{"id":1032,"date":"2024-05-02T18:15:02","date_gmt":"2024-05-02T18:15:02","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/?post_type=chapter&p=1032"},"modified":"2025-08-13T15:23:46","modified_gmt":"2025-08-13T15:23:46","slug":"equations-of-lines-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/collegealgebra\/chapter\/equations-of-lines-learn-it-2\/","title":{"raw":"Equations of Lines: Learn It 2","rendered":"Equations of Lines: Learn It 2"},"content":{"raw":"

Finding a Linear Equation<\/h2>\r\nBuilding on our understanding of solving equations with a single variable and our introduction to slope, we now turn our attention to linear equations involving two variables. These equations allow us to model relationships between two changing quantities and form the basis for many real-world applications. By exploring the slope-intercept form of linear equations, we'll connect our algebraic knowledge with graphical representations, providing a powerful tool for analyzing and predicting linear relationships.\r\n

Slope-Intercept Form<\/h3>\r\nPerhaps the most familiar form of a linear equation is the slope-intercept form, written as [latex]y=mx+b[\/latex], where [latex]m=\\text{ slope }[\/latex] and [latex]b=y-\\text{intercept}[\/latex].\r\n\r\n
\r\n
\r\n

slope-intercept form<\/h3>\r\nThe slope-intercept form of a line is written as:\r\n

[latex]y = mx+b[\/latex]<\/p>\r\nwhere:\r\n

    \r\n \t
  • [latex]m[\/latex] is the slope of the line, representing the rate of change or steepness of the line.<\/li>\r\n \t
  • [latex]b[\/latex] is the y-intercept, which is the point where the line crosses the y-axis. This value indicates where the line will pass through the y-axis when [latex]x=0[\/latex].<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/section>
    To calculate slope given two points, [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] and [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex], [latex]m=\\frac{\\text{rise}}{\\text{run}} = \\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex].<\/section>
    Find the equation of the line for the graph below.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]\"This x,y coordinate plane with a line and points[\/caption]\r\n\r\n\r\nStep 1: Calculate the Slope ([latex]m[\/latex])<\/strong>The slope of a line is calculated using the formula [latex]m=\\frac{\\text{rise}}{\\text{run}} = \\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex].<\/span>\r\n
      \r\n \t
    • Selecting two points from the graph: [latex](-2, 1)[\/latex] and [latex](2, 3)[\/latex].<\/li>\r\n \t
    • Using these points, we can calculate the slope:<\/li>\r\n<\/ul>\r\n

      [latex]m = \\dfrac{y_2 - y_1}{x_2 - x_1} = \\dfrac{3 - 1}{2 - (-2)} = \\dfrac{2}{4} = \\dfrac{1}{2}[\/latex]<\/p>\r\nStep 2: Find the [latex]y[\/latex]-intercept ([latex]b[\/latex])<\/strong>\r\n\r\nThe [latex]y[\/latex]-intercept is the value of [latex]y[\/latex] when [latex]x=0[\/latex]. From the graph, it is apparent that when [latex]x=0, y=2[\/latex]. Therefore, [latex]b=2[\/latex].\r\n\r\nStep 3: Write the Equation<\/strong>\r\n\r\nNow that we have the slope and [latex]y[\/latex]-intercept, we can write the equation of the line:\r\n

      [latex]y = \\dfrac{1}{2}x+2[\/latex]<\/p>\r\n\r\n<\/section>

      [ohm2_question hide_question_numbers=1]18924[\/ohm2_question]<\/section>
      Identify the slope and y-<\/em>intercept given the equation [latex]y=-\\frac{3}{4}x - 4[\/latex].\r\n[reveal-answer q=\"757424\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"757424\"]As the line is in [latex]y=mx+b[\/latex] form, the given line has a slope of [latex]m=-\\frac{3}{4}[\/latex]. The y-<\/em>intercept is [latex]b=-4[\/latex], or, [latex](0, -4)[\/latex] in ordered pair format.Analysis of the Solution<\/strong>The y<\/em>-intercept is the point at which the line crosses the y-<\/em>axis. On the y-<\/em>axis, [latex]x=0[\/latex]. We can always identify the y-<\/em>intercept when the line is in slope-intercept form, as it will always equal b.<\/em> Or, just substitute [latex]x=0[\/latex] and solve for y.<\/em>[\/hidden-answer]<\/section>
      [ohm2_question hide_question_numbers=1]18925[\/ohm2_question]<\/section>","rendered":"

      Finding a Linear Equation<\/h2>\n

      Building on our understanding of solving equations with a single variable and our introduction to slope, we now turn our attention to linear equations involving two variables. These equations allow us to model relationships between two changing quantities and form the basis for many real-world applications. By exploring the slope-intercept form of linear equations, we’ll connect our algebraic knowledge with graphical representations, providing a powerful tool for analyzing and predicting linear relationships.<\/p>\n

      Slope-Intercept Form<\/h3>\n

      Perhaps the most familiar form of a linear equation is the slope-intercept form, written as [latex]y=mx+b[\/latex], where [latex]m=\\text{ slope }[\/latex] and [latex]b=y-\\text{intercept}[\/latex].<\/p>\n

      \n
      \n

      slope-intercept form<\/h3>\n

      The slope-intercept form of a line is written as:<\/p>\n

      [latex]y = mx+b[\/latex]<\/p>\n

      where:<\/p>\n

        \n
      • [latex]m[\/latex] is the slope of the line, representing the rate of change or steepness of the line.<\/li>\n
      • [latex]b[\/latex] is the y-intercept, which is the point where the line crosses the y-axis. This value indicates where the line will pass through the y-axis when [latex]x=0[\/latex].<\/li>\n<\/ul>\n<\/div>\n<\/section>\n
        To calculate slope given two points, [latex]\\left({x}_{1},{y}_{1}\\right)[\/latex] and [latex]\\left({x}_{2},{y}_{2}\\right)[\/latex], [latex]m=\\frac{\\text{rise}}{\\text{run}} = \\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex].<\/section>\n
        Find the equation of the line for the graph below.<\/p>\n
        \"This
        x,y coordinate plane with a line and points<\/figcaption><\/figure>\n


        \nStep 1: Calculate the Slope ([latex]m[\/latex])<\/strong>The slope of a line is calculated using the formula [latex]m=\\frac{\\text{rise}}{\\text{run}} = \\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}[\/latex].<\/span><\/p>\n

          \n
        • Selecting two points from the graph: [latex](-2, 1)[\/latex] and [latex](2, 3)[\/latex].<\/li>\n
        • Using these points, we can calculate the slope:<\/li>\n<\/ul>\n

          [latex]m = \\dfrac{y_2 - y_1}{x_2 - x_1} = \\dfrac{3 - 1}{2 - (-2)} = \\dfrac{2}{4} = \\dfrac{1}{2}[\/latex]<\/p>\n

          Step 2: Find the [latex]y[\/latex]-intercept ([latex]b[\/latex])<\/strong><\/p>\n

          The [latex]y[\/latex]-intercept is the value of [latex]y[\/latex] when [latex]x=0[\/latex]. From the graph, it is apparent that when [latex]x=0, y=2[\/latex]. Therefore, [latex]b=2[\/latex].<\/p>\n

          Step 3: Write the Equation<\/strong><\/p>\n

          Now that we have the slope and [latex]y[\/latex]-intercept, we can write the equation of the line:<\/p>\n

          [latex]y = \\dfrac{1}{2}x+2[\/latex]<\/p>\n<\/section>\n