{"id":916,"date":"2025-10-14T15:55:51","date_gmt":"2025-10-14T15:55:51","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/calculus3\/?post_type=chapter&#038;p=916"},"modified":"2025-10-22T14:33:10","modified_gmt":"2025-10-22T14:33:10","slug":"lines-and-planes-in-space-learn-it-3","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/calculus3\/chapter\/lines-and-planes-in-space-learn-it-3\/","title":{"raw":"Lines and Planes in Space: Learn It 3","rendered":"Lines and Planes in Space: Learn It 3"},"content":{"raw":"<h2 data-type=\"title\">Relationships between Lines<\/h2>\r\n<div data-type=\"example\">\r\n<p class=\"whitespace-normal break-words\">In two dimensions, two lines have only three possible relationships: they are equal (the same line), parallel but distinct, or they intersect at exactly one point. Three dimensions introduces a fourth possibility that doesn't exist in 2D geometry.<\/p>\r\n<p class=\"whitespace-normal break-words\">When working with two lines in three-dimensional space, exactly one of these four relationships must be true:<\/p>\r\n\r\n<ol class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\"><strong>Equal lines<\/strong>: The lines are identical (same direction, same points)<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Parallel lines<\/strong>: The lines have the same direction but never meet<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Intersecting lines<\/strong>: The lines cross at exactly one point<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Skew lines<\/strong>: The lines are not parallel and do not intersect<\/li>\r\n<\/ol>\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>skew lines<\/h3>\r\nTwo lines are skew if they are not parallel but do not intersect. This relationship is unique to three-dimensional space and cannot occur in a plane.\r\n\r\n<\/section>\r\n\r\n[caption id=\"attachment_5166\" align=\"aligncenter\" width=\"418\"]<img class=\"size-full wp-image-5166\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27212930\/2.67.jpg\" alt=\"This figure has two line segments. They are 3-dimensional, are not parallel, and do not intersect. The directions are different and one is above the other.\" width=\"418\" height=\"117\" \/> Figure 5. In three dimensions, it is possible that two lines do not cross, even when they have different directions.[\/caption]\r\n\r\n<\/div>\r\n<div data-type=\"example\">\r\n<p class=\"whitespace-normal break-words\">To classify the relationship between two lines, we need to answer two key questions:<\/p>\r\n\r\n<ol class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal space-y-2.5 pl-7\">\r\n \t<li class=\"whitespace-normal break-words\"><strong>Are the direction vectors parallel?<\/strong> (Do the lines have the same or opposite directions?)<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Do the lines share any points?<\/strong> (Is there a common point on both lines?)<\/li>\r\n<\/ol>\r\nThe answers to these questions determine the relationship.\r\n\r\n<\/div>\r\n<div data-type=\"example\"><\/div>\r\n<div data-type=\"example\">\r\n\r\n[caption id=\"attachment_5167\" align=\"aligncenter\" width=\"610\"]<img class=\"size-full wp-image-5167\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213057\/2.68.jpg\" alt=\"This figure is a table with two rows and two columns. Above the columns is the question \u201cLines share a common point?\u201d The first column is labeled \u201cyes,\u201d and the second column is labeled \u201cno.\u201d To the left of the rows is the question \u201cDirection vectors are parallel?\u201d The first row is labeled \u201cyes,\u201d and the second row is labeled \u201cno.\u201d The entries of the first row are \u201cequal\u201d and \u201cparallel but not equal.\u201d The entries in the second row are \u201cintersecting\u201d and \u201cskew.\u201d\" width=\"610\" height=\"334\" \/> Figure 6. Determine the relationship between two lines based on whether their direction vectors are parallel and whether they share a point.[\/caption]\r\n\r\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\r\n<h3>line classification<\/h3>\r\n<ul>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Direction vectors parallel AND lines share a point<\/strong> \u2192 Lines are equal<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Direction vectors parallel AND lines share no points<\/strong> \u2192 Lines are parallel but distinct<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Direction vectors not parallel AND lines share a point<\/strong> \u2192 Lines intersect<\/li>\r\n \t<li class=\"whitespace-normal break-words\"><strong>Direction vectors not parallel AND lines share no points<\/strong> \u2192 Lines are skew<\/li>\r\n<\/ul>\r\n<\/section><section class=\"textbox proTip\" aria-label=\"Pro Tip\">In 2D, if two lines aren't parallel, they must intersect. In 3D, they might \"miss\" each other entirely\u2014imagine one line running east-west on the ground floor of a building while another runs north-south on the second floor.<\/section><\/div>\r\n<section class=\"textbox example\" aria-label=\"Example\">\r\n<p id=\"fs-id1163723283999\">For each pair of lines, determine whether the lines are equal, parallel but not equal, skew, or intersecting.<\/p>\r\n\r\n<ol id=\"fs-id1163723284004\" type=\"a\">\r\n \t<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=2s-1[\/latex],\u00a0[latex]y=s-1[\/latex],\u00a0[latex]z=s-4[\/latex]\r\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]x=t-3[\/latex],\u00a0[latex]y=3t+8[\/latex],\u00a0[latex]z=5-2t[\/latex]<\/li>\r\n \t<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=-y=z[\/latex]\r\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]\\frac{x-3}2=y=z-2[\/latex]<\/li>\r\n \t<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=6s-1[\/latex],\u00a0[latex]y=-2s[\/latex], [latex]z=3s+1[\/latex]\r\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]\\frac{x-4}6=\\frac{y+3}{-2}=\\frac{z-1}3[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"849520983\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"849520983\"]\r\n<ol id=\"fs-id1163724052863\" type=\"a\">\r\n \t<li>Line [latex]L_1[\/latex] has direction vector [latex]{\\bf{v_1}}=\\langle2,1,1\\rangle[\/latex]; line [latex]L_2[\/latex] has direction vector [latex]{\\bf{v_2}}=\\langle1,3,-2\\rangle[\/latex]. Because the direction vectors are not parallel vectors, the lines are either intersecting or skew. To determine whether the lines intersect, we see if there is a point, [latex](x, y, z)[\/latex], that lies on both lines. To find this point, we use the parametric equations to create a system of equalities:<span data-type=\"newline\">\r\n<\/span>\r\n<p style=\"text-align: center;\">[latex]2s-1=t-3; \\quad s-1=3t+8; \\quad s-4=5-2t[\/latex].<\/p>\r\n<span data-type=\"newline\">\r\n<\/span>By the first equation, [latex]t=2s+2[\/latex]. Substituting into the second equation yields<span data-type=\"newline\">\r\n<\/span>\r\n<p style=\"text-align: center;\">[latex]\\begin{aligned}\r\ns-1&amp;=3(2s+2)+8 \\\\\r\ns-1&amp;=6s+6+8 \\\\\r\n5s&amp;=-15 \\\\\r\ns&amp;=-3.\r\n\\end{aligned}[\/latex]<\/p>\r\n<span data-type=\"newline\">\r\n<\/span>Substitution into the third equation, however, yields a contradiction:<span data-type=\"newline\">\r\n<\/span>\r\n<p style=\"text-align: center;\">[latex]\\begin{aligned}\r\ns-4&amp;=5-2(2s+2) \\\\\r\ns-4&amp;=5-4s-4 \\\\\r\n5s&amp;=5 \\\\\r\ns&amp;=1.\r\n\\end{aligned}[\/latex]<\/p>\r\n<span data-type=\"newline\">\r\n<\/span>There is no single point that satisfies the parametric equations for [latex]L_1[\/latex] and [latex]L_2[\/latex] simultaneously. These lines do not intersect, so they are skew (see the following figure).<span data-type=\"newline\">\r\n<\/span>\r\n\r\n[caption id=\"attachment_5168\" align=\"aligncenter\" width=\"376\"]<img class=\"size-full wp-image-5168\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213249\/Example-2.48.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two skew lines drawn. They do not intersect and are not parallel.\" width=\"376\" height=\"380\" \/> Figure 7. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] are skew.[\/caption]<\/li>\r\n \t<li>Line [latex]L_1[\/latex] has direction vector [latex]{\\bf{v_1}}=\\langle1,-1,1\\rangle[\/latex] and passes through the origin, [latex](0, 0, 0)[\/latex]. Line [latex]L_2[\/latex] has a different direction vector, [latex]{\\bf{v_2}}=\\langle2,1,1\\rangle[\/latex], so these lines are not parallel or equal. Let [latex]r[\/latex] represent the parameter for line [latex]L_1[\/latex] and let [latex]s[\/latex] represent the parameter for [latex]L_2[\/latex]:<span data-type=\"newline\">\r\n<\/span>\r\n<p style=\"text-align: center;\">[latex]\\begin{aligned}\r\nx&amp;=r &amp;\\quad x&amp;=2s+3 \\\\\r\ny&amp;=-r &amp;\\quad y&amp;=s \\\\\r\nz&amp;=r &amp;\\quad z&amp;=s+2\r\n\\end{aligned}[\/latex].<\/p>\r\n<span data-type=\"newline\">\r\n<\/span>Solve the system of equations to find [latex]r=1[\/latex] and [latex]s=-1[\/latex]. If we need to find the point of intersection, we can substitute these parameters into the original equations to get [latex](1, -1, 1)[\/latex] (see the following figure).<span data-type=\"newline\">\r\n<\/span>\r\n\r\n[caption id=\"attachment_5169\" align=\"aligncenter\" width=\"514\"]<img class=\"size-full wp-image-5169\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213452\/Example-2.48b.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two lines drawn. They intersect at the point (1,-1,1).\" width=\"514\" height=\"501\" \/> Figure 8. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] intersect at [latex](1, -1, 1)[\/latex].[\/caption]<\/li>\r\n \t<li>Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] have equivalent direction vectors: [latex]{\\bf{v}}=\\langle6,-2,3\\rangle[\/latex]. These two lines are parallel (see the following figure).<span data-type=\"newline\">\r\n<\/span>[caption id=\"attachment_5170\" align=\"aligncenter\" width=\"397\"]<img class=\"size-full wp-image-5170\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213531\/Example-2.48c.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two lines drawn. They do not intersect and are parallel.\" width=\"397\" height=\"378\" \/> Figure 9. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] are parallel.[\/caption]<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<\/section>","rendered":"<h2 data-type=\"title\">Relationships between Lines<\/h2>\n<div data-type=\"example\">\n<p class=\"whitespace-normal break-words\">In two dimensions, two lines have only three possible relationships: they are equal (the same line), parallel but distinct, or they intersect at exactly one point. Three dimensions introduces a fourth possibility that doesn&#8217;t exist in 2D geometry.<\/p>\n<p class=\"whitespace-normal break-words\">When working with two lines in three-dimensional space, exactly one of these four relationships must be true:<\/p>\n<ol class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\"><strong>Equal lines<\/strong>: The lines are identical (same direction, same points)<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Parallel lines<\/strong>: The lines have the same direction but never meet<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Intersecting lines<\/strong>: The lines cross at exactly one point<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Skew lines<\/strong>: The lines are not parallel and do not intersect<\/li>\n<\/ol>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>skew lines<\/h3>\n<p>Two lines are skew if they are not parallel but do not intersect. This relationship is unique to three-dimensional space and cannot occur in a plane.<\/p>\n<\/section>\n<figure id=\"attachment_5166\" aria-describedby=\"caption-attachment-5166\" style=\"width: 418px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5166\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27212930\/2.67.jpg\" alt=\"This figure has two line segments. They are 3-dimensional, are not parallel, and do not intersect. The directions are different and one is above the other.\" width=\"418\" height=\"117\" \/><figcaption id=\"caption-attachment-5166\" class=\"wp-caption-text\">Figure 5. In three dimensions, it is possible that two lines do not cross, even when they have different directions.<\/figcaption><\/figure>\n<\/div>\n<div data-type=\"example\">\n<p class=\"whitespace-normal break-words\">To classify the relationship between two lines, we need to answer two key questions:<\/p>\n<ol class=\"[&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-decimal space-y-2.5 pl-7\">\n<li class=\"whitespace-normal break-words\"><strong>Are the direction vectors parallel?<\/strong> (Do the lines have the same or opposite directions?)<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Do the lines share any points?<\/strong> (Is there a common point on both lines?)<\/li>\n<\/ol>\n<p>The answers to these questions determine the relationship.<\/p>\n<\/div>\n<div data-type=\"example\"><\/div>\n<div data-type=\"example\">\n<figure id=\"attachment_5167\" aria-describedby=\"caption-attachment-5167\" style=\"width: 610px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5167\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213057\/2.68.jpg\" alt=\"This figure is a table with two rows and two columns. Above the columns is the question \u201cLines share a common point?\u201d The first column is labeled \u201cyes,\u201d and the second column is labeled \u201cno.\u201d To the left of the rows is the question \u201cDirection vectors are parallel?\u201d The first row is labeled \u201cyes,\u201d and the second row is labeled \u201cno.\u201d The entries of the first row are \u201cequal\u201d and \u201cparallel but not equal.\u201d The entries in the second row are \u201cintersecting\u201d and \u201cskew.\u201d\" width=\"610\" height=\"334\" \/><figcaption id=\"caption-attachment-5167\" class=\"wp-caption-text\">Figure 6. Determine the relationship between two lines based on whether their direction vectors are parallel and whether they share a point.<\/figcaption><\/figure>\n<section class=\"textbox keyTakeaway\" aria-label=\"Key Takeaway\">\n<h3>line classification<\/h3>\n<ul>\n<li class=\"whitespace-normal break-words\"><strong>Direction vectors parallel AND lines share a point<\/strong> \u2192 Lines are equal<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Direction vectors parallel AND lines share no points<\/strong> \u2192 Lines are parallel but distinct<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Direction vectors not parallel AND lines share a point<\/strong> \u2192 Lines intersect<\/li>\n<li class=\"whitespace-normal break-words\"><strong>Direction vectors not parallel AND lines share no points<\/strong> \u2192 Lines are skew<\/li>\n<\/ul>\n<\/section>\n<section class=\"textbox proTip\" aria-label=\"Pro Tip\">In 2D, if two lines aren&#8217;t parallel, they must intersect. In 3D, they might &#8220;miss&#8221; each other entirely\u2014imagine one line running east-west on the ground floor of a building while another runs north-south on the second floor.<\/section>\n<\/div>\n<section class=\"textbox example\" aria-label=\"Example\">\n<p id=\"fs-id1163723283999\">For each pair of lines, determine whether the lines are equal, parallel but not equal, skew, or intersecting.<\/p>\n<ol id=\"fs-id1163723284004\" type=\"a\">\n<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=2s-1[\/latex],\u00a0[latex]y=s-1[\/latex],\u00a0[latex]z=s-4[\/latex]<br \/>\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]x=t-3[\/latex],\u00a0[latex]y=3t+8[\/latex],\u00a0[latex]z=5-2t[\/latex]<\/li>\n<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=-y=z[\/latex]<br \/>\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]\\frac{x-3}2=y=z-2[\/latex]<\/li>\n<li><span data-type=\"newline\">[latex]L_1[\/latex]:\u00a0[latex]x=6s-1[\/latex],\u00a0[latex]y=-2s[\/latex], [latex]z=3s+1[\/latex]<br \/>\n<\/span>[latex]L_2[\/latex]:\u00a0[latex]\\frac{x-4}6=\\frac{y+3}{-2}=\\frac{z-1}3[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"q849520983\">Show Solution<\/button><\/p>\n<div id=\"q849520983\" class=\"hidden-answer\" style=\"display: none\">\n<ol id=\"fs-id1163724052863\" type=\"a\">\n<li>Line [latex]L_1[\/latex] has direction vector [latex]{\\bf{v_1}}=\\langle2,1,1\\rangle[\/latex]; line [latex]L_2[\/latex] has direction vector [latex]{\\bf{v_2}}=\\langle1,3,-2\\rangle[\/latex]. Because the direction vectors are not parallel vectors, the lines are either intersecting or skew. To determine whether the lines intersect, we see if there is a point, [latex](x, y, z)[\/latex], that lies on both lines. To find this point, we use the parametric equations to create a system of equalities:<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<p style=\"text-align: center;\">[latex]2s-1=t-3; \\quad s-1=3t+8; \\quad s-4=5-2t[\/latex].<\/p>\n<p><span data-type=\"newline\"><br \/>\n<\/span>By the first equation, [latex]t=2s+2[\/latex]. Substituting into the second equation yields<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<p style=\"text-align: center;\">[latex]\\begin{aligned}  s-1&=3(2s+2)+8 \\\\  s-1&=6s+6+8 \\\\  5s&=-15 \\\\  s&=-3.  \\end{aligned}[\/latex]<\/p>\n<p><span data-type=\"newline\"><br \/>\n<\/span>Substitution into the third equation, however, yields a contradiction:<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<p style=\"text-align: center;\">[latex]\\begin{aligned}  s-4&=5-2(2s+2) \\\\  s-4&=5-4s-4 \\\\  5s&=5 \\\\  s&=1.  \\end{aligned}[\/latex]<\/p>\n<p><span data-type=\"newline\"><br \/>\n<\/span>There is no single point that satisfies the parametric equations for [latex]L_1[\/latex] and [latex]L_2[\/latex] simultaneously. These lines do not intersect, so they are skew (see the following figure).<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<figure id=\"attachment_5168\" aria-describedby=\"caption-attachment-5168\" style=\"width: 376px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5168\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213249\/Example-2.48.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two skew lines drawn. They do not intersect and are not parallel.\" width=\"376\" height=\"380\" \/><figcaption id=\"caption-attachment-5168\" class=\"wp-caption-text\">Figure 7. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] are skew.<\/figcaption><\/figure>\n<\/li>\n<li>Line [latex]L_1[\/latex] has direction vector [latex]{\\bf{v_1}}=\\langle1,-1,1\\rangle[\/latex] and passes through the origin, [latex](0, 0, 0)[\/latex]. Line [latex]L_2[\/latex] has a different direction vector, [latex]{\\bf{v_2}}=\\langle2,1,1\\rangle[\/latex], so these lines are not parallel or equal. Let [latex]r[\/latex] represent the parameter for line [latex]L_1[\/latex] and let [latex]s[\/latex] represent the parameter for [latex]L_2[\/latex]:<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<p style=\"text-align: center;\">[latex]\\begin{aligned}  x&=r &\\quad x&=2s+3 \\\\  y&=-r &\\quad y&=s \\\\  z&=r &\\quad z&=s+2  \\end{aligned}[\/latex].<\/p>\n<p><span data-type=\"newline\"><br \/>\n<\/span>Solve the system of equations to find [latex]r=1[\/latex] and [latex]s=-1[\/latex]. If we need to find the point of intersection, we can substitute these parameters into the original equations to get [latex](1, -1, 1)[\/latex] (see the following figure).<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<figure id=\"attachment_5169\" aria-describedby=\"caption-attachment-5169\" style=\"width: 514px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5169\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213452\/Example-2.48b.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two lines drawn. They intersect at the point (1,-1,1).\" width=\"514\" height=\"501\" \/><figcaption id=\"caption-attachment-5169\" class=\"wp-caption-text\">Figure 8. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] intersect at [latex](1, -1, 1)[\/latex].<\/figcaption><\/figure>\n<\/li>\n<li>Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] have equivalent direction vectors: [latex]{\\bf{v}}=\\langle6,-2,3\\rangle[\/latex]. These two lines are parallel (see the following figure).<span data-type=\"newline\"><br \/>\n<\/span><\/p>\n<figure id=\"attachment_5170\" aria-describedby=\"caption-attachment-5170\" style=\"width: 397px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-5170\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/5667\/2021\/08\/27213531\/Example-2.48c.jpg\" alt=\"This figure is the 3-dimensional coordinate system. There are two lines drawn. They do not intersect and are parallel.\" width=\"397\" height=\"378\" \/><figcaption id=\"caption-attachment-5170\" class=\"wp-caption-text\">Figure 9. Lines [latex]L_1[\/latex] and [latex]L_2[\/latex] are parallel.<\/figcaption><\/figure>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/section>\n","protected":false},"author":15,"menu_order":13,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-916","chapter","type-chapter","status-publish","hentry"],"part":422,"module-header":"- Select Header -","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/916","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":4,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/916\/revisions"}],"predecessor-version":[{"id":1675,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/916\/revisions\/1675"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/parts\/422"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapters\/916\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/media?parent=916"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/pressbooks\/v2\/chapter-type?post=916"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/contributor?post=916"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus3\/wp-json\/wp\/v2\/license?post=916"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}