zero, and we find the <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts at locations where the output is zero. Notice\u00a0that the number of <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts can vary depending upon the location of the graph.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"975\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/02170357\/CNX_Precalc_Figure_03_02_0132.jpg\" alt=\"Three graphs where the first graph shows a parabola with no x-intercept, the second is a parabola with one \u2013intercept, and the third parabola is of two x-intercepts.\" width=\"975\" height=\"317\" \/> Number of <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts of a parabola[\/caption]While factoring is often the first method we try when solving for [latex]x[\/latex]-intercepts, it's not always possible or practical. Some quadratic equations cannot be easily factored, especially those with irrational or complex roots. In these cases, you'll need a more powerful tool: the quadratic formula.\r\n\r\n<section class=\"textbox recall\" aria-label=\"Recall\">\r\n<p class=\"whitespace-pre-wrap break-words\">The quadratic formula for an equation in the form [latex]ax^2 + bx + c = 0[\/latex] is:<\/p>\r\n<p class=\"whitespace-pre-wrap break-words\" style=\"text-align: center;\">[latex]x = \\frac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}[\/latex]<\/p>\r\n<p class=\"whitespace-pre-wrap break-words\">Where:<\/p>\r\n\r\n<ul class=\"-mt-1 list-disc space-y-2 pl-8\">\r\n \t<li class=\"whitespace-normal break-words\">[latex]a[\/latex] is the coefficient of [latex]x^2[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words\">[latex]b[\/latex] is the coefficient of [latex]x[\/latex]<\/li>\r\n \t<li class=\"whitespace-normal break-words\">[latex]c[\/latex] is the constant term<\/li>\r\n \t<li class=\"whitespace-normal break-words\">[latex]\\pm[\/latex] means we consider both addition and subtraction<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Solve [latex]{x}^{2}+x+2=0[\/latex] using the quadratic formula.[reveal-answer q=\"757696\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"757696\"]Let\u2019s begin by writing the quadratic formula:<center>[latex]x=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a}[\/latex]<\/center>When applying the quadratic formula, we identify the coefficients [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex]. For the equation [latex]{x}^{2}+x+2=0[\/latex], we have [latex]a=1[\/latex], [latex]b=1[\/latex], and [latex]c=2[\/latex].\u00a0Substituting these values into the formula we have:\r\n<p style=\"text-align: center;\">[latex]\\begin{align}x&amp;=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a} \\\\[1.5mm] &amp;=\\dfrac{-1\\pm \\sqrt{{1}^{2}-4\\cdot 1\\cdot \\left(2\\right)}}{2\\cdot 1} \\\\[1.5mm] &amp;=\\dfrac{-1\\pm \\sqrt{1 - 8}}{2} \\\\[1.5mm] &amp;=\\dfrac{-1\\pm \\sqrt{-7}}{2} \\\\[1.5mm] &amp;=\\dfrac{-1\\pm i\\sqrt{7}}{2} \\end{align}[\/latex]<\/p>\r\nThe solutions to the equation are [latex]x=\\dfrac{-1+i\\sqrt{7}}{2}[\/latex] and [latex]x=\\dfrac{-1-i\\sqrt{7}}{2}[\/latex] or [latex]x=-\\dfrac{1}{2}+\\dfrac{i\\sqrt{7}}{2}[\/latex] and [latex]x=-\\dfrac{1}{2}-\\dfrac{i\\sqrt{7}}{2}[\/latex].\r\n\r\n<strong>Analysis of the Solution<\/strong>\r\n\r\nThis quadratic equation has only non-real solutions.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section>Now you will hopefully begin to understand why we introduced complex numbers at the beginning of this module. The example we just solved demonstrates a crucial concept in algebra: not all quadratic equations have real solutions. When the discriminant ([latex]b^2 - 4ac[\/latex]) is negative, we encounter complex roots. These complex roots always come in conjugate pairs, meaning if [latex]a + bi[\/latex] is a solution, then [latex]a - bi[\/latex] is also a solution.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">Consider the following function: [latex]f(x)=x^2+2x+3[\/latex], and it's graph below:\r\n\r\n[caption id=\"attachment_4477\" align=\"alignnone\" width=\"300\"]<img class=\"wp-image-4477 size-medium\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1916\/2016\/11\/18034032\/desmos-graph-300x300.png\" alt=\"Graph of quadratic function with the following points (-1,2), (-2,3), (0,3), (1,6), (-3,6). \" width=\"300\" height=\"300\" \/> Graph of a quadratic function[\/caption]\r\n\r\nDoes this function have roots? It's probably obvious that this function does not cross the [latex]x[\/latex]-axis, therefore it doesn't have any [latex]x[\/latex]-intercepts. Recall that the [latex]x[\/latex]-intercepts of a function are found by setting the function equal to zero:\r\n<p style=\"text-align: center;\">[latex]x^2+2x+3=0[\/latex]<\/p>\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Find the [latex]x[\/latex]-intercepts of the quadratic function.\r\n<p style=\"text-align: center;\">[latex]f(x)=x^2+2x+3[\/latex]<\/p>\r\n[reveal-answer q=\"698410\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"698410\"]\r\n\r\nThe [latex]x[\/latex]-intercepts of the function\u00a0[latex]f(x)=x^2+2x+3[\/latex] are found by setting it equal to zero, and solving for [latex]x[\/latex] since the [latex]y[\/latex] values of the [latex]x[\/latex]-intercepts are zero.\r\n\r\nFirst, identify [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex].\r\n<p style=\"text-align: center;\">[latex]x^2+2x+3=0[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]a=1,b=2,c=3[\/latex]<\/p>\r\nSubstitute these values into the quadratic formula.\r\n<p style=\"text-align: center;\">[latex]\\begin{align}x&amp;=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a}\\\\[1mm]&amp;=\\dfrac{-2\\pm \\sqrt{{2}^{2}-4(1)(3)}}{2(1)}\\\\[1mm]&amp;=\\dfrac{-2\\pm \\sqrt{4-12}}{2} \\\\[1mm]&amp;=\\dfrac{-2\\pm \\sqrt{-8}}{2}\\\\[1mm]&amp;=\\dfrac{-2\\pm 2i\\sqrt{2}}{2} \\\\[1mm]&amp;=-1\\pm i\\sqrt{2}\\\\[1mm]x&amp;=-1+i\\sqrt{2},-1-i\\sqrt{2}\\end{align}[\/latex]<\/p>\r\nThe solutions to this equation are complex, therefore there are no [latex]x[\/latex]-intercepts for the function\u00a0[latex]f(x)=x^2+2x+3[\/latex] in the set of real numbers that can be plotted on the Cartesian Coordinate plane. The graph of the function is plotted on the Cartesian Coordinate plane below:\r\n\r\n[caption id=\"attachment_4477\" align=\"aligncenter\" width=\"300\"]<img class=\"wp-image-4477 size-medium\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1916\/2016\/11\/18034032\/desmos-graph-300x300.png\" alt=\"Graph of quadratic function with the following points (-1,2), (-2,3), (0,3), (1,6), (-3,6). \" width=\"300\" height=\"300\" \/> Graph of quadratic function with no [latex]x[\/latex]-intercepts in the real numbers.[\/caption]Note how the graph does not cross the [latex]x[\/latex]-axis, therefore there are no real [latex]x[\/latex]-intercepts for this function.[\/hidden-answer]<\/section><section aria-label=\"Example\">\r\n<div><section aria-label=\"Try It\">\r\n<h3>The Discriminant<\/h3>\r\nThe <strong>quadratic formula<\/strong> not only generates the solutions to a quadratic equation, it tells us about the nature of the solutions when we consider the <strong>discriminant<\/strong>, or the expression under the radical, [latex]{b}^{2}-4ac[\/latex]. The discriminant tells us whether the solutions are real numbers or complex numbers as well as how many solutions of each type to expect. The table below\u00a0relates the value of the discriminant to the solutions of a quadratic equation.\r\n<table summary=\"A table with 5 rows and 2 columns. The entries in the first row are: Value of Discriminant and Results. The entries in the second row are: b squared minus four times a times c equals zero and One rational solution (double solution). The entries in the third row are: b squared minus four times a times c is greater than zero, perfect square and Two rational solutions. The entries in the fourth row are: b squared minus four times a times c is greater than zero, not a perfect square and Two irrational solutions. The entries in the fifth row are: b squared minus four times a times c is less than zero and Two complex solutions.\">\r\n<thead>\r\n<tr>\r\n<th>Value of Discriminant<\/th>\r\n<th>Results<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>[latex]{b}^{2}-4ac=0[\/latex]<\/td>\r\n<td>One rational solution (double solution)<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex]{b}^{2}-4ac&gt;0[\/latex], perfect square<\/td>\r\n<td>Two rational solutions<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex]{b}^{2}-4ac&gt;0[\/latex], not a perfect square<\/td>\r\n<td>Two irrational solutions<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex]{b}^{2}-4ac&lt;0[\/latex]<\/td>\r\n<td>Two complex solutions<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/section><\/div>\r\n<section class=\"textbox keyTakeaway\">\r\n<h3>discriminant<\/h3>\r\nFor [latex]a{x}^{2}+bx+c=0[\/latex], where [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex] are real numbers, the <strong>discriminant<\/strong> is the expression under the radical in the quadratic formula:\r\n\r\n&nbsp;\r\n<p style=\"text-align: center;\">[latex]{b}^{2}-4ac[\/latex].<\/p>\r\n&nbsp;\r\n\r\nIt tells us whether the solutions are real numbers or complex numbers and how many solutions of each type to expect.\r\n\r\n<\/section><section class=\"textbox example\">Use the discriminant to find the nature of the solutions to the following quadratic equations:\r\n<ol>\r\n \t<li>[latex]{x}^{2}+4x+4=0[\/latex]<\/li>\r\n \t<li>[latex]8{x}^{2}+14x+3=0[\/latex]<\/li>\r\n \t<li>[latex]3{x}^{2}-5x - 2=0[\/latex]<\/li>\r\n \t<li>[latex]3{x}^{2}-10x+15=0[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"229118\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"229118\"]\r\n\r\nCalculate the discriminant [latex]{b}^{2}-4ac[\/latex] for each equation and state the expected type of solutions.\r\n<ol>\r\n \t<li>[latex]{x}^{2}+4x+4=0[\/latex]: [latex]{b}^{2}-4ac={\\left(4\\right)}^{2}-4\\left(1\\right)\\left(4\\right)=0[\/latex]. There will be one rational double solution.<\/li>\r\n \t<li>[latex]8{x}^{2}+14x+3=0[\/latex]: [latex]{b}^{2}-4ac={\\left(14\\right)}^{2}-4\\left(8\\right)\\left(3\\right)=100[\/latex]. As [latex]100[\/latex] is a perfect square, there will be two rational solutions.<\/li>\r\n \t<li>[latex]3{x}^{2}-5x - 2=0[\/latex]: [latex]{b}^{2}-4ac={\\left(-5\\right)}^{2}-4\\left(3\\right)\\left(-2\\right)=49[\/latex]. As [latex]49[\/latex] is a perfect square, there will be two rational solutions.<\/li>\r\n \t<li>[latex]3{x}^{2}-10x+15=0[\/latex]: [latex]{b}^{2}-4ac={\\left(-10\\right)}^{2}-4\\left(3\\right)\\left(15\\right)=-80[\/latex]. There will be two complex solutions.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]18968[\/ohm2_question]<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]18970[\/ohm2_question]<\/section><\/section>","rendered":"<h2>Complex\u00a0Roots<\/h2>\n<p>Recall that we find the <span class=\"s1\">[latex]y[\/latex]<\/span>-intercept of a quadratic by evaluating the function at an input of zero, and we find the <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts at locations where the output is zero. Notice\u00a0that the number of <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts can vary depending upon the location of the graph.<\/p>\n<figure style=\"width: 975px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/11\/02170357\/CNX_Precalc_Figure_03_02_0132.jpg\" alt=\"Three graphs where the first graph shows a parabola with no x-intercept, the second is a parabola with one \u2013intercept, and the third parabola is of two x-intercepts.\" width=\"975\" height=\"317\" \/><figcaption class=\"wp-caption-text\">Number of <span class=\"s1\">[latex]x[\/latex]<\/span>-intercepts of a parabola<\/figcaption><\/figure>\n<p>While factoring is often the first method we try when solving for [latex]x[\/latex]-intercepts, it&#8217;s not always possible or practical. Some quadratic equations cannot be easily factored, especially those with irrational or complex roots. In these cases, you&#8217;ll need a more powerful tool: the quadratic formula.<\/p>\n<section class=\"textbox recall\" aria-label=\"Recall\">\n<p class=\"whitespace-pre-wrap break-words\">The quadratic formula for an equation in the form [latex]ax^2 + bx + c = 0[\/latex] is:<\/p>\n<p class=\"whitespace-pre-wrap break-words\" style=\"text-align: center;\">[latex]x = \\frac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}[\/latex]<\/p>\n<p class=\"whitespace-pre-wrap break-words\">Where:<\/p>\n<ul class=\"-mt-1 list-disc space-y-2 pl-8\">\n<li class=\"whitespace-normal break-words\">[latex]a[\/latex] is the coefficient of [latex]x^2[\/latex]<\/li>\n<li class=\"whitespace-normal break-words\">[latex]b[\/latex] is the coefficient of [latex]x[\/latex]<\/li>\n<li class=\"whitespace-normal break-words\">[latex]c[\/latex] is the constant term<\/li>\n<li class=\"whitespace-normal break-words\">[latex]\\pm[\/latex] means we consider both addition and subtraction<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Solve [latex]{x}^{2}+x+2=0[\/latex] using the quadratic formula.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q757696\">Show Solution<\/button><\/p>\n<div id=\"q757696\" class=\"hidden-answer\" style=\"display: none\">Let\u2019s begin by writing the quadratic formula:<\/p>\n<div style=\"text-align: center;\">[latex]x=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a}[\/latex]<\/div>\n<p>When applying the quadratic formula, we identify the coefficients [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex]. For the equation [latex]{x}^{2}+x+2=0[\/latex], we have [latex]a=1[\/latex], [latex]b=1[\/latex], and [latex]c=2[\/latex].\u00a0Substituting these values into the formula we have:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}x&=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a} \\\\[1.5mm] &=\\dfrac{-1\\pm \\sqrt{{1}^{2}-4\\cdot 1\\cdot \\left(2\\right)}}{2\\cdot 1} \\\\[1.5mm] &=\\dfrac{-1\\pm \\sqrt{1 - 8}}{2} \\\\[1.5mm] &=\\dfrac{-1\\pm \\sqrt{-7}}{2} \\\\[1.5mm] &=\\dfrac{-1\\pm i\\sqrt{7}}{2} \\end{align}[\/latex]<\/p>\n<p>The solutions to the equation are [latex]x=\\dfrac{-1+i\\sqrt{7}}{2}[\/latex] and [latex]x=\\dfrac{-1-i\\sqrt{7}}{2}[\/latex] or [latex]x=-\\dfrac{1}{2}+\\dfrac{i\\sqrt{7}}{2}[\/latex] and [latex]x=-\\dfrac{1}{2}-\\dfrac{i\\sqrt{7}}{2}[\/latex].<\/p>\n<p><strong>Analysis of the Solution<\/strong><\/p>\n<p>This quadratic equation has only non-real solutions.<\/p>\n<\/div>\n<\/div>\n<\/section>\n<p>Now you will hopefully begin to understand why we introduced complex numbers at the beginning of this module. The example we just solved demonstrates a crucial concept in algebra: not all quadratic equations have real solutions. When the discriminant ([latex]b^2 - 4ac[\/latex]) is negative, we encounter complex roots. These complex roots always come in conjugate pairs, meaning if [latex]a + bi[\/latex] is a solution, then [latex]a - bi[\/latex] is also a solution.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">Consider the following function: [latex]f(x)=x^2+2x+3[\/latex], and it&#8217;s graph below:<\/p>\n<figure id=\"attachment_4477\" aria-describedby=\"caption-attachment-4477\" style=\"width: 300px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-4477 size-medium\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1916\/2016\/11\/18034032\/desmos-graph-300x300.png\" alt=\"Graph of quadratic function with the following points (-1,2), (-2,3), (0,3), (1,6), (-3,6).\" width=\"300\" height=\"300\" \/><figcaption id=\"caption-attachment-4477\" class=\"wp-caption-text\">Graph of a quadratic function<\/figcaption><\/figure>\n<p>Does this function have roots? It&#8217;s probably obvious that this function does not cross the [latex]x[\/latex]-axis, therefore it doesn&#8217;t have any [latex]x[\/latex]-intercepts. Recall that the [latex]x[\/latex]-intercepts of a function are found by setting the function equal to zero:<\/p>\n<p style=\"text-align: center;\">[latex]x^2+2x+3=0[\/latex]<\/p>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Find the [latex]x[\/latex]-intercepts of the quadratic function.<\/p>\n<p style=\"text-align: center;\">[latex]f(x)=x^2+2x+3[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q698410\">Show Solution<\/button><\/p>\n<div id=\"q698410\" class=\"hidden-answer\" style=\"display: none\">\n<p>The [latex]x[\/latex]-intercepts of the function\u00a0[latex]f(x)=x^2+2x+3[\/latex] are found by setting it equal to zero, and solving for [latex]x[\/latex] since the [latex]y[\/latex] values of the [latex]x[\/latex]-intercepts are zero.<\/p>\n<p>First, identify [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]x^2+2x+3=0[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]a=1,b=2,c=3[\/latex]<\/p>\n<p>Substitute these values into the quadratic formula.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{align}x&=\\dfrac{-b\\pm \\sqrt{{b}^{2}-4ac}}{2a}\\\\[1mm]&=\\dfrac{-2\\pm \\sqrt{{2}^{2}-4(1)(3)}}{2(1)}\\\\[1mm]&=\\dfrac{-2\\pm \\sqrt{4-12}}{2} \\\\[1mm]&=\\dfrac{-2\\pm \\sqrt{-8}}{2}\\\\[1mm]&=\\dfrac{-2\\pm 2i\\sqrt{2}}{2} \\\\[1mm]&=-1\\pm i\\sqrt{2}\\\\[1mm]x&=-1+i\\sqrt{2},-1-i\\sqrt{2}\\end{align}[\/latex]<\/p>\n<p>The solutions to this equation are complex, therefore there are no [latex]x[\/latex]-intercepts for the function\u00a0[latex]f(x)=x^2+2x+3[\/latex] in the set of real numbers that can be plotted on the Cartesian Coordinate plane. The graph of the function is plotted on the Cartesian Coordinate plane below:<\/p>\n<figure id=\"attachment_4477\" aria-describedby=\"caption-attachment-4477\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-4477 size-medium\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1916\/2016\/11\/18034032\/desmos-graph-300x300.png\" alt=\"Graph of quadratic function with the following points (-1,2), (-2,3), (0,3), (1,6), (-3,6).\" width=\"300\" height=\"300\" \/><figcaption id=\"caption-attachment-4477\" class=\"wp-caption-text\">Graph of quadratic function with no [latex]x[\/latex]-intercepts in the real numbers.<\/figcaption><\/figure>\n<p>Note how the graph does not cross the [latex]x[\/latex]-axis, therefore there are no real [latex]x[\/latex]-intercepts for this function.<\/p><\/div>\n<\/div>\n<\/section>\n<section aria-label=\"Example\">\n<div>\n<section aria-label=\"Try It\">\n<h3>The Discriminant<\/h3>\n<p>The <strong>quadratic formula<\/strong> not only generates the solutions to a quadratic equation, it tells us about the nature of the solutions when we consider the <strong>discriminant<\/strong>, or the expression under the radical, [latex]{b}^{2}-4ac[\/latex]. The discriminant tells us whether the solutions are real numbers or complex numbers as well as how many solutions of each type to expect. The table below\u00a0relates the value of the discriminant to the solutions of a quadratic equation.<\/p>\n<table summary=\"A table with 5 rows and 2 columns. The entries in the first row are: Value of Discriminant and Results. The entries in the second row are: b squared minus four times a times c equals zero and One rational solution (double solution). The entries in the third row are: b squared minus four times a times c is greater than zero, perfect square and Two rational solutions. The entries in the fourth row are: b squared minus four times a times c is greater than zero, not a perfect square and Two irrational solutions. The entries in the fifth row are: b squared minus four times a times c is less than zero and Two complex solutions.\">\n<thead>\n<tr>\n<th>Value of Discriminant<\/th>\n<th>Results<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]{b}^{2}-4ac=0[\/latex]<\/td>\n<td>One rational solution (double solution)<\/td>\n<\/tr>\n<tr>\n<td>[latex]{b}^{2}-4ac>0[\/latex], perfect square<\/td>\n<td>Two rational solutions<\/td>\n<\/tr>\n<tr>\n<td>[latex]{b}^{2}-4ac>0[\/latex], not a perfect square<\/td>\n<td>Two irrational solutions<\/td>\n<\/tr>\n<tr>\n<td>[latex]{b}^{2}-4ac<0[\/latex]<\/td>\n<td>Two complex solutions<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/section>\n<\/div>\n<section class=\"textbox keyTakeaway\">\n<h3>discriminant<\/h3>\n<p>For [latex]a{x}^{2}+bx+c=0[\/latex], where [latex]a[\/latex], [latex]b[\/latex], and [latex]c[\/latex] are real numbers, the <strong>discriminant<\/strong> is the expression under the radical in the quadratic formula:<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center;\">[latex]{b}^{2}-4ac[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p>It tells us whether the solutions are real numbers or complex numbers and how many solutions of each type to expect.<\/p>\n<\/section>\n<section class=\"textbox example\">Use the discriminant to find the nature of the solutions to the following quadratic equations:<\/p>\n<ol>\n<li>[latex]{x}^{2}+4x+4=0[\/latex]<\/li>\n<li>[latex]8{x}^{2}+14x+3=0[\/latex]<\/li>\n<li>[latex]3{x}^{2}-5x - 2=0[\/latex]<\/li>\n<li>[latex]3{x}^{2}-10x+15=0[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q229118\">Show Solution<\/button><\/p>\n<div id=\"q229118\" class=\"hidden-answer\" style=\"display: none\">\n<p>Calculate the discriminant [latex]{b}^{2}-4ac[\/latex] for each equation and state the expected type of solutions.<\/p>\n<ol>\n<li>[latex]{x}^{2}+4x+4=0[\/latex]: [latex]{b}^{2}-4ac={\\left(4\\right)}^{2}-4\\left(1\\right)\\left(4\\right)=0[\/latex]. There will be one rational double solution.<\/li>\n<li>[latex]8{x}^{2}+14x+3=0[\/latex]: [latex]{b}^{2}-4ac={\\left(14\\right)}^{2}-4\\left(8\\right)\\left(3\\right)=100[\/latex]. As [latex]100[\/latex] is a perfect square, there will be two rational solutions.<\/li>\n<li>[latex]3{x}^{2}-5x - 2=0[\/latex]: [latex]{b}^{2}-4ac={\\left(-5\\right)}^{2}-4\\left(3\\right)\\left(-2\\right)=49[\/latex]. As [latex]49[\/latex] is a perfect square, there will be two rational solutions.<\/li>\n<li>[latex]3{x}^{2}-10x+15=0[\/latex]: [latex]{b}^{2}-4ac={\\left(-10\\right)}^{2}-4\\left(3\\right)\\left(15\\right)=-80[\/latex]. There will be two complex solutions.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm18968\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=18968&theme=lumen&iframe_resize_id=ohm18968&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm18970\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=18970&theme=lumen&iframe_resize_id=ohm18970&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<\/section>\n","protected":false},"author":15,"menu_order":15,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":185,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/4154"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":10,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/4154\/revisions"}],"predecessor-version":[{"id":7728,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/4154\/revisions\/7728"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/parts\/185"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/4154\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/media?parent=4154"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=4154"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/contributor?post=4154"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/license?post=4154"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}