We now know that the slope of the tangent line is [latex]-\frac{1}{4}[/latex]. To find the equation of the tangent line, we also need a point on the line. We know that [latex]f(2)=\frac{1}{2}[/latex]. Since the tangent line passes through the point [latex](2,\frac{1}{2})[/latex] we can use the point-slope equation of a line to find the equation of the tangent line. Thus the tangent line has the equation [latex]y=-\frac{1}{4}x+1[/latex]. The graphs of [latex]f(x)=\frac{1}{x}[/latex] and [latex]y=-\frac{1}{4}x+1[/latex] are shown in Figure 6.
Find the slope of the line tangent to the graph of [latex]f(x)=\sqrt{x}[/latex] at [latex]x=4[/latex].
Use either definition. Multiply the numerator and the denominator by a conjugate.
[latex]\dfrac{1}{4}[/latex]
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For [latex]f(x)=3x^2-4x+1[/latex], find [latex]f^{\prime}(2)[/latex] by using the first definition.
Substitute the given function and value directly into the equation.
[latex]\begin{array}{lllll}f^{\prime}(x)& =\underset{x\to 2}{\lim}\frac{f(x)-f(2)}{x-2} & & & \text{Apply the definition.} \\ & =\underset{x\to 2}{\lim}\frac{(3x^2-4x+1)-5}{x-2} & & & \text{Substitute} \, f(x)=3x^2-4x+1 \, \text{and} \, f(2)=5. \\ & =\underset{x\to 2}{\lim}\frac{(x-2)(3x+2)}{x-2} & & & \text{Simplify and factor the numerator.} \\ & =\underset{x\to 2}{\lim}(3x+2) & & & \text{Cancel the common factor.} \\ & =8 & & & \text{Evaluate the limit.} \end{array}[/latex]
For [latex]f(x)=x^2+3x+2[/latex], find [latex]f^{\prime}(1)[/latex].
Use either the first definition, the second, or try both.
[latex]f^{\prime}(1)=5[/latex]
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For a position function [latex]s(t)[/latex], average velocity over [latex][a,t][/latex] is: [latex]v_{\text{avg}} = \frac{s(t) - s(a)}{t - a}[/latex]
Instantaneous Velocity:
Limit of average velocity as time interval approaches zero
Equivalent to the derivative of the position function: [latex]v(a) = s'(a) = \lim_{t \to a} \frac{s(t) - s(a)}{t - a}[/latex]
Instantaneous Rate of Change:
Generalization of instantaneous velocity to any function
For a function [latex]f(x)[/latex], the instantaneous rate of change at [latex]a[/latex] is [latex]f'(a)[/latex]
Graphical Interpretation:
Average velocity: Slope of secant line
Instantaneous velocity: Slope of tangent line
A rock is dropped from a height of [latex]64[/latex] feet. Its height above ground at time [latex]t[/latex] seconds later is given by [latex]s(t)=-16t^2+64, \, 0\le t\le 2[/latex]. Find its instantaneous velocity [latex]1[/latex] second after it is dropped, using the definition of a derivative.
[latex]v(t)=s^{\prime}(t)[/latex].
[latex]-32[/latex] ft/sec
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A toy company can sell [latex]x[/latex] electronic gaming systems at a price of [latex]p=-0.01x+400[/latex] dollars per gaming system. The cost of manufacturing [latex]x[/latex] systems is given by [latex]C(x)=100x+10,000[/latex] dollars. Find the rate of change of profit when [latex]10,000[/latex] games are produced. Should the toy company increase or decrease production?
The profit [latex]P(x)[/latex] earned by producing [latex]x[/latex] gaming systems is [latex]R(x)-C(x)[/latex], where [latex]R(x)[/latex] is the revenue obtained from the sale of [latex]x[/latex] games. Since the company can sell [latex]x[/latex] games at [latex]p=-0.01x+400[/latex] per game,