{"id":949,"date":"2025-10-14T16:32:49","date_gmt":"2025-10-14T16:32:49","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/calculus3\/?post_type=chapter&#038;p=949"},"modified":"2025-10-24T13:16:12","modified_gmt":"2025-10-24T13:16:12","slug":"introduction-to-vector-valued-functions-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/calculus3\/chapter\/introduction-to-vector-valued-functions-learn-it-3\/","title":{"raw":"Introduction to Vector-Valued Functions: Learn It 3","rendered":"Introduction to Vector-Valued Functions: Learn It 3"},"content":{"raw":"<h2>Limits and Continuity of a Vector-Valued Function<\/h2>\r\n<p class=\"whitespace-normal break-words\">Understanding limits of vector-valued functions is essential for studying their calculus. The process builds directly on what you know about limits of single-variable functions.<\/p>\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>limit of a vector valued function<\/h3>\r\nA vector-valued function [latex]{\\bf{r}}[\/latex] approaches the limit [latex]\\bf{L}[\/latex] as [latex]t[\/latex] approaches [latex]a[\/latex], written:\r\n<div style=\"text-align: center;\">[latex]\\displaystyle{\\lim_{t\\to{a}}}\\;{\\bf{r}}\\,(t)={\\bf{L}}[\/latex],<\/div>\r\n&nbsp;\r\n\r\nprovided:\r\n<div style=\"text-align: center;\">[latex]\\displaystyle{\\lim_{t\\to{a}}}\\left\\|{\\bf{r}}\\,(t)-{\\bf{L}}\\right\\|=0[\/latex].<\/div>\r\n&nbsp;\r\n\r\n<\/section>\r\n<p class=\"whitespace-normal break-words\">This is the rigorous definition, but in practice we use a simpler approach: calculate the limit of each component function separately.<\/p>\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>limit of a vector-valued function theorem<\/h3>\r\n<p class=\"whitespace-normal break-words\">Let [latex]f[\/latex], [latex]g[\/latex], and [latex]h[\/latex] be functions of [latex]t[\/latex].<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>For plane curves:<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\underset{t\\to a}{\\text{lim}}{\\bf{r}}(t)=\\bigg[\\underset{t\\to a}{\\text{lim}}f(t)\\bigg]{\\bf{i}}+\\bigg[\\underset{t\\to a}{\\text{lim}}g(t)\\bigg]{\\bf{j}}[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\">provided the limits [latex]\\underset{t\\to a}{\\text{lim}}f(t)[\/latex] and [latex]\\underset{t\\to a}{\\text{lim}}g(t)[\/latex] exist.<\/p>\r\n<p class=\"whitespace-normal break-words\"><strong>For space curves:<\/strong><\/p>\r\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\underset{t\\to a}{\\text{lim}}{\\bf{r}}(t)=\\bigg[\\underset{t\\to a}{\\text{lim}}f(t)\\bigg]{\\bf{i}}+\\bigg[\\underset{t\\to a}{\\text{lim}}g(t)\\bigg]{\\bf{j}}+\\bigg[\\underset{t\\to a}{\\text{lim}}h(t)\\bigg]{\\bf{k}}[\/latex]<\/p>\r\n<p class=\"whitespace-normal break-words\">provided the limits [latex]\\underset{t\\to a}{\\text{lim}}f(t)[\/latex], [latex]\\underset{t\\to a}{\\text{lim}}g(t)[\/latex], and [latex]\\underset{t\\to a}{\\text{lim}}h(t)[\/latex] exist.<\/p>\r\n\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">Think of this as taking the limit \"component by component.\" Each component function follows the same limit rules you learned in Calculus 1.<\/section>In the following example, we show how to calculate the limit of a vector-valued function.\r\n\r\n<section class=\"textbox example\" aria-label=\"Example\">For each of the following vector-valued functions, calculate [latex]\\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)[\/latex] for\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li style=\"list-style-type: none;\">\r\n<ol style=\"list-style-type: lower-alpha;\">a. [latex]{\\bf{r}}\\,(t)=(t^{2}-3t+4)\\,{\\bf{i}}+(4t+3)\\,{\\bf{j}}[\/latex]<\/ol>\r\n<ol style=\"list-style-type: lower-alpha;\">b. [latex]{\\bf{r}}\\,(t)=\\frac{2t-4}{t+1}\\,{\\bf{i}}+\\frac{t}{t^{2}+1}\\,{\\bf{j}}+(4t-3)\\,{\\bf{k}}[\/latex]<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<div id=\"fs-id1167793461764\" class=\"exercise\">[reveal-answer q=\"fs-id1167795055165\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1167795055165\"]\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>Use the Limit of a Vector-Valued Function theorem and substitute the value [latex]t=3[\/latex] into the two component expression:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{ccc}\\hfill \\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)&amp;=\\hfill&amp;{\\displaystyle\\lim_{t{\\to}3}\\big[(t^{2}-3t+4)\\,{\\bf{i}}+(4t+3)\\,{\\bf{j}}\\big]}\\hfill \\\\ \\hfill &amp; =\\hfill &amp; {\\bigg[\\displaystyle\\lim_{t{\\to}3}{(t^{2}-3t+4)}\\bigg]\\,{\\bf{i}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(4t+3)}\\bigg]\\,{\\bf{j}}} \\hfill \\\\ \\hfill &amp; =\\hfill &amp; {4\\,{\\bf{i}}+15\\,{\\bf{j}}}\\hfill \\\\ \\hfill \\end{array}[\/latex]<\/div>\r\n&nbsp;<\/li>\r\n \t<li>Use the Limit of a Vector-Valued Function theorem and substitute the value [latex]t=3[\/latex] into the three component expression:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{ccc}\\hfill \\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)&amp;=\\hfill&amp;{\\displaystyle\\lim_{t{\\to}3}\\bigg(\\frac{2t-4}{t+1}\\,{\\bf{i}}+\\frac{t}{t^{2}+1}\\,{\\bf{j}}+(4t-3){\\bf{k}}\\bigg)}\\hfill \\\\ \\hfill &amp; =\\hfill &amp; {\\bigg[\\displaystyle\\lim_{t{\\to}3}{(\\frac{2t-4}{t+1})}\\bigg]\\,{\\bf{i}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(\\frac{t}{t^{2}+1})}\\bigg]\\,{\\bf{j}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(4t-3)}\\bigg]\\,{\\bf{k}}} \\hfill \\\\ \\hfill &amp; =\\hfill &amp; {\\frac{1}{2}\\,{\\bf{i}}+\\frac{3}{10}\\,{\\bf{j}}+9\\,{\\bf{k}}}\\hfill \\\\ \\hfill \\end{array}[\/latex]<\/div>\r\n&nbsp;<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/section>Now that we can calculate limits of vector-valued functions, we can define what it means for such a function to be continuous.\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>continuity of a vector-valued function<\/h3>\r\n<p class=\"whitespace-normal break-words\">Let [latex]f[\/latex], [latex]g[\/latex], and [latex]h[\/latex] be functions of [latex]t[\/latex].<\/p>\r\n<p class=\"whitespace-normal break-words\">The vector-valued function [latex]{\\bf{r}}(t)=f(t){\\bf{i}}+g(t){\\bf{j}}[\/latex] is continuous at point [latex]t=a[\/latex] if three conditions hold:<\/p>\r\n\r\n<ol>\r\n \t<li>[latex]{\\bf{r}}\\,(a)[\/latex] exists<\/li>\r\n \t<li>[latex]\\displaystyle\\lim_{t{\\to}a}{\\bf{r}}\\,(t)[\/latex] exists<\/li>\r\n \t<li>[latex]\\displaystyle\\lim_{t{\\to}a}{\\bf{r}}\\,(t)={\\bf{r}}\\,(a)[\/latex]<\/li>\r\n<\/ol>\r\nSimilarly, [latex]{\\bf{r}}(t)=f(t){\\bf{i}}+g(t){\\bf{j}}+h(t){\\bf{k}}[\/latex] is continuous at point [latex]t=a[\/latex] if the same three conditions hold.\r\n\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">These three conditions should look familiar\u2014they're the same requirements for continuity you learned with single-variable functions. A vector-valued function is continuous at a point when you can draw its graph through that point without lifting your pencil.<\/section>","rendered":"<h2>Limits and Continuity of a Vector-Valued Function<\/h2>\n<p class=\"whitespace-normal break-words\">Understanding limits of vector-valued functions is essential for studying their calculus. The process builds directly on what you know about limits of single-variable functions.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>limit of a vector valued function<\/h3>\n<p>A vector-valued function [latex]{\\bf{r}}[\/latex] approaches the limit [latex]\\bf{L}[\/latex] as [latex]t[\/latex] approaches [latex]a[\/latex], written:<\/p>\n<div style=\"text-align: center;\">[latex]\\displaystyle{\\lim_{t\\to{a}}}\\;{\\bf{r}}\\,(t)={\\bf{L}}[\/latex],<\/div>\n<p>&nbsp;<\/p>\n<p>provided:<\/p>\n<div style=\"text-align: center;\">[latex]\\displaystyle{\\lim_{t\\to{a}}}\\left\\|{\\bf{r}}\\,(t)-{\\bf{L}}\\right\\|=0[\/latex].<\/div>\n<p>&nbsp;<\/p>\n<\/section>\n<p class=\"whitespace-normal break-words\">This is the rigorous definition, but in practice we use a simpler approach: calculate the limit of each component function separately.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>limit of a vector-valued function theorem<\/h3>\n<p class=\"whitespace-normal break-words\">Let [latex]f[\/latex], [latex]g[\/latex], and [latex]h[\/latex] be functions of [latex]t[\/latex].<\/p>\n<p class=\"whitespace-normal break-words\"><strong>For plane curves:<\/strong><\/p>\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\underset{t\\to a}{\\text{lim}}{\\bf{r}}(t)=\\bigg[\\underset{t\\to a}{\\text{lim}}f(t)\\bigg]{\\bf{i}}+\\bigg[\\underset{t\\to a}{\\text{lim}}g(t)\\bigg]{\\bf{j}}[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\">provided the limits [latex]\\underset{t\\to a}{\\text{lim}}f(t)[\/latex] and [latex]\\underset{t\\to a}{\\text{lim}}g(t)[\/latex] exist.<\/p>\n<p class=\"whitespace-normal break-words\"><strong>For space curves:<\/strong><\/p>\n<p class=\"whitespace-normal break-words\" style=\"text-align: center;\">[latex]\\underset{t\\to a}{\\text{lim}}{\\bf{r}}(t)=\\bigg[\\underset{t\\to a}{\\text{lim}}f(t)\\bigg]{\\bf{i}}+\\bigg[\\underset{t\\to a}{\\text{lim}}g(t)\\bigg]{\\bf{j}}+\\bigg[\\underset{t\\to a}{\\text{lim}}h(t)\\bigg]{\\bf{k}}[\/latex]<\/p>\n<p class=\"whitespace-normal break-words\">provided the limits [latex]\\underset{t\\to a}{\\text{lim}}f(t)[\/latex], [latex]\\underset{t\\to a}{\\text{lim}}g(t)[\/latex], and [latex]\\underset{t\\to a}{\\text{lim}}h(t)[\/latex] exist.<\/p>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">Think of this as taking the limit &#8220;component by component.&#8221; Each component function follows the same limit rules you learned in Calculus 1.<\/section>\n<p>In the following example, we show how to calculate the limit of a vector-valued function.<\/p>\n<section class=\"textbox example\" aria-label=\"Example\">For each of the following vector-valued functions, calculate [latex]\\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)[\/latex] for<\/p>\n<ol style=\"list-style-type: lower-alpha;\">\n<li style=\"list-style-type: none;\">\n<ol style=\"list-style-type: lower-alpha;\"> <\/ol>\n<ol style=\"list-style-type: lower-alpha;\"> <\/ol>\n<\/li>\n<\/ol>\n<div id=\"fs-id1167793461764\" class=\"exercise\">\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"qfs-id1167795055165\">Show Solution<\/button><\/p>\n<div id=\"qfs-id1167795055165\" class=\"hidden-answer\" style=\"display: none\">\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Use the Limit of a Vector-Valued Function theorem and substitute the value [latex]t=3[\/latex] into the two component expression:\n<div style=\"text-align: center;\">[latex]\\begin{array}{ccc}\\hfill \\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)&=\\hfill&{\\displaystyle\\lim_{t{\\to}3}\\big[(t^{2}-3t+4)\\,{\\bf{i}}+(4t+3)\\,{\\bf{j}}\\big]}\\hfill \\\\ \\hfill & =\\hfill & {\\bigg[\\displaystyle\\lim_{t{\\to}3}{(t^{2}-3t+4)}\\bigg]\\,{\\bf{i}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(4t+3)}\\bigg]\\,{\\bf{j}}} \\hfill \\\\ \\hfill & =\\hfill & {4\\,{\\bf{i}}+15\\,{\\bf{j}}}\\hfill \\\\ \\hfill \\end{array}[\/latex]<\/div>\n<p>&nbsp;<\/li>\n<li>Use the Limit of a Vector-Valued Function theorem and substitute the value [latex]t=3[\/latex] into the three component expression:\n<div style=\"text-align: center;\">[latex]\\begin{array}{ccc}\\hfill \\displaystyle\\lim_{t{\\to}3}{\\bf{r}}\\,(t)&=\\hfill&{\\displaystyle\\lim_{t{\\to}3}\\bigg(\\frac{2t-4}{t+1}\\,{\\bf{i}}+\\frac{t}{t^{2}+1}\\,{\\bf{j}}+(4t-3){\\bf{k}}\\bigg)}\\hfill \\\\ \\hfill & =\\hfill & {\\bigg[\\displaystyle\\lim_{t{\\to}3}{(\\frac{2t-4}{t+1})}\\bigg]\\,{\\bf{i}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(\\frac{t}{t^{2}+1})}\\bigg]\\,{\\bf{j}}+\\bigg[\\displaystyle\\lim_{t{\\to}3}{(4t-3)}\\bigg]\\,{\\bf{k}}} \\hfill \\\\ \\hfill & =\\hfill & {\\frac{1}{2}\\,{\\bf{i}}+\\frac{3}{10}\\,{\\bf{j}}+9\\,{\\bf{k}}}\\hfill \\\\ \\hfill \\end{array}[\/latex]<\/div>\n<p>&nbsp;<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<p>Now that we can calculate limits of vector-valued functions, we can define what it means for such a function to be continuous.<\/p>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>continuity of a vector-valued function<\/h3>\n<p class=\"whitespace-normal break-words\">Let [latex]f[\/latex], [latex]g[\/latex], and [latex]h[\/latex] be functions of [latex]t[\/latex].<\/p>\n<p class=\"whitespace-normal break-words\">The vector-valued function [latex]{\\bf{r}}(t)=f(t){\\bf{i}}+g(t){\\bf{j}}[\/latex] is continuous at point [latex]t=a[\/latex] if three conditions hold:<\/p>\n<ol>\n<li>[latex]{\\bf{r}}\\,(a)[\/latex] exists<\/li>\n<li>[latex]\\displaystyle\\lim_{t{\\to}a}{\\bf{r}}\\,(t)[\/latex] exists<\/li>\n<li>[latex]\\displaystyle\\lim_{t{\\to}a}{\\bf{r}}\\,(t)={\\bf{r}}\\,(a)[\/latex]<\/li>\n<\/ol>\n<p>Similarly, [latex]{\\bf{r}}(t)=f(t){\\bf{i}}+g(t){\\bf{j}}+h(t){\\bf{k}}[\/latex] is continuous at point [latex]t=a[\/latex] if the same three conditions hold.<\/p>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">These three conditions should look familiar\u2014they&#8217;re the same requirements for continuity you learned with single-variable functions. A vector-valued function is continuous at a point when you can draw its graph through that point without lifting your pencil.<\/section>\n","protected":false},"author":15,"menu_order":8,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-949","chapter","type-chapter","status-publish","hentry"],"part":424,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/949","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":7,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/949\/revisions"}],"predecessor-version":[{"id":1752,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/949\/revisions\/1752"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/parts\/424"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/949\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/media?parent=949"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapter-type?post=949"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/contributor?post=949"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/license?post=949"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}