{"id":1137,"date":"2024-04-11T16:52:46","date_gmt":"2024-04-11T16:52:46","guid":{"rendered":"https:\/\/content.one.lumenlearning.com\/calculus1\/?post_type=chapter&#038;p=1137"},"modified":"2024-08-05T12:27:45","modified_gmt":"2024-08-05T12:27:45","slug":"inverse-functions-learn-it-2","status":"publish","type":"chapter","link":"https:\/\/content.one.lumenlearning.com\/calculus1\/chapter\/inverse-functions-learn-it-2\/","title":{"raw":"Inverse Functions: Learn It 2","rendered":"Inverse Functions: Learn It 2"},"content":{"raw":"<h2>Finding a Function\u2019s Inverse<\/h2>\r\n<p id=\"fs-id1170572150503\">To find the inverse of a function, you first ensure the function is one-to-one.\u00a0<\/p>\r\n<p>When given a one-to-one function, to find its inverse, solve the equation[latex] y=f(x)[\/latex] for [latex]x[\/latex], and then swap the roles of [latex]x[\/latex] and [latex]y[\/latex]. The new equation [latex]x=f^{\u22121}(y)[\/latex] represents the inverse function [latex]f^{-1}[\/latex], which switches the original function\u2019s inputs and outputs. This process is essential when plotting both the function and its inverse on the same graph, as their coordinates are reflections of each other across the line [latex]y=x[\/latex].<\/p>\r\n<section class=\"textbox questionHelp\">\r\n<p><strong>How to: Find an Inverse Function<\/strong><\/p>\r\n<ol id=\"fs-id1170572450945\">\r\n\t<li>Solve the equation [latex]y=f(x)[\/latex] for [latex]x[\/latex].<\/li>\r\n\t<li>Interchange the variables [latex]x[\/latex] and [latex]y[\/latex] and write [latex]y=f^{-1}(x)[\/latex].<\/li>\r\n<\/ol>\r\n<\/section>\r\n<p>To complete the first step to finding an inverse function, we must isolate a variable in a given equation.<\/p>\r\n<section class=\"textbox recall\">\r\n<p><strong>Recall Isolating a Variable in a Formula<\/strong><\/p>\r\n<ol>\r\n\t<li>Identify the variable you want to isolate and the terms it's associated with.<\/li>\r\n\t<li>Use inverse operations to 'undo' any arithmetic or algebraic actions applied to the variable (addition is undone by subtraction, multiplication by division, etc.).<\/li>\r\n\t<li>Perform the same operation on both sides of the equation to maintain equality.<\/li>\r\n\t<li>Repeat the process until the variable is by itself on one side of the equation.<\/li>\r\n\t<li>Simplify the equation as needed to achieve the simplest form with the variable isolated.<\/li>\r\n<\/ol>\r\n<\/section>\r\n<section class=\"textbox example\">\r\n<p id=\"fs-id1170572546520\">Find the inverse for the function [latex]f(x)=3x-4[\/latex]. State the domain and range of the inverse function. Verify that [latex]f^{-1}(f(x))=x[\/latex].<\/p>\r\n<p>[reveal-answer q=\"fs-id1170572481500\"]Show Solution[\/reveal-answer]<br \/>\r\n[hidden-answer a=\"fs-id1170572481500\"]<\/p>\r\n<p id=\"fs-id1170572481500\">Follow the steps outlined in the strategy.<\/p>\r\n<p id=\"fs-id1170572548820\">Step 1. If [latex]y=3x-4[\/latex], then [latex]3x=y+4[\/latex] and [latex]x=\\frac{1}{3}y+\\frac{4}{3}[\/latex].<\/p>\r\n<p id=\"fs-id1170572479776\">Step 2. Rewrite as [latex]y=\\frac{1}{3}x+\\frac{4}{3}[\/latex] and let [latex]y=f^{-1}(x)[\/latex].<\/p>\r\n<p id=\"fs-id1170572453043\">Therefore, [latex]f^{-1}(x)=\\frac{1}{3}x+\\frac{4}{3}[\/latex].<\/p>\r\n<p id=\"fs-id1170572240611\">Since the domain of [latex]f[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex], the range of [latex]f^{-1}[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex]. Since the range of [latex]f[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex], the domain of [latex]f^{-1}[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex].<\/p>\r\n<p id=\"fs-id1170572222969\">You can verify that [latex]f^{-1}(f(x))=x[\/latex] by writing<\/p>\r\n<div id=\"fs-id1170572453591\" class=\"equation unnumbered\">[latex]f^{-1}(f(x))=f^{-1}(3x-4)=\\frac{1}{3}(3x-4)+\\frac{4}{3}=x-\\frac{4}{3}+\\frac{4}{3}=x[\/latex].<\/div>\r\n<p>&nbsp;<\/p>\r\n<p id=\"fs-id1170572546429\">Note that for [latex]f^{-1}(x)[\/latex] to be the inverse of [latex]f(x)[\/latex], both [latex]f^{-1}(f(x))=x[\/latex] and [latex]f(f^{-1}(x))=x[\/latex] for all [latex]x[\/latex] in the domain of the inside function.<\/p>\r\n\r\nWatch the following video to see the worked solution to this example.<center><iframe title=\"YouTube video player\" src=\"https:\/\/www.youtube.com\/embed\/JFQ8maupdT8?controls=0&amp;start=215&amp;end=405&amp;autoplay=0\" width=\"750\" height=\"450\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" data-mce-fragment=\"1\"><\/iframe><\/center>For closed captioning, open the video on its original page by clicking the Youtube logo in the lower right-hand corner of the video display. In YouTube, the video will begin at the same starting point as this clip, but will continue playing until the very end.\r\n\r\n<p>You can view the transcript for this video using <a href=\"https:\/\/oerfiles.s3.us-west-2.amazonaws.com\/Calculus\/Calculus1+Videos\/1.4InverseFunctions215to405_transcript.txt\" target=\"_blank\" rel=\"noopener\">this link<\/a> (opens in new window).<\/p>\r\n<p>[\/hidden-answer]<\/p>\r\n<\/section>\r\n<section class=\"textbox tryIt\">\r\n<p>[ohm_question hide_question_numbers=1]217478[\/ohm_question]<\/p>\r\n<\/section>","rendered":"<h2>Finding a Function\u2019s Inverse<\/h2>\n<p id=\"fs-id1170572150503\">To find the inverse of a function, you first ensure the function is one-to-one.\u00a0<\/p>\n<p>When given a one-to-one function, to find its inverse, solve the equation[latex]y=f(x)[\/latex] for [latex]x[\/latex], and then swap the roles of [latex]x[\/latex] and [latex]y[\/latex]. The new equation [latex]x=f^{\u22121}(y)[\/latex] represents the inverse function [latex]f^{-1}[\/latex], which switches the original function\u2019s inputs and outputs. This process is essential when plotting both the function and its inverse on the same graph, as their coordinates are reflections of each other across the line [latex]y=x[\/latex].<\/p>\n<section class=\"textbox questionHelp\">\n<p><strong>How to: Find an Inverse Function<\/strong><\/p>\n<ol id=\"fs-id1170572450945\">\n<li>Solve the equation [latex]y=f(x)[\/latex] for [latex]x[\/latex].<\/li>\n<li>Interchange the variables [latex]x[\/latex] and [latex]y[\/latex] and write [latex]y=f^{-1}(x)[\/latex].<\/li>\n<\/ol>\n<\/section>\n<p>To complete the first step to finding an inverse function, we must isolate a variable in a given equation.<\/p>\n<section class=\"textbox recall\">\n<p><strong>Recall Isolating a Variable in a Formula<\/strong><\/p>\n<ol>\n<li>Identify the variable you want to isolate and the terms it&#8217;s associated with.<\/li>\n<li>Use inverse operations to &#8216;undo&#8217; any arithmetic or algebraic actions applied to the variable (addition is undone by subtraction, multiplication by division, etc.).<\/li>\n<li>Perform the same operation on both sides of the equation to maintain equality.<\/li>\n<li>Repeat the process until the variable is by itself on one side of the equation.<\/li>\n<li>Simplify the equation as needed to achieve the simplest form with the variable isolated.<\/li>\n<\/ol>\n<\/section>\n<section class=\"textbox example\">\n<p id=\"fs-id1170572546520\">Find the inverse for the function [latex]f(x)=3x-4[\/latex]. State the domain and range of the inverse function. Verify that [latex]f^{-1}(f(x))=x[\/latex].<\/p>\n<p><div class=\"qa-wrapper\" style=\"display: block\"><button class=\"show-answer show-answer-button collapsed\" data-target=\"qfs-id1170572481500\">Show Solution<\/button><\/p>\n<div id=\"qfs-id1170572481500\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1170572481500\">Follow the steps outlined in the strategy.<\/p>\n<p id=\"fs-id1170572548820\">Step 1. If [latex]y=3x-4[\/latex], then [latex]3x=y+4[\/latex] and [latex]x=\\frac{1}{3}y+\\frac{4}{3}[\/latex].<\/p>\n<p id=\"fs-id1170572479776\">Step 2. Rewrite as [latex]y=\\frac{1}{3}x+\\frac{4}{3}[\/latex] and let [latex]y=f^{-1}(x)[\/latex].<\/p>\n<p id=\"fs-id1170572453043\">Therefore, [latex]f^{-1}(x)=\\frac{1}{3}x+\\frac{4}{3}[\/latex].<\/p>\n<p id=\"fs-id1170572240611\">Since the domain of [latex]f[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex], the range of [latex]f^{-1}[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex]. Since the range of [latex]f[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex], the domain of [latex]f^{-1}[\/latex] is [latex](\u2212\\infty ,\\infty)[\/latex].<\/p>\n<p id=\"fs-id1170572222969\">You can verify that [latex]f^{-1}(f(x))=x[\/latex] by writing<\/p>\n<div id=\"fs-id1170572453591\" class=\"equation unnumbered\">[latex]f^{-1}(f(x))=f^{-1}(3x-4)=\\frac{1}{3}(3x-4)+\\frac{4}{3}=x-\\frac{4}{3}+\\frac{4}{3}=x[\/latex].<\/div>\n<p>&nbsp;<\/p>\n<p id=\"fs-id1170572546429\">Note that for [latex]f^{-1}(x)[\/latex] to be the inverse of [latex]f(x)[\/latex], both [latex]f^{-1}(f(x))=x[\/latex] and [latex]f(f^{-1}(x))=x[\/latex] for all [latex]x[\/latex] in the domain of the inside function.<\/p>\n<p>Watch the following video to see the worked solution to this example.<\/p>\n<div style=\"text-align: center;\"><iframe loading=\"lazy\" title=\"YouTube video player\" src=\"https:\/\/www.youtube.com\/embed\/JFQ8maupdT8?controls=0&amp;start=215&amp;end=405&amp;autoplay=0\" width=\"750\" height=\"450\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" data-mce-fragment=\"1\"><\/iframe><\/div>\n<p>For closed captioning, open the video on its original page by clicking the Youtube logo in the lower right-hand corner of the video display. In YouTube, the video will begin at the same starting point as this clip, but will continue playing until the very end.<\/p>\n<p>You can view the transcript for this video using <a href=\"https:\/\/oerfiles.s3.us-west-2.amazonaws.com\/Calculus\/Calculus1+Videos\/1.4InverseFunctions215to405_transcript.txt\" target=\"_blank\" rel=\"noopener\">this link<\/a> (opens in new window).<\/p>\n<\/div>\n<\/div>\n<\/section>\n<section class=\"textbox tryIt\">\n<iframe loading=\"lazy\" id=\"ohm217478\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=217478&theme=lumen&iframe_resize_id=ohm217478&source=tnh\" width=\"100%\" height=\"150\"><\/iframe><br \/>\n<\/section>\n","protected":false},"author":15,"menu_order":12,"template":"","meta":{"_candela_citation":"[]","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"part":759,"module-header":"learn_it","content_attributions":[],"internal_book_links":[],"video_content":null,"cc_video_embed_content":{"cc_scripts":"","media_targets":[]},"try_it_collection":null,"_links":{"self":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapters\/1137"}],"collection":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/wp\/v2\/users\/15"}],"version-history":[{"count":6,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapters\/1137\/revisions"}],"predecessor-version":[{"id":4475,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapters\/1137\/revisions\/4475"}],"part":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/parts\/759"}],"metadata":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapters\/1137\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/wp\/v2\/media?parent=1137"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/pressbooks\/v2\/chapter-type?post=1137"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/wp\/v2\/contributor?post=1137"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/content.one.lumenlearning.com\/calculus1\/wp-json\/wp\/v2\/license?post=1137"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}