Defining the Derivative: Fresh Take

  • Calculate the slope of a tangent line to a curve and find its equation
  • Find the derivative of a function at a given point
  • Explain how velocity measures speed over time, and compare average velocity over a period with the exact speed at a specific moment

Tangent Lines

The Main Idea 

  • Secant Lines and Difference Quotients:
    • Slope of a secant line: [latex]m_{\text{sec}} = \frac{f(x) - f(a)}{x - a}[/latex]
    • Difference quotient with increment [latex]h[/latex]: [latex]Q = \frac{f(a+h) - f(a)}{h}[/latex]
  • Tangent Lines:
    • Limit of secant lines as they approach a point
    • Slope of tangent line: [latex]m_{\text{tan}} = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}[/latex] or [latex]m_{\text{tan}} = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}[/latex]
  • Local Linearity:
    • Near the point of tangency, the function appears linear
    • Tangent line provides a good approximation of the function
  • Equation of Tangent Line:
    • Use point-slope form: [latex]y - y_1 = m(x - x_1)[/latex]
    • [latex](x_1, y_1)[/latex] is the point of tangency, [latex]m[/latex] is the slope of the tangent line

Find the equation of the line tangent to the graph of [latex]f(x)=\dfrac{1}{x}[/latex] at [latex]x=2[/latex].

Find the slope of the line tangent to the graph of [latex]f(x)=\sqrt{x}[/latex] at [latex]x=4[/latex].

Watch the following video to see the worked solution to this example.

For closed captioning, open the video on its original page by clicking the Youtube logo in the lower right-hand corner of the video display. In YouTube, the video will begin at the same starting point as this clip, but will continue playing until the very end.

You can view the transcript for this segmented clip of “3.1 Defining the Derivative” here (opens in new window).

Find the equation of the line tangent to [latex]f(x) = x^2[/latex] at [latex]x = 3[/latex].

The Derivative of a Function at a Point

The Main Idea 

  • Definition of the Derivative:
    • The derivative is the instantaneous rate of change of a function at a point
    • It’s equivalent to the slope of the tangent line at that point
  • Notations for the Derivative:
    • [latex]f'(a)[/latex] denotes the derivative of [latex]f(x)[/latex] at [latex]x = a[/latex]
  • Two Equivalent Definitions:
    • [latex]f'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}[/latex]
    • [latex]f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}[/latex]
  • Formal definition of a derivative:

               The derivative of a function [latex]f(x)[/latex] at a point [latex]a[/latex] is defined as:

    [latex]f'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}[/latex]

               or equivalently:

    [latex]f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h}[/latex]

               provided these limits exist.

For [latex]f(x)=3x^2-4x+1[/latex], find [latex]f^{\prime}(2)[/latex] by using the first definition.

For [latex]f(x)=x^2+3x+2[/latex], find [latex]f^{\prime}(1)[/latex].

Watch the following video to see the worked solution to this example.

For closed captioning, open the video on its original page by clicking the Youtube logo in the lower right-hand corner of the video display. In YouTube, the video will begin at the same starting point as this clip, but will continue playing until the very end.

You can view the transcript for this segmented clip of “3.1 Defining the Derivative” here (opens in new window).

Find [latex]f'(2)[/latex] for [latex]f(x) = 3x^2 - 4x + 1[/latex] using the second definition.

Velocities and Rates of Change

The Main Idea 

  • Average Velocity:
    • For a position function [latex]s(t)[/latex], average velocity over [latex][a,t][/latex] is: [latex]v_{\text{avg}} = \frac{s(t) - s(a)}{t - a}[/latex]
  • Instantaneous Velocity:
    • Limit of average velocity as time interval approaches zero
    • Equivalent to the derivative of the position function: [latex]v(a) = s'(a) = \lim_{t \to a} \frac{s(t) - s(a)}{t - a}[/latex]
  • Instantaneous Rate of Change:
    • Generalization of instantaneous velocity to any function
    • For a function [latex]f(x)[/latex], the instantaneous rate of change at [latex]a[/latex] is [latex]f'(a)[/latex]
  • Graphical Interpretation:
    • Average velocity: Slope of secant line
    • Instantaneous velocity: Slope of tangent line

A rock is dropped from a height of [latex]64[/latex] feet. Its height above ground at time [latex]t[/latex] seconds later is given by [latex]s(t)=-16t^2+64, \, 0\le t\le 2[/latex]. Find its instantaneous velocity [latex]1[/latex] second after it is dropped, using the definition of a derivative.

Watch the following video to see the worked solution to this example.

For closed captioning, open the video on its original page by clicking the Youtube logo in the lower right-hand corner of the video display. In YouTube, the video will begin at the same starting point as this clip, but will continue playing until the very end.

You can view the transcript for this segmented clip of “3.1 Defining the Derivative” here (opens in new window).

A toy company can sell [latex]x[/latex] electronic gaming systems at a price of [latex]p=-0.01x+400[/latex] dollars per gaming system. The cost of manufacturing [latex]x[/latex] systems is given by [latex]C(x)=100x+10,000[/latex] dollars. Find the rate of change of profit when [latex]10,000[/latex] games are produced. Should the toy company increase or decrease production?