{"id":1600,"date":"2024-05-30T00:42:59","date_gmt":"2024-05-30T00:42:59","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/?post_type=chapter&#038;p=1600"},"modified":"2025-08-13T23:01:52","modified_gmt":"2025-08-13T23:01:52","slug":"transformations-of-functions-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/chapter\/transformations-of-functions-learn-it-3\/","title":{"raw":"Transformations of Functions: Learn It 3","rendered":"Transformations of Functions: Learn It 3"},"content":{"raw":"<h2>Graphing Functions Using Reflections about the Axes<\/h2>\r\nAnother transformation that can be applied to a function is a reflection over the [latex]x[\/latex]- or [latex]y[\/latex]-axis. A <strong>vertical reflection<\/strong> reflects a graph vertically across the [latex]x[\/latex]-axis, while a <strong>horizontal reflection<\/strong> reflects a graph horizontally across the [latex]y[\/latex]-axis.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203556\/CNX_Precalc_Figure_01_05_0122.jpg\" alt=\"Graph of the vertical and horizontal reflection of a function.\" width=\"487\" height=\"442\" \/> Graph of the vertical and horizontal reflection of a function[\/caption]\r\n\r\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">Notice that the vertical reflection produces a new graph that is a mirror image of the base or original graph about the [latex]x[\/latex]-axis. The horizontal reflection produces a new graph that is a mirror image of the base or original graph about the [latex]y[\/latex]-axis.<\/section><section class=\"textbox keyTakeaway\">\r\n<h3>reflections<\/h3>\r\nA <strong>vertical reflection<\/strong> <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">reflects a graph vertically across the [latex]x[\/latex]-axis. <\/span>This transformation changes the sign of the output values of [latex]f(x)[\/latex].\r\n<ul>\r\n \t<li>If you reflect the graph of a function [latex]f(x)[\/latex] over the [latex]x[\/latex]-axis, the new function [latex]g(x)[\/latex] is given by:<\/li>\r\n<\/ul>\r\n<p style=\"text-align: center;\">[latex]g(x) = -f(x)[\/latex]<\/p>\r\n&nbsp;\r\n\r\nA <strong>horizontal reflection<\/strong> <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">reflects a graph horizontally across the [latex]y[\/latex]-axis. <\/span>This transformation changes the sign of the input values of [latex]f(x)[\/latex].\r\n<ul>\r\n \t<li>If you reflect the graph of a function [latex]f(x)[\/latex] over the [latex]y[\/latex]-axis, the new function [latex]g(x)[\/latex] is given by:<\/li>\r\n<\/ul>\r\n<p style=\"text-align: center;\">[latex]g(x) = f(-x)[\/latex]<\/p>\r\n\r\n<\/section><section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a function, reflect the graph both vertically and horizontally.<\/strong>\r\n<ol>\r\n \t<li>Multiply all outputs by \u20131 for a vertical reflection. The new graph is a reflection of the original graph about the [latex]x[\/latex]-axis.<\/li>\r\n \t<li>Multiply all inputs by \u20131 for a horizontal reflection. The new graph is a reflection of the original graph about the [latex]y[\/latex]-axis.<\/li>\r\n<\/ol>\r\n<\/section><section class=\"textbox example\">Reflect the graph of [latex]s\\left(t\\right)=\\sqrt{t}[\/latex]\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>vertically<\/li>\r\n \t<li>horizontally<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"211400\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"211400\"]\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>Reflecting the graph vertically means that each output value will be reflected over the horizontal [latex]t[\/latex]<em>-<\/em>axis as shown below.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"777\"]<img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203559\/CNX_Precalc_Figure_01_05_0132.jpg\" alt=\"Graph of the vertical reflection of the square root function.\" width=\"777\" height=\"352\" \/> Vertical reflection of the square root function[\/caption]\r\n\r\n<strong>Table of values<\/strong>\r\n<table style=\"border-collapse: collapse; width: 89.9698%;\">\r\n<tbody>\r\n<tr>\r\n<td style=\"width: 18.8123%;\">[latex]t[\/latex]<\/td>\r\n<td style=\"width: 30.0399%;\">[latex]s(t) = \\sqrt{t}[\/latex]<\/td>\r\n<td style=\"width: 41.1178%;\">Reflected Function [latex]V(t)[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 18.8123%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 30.0399%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 41.1178%;\">[latex]0[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 18.8123%;\">[latex]1[\/latex]<\/td>\r\n<td style=\"width: 30.0399%;\">[latex]1[\/latex]<\/td>\r\n<td style=\"width: 41.1178%;\">[latex]-1[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 18.8123%;\">[latex]4[\/latex]<\/td>\r\n<td style=\"width: 30.0399%;\">[latex]2[\/latex]<\/td>\r\n<td style=\"width: 41.1178%;\">[latex]-2[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nBecause each output value is the opposite of the original output value, we can write\r\n<p style=\"text-align: center;\">[latex]V\\left(t\\right)=-s\\left(t\\right)\\text{ or }V\\left(t\\right)=-\\sqrt{t}[\/latex]<\/p>\r\nNotice that this is an outside change, or vertical shift, that affects the output [latex]s\\left(t\\right)[\/latex] values, so the negative sign belongs outside of the function.<\/li>\r\n \t<li>Reflecting horizontally means that each input value will be reflected over the vertical axis as shown below.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"777\"]<img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203602\/CNX_Precalc_Figure_01_05_0142.jpg\" alt=\"Graph of the horizontal reflection of the square root function.\" width=\"777\" height=\"352\" \/> Horizontal reflection of the square root function[\/caption]\r\n\r\n<strong>Table for [latex]s(t) = \\sqrt{t}[\/latex]<\/strong>\r\n<table style=\"border-collapse: collapse; width: 77.5426%;\">\r\n<tbody>\r\n<tr>\r\n<td style=\"width: 25%;\">[latex]t[\/latex]<\/td>\r\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\r\n<td style=\"width: 17.6647%;\">[latex]4[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 25%;\">[latex]s(t) = \\sqrt{t}[\/latex]<\/td>\r\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\r\n<td style=\"width: 17.6647%;\">[latex]2[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<strong>Table for reflected function\u00a0<\/strong>\r\n<table style=\"border-collapse: collapse; width: 77.5426%;\">\r\n<tbody>\r\n<tr>\r\n<td style=\"width: 25%;\">[latex]t[\/latex]<\/td>\r\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 17.3652%;\">[latex]-1[\/latex]<\/td>\r\n<td style=\"width: 17.6647%;\">[latex]-4[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"width: 25%;\">[latex]H(t)[\/latex]<\/td>\r\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\r\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\r\n<td style=\"width: 17.6647%;\">[latex]2[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nBecause each input value is the opposite of the original input value, we can write\r\n<p style=\"text-align: center;\">[latex]H\\left(t\\right)=s\\left(-t\\right)\\text{ or }H\\left(t\\right)=\\sqrt{-t}[\/latex]<\/p>\r\nNotice that this is an inside change or horizontal change that affects the input values, so the negative sign is on the inside of the function.<\/li>\r\n<\/ol>\r\nNote that these transformations can affect the domain and range of the functions. While the original square root function has domain [latex]\\left[0,\\infty \\right)[\/latex] and range [latex]\\left[0,\\infty \\right)[\/latex], the vertical reflection gives the [latex]V\\left(t\\right)[\/latex] function the range [latex]\\left(-\\infty ,0\\right][\/latex] and the horizontal reflection gives the [latex]H\\left(t\\right)[\/latex] function the domain [latex]\\left(-\\infty ,0\\right][\/latex].[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">A function [latex]f\\left(x\\right)[\/latex] is given. Create a table for the functions below.\r\n<ol>\r\n \t<li>[latex]g\\left(x\\right)=-f\\left(x\\right)[\/latex]<\/li>\r\n \t<li>[latex]h\\left(x\\right)=f\\left(-x\\right)[\/latex]<\/li>\r\n<\/ol>\r\n<table id=\"Table_01_05_05\" summary=\"Two rows and five columns. The first row is labeled,\"><colgroup> <col \/> <col \/> <col \/> <col \/> <col \/><\/colgroup>\r\n<tbody>\r\n<tr>\r\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td>[latex]2[\/latex]<\/td>\r\n<td>[latex]4[\/latex]<\/td>\r\n<td>[latex]6[\/latex]<\/td>\r\n<td>[latex]8[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><strong>[latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\r\n<td>[latex]1[\/latex]<\/td>\r\n<td>[latex]3[\/latex]<\/td>\r\n<td>[latex]7[\/latex]<\/td>\r\n<td>[latex]11[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n[reveal-answer q=\"608272\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"608272\"]\r\n<ol>\r\n \t<li>For [latex]g\\left(x\\right)[\/latex], the negative sign outside the function indicates a vertical reflection, so the [latex]x[\/latex]-values stay the same and each output value will be the opposite of the original output value.\r\n<table summary=\"Two rows and five columns. The first row is labeled,\"><colgroup> <col \/> <col \/> <col \/> <col \/> <col \/><\/colgroup>\r\n<tbody>\r\n<tr>\r\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td>[latex]2[\/latex]<\/td>\r\n<td>[latex]4[\/latex]<\/td>\r\n<td>[latex]6[\/latex]<\/td>\r\n<td>[latex]8[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><strong>[latex]g\\left(x\\right)[\/latex] <\/strong><\/td>\r\n<td>[latex]\u20131[\/latex]<\/td>\r\n<td>[latex]\u20133[\/latex]<\/td>\r\n<td>[latex]\u20137[\/latex]<\/td>\r\n<td>[latex]\u201311[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n \t<li>For [latex]h\\left(x\\right)[\/latex], the negative sign inside the function indicates a horizontal reflection, so each input value will be the opposite of the original input value and the [latex]h\\left(x\\right)[\/latex] values stay the same as the [latex]f\\left(x\\right)[\/latex] values.\r\n<table id=\"Table_01_05_07\" summary=\"Two rows and five columns. The first row is labeled,\"><colgroup> <col \/> <col \/> <col \/> <col \/> <col \/><\/colgroup>\r\n<tbody>\r\n<tr>\r\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td>[latex]\u22122[\/latex]<\/td>\r\n<td>[latex]\u22124[\/latex]<\/td>\r\n<td>[latex]\u22126[\/latex]<\/td>\r\n<td>[latex]\u22128[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><strong>[latex]h\\left(x\\right)[\/latex] <\/strong><\/td>\r\n<td>[latex]1[\/latex]<\/td>\r\n<td>[latex]3[\/latex]<\/td>\r\n<td>[latex]7[\/latex]<\/td>\r\n<td>[latex]11[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]19147[\/ohm2_question]<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]19148[\/ohm2_question]<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]19149[\/ohm2_question]<\/section>","rendered":"<h2>Graphing Functions Using Reflections about the Axes<\/h2>\n<p>Another transformation that can be applied to a function is a reflection over the [latex]x[\/latex]&#8211; or [latex]y[\/latex]-axis. A <strong>vertical reflection<\/strong> reflects a graph vertically across the [latex]x[\/latex]-axis, while a <strong>horizontal reflection<\/strong> reflects a graph horizontally across the [latex]y[\/latex]-axis.<\/p>\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203556\/CNX_Precalc_Figure_01_05_0122.jpg\" alt=\"Graph of the vertical and horizontal reflection of a function.\" width=\"487\" height=\"442\" \/><figcaption class=\"wp-caption-text\">Graph of the vertical and horizontal reflection of a function<\/figcaption><\/figure>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">Notice that the vertical reflection produces a new graph that is a mirror image of the base or original graph about the [latex]x[\/latex]-axis. The horizontal reflection produces a new graph that is a mirror image of the base or original graph about the [latex]y[\/latex]-axis.<\/section>\n<section class=\"textbox keyTakeaway\">\n<h3>reflections<\/h3>\n<p>A <strong>vertical reflection<\/strong> <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">reflects a graph vertically across the [latex]x[\/latex]-axis. <\/span>This transformation changes the sign of the output values of [latex]f(x)[\/latex].<\/p>\n<ul>\n<li>If you reflect the graph of a function [latex]f(x)[\/latex] over the [latex]x[\/latex]-axis, the new function [latex]g(x)[\/latex] is given by:<\/li>\n<\/ul>\n<p style=\"text-align: center;\">[latex]g(x) = -f(x)[\/latex]<\/p>\n<p>&nbsp;<\/p>\n<p>A <strong>horizontal reflection<\/strong> <span style=\"font-family: 'Public Sans', -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">reflects a graph horizontally across the [latex]y[\/latex]-axis. <\/span>This transformation changes the sign of the input values of [latex]f(x)[\/latex].<\/p>\n<ul>\n<li>If you reflect the graph of a function [latex]f(x)[\/latex] over the [latex]y[\/latex]-axis, the new function [latex]g(x)[\/latex] is given by:<\/li>\n<\/ul>\n<p style=\"text-align: center;\">[latex]g(x) = f(-x)[\/latex]<\/p>\n<\/section>\n<section class=\"textbox questionHelp\" aria-label=\"Question Help\"><strong>How To: Given a function, reflect the graph both vertically and horizontally.<\/strong><\/p>\n<ol>\n<li>Multiply all outputs by \u20131 for a vertical reflection. The new graph is a reflection of the original graph about the [latex]x[\/latex]-axis.<\/li>\n<li>Multiply all inputs by \u20131 for a horizontal reflection. The new graph is a reflection of the original graph about the [latex]y[\/latex]-axis.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\">Reflect the graph of [latex]s\\left(t\\right)=\\sqrt{t}[\/latex]<\/p>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>vertically<\/li>\n<li>horizontally<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q211400\">Show Solution<\/button><\/p>\n<div id=\"q211400\" class=\"hidden-answer\" style=\"display: none\">\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Reflecting the graph vertically means that each output value will be reflected over the horizontal [latex]t[\/latex]<em>&#8211;<\/em>axis as shown below.<br \/>\n<figure style=\"width: 777px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203559\/CNX_Precalc_Figure_01_05_0132.jpg\" alt=\"Graph of the vertical reflection of the square root function.\" width=\"777\" height=\"352\" \/><figcaption class=\"wp-caption-text\">Vertical reflection of the square root function<\/figcaption><\/figure>\n<p><strong>Table of values<\/strong><\/p>\n<table style=\"border-collapse: collapse; width: 89.9698%;\">\n<tbody>\n<tr>\n<td style=\"width: 18.8123%;\">[latex]t[\/latex]<\/td>\n<td style=\"width: 30.0399%;\">[latex]s(t) = \\sqrt{t}[\/latex]<\/td>\n<td style=\"width: 41.1178%;\">Reflected Function [latex]V(t)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 18.8123%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 30.0399%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 41.1178%;\">[latex]0[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 18.8123%;\">[latex]1[\/latex]<\/td>\n<td style=\"width: 30.0399%;\">[latex]1[\/latex]<\/td>\n<td style=\"width: 41.1178%;\">[latex]-1[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 18.8123%;\">[latex]4[\/latex]<\/td>\n<td style=\"width: 30.0399%;\">[latex]2[\/latex]<\/td>\n<td style=\"width: 41.1178%;\">[latex]-2[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Because each output value is the opposite of the original output value, we can write<\/p>\n<p style=\"text-align: center;\">[latex]V\\left(t\\right)=-s\\left(t\\right)\\text{ or }V\\left(t\\right)=-\\sqrt{t}[\/latex]<\/p>\n<p>Notice that this is an outside change, or vertical shift, that affects the output [latex]s\\left(t\\right)[\/latex] values, so the negative sign belongs outside of the function.<\/li>\n<li>Reflecting horizontally means that each input value will be reflected over the vertical axis as shown below.<br \/>\n<figure style=\"width: 777px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18203602\/CNX_Precalc_Figure_01_05_0142.jpg\" alt=\"Graph of the horizontal reflection of the square root function.\" width=\"777\" height=\"352\" \/><figcaption class=\"wp-caption-text\">Horizontal reflection of the square root function<\/figcaption><\/figure>\n<p><strong>Table for [latex]s(t) = \\sqrt{t}[\/latex]<\/strong><\/p>\n<table style=\"border-collapse: collapse; width: 77.5426%;\">\n<tbody>\n<tr>\n<td style=\"width: 25%;\">[latex]t[\/latex]<\/td>\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\n<td style=\"width: 17.6647%;\">[latex]4[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 25%;\">[latex]s(t) = \\sqrt{t}[\/latex]<\/td>\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\n<td style=\"width: 17.6647%;\">[latex]2[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>Table for reflected function\u00a0<\/strong><\/p>\n<table style=\"border-collapse: collapse; width: 77.5426%;\">\n<tbody>\n<tr>\n<td style=\"width: 25%;\">[latex]t[\/latex]<\/td>\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 17.3652%;\">[latex]-1[\/latex]<\/td>\n<td style=\"width: 17.6647%;\">[latex]-4[\/latex]<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 25%;\">[latex]H(t)[\/latex]<\/td>\n<td style=\"width: 17.515%;\">[latex]0[\/latex]<\/td>\n<td style=\"width: 17.3652%;\">[latex]1[\/latex]<\/td>\n<td style=\"width: 17.6647%;\">[latex]2[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Because each input value is the opposite of the original input value, we can write<\/p>\n<p style=\"text-align: center;\">[latex]H\\left(t\\right)=s\\left(-t\\right)\\text{ or }H\\left(t\\right)=\\sqrt{-t}[\/latex]<\/p>\n<p>Notice that this is an inside change or horizontal change that affects the input values, so the negative sign is on the inside of the function.<\/li>\n<\/ol>\n<p>Note that these transformations can affect the domain and range of the functions. While the original square root function has domain [latex]\\left[0,\\infty \\right)[\/latex] and range [latex]\\left[0,\\infty \\right)[\/latex], the vertical reflection gives the [latex]V\\left(t\\right)[\/latex] function the range [latex]\\left(-\\infty ,0\\right][\/latex] and the horizontal reflection gives the [latex]H\\left(t\\right)[\/latex] function the domain [latex]\\left(-\\infty ,0\\right][\/latex].<\/p><\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">A function [latex]f\\left(x\\right)[\/latex] is given. Create a table for the functions below.<\/p>\n<ol>\n<li>[latex]g\\left(x\\right)=-f\\left(x\\right)[\/latex]<\/li>\n<li>[latex]h\\left(x\\right)=f\\left(-x\\right)[\/latex]<\/li>\n<\/ol>\n<table id=\"Table_01_05_05\" summary=\"Two rows and five columns. The first row is labeled,\">\n<colgroup>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/><\/colgroup>\n<tbody>\n<tr>\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\n<td>[latex]2[\/latex]<\/td>\n<td>[latex]4[\/latex]<\/td>\n<td>[latex]6[\/latex]<\/td>\n<td>[latex]8[\/latex]<\/td>\n<\/tr>\n<tr>\n<td><strong>[latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\n<td>[latex]1[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<td>[latex]7[\/latex]<\/td>\n<td>[latex]11[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q608272\">Show Solution<\/button><\/p>\n<div id=\"q608272\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>For [latex]g\\left(x\\right)[\/latex], the negative sign outside the function indicates a vertical reflection, so the [latex]x[\/latex]-values stay the same and each output value will be the opposite of the original output value.<br \/>\n<table summary=\"Two rows and five columns. The first row is labeled,\">\n<colgroup>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/><\/colgroup>\n<tbody>\n<tr>\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\n<td>[latex]2[\/latex]<\/td>\n<td>[latex]4[\/latex]<\/td>\n<td>[latex]6[\/latex]<\/td>\n<td>[latex]8[\/latex]<\/td>\n<\/tr>\n<tr>\n<td><strong>[latex]g\\left(x\\right)[\/latex] <\/strong><\/td>\n<td>[latex]\u20131[\/latex]<\/td>\n<td>[latex]\u20133[\/latex]<\/td>\n<td>[latex]\u20137[\/latex]<\/td>\n<td>[latex]\u201311[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>For [latex]h\\left(x\\right)[\/latex], the negative sign inside the function indicates a horizontal reflection, so each input value will be the opposite of the original input value and the [latex]h\\left(x\\right)[\/latex] values stay the same as the [latex]f\\left(x\\right)[\/latex] values.<br \/>\n<table id=\"Table_01_05_07\" summary=\"Two rows and five columns. The first row is labeled,\">\n<colgroup>\n<col \/>\n<col \/>\n<col \/>\n<col \/>\n<col \/><\/colgroup>\n<tbody>\n<tr>\n<td><strong>[latex]x[\/latex]<\/strong><\/td>\n<td>[latex]\u22122[\/latex]<\/td>\n<td>[latex]\u22124[\/latex]<\/td>\n<td>[latex]\u22126[\/latex]<\/td>\n<td>[latex]\u22128[\/latex]<\/td>\n<\/tr>\n<tr>\n<td><strong>[latex]h\\left(x\\right)[\/latex] <\/strong><\/td>\n<td>[latex]1[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<td>[latex]7[\/latex]<\/td>\n<td>[latex]11[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm19147\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=19147&theme=lumen&iframe_resize_id=ohm19147&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm19148\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=19148&theme=lumen&iframe_resize_id=ohm19148&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm19149\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=19149&theme=lumen&iframe_resize_id=ohm19149&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":12,"menu_order":13,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":142,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1600"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/users\/12"}],"version-history":[{"count":9,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1600\/revisions"}],"predecessor-version":[{"id":7670,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1600\/revisions\/7670"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/parts\/142"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1600\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/media?parent=1600"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1600"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/contributor?post=1600"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/license?post=1600"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}