{"id":1576,"date":"2024-05-28T22:46:14","date_gmt":"2024-05-28T22:46:14","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/?post_type=chapter&#038;p=1576"},"modified":"2024-12-05T18:13:36","modified_gmt":"2024-12-05T18:13:36","slug":"combinations-and-compositions-of-functions-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/chapter\/combinations-and-compositions-of-functions-learn-it-4\/","title":{"raw":"Combinations and Compositions of Functions: Learn It 4","rendered":"Combinations and Compositions of Functions: Learn It 4"},"content":{"raw":"<h2>Decomposing a Composite Function<\/h2>\r\nIn some cases, it is necessary to decompose a complicated function. In other words, we can write it as a composition of two simpler functions. There may be more than one way to decompose a composite function, so we may choose the decomposition that appears to be most expedient.\r\n\r\n<section class=\"textbox example\"><strong>Write [latex]f(x)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.<\/strong>\r\n\r\n<hr \/>\r\n\r\n<strong>\r\n<\/strong>We are looking for two functions, [latex]g[\/latex] and [latex]h[\/latex], so [latex]f\\left(x\\right)=g\\left(h\\left(x\\right)\\right)[\/latex]. To do this, we look for a function inside a function in the formula for [latex]f\\left(x\\right)[\/latex].There are multiple ways to express [latex]f(x)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.[reveal-answer q=\"53139\"]Option 1[\/reveal-answer]\r\n[hidden-answer a=\"53139\"]\r\n<ul>\r\n \t<li>[latex]h(x) = 5 - x^2[\/latex]<\/li>\r\n \t<li>[latex]g(x) = \\sqrt{x}[\/latex]<\/li>\r\n<\/ul>\r\nThus:\r\n\r\n<center>[latex]\\begin{align*} f(x) = g(h(x)) &amp;= g(5 - x^2) \\\\ \\text{Since } g(x) &amp;= \\sqrt{x}, \\text{ we have:} \\\\ g(5 - x^2) &amp;= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/center>\r\n\r\n[\/hidden-answer]\r\n\r\n[reveal-answer q=\"80338\"]Option 2[\/reveal-answer]\r\n[hidden-answer a=\"80338\"]\r\n<ul>\r\n \t<li>[latex]h(x) = x^2[\/latex]<\/li>\r\n \t<li>[latex]g(x) = \\sqrt{5 - x}[\/latex]<\/li>\r\n<\/ul>\r\nThus:\r\n\r\n<center>[latex]\\begin{align*} f(x) = g(h(x)) &amp;= g(x^2) \\\\ \\text{Since } g(x) &amp;= \\sqrt{5 - x}, \\text{ we have:} \\\\ g(x^2) &amp;= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/center>\r\n\r\n[\/hidden-answer]\r\n\r\n[reveal-answer q=\"399617\"]Option 3[\/reveal-answer]\r\n[hidden-answer a=\"399617\"]\r\n<ul>\r\n \t<li>[latex]h(x) = x[\/latex]<\/li>\r\n \t<li>[latex]g(x) = \\sqrt{5 - x^2}[\/latex]<\/li>\r\n<\/ul>\r\nThus:\r\n\r\n<center>[latex]\\begin{align*} f(x) = g(h(x)) &amp;= g(x) \\\\ \\text{Since } g(x) &amp;= \\sqrt{5 - x^2}, \\text{ we have:} \\\\ g(x) &amp;= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/center>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox example\" aria-label=\"Example\">Write [latex]f\\left(x\\right)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.[reveal-answer q=\"702975\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"702975\"]We are looking for two functions, [latex]g[\/latex] and [latex]h[\/latex], so [latex]f\\left(x\\right)=g\\left(h\\left(x\\right)\\right)[\/latex]. To do this, we look for a function inside a function in the formula for [latex]f\\left(x\\right)[\/latex]. As one possibility, we might notice that the expression [latex]5-{x}^{2}[\/latex] is the inside of the square root. We could then decompose the function as\r\n<p style=\"text-align: center;\">[latex]h\\left(x\\right)=5-{x}^{2}\\hspace{2mm}\\text{and}\\hspace{2mm}g\\left(x\\right)=\\sqrt{x}[\/latex]<\/p>\r\nWe can check our answer by recomposing the functions.\r\n<p style=\"text-align: center;\">[latex]g\\left(h\\left(x\\right)\\right)=g\\left(5-{x}^{2}\\right)=\\sqrt{5-{x}^{2}}[\/latex]<\/p>\r\n<strong>Analysis of the Solution<\/strong>\r\n\r\nFor every composition there are infinitely many possible function pairs that will work. In this case, another function pair where\u00a0[latex]g\\left(h\\left(x\\right)\\right)=\\sqrt{5-{x}^{2}}[\/latex]\u00a0 is\u00a0 [latex]h(x)=x^2[\/latex] and [latex]g(x)=\\sqrt{5-x}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]19138[\/ohm2_question]<\/section><section class=\"textbox tryIt\">[ohm2_question hide_question_numbers=1]19139[\/ohm2_question]<\/section>","rendered":"<h2>Decomposing a Composite Function<\/h2>\n<p>In some cases, it is necessary to decompose a complicated function. In other words, we can write it as a composition of two simpler functions. There may be more than one way to decompose a composite function, so we may choose the decomposition that appears to be most expedient.<\/p>\n<section class=\"textbox example\"><strong>Write [latex]f(x)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.<\/strong><\/p>\n<hr \/>\n<p><strong><br \/>\n<\/strong>We are looking for two functions, [latex]g[\/latex] and [latex]h[\/latex], so [latex]f\\left(x\\right)=g\\left(h\\left(x\\right)\\right)[\/latex]. To do this, we look for a function inside a function in the formula for [latex]f\\left(x\\right)[\/latex].There are multiple ways to express [latex]f(x)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q53139\">Option 1<\/button><\/p>\n<div id=\"q53139\" class=\"hidden-answer\" style=\"display: none\">\n<ul>\n<li>[latex]h(x) = 5 - x^2[\/latex]<\/li>\n<li>[latex]g(x) = \\sqrt{x}[\/latex]<\/li>\n<\/ul>\n<p>Thus:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align*} f(x) = g(h(x)) &= g(5 - x^2) \\\\ \\text{Since } g(x) &= \\sqrt{x}, \\text{ we have:} \\\\ g(5 - x^2) &= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/div>\n<\/div>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q80338\">Option 2<\/button><\/p>\n<div id=\"q80338\" class=\"hidden-answer\" style=\"display: none\">\n<ul>\n<li>[latex]h(x) = x^2[\/latex]<\/li>\n<li>[latex]g(x) = \\sqrt{5 - x}[\/latex]<\/li>\n<\/ul>\n<p>Thus:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align*} f(x) = g(h(x)) &= g(x^2) \\\\ \\text{Since } g(x) &= \\sqrt{5 - x}, \\text{ we have:} \\\\ g(x^2) &= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/div>\n<\/div>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q399617\">Option 3<\/button><\/p>\n<div id=\"q399617\" class=\"hidden-answer\" style=\"display: none\">\n<ul>\n<li>[latex]h(x) = x[\/latex]<\/li>\n<li>[latex]g(x) = \\sqrt{5 - x^2}[\/latex]<\/li>\n<\/ul>\n<p>Thus:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{align*} f(x) = g(h(x)) &= g(x) \\\\ \\text{Since } g(x) &= \\sqrt{5 - x^2}, \\text{ we have:} \\\\ g(x) &= \\sqrt{5 - x^2} \\end{align*}[\/latex]<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox example\" aria-label=\"Example\">Write [latex]f\\left(x\\right)=\\sqrt{5-{x}^{2}}[\/latex] as the composition of two functions.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q702975\">Show Solution<\/button><\/p>\n<div id=\"q702975\" class=\"hidden-answer\" style=\"display: none\">We are looking for two functions, [latex]g[\/latex] and [latex]h[\/latex], so [latex]f\\left(x\\right)=g\\left(h\\left(x\\right)\\right)[\/latex]. To do this, we look for a function inside a function in the formula for [latex]f\\left(x\\right)[\/latex]. As one possibility, we might notice that the expression [latex]5-{x}^{2}[\/latex] is the inside of the square root. We could then decompose the function as<\/p>\n<p style=\"text-align: center;\">[latex]h\\left(x\\right)=5-{x}^{2}\\hspace{2mm}\\text{and}\\hspace{2mm}g\\left(x\\right)=\\sqrt{x}[\/latex]<\/p>\n<p>We can check our answer by recomposing the functions.<\/p>\n<p style=\"text-align: center;\">[latex]g\\left(h\\left(x\\right)\\right)=g\\left(5-{x}^{2}\\right)=\\sqrt{5-{x}^{2}}[\/latex]<\/p>\n<p><strong>Analysis of the Solution<\/strong><\/p>\n<p>For every composition there are infinitely many possible function pairs that will work. In this case, another function pair where\u00a0[latex]g\\left(h\\left(x\\right)\\right)=\\sqrt{5-{x}^{2}}[\/latex]\u00a0 is\u00a0 [latex]h(x)=x^2[\/latex] and [latex]g(x)=\\sqrt{5-x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm19138\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=19138&theme=lumen&iframe_resize_id=ohm19138&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n<section class=\"textbox tryIt\"><iframe loading=\"lazy\" id=\"ohm19139\" class=\"resizable\" src=\"https:\/\/ohm.one.lumenlearning.com\/multiembedq.php?id=19139&theme=lumen&iframe_resize_id=ohm19139&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><\/section>\n","protected":false},"author":12,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":142,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1576"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/users\/12"}],"version-history":[{"count":17,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1576\/revisions"}],"predecessor-version":[{"id":6687,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1576\/revisions\/6687"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/parts\/142"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1576\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/media?parent=1576"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1576"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/contributor?post=1576"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/wp-json\/wp\/v2\/license?post=1576"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}